How to replace spaces between words with another word? - google-sheets

I have a cell G which stores random words like "Hello, How are you"
I want to replace all the spaces with %20 to make it
"Hello%20,%20How%20%are%20you"
How can i replace spaces with %20?
Thanks

try like this:
=SUBSTITUTE(G1; " "; "%20")

Select the cells you wish to change and run this:
Sub SpaceChanger()
Dim rng As Range, r As Range
Set rng = Intersect(Selection, ActiveSheet.UsedRange)
For Each r In rng
If r.Value <> "" Then
If InStr(r.Value, " ") <> 0 Then
r.Value = Replace(r.Value, " ", "%20")
End If
End If
Next r
End Sub
(using a macro will allow you to change the values "in place")

Related

Trying to make function which takes string as input and returns no. of words in whole string

**It takes Input as a string such as this - 'Nice one'
And Output gives - 4,3 (which is no. Of words in sentence or string)
**
function countx(str)
local count = {}
for i = 1, string.len(str) do
s = ''
while (i<=string.len(str) and string.sub(str, i, i) ~= ' ' ) do
s = s .. string.sub(str, i, i)
i = i+1
end
if (string.len(s)>0) then
table.insert(count,string.len(s))
end
end
return table.concat(count, ',')
end
You can find a simple alternative with your new requirements:
function CountWordLength (String)
local Results = { }
local Continue = true
local Position = 1
local SpacePosition
while Continue do
SpacePosition = string.find(String, " ", Position)
if SpacePosition then
Results[#Results + 1] = SpacePosition - Position
Position = SpacePosition + 1
-- if needed to print the string
-- local SubString = String:sub(Position, SpacePosition)
-- print(SubString)
else
Continue = false
end
end
Results[#Results + 1] = #String - Position + 1
return Results
end
Results = CountWordLength('I am a boy')
for Index, Value in ipairs(Results) do
print(Value)
end
Which gives the following results:
1
2
1
3
def countLenWords(s):
s=s.split(" ")
s=map(len,s)
s=map(str,s)
s=list(s)
return s
The above functions returns a list containing number of characters in each word
s=s.split(" ") splits string with delimiter " " (space)
s=map(len,s) maps the words into length of the words in int
s=map(str,s) maps the values into string
s=list(s) converts map object to list
Short version of above function (all in one line)
def countLenWords(s):
return list(map(str,map(len,s.split(" "))))
-- Localise for performance.
local insert = table.insert
local text = 'I am a poor boy straight. I do not need sympathy'
local function word_lengths (text)
local lengths = {}
for word in text:gmatch '[%l%u]+' do
insert (lengths, word:len())
end
return lengths
end
print ('{' .. table.concat (word_lengths (text), ', ') .. '}')
gmatch returns an iterator over matches of a pattern in a string.
[%l%u]+ is a Lua regular expression (see http://lua-users.org/wiki/PatternsTutorial) matching at least one lowercase or uppercase letter:
[] is a character class: a set of characters. It matches anything inside brackets, e.g. [ab] will match both a and b,
%l is any lowercase Latin letter,
%u is any uppercase Latin letter,
+ means one or more repeats.
Therefore, text:gmatch '[%l%u]+' will return an iterator that will produce words, consisting of Latin letters, one by one, until text is over. This iterator is used in generic for (see https://www.lua.org/pil/4.3.5.html); and on any iteration word will contain a full match of the regular expression.

Concatenate dynamic text values based on criteria in excel

I have a worksheet were I am trying to concatenate dynamic text values based on =TODAY()
So I have B3:B1000 being the fields where users will enter in text. D3:D1000 is where the user enters the date they filled it in. I3 is =TODAY()
How do I concatenate text values in B3:B1000 based on if the dates in the D3:D1000 = I3? and have that concatenation always update based on I3?
I would also need a delimiter of ", "
Got it working after some trail and error and some deeper searching :)
Function ConcatenateIf(CriteriaRange As Range, Condition As Variant, _
ConcatenateRange As Range, Optional Separator As String = ",") As Variant
Dim i As Long
Dim strResult As String
On Error GoTo ErrHandler
If CriteriaRange.Count <> ConcatenateRange.Count Then
ConcatenateIf = CVErr(xlErrRef)
Exit Function
End If
For i = 1 To CriteriaRange.Count
If CriteriaRange.Cells(i).Value = Condition Then
strResult = strResult & Separator & ConcatenateRange.Cells(i).Value
End If
Next i
If strResult <> "" Then
strResult = Mid(strResult, Len(Separator) + 1)
End If
ConcatenateIf = strResult
Exit Function
ErrHandler:
ConcatenateIf = CVErr(xlErrValue)
End Function
and then used this concatenate function =ConcatenateIf(D3:D1000,I3,B3:B1000,", ")

Lua gsub second instance

I'm using
local mystring = 'Thats a really nice house.'
string.gsub(mystring,"% ", "/",1)
to replace the first white space character with an slash.
But how to replace only the second occurrence of the white space?
You can use a function as replacement value in string.gsub and count the matches yourself:
local mystring = "Thats a really nice house."
local cnt = 0
print( string.gsub( mystring, " ", function( m )
cnt = cnt + 1
if cnt == 2 then
return "/"
end
end ) )
Try string.gsub(mystring,"(.- .-) ", "%1/",1).
You can replace the first instance with something else (assuming the replacement is not present in the string itself, which you can check), then replace it back:
print(mystring:gsub("% ", "\1",1):gsub("% ", "/",1):gsub("\1","% ", 1))
This prints: Thats a/really nice house.. Also, you don't need to escape spaces with %.

Parsing POST request with unexpected URL encoding

This question follows an earlier one.
Here is some code that reproduces the problem:
POST:
str = "accountRequest=<NewUser>" & vbLf & _
"Hello" & vbTab & "World" & vbLf & _
"</NewUser>"
Set objHTTP = Server.CreateObject("Msxml2.ServerXMLHTTP.3.0")
objHTTP.open "POST", "service.asp", False
objHTTP.setRequestHeader "Content-Type", "application/x-www-form-urlencoded"
objHTTP.send str
response.Write(objHTTP.responseText)
Set objHTTP = Nothing
service.asp:
function w (str)
response.Write(str & "<br>")
end function
str = request.Form("accountRequest")
w(str)
w("Tabs: "& InStr(str,vbTab))
w("Lines: "& InStr(str,vbLf))
output:
HelloWorld
Tabs: 0
Lines: 0
Can anyone please help?
Try:
Replace(Request.Form("accountRequest"), vbLF, vbCRLF))
Or:
Replace(Request.Form("accountRequest"), vbLF, "<br>"))|
Depending on where you're displaying it, either should work.
Or possibly this:
Function URLDecode(sConvert)
Dim aSplit
Dim sOutput
Dim I
If IsNull(sConvert) Then
URLDecode = ""
Exit Function
End If
' convert all pluses to spaces
sOutput = REPLACE(sConvert, "+", " ")
' next convert %hexdigits to the character
aSplit = Split(sOutput, "%")
If IsArray(aSplit) Then
sOutput = aSplit(0)
For I = 0 to UBound(aSplit) - 1
sOutput = sOutput & _
Chr("&H" & Left(aSplit(i + 1), 2)) &_
Right(aSplit(i + 1), Len(aSplit(i + 1)) - 2)
Next
End If
URLDecode = sOutput
End Function
From here: http://www.aspnut.com/reference/encoding.asp
If they are coming across the wire as the actual "\" and "n" characters, you can do a replace on those characters with the appropriate vbCRLF and vbTAB constants.
Finally figured out that ASP Request.Form method doesn't preserve tabs if they're in the "\t" format (as opposed to URL encoded). However, PHP's $_POST does.

Open Office Spreadsheet (Calc) - Concatenate text cells with delimiters

I am using Open Office's spreadsheet program and am trying to concatenate several text cells together with delimeters. For example, suppose I have the cells below:
+--------+
| cell 1 |
+--------+
| cell 2 |
+--------+
| cell 3 |
+--------+
| cell 4 |
+--------+
| cell 5 |
+--------+
I would like to concatenate them with delimiters so that the result is in one cell like this one:
+----------------------------------------------+
| (cell 1),(cell 2),(cell 3),(cell 4),(cell 5) |
+----------------------------------------------+
My first thought was to try and make a macro or something, but I don't think open office supports those. Any ideas?
Thanks a lot Markus for finding a solution to this.
Here are some slightly more detailed instructions for the benefit of OpenOffice Basic newbies like myself. This applies to version 3.1:
Tools -> Macros -> Organize Macros -> OpenOffice.org Basic...
Now select from the explorer tree where you want your function live,
e.g. it can be in your own macro library (My Macros / Standard) or
stored directly in the current spreadsheet.
Now enter a new Macro name and click New to open the OO.org Basic IDE. You'll see a REM
statement and some stub Sub definitions. Delete all that and replace
it with:
Function STRJOIN(range, Optional delimiter As String, Optional before As String, Optional after As String)
Dim row, col As Integer
Dim result, cell As String
result = ""
If IsMissing(delimiter) Then
delimiter = ","
End If
If IsMissing(before) Then
before = ""
End If
If IsMissing(after) Then
after = ""
End If
If NOT IsMissing(range) Then
If NOT IsArray(range) Then
result = before & range & after
Else
For row = LBound(range, 1) To UBound(range, 1)
For col = LBound(range, 2) To UBound(range, 2)
cell = range(row, col)
If cell <> 0 AND Len(Trim(cell)) <> 0 Then
If result <> "" Then
result = result & delimiter
End If
result = result & before & range(row, col) & after
End If
Next
Next
End If
End If
STRJOIN = result
End Function
The above code has some slight improvements from Markus' original:
Doesn't start with a delimiter when the first cell in the range is empty.
Allows optional choice of the delimiter (defaults to ","), and the
strings which go before and after each non-blank entry in the range
(default to "").
I renamed it STRJOIN since "join" is the typical name of this
function in several popular languages, such as Perl, Python, and Ruby.
Variables all lowercase
Now save the macro, go to the cell where you want the join to appear,
and type:
=STRJOIN(C3:C50)
replacing C3:C50 with the range of strings you want to join.
To customise the delimiter, instead use something like:
=STRJOIN(C3:C50; " / ")
If you wanted to join a bunch of email addresses, you could use:
=STRJOIN(C3:C50; ", "; "<"; ">")
and the result would be something like
<foo#bar.com>, <baz#qux.org>, <another#email.address>, <and#so.on>
Well, after a lot more searching and experimenting, I found you can make your own functions in calc. This is a function I made that does what I want:
Function STRCONCAT(range)
Dim Row, Col As Integer
Dim Result As String
Dim Temp As String
Result = ""
Temp = ""
If NOT IsMissing(range) Then
If NOT IsArray(range) Then
Result = "(" & range & ")"
Else
For Row = LBound(range, 1) To UBound(range, 1)
For Col = LBound(range, 2) To UBound(range, 2)
Temp = range(Row, Col)
Temp = Trim(Temp)
If range(Row, Col) <> 0 AND Len(Temp) <> 0 Then
If(NOT (Row = 1 AND Col = 1)) Then Result = Result & ", "
Result = Result & "(" & range(Row, Col) & ") "
End If
Next
Next
End If
End If
STRCONCAT = Result
End Function
Ever so often I'd enjoy the ease and quickness of replace & calculation Options as well as in general the quick handling & modifying Options, when once again sitting in front of a dumped-file-lists or whatsoever.
I never understood why they didn't include such an essential function right from the start, really.
It's based on Adam's script, but with the extension to swap CONCAT from horizontal to vertical, while still keeping the delimiters in order.
Function CONCAT2D(Optional range, Optional delx As String, Optional dely As String, _
Optional xcell As String, Optional cellx As String, _
Optional swop As Integer)
Dim xy(1), xyi(1), s(1) As Integer
Dim out, cell, del, dxy(1) As String
'ReDim range(2, 1) 'Gen.RandomMatrix 4 Debugging
'For i = LBound(range, 1) To UBound(range, 1)
' For j = LBound(range, 2) To UBound(range, 2)
' Randomize
' range(i,j) = Int((100 * Rnd) )
' Next
'Next
out = ""
If IsMissing(delx) Then : delx = "," : End If
If IsMissing(dely) Then : dely = delx() : End If
If IsMissing(xcell) Then : xcell = "" : End If
If IsMissing(cellx) Then : cellx = xcell() : End If
If IsMissing(swop) Then : swop = 0 : End If
dxy(0) = delx() : dxy(1) = dely()
xyi(0) = 1 : xyi(1) = 2
If swop = 0 Then : s(0) = 0 : s(1) = 1
Else s(0) = 1 : s(1) = 0 : End If
If NOT IsMissing(range) Then
If NOT IsArray(range) _
Then : out = xcell & range & cellx
Else del = delx
For xy(s(0)) = LBound(range, xyi(s(0))) To UBound(range, xyi(s(0))
For xy(s(1)) = LBound(range, xyi(s(1))) To UBound(range, xyi(s(1))
cell = range(xy(0), xy(1))
If cell <> 0 AND Len(Trim(cell)) <> 0 _
Then : If out <> "" Then : out = out & del : End If
out = out & xcell & cell & cellx
del = dxy(s(0))
End If
Next : del = dxy(s(1))
Next
End If
Else out = "ERR"
End If
CONCAT2D = out
End Function

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