I have this information:
Days Dec'15 Jan'16
---------------------
Sun 27
Mon 28
Tue 29
Wed 30
Thu 31
Fri 1
Sat 2
I have 1st Jan'16. So I have to get Fri and then the difference of days from the Sun. So, in this case, the difference should be 5. Because, before Friday there are 5 other days. So if I want to know it for 2nd Jan'16 it should be 6. And likewise.
How do I get it easy with date functions?
The following code may help you
extension Date {
func weekdayDiffence() -> Int {
return Calendar.current.dateComponents([Calendar.Component.weekday], from: self).weekday ?? 0
}
}
Example
let d = Date().weekdayDiffence()
print(d)
I am getting nil for some values while using dateFromString in swift. I searched a lot but in vain.
Following is my code:
let strDate = self.sortedDict.valueForKey("TIME").objectAtIndex(indexPath.row).objectAtIndex(0) as? String
print(strDate);
let st_date = frmt.dateFromString(strDate!)
let frmt1:NSDateFormatter = NSDateFormatter()
frmt1.locale = NSLocale(localeIdentifier: localeStr)
frmt1.dateFormat = "MMM, dd yyyy hh:mm a"
if st_date != nil {
print(st_date)
}
Output console:
Optional("September, 20 2015 10:00:00")
Optional(2015-09-20 10:00:00 +0000)
Optional("October, 04 2015 10:00:00")
Optional(2015-10-04 10:00:00 +0000)
Optional("October, 04 2015 14:00:00") // nil
Optional("October, 18 2015 15:00:00") // nil
Optional("September, 20 2015 14:00:00") // nil
Optional("September, 27 2015 10:00:00")
Optional(2015-09-27 10:00:00 +0000)
Optional("September, 27 2015 12:00:00")
Optional(2015-09-27 00:00:00 +0000)
Optional("September, 27 2015 14:00:00")
Optional("October, 03 2015 14:00:00") //nil
Optional("October, 03 2015 16:00:00") //nil
The format is same for all date strings still I get nil for few values. Why so? Please help. Where am I getting wrong?
format should be HH for 24 hours even you are getting values only for 12 hours.
frmt1.dateFormat = "MMM, dd yyyy HH:mm a"
My network only achieve around 80%, but the reported best score is around 85% accuracy. I m using same input data and same initalization. I dont know whats wrong, so I try to check my gradients and implemented what is recommended for gradient checking: http://ufldl.stanford.edu/tutorial/supervised/DebuggingGradientChecking/
But i m not sure, if my implementation is correct:
public void gradientchecking(double[] theta){
System.out.println("Gradient Checking started");
//costfunction returns cost and gradients
IPair<Double, double[]> org = costfunction(theta);
double[] theta_pos = new double[theta.length];
double[] theta_neg = new double[theta.length];
for (int i = 0; i < theta.length; i++) {
theta_pos[i]= theta[i];
theta_neg[i]=theta[i];
}
double mu = 1e-5;
for (int k = 0; k < 20; k++) {
theta_pos[k] = theta_pos[k] + mu;
theta_neg[k] = theta_neg[k] - mu;
IPair<Double, double[]> pos = costfunction(theta_pos);
IPair<Double, double[]> neg = costfunction(theta_neg);
System.out.println("Org: "+org.getSecond()[k] +" check:"+ ((pos.getSecond()[k]-neg.getSecond()[k])/(2*mu)));
//System.out.println("Org: "+org.getSecond()[k] +"check:"+ ((pos.getSecond()[k]-neg.getSecond()[k])/(2*mu)));
theta_pos[k] = theta_pos[k] - mu;
theta_neg[k] = theta_neg[k] + mu;
}
}
}
I got the following result after a freshly initialized theta:
Gradient Checking started
Cost: 1.1287071297725055 | Wrong: 124 | start: Thu Jul 30 22:57:08 CEST 2015 |end: Thu Jul 30 22:57:18 CEST 2015
Cost: 1.128707130295382 | Wrong: 124 | start: Thu Jul 30 22:57:18 CEST 2015 |end: Thu Jul 30 22:57:28 CEST 2015
Cost: 1.1287071292496391 | Wrong: 124 | start: Thu Jul 30 22:57:28 CEST 2015 |end: Thu Jul 30 22:57:38 CEST 2015
Org: 5.2287135944026004E-5 check:1.0184607936733826E-4
Cost: 1.1287071299252593 | Wrong: 124 | start: Thu Jul 30 22:57:38 CEST 2015 |end: Thu Jul 30 22:57:47 CEST 2015
Cost: 1.1287071296197628 | Wrong: 124 | start: Thu Jul 30 22:57:47 CEST 2015 |end: Thu Jul 30 22:57:56 CEST 2015
Org: 1.5274823511207024E-5 check:1.141254586229615E-4
Cost: 1.1287071299063134 | Wrong: 124 | start: Thu Jul 30 22:57:56 CEST 2015 |end: Thu Jul 30 22:58:05 CEST 2015
Cost: 1.1287071296387077 | Wrong: 124 | start: Thu Jul 30 22:58:05 CEST 2015 |end: Thu Jul 30 22:58:14 CEST 2015
Org: 1.3380293717695182E-5 check:1.0008639478696018E-4
Cost: 1.1287071297943114 | Wrong: 124 | start: Thu Jul 30 22:58:14 CEST 2015 |end: Thu Jul 30 22:58:23 CEST 2015
Cost: 1.1287071297507094 | Wrong: 124 | start: Thu Jul 30 22:58:23 CEST 2015 |end: Thu Jul 30 22:58:32 CEST 2015
Org: 2.1800899147740388E-6 check:9.980780136716263E-5
that indicates that my gradient calculation has an error, or the gradientchecking() method. I m not sure, can somebody help me?
In Java arrays are reference types.
int[] arr = { 8,7,6,5,4,3,2,1,8};
int[] b = arr;
b [0] = -10;
for (int i:arr) {
System.out.print (' ');
System.out.print (i);
}
outputs -10 7 6 5 4 3 2 1 8
So i mean that you incorrectly creating arrays
double[] theta_pos = theta;
double[] theta_neg = theta;
they are just references to theta, and by changing their contents you change theta also, +mu-mu = 0. Use clone() methods while copying array.
double[] theta_pos = theta.clone();
double[] theta_neg = theta.clone();
But remember that clone may not work as you expecting in some cases, with simple(non-reference) types it works ideal. Look at this
Does calling clone() on an array also clone its contents?
I want a parsing script/ code solution in any programing language.
The file is too large to be open in Excel.
Problem:
I have large text file (300MB) which look like this:
[0] 2014 Jul 23 08:15:16.675
Current SFN = 604
Current Subframe Number = 3
Is Restricted = false
Cell Timing[0] = 298955
[1] 2014 Jul 24 08:15:16.675
Current SFN = 605
Current Subframe Number = 4
Is Restricted = false
Cell Timing[0] = 298900
[2] 2014 Jul 25 08:15:16.675
Current SFN = 700
Current Subframe Number = 7
Is Restricted = false
Cell Timing[0] = 39025
Wanted output:
5 columns ( Date , Current SFN , Current Subframe Number , Is Restricted , Cell Timing[0] )
Date Current SFN Current Subframe Number Is Restricted Cell Timing[0]
2014 Jul 23 08:15:16.675 604 3 TRUE 298955
2014 Jul 24 08:15:16.675 605 4 FALSE 298900
2014 Jul 25 08:15:16.675 700 7 FALSE 39025
The following Ruby code gets me the first day of each month :
require 'active_support/all'
# get the date at the beginning of this month
date = Date.today.beginning_of_month
# get the first day of the next 5 months
5.times do |num|
date = date.next_month
p date
end
Which gives :
=> Fri, 01 Aug 2014
=> Mon, 01 Sep 2014
=> Wed, 01 Oct 2014
=> Sat, 01 Nov 2014
=> Mon, 01 Dec 2014
But how do I get the first Thursday of each month? i.e.
=> Thu, 07 Aug 2014
=> Thu, 04 Sep 2014
=> Thu, 02 Oct 2014
=> Thu, 06 Nov 2014
=> Thu, 04 Dec 2014
There's no need for iterations or conditions just get the so called delta of days till next thursday:
#4 is thursday because wday starts at 0 (sunday)
date = Date.today.beginning_of_month
date += (4 - date.wday) % 7
p date
=> Thu, 03 Jul 2014
That my opinion:
date_begin = Date.today.beginning_of_month
date_end = date_begin + 5.month
[*date_begin..date_end].select(&:thursday?).uniq(&:month)
=> [Thu, 03 Jul 2014, Thu, 07 Aug 2014, Thu, 04 Sep 2014, Thu, 02 Oct 2014, Thu, 06 Nov 2014]
Just for fun
class Date
def skip_to_thursday
# given current weekday, how many days we need to add for it to become thursday
# for example, for monday (weekday 1) it's 3 days
offset = lambda {|x| (4-x) % 7 }
self + offset[wday]
end
end
# get the date at the beginning of this month
date = Date.today.beginning_of_month
date.skip_to_thursday # => Thu, 03 Jul 2014
Here is my way :
def first_thursday
date = Date.today.beginning_of_month
date += 1 until date.wday == 4
date
end
first_thursday # => Thu, 03 Jul 2014
you can use something like this:
def first_thursday(months_ahead)
start_of_month = months_ahead.months.from_now.beginning_of_month.to_date
start_of_month += (4 - start_of_month.cwday) % 7
end
first_thursday 1
=> Thu, 07 Aug 2014
first_thursday 2
=> Thu, 04 Sep 2014
I ran into this problem for a recurring_events feature that I needed to build. I changed some of the variables to find the first Thursday but it also shows how you could evolve the answer to find the 2nd or 3rd Thursday (or any day of the week for that matter) if you had a week and day of the week count.
def find_thursday
start_of_month = DateTime.now.beginning_of_month
month_day = nil
loop do
month_day = start_of_month += 1.day
break if month_day.wday == find_weekday("Thu")
end
return month_day
end
def find_weekday
d = default_weekdays.find { |d| d[:day] == start_date.strftime("%a") }
d[:count]
end
def default_weekdays
return [
{ day: 'Sun', count: 0 },
{ day: 'Mon', count: 1 },
{ day: 'Tue', count: 2 },
{ day: 'Wed', count: 3 },
{ day: 'Thu', count: 4 },
{ day: 'Fri', count: 5 },
{ day: 'Sat', count: 6 },
]
end