removing comma from number in sybase - parsing

i have this morning an issue with 1 field. In particular i have a number with decimal separation that is not expected. E.G -98,060;
sometime the numbers are without the comma so -2032; -3452; etc. How can i update below query so that i can replace number with -98,060; like this -98060 ?
thank you
CONVERT(NUMERIC(20,6),SUBSTRING(case when rtrim(ltrim(tab1.comment)) is not null
then tab1.comment else '0;0' end,1,(CHARINDEX(';',case when rtrim(ltrim(tab1.comment)) is not null
then tab1.comment else '0;0' end)-1))) as COMMENT,
The above logic currently transform the value from -24556; to -24556 without ";"
Now that i have -98,060; so a value with a command inside the above formula crashed. How can i update above formula so that after the transformation of number like this -98,060; i have -98060 ? thank you

Related

COUNTIF with IMPORTRANGE result keep showing only 0 or 1? WHY?

I have one spreadheet that includes name, id and amount of numbers data in it and i want to make the report in other spreadsheet.
i want to count the name column that is not blank, so i type this
=COUNTIF(importrange("gsheet link","Payroll 16-31 Jan!B3:B"),"<>")
but the result is "1" in fact that there are 3670 names on the column
=COUNTIF(importrange("gsheet link","Payroll 16-31 Jan!B3:B"),"<>"&"")
but still not working
can someone help?
I want to get the exact calculation of those data
Two things: have you connected the spreadsheets? If not, use IMPORTRANGE outside COUNTIF, something like =importrange("gsheet link","A1") . Accept the permissions and see if COUNTIF now does it right
If it doesn't, try with COUNTA that is specifically defined for counting non blank cells:. =COUNTA(importrange("gsheet link","Payroll 16-31 Jan!B3:B"))

How can I get the last numerical value value in a column in Google Sheets?

I need to find the last numerical value in a column. I was using this formula to get the last value in column G, but I made some changes and it no longer works: =INDEX(G:G, COUNTA(G:G), 1). My column now looks like this:
645
2345
4674.2345
123.1
"-"
"-"
"-"
...and the formula returns "-". I want it to return 123.1. How can I do this?
There are many ways to go about this. Here is one of them:
=QUERY(FILTER({G:G,ROW(G:G)},ISNUMBER(G:G)),"Select Col1 ORDER BY Col2 Desc LIMIT 1")
FILTER creates a virtual array of only numeric values in G in the first column and the row of those numeric values in the second column.
QUERY returns flips the order by row number and returns only the new top value from the first column (which winds up being your last numeric value in the original range).
However, if your numeric values start at G1, and if there are only numeric values up to where you start adding hyphens in cells, you could just alter your original formula like this:
=INDEX(G:G,COUNT(G:G))
This would work because COUNT only counts numeric values while COUNTA counts all non-null values (including errors BTW).
Not to take anything away from the accepted answer, but I've been working on this a bit lately in relation to this for the never-ending last row discussion and thought I'd share some potential similar solutions. These ideas are inspired by a pattern of google sheet array questions that seem to be coming up more often. I am also intentionally using different ways to do the same thing just to give people some ideas (i.e. left and Regex).
Last Row that is...
Number: =max(filter(row(G:G),isnumber(G:G)))
Text: =max(filter(row(G:G),isText(G:G)))
An error: =max(filter(row(G:G),iserror(G:G)))
Under 0 : =max(filter(row(G:G),G:G<0))
Also exists in column D: =max(filter(row(G:G),ISNUMBER(match(G:G,D:D,0))))
Not Blank: =max(filter(row(A:A),NOT(ISBLANK(A:A))))
Starts with ab: =max(filter(row(G:G),left(G:G,2)="ab"))
Contains the character !: =max(filter(row(G:G),isnumber(Find("!",G:G))))
Starts with a number: =max(filter(row(G:G),REGEXMATCH(G:G,"^\d")))
Only contains letters: =max(filter(row(G:G),REGEXMATCH(G:G,"^[a-zA-Z]+$")
Last four digits are upper case: =Max(filter(row(G:G),REGEXMATCH(G:G,"[A-Z]{4}$")))
To get the actual value (which I realize was the actual question), just wrap an index function around the Max function. So for this question, a solution could be :
=Index(G:G,max(filter(row(G:G),isnumber(G:G))))

Repeat row wise a string number of times in corresponding column

Here is a screen shot of some data:
I would like to build a new column that is the the string in column A the total number of times it occurs.
So entry "Too expensive" would be on 26 rows then under that would start "Don't want it" taking up 6 rows, then "too expensive" (different since lower case) would take up another 6 + 5 from row 14.
So just a new column that is each string the number of times it appears. Inverse pivot tabling, if you will.
How would I do that? I tried playing with rept() but that put everything in one cell.
It looks like most likely you first need a helper column to basically unique the values so in column C you would put :
=UNIQUE(A:A)
and for the sake of explanation, if you want to see how it breaks down, in column D you can put
=sum(FILTER(B2:B,exact(C2,A2:A)))
The reason for using exact , is that otherwise it wont be case sensitive.
Once you have your final number for the REPT function you consutruct your repeatable value with a delimiter:
=rept(C2&";",D2)
This helps out split them out properly later into a column, if you rept the value with out the semicolon you will see the same result your describing up top where they are all mashed together.
Currently at this point this is what you would see:
To save some space I nest the sum filter into the rept function so I can remove column D:
=REPT(C2&";",sum(FILTER(B2:B,exact(C2,A2:A))))
I then join all those and split them out one last time using the ; as a delimiter:
=TRANSPOSE(SPLIT(JOIN(";",D2:D4),";"))
Alternatively, see if this works ?
=ArrayFormula(trim(transpose(split(query(rept(A2:A&char(10),B2:B),,50000), char(10)))))

Return only filled cells in Google Sheets QUERY

I have this formula in my sheet:
=query('Character Analysis'!$H62:$L83,"select H,I,J,K,L where H is not null order by L DESC",0)
Only the first two of the source rows have data in them, but on the sheet with the query formula it appears to be pulling all the rows in the range, even the blank ones. If I type something in the 3rd row on the query formula sheet, it gives me an error saying "Array result was not expanded because it would overwrite data in ________." But it doesn't need that room because there are only two rows of data in the query result.
I tried adding the "is not null" language in hopes that it would limit the returned result to only filled cells, but it's not working.
How can I tell my query to only pull data from filled cells in the source range?
I figured out a workaround, at least to the degree that it works for me. It's not a true answer as I'd still like to know why the "is not null" language isn't working, but this is giving me exactly what I need: You can just limit the number of returned rows to the number of source rows with data by counting them:
=query('Character Analysis'!$H62:$L83,"select H,I,J,K,L order by L DESC limit "&COUNT('Character Analysis'!$L62:$L83)&"",0)
According to source
You can:
Using a ‘where’ clause to eliminate blank rows
If a named range is defined using entire column (ie including blank rows) you may find these blanks appear in the query result (which, depending on the sort order, could be at the top!). To stop these appearing include a where clause using this syntax (assuming column A):
"...where A <> ' ' " (for text fields)
"...where A <>0" (for numeric fields)
This means ‘where values in column a are not zero-length text.

Countif with len in Google Spreadsheet

I have a column XXX like this :
XXX
A
Aruin
Avolyn
B
Batracia
Buna
...
I would like to count a cell only if the string in the cell has a length > 1.
How to do that?
I'm trying :
COUNTIF(XXX1:XXX30, LEN(...) > 1)
But what should I write instead of ... ?
Thank you in advance.
For ranges that contain strings, I have used a formula like below, which counts any value that starts with one character (the ?) followed by 0 or more characters (the *). I haven't tested on ranges that contain numbers.
=COUNTIF(range,"=?*")
To do this in one cell, without needing to create a separate column or use arrayformula{}, you can use sumproduct.
=SUMPRODUCT(LEN(XXX1:XXX30)>1)
If you have an array of True/False values then you can use -- to force them to be converted to numeric values like this:
=SUMPRODUCT(--(LEN(XXX1:XXX30)>1))
Credit to #greg who posted this in the comments - I think it is arguably the best answer and should be displayed as such. Sumproduct is a powerful function that can often to be used to get around shortcomings in countif type formulae.
Create another list using an =ARRAYFORMULA(len(XXX1:XXX30)>1) and then do a COUNTIF based on that new list: =countif(XXY1:XXY30,true()).
A simple formula that works for my needs is =ROWS(FILTER(range,LEN(range)>X))
The Google Sheets criteria syntax seems inconsistent, because the expression that works fine with FILTER() gives an erroneous zero result with COUNTIF().
Here's a demo worksheet
Another approach is to use the QUERY function.
This way you can write a simple SQL like statement to achieve this.
For example:
=QUERY(XXX1:XXX30,"SELECT COUNT(X) WHERE X MATCHES '.{1,}'")
To explain the MATCHES criteria:
It is a regex that matches every cell that contains 1 or more characters.
The . operator matches any character.
The {1,} qualifies that you only want to match cells that have at 1 or more characters in them.
Here is a link to another SO question that describes this method.

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