im trying to mark matching URLs red.
I have two sheets with URL Data.
My custom Formula looks like this:
match(A2,indirect(Sheet2!A2:A),0)
wondering why there is an error if i use =match(A2,indirect(LostURLs!A2:A),0)
so with the additional =
Anyways both methods are not working and im wondering why?
Indirect excepts the first argument to be "a cell reference as string".
So please try
=match(A2,indirect("LostURLs!A2:A"),0)
and see if that works?
Note: depending on if you want the formatting for a single cell, a column or a row you may have to use a dollar sign in the first argument of the match() function
E.g: If you'd want to repeat the formatting for column A, you would have to use
=match($A2,indirect("LostURLs!A2:A"),0)
For row 2 that would be:
=match(A$2,indirect("LostURLs!A2:A"),0)
and for a single cell
=match($A$2,indirect("LostURLs!A2:A"),0)
NOTE: Depending on your locale, you may have to change the comma's to semi-colons.
perhaps try:
=MATCH(A2; INDIRECT("LostURLs!A2:A"); 0)
Related
emails
vera#mail.com
estebangarrido#mail.c
hurtado#mail com
jmariano2mail.com
How can I pass a fuction which correct all domains to #mail.com. I know I have to use =RIGHT(,9) but when you reach the last error it does not apply
Try below formula-
=ArrayFormula(IF(A2:A="",,QUERY(SPLIT(SUBSTITUTE(SUBSTITUTE(A2:A,"mail","|"),"#",""),"|"),"select Col1",0)&"#mail.com"))
This should also work.
=INDEX(IF(LEN(A2:A),QUERY(SPLIT(SUBSTITUTE(SUBSTITUTE(A2:A,"mail","|"),"#",""),"|"),"select Col1")&"#mail.com",""))
Answer
The following formula should produce the results you desire. It assumes that the data you provide is in cells A2:A5 of your spreadsheet. If this is not the case, adjust the A2:A5 portion of the formula appropriately.
=ARRAYFORMULA(REGEXREPLACE(A2:A5,"[#|2].*","#mail.com"))
Explanation
This formula uses REGEXREPLACE to get rid of all rogue characters and replace them with #mail.com. The first argument of REGEXREPLACE is the string to be evaluated. In this case, that is the range from A2 through A5. The second argument is which characters to look for. In this case that is all characters (done using .*) that follow either an at-sign or a numeral two (done using [#|2]). The third argument is which new string to replace the found characters with. In this case that is #mail.com, the correct domain without typos.
The REGEXREPLACE is wrapped in =ARRAYFORMULA because normally REGEXREPLACE can only be used with a single cell rather than a range of cells.
Please note that this solution relies on the assumption you stated that "Everything before # or 2 is correct."
Here's the straightforward version of my question:
I want to change the following formula to an array formula...
Original formula (from cell J2):
=if(F4="VM:",G4,J1)
My attempt at converting to an array formula (in cell K1):
=arrayformula(if(row(A:A)=1,G3,if(F:F = "VM:",G:G,indirect("K"&row(A:A)-1))))
This works on rows where F = "VM:", but returns a #REF error on other rows. Function INDIRECT parameter 1 value is 'K0'. It is not a valid cell/range reference.
Thoughts on how to fix this?
The more complex version of my question. i.e. Why am I trying to do this?...
I have a weird spreadsheet with data that should really be in a Wiki.
I want to create filter views for each person so they can easily filter on only their own vendors. The original formula will work, but as more vendors are added, I'd like for the formula to automatically work for those rows as well.
If there's a better way to do this, I'm listening.
I don't exactly understand your needs, but If you want to autopopulate your formula, then you only need this code in desire column in row 4 (you can change this to any other - this will autofill down from this point):
=ArrayFormula(if(F4:F="VM:",G4:G,J1:J))
Is this what you are trying to get?
After clarification:
You need this code in J2 only:
=ArrayFormula(VLOOKUP(ROW(J2:J),
QUERY({F:G,ROW(G:G)},"select Col3,Col2 where Col1='VM:'",1)
,2,1)
)
Works for you?
maybe you just need to hide errors?
=IFERROR(ARRAYFORMULA(IF(ROW(A:A)=1,G3,IF(F:F = "VM:",G:G,INDIRECT("K"&ROW(A:A)-1)))),)
I watched a tutorial where the author uses an IF statement along with the ARRAYFORMULA function to add a title row to a column of data. Links are given to the docs; however, for an example of how to use ARRAYFORMULA see this answer.
An example can be seen below:
I was able to populate the C column by placing the following formula in C1:
=ARRAYFORMULA(if(row(A:A) = 1, "spent", B:B - A:A))
I'm confused about the syntax. I understand that X:X references the entire X column but I don't understand how it's being used to check if we're at cell A1 in one context and then being used to apply mass formulas in another context.
How does the above line work?
Can you illustrate with some examples?
It sounds to me that the information you learned led you to expect that row(A:A)=1 translates to row A1?
It works a little different than that, the syntax as your using it now, is basically saying if any row in A:A has a value of 1, then write "spent" else subtract B-A
My suggestion:
use a literal array to make your header, then use the if(arrayformula) to only populate rows with values, for aesthetics:
Example:
={"Spent";arrayformula(if(isnumber(A2:A),B2:B-A2:A,))}
Explanation:
The {} allow you to build a literal array, and using a semicolon instead of a comma allows you to stack your cells vertically, following that we check if there is a value in column A, if so, subtract A from B, else leave it blank.
why not just put the column title directly on the first row cell, and start the array formula from the 2nd row, using the A2:A, B2:B syntax?
If something does not have to be in a formula, better put it directly on the cell - simpler for others to understand what's going on, and the formula will be simpler.
If you put the array formula in line 2, and someone sorts the data, then the arrayformula will move. If it is in the header line, this is less likely to happen.
You can also use the IFS function to achieve a similar effect to the array,
=arrayformula(ifs(row(A1:A)=1,"Spent",A1:A="",,True,B1:B-A1:A)
Here the first condition checks the row number, and if it is row ONE, then inserts a Column Header.
The Second condition - A1:A="",, - ensures that blank lines are ignored.
The Third condition True (ELSE) performs the calculation.
This method also allows for different calculations to performed on different rows depending on requirements.
I have a data set with 77 rows. One of the columns (let's call it C) contains a name value. I would like to highlight the row if the name in column C is found in a list of names in another column.
Currently, I'm able to check only a single value, instead of a list of values. In conditional format rules, I'm able to enter the following formula
=$C:$C=$GU$1
This, of course, only checks the value against the first name in column GU. I tried to add :$GU$100 to the condition, but that won't work as the condition is now checking if the entry is the same as the entire value from GU1:GU100.
I thought I might try to use a FIND() method to see if the substring were in the larger string. To do that, I attempted the following:
=$C:$C=IF(ISNUMBER(FIND($C$1,$GU$1:$GU$100)),1,0)
While this did not return an error, it also did not highlight any rows. I'm unsure how to format one row based on whether or not the value in that row is an entry in a list elsewhere. Any ideas?
Please select your 'entire row' range (here assumed ColumnsA:G) and Format, Conditional formatting..., Format cells if..., Custom formula is:
=match($C1,$H:$H,0)
choose your Formatting style and Done. Where ColumnH is assumed to have your list.
You can add conditional formatting like this with the custom function option and applying to column C, pretending that the list with names your matching against is in column J:
=IF(ISTEXT(VLOOKUP(C1:C,J:J,1,false)),TRUE,FALSE)
I have a column XXX like this :
XXX
A
Aruin
Avolyn
B
Batracia
Buna
...
I would like to count a cell only if the string in the cell has a length > 1.
How to do that?
I'm trying :
COUNTIF(XXX1:XXX30, LEN(...) > 1)
But what should I write instead of ... ?
Thank you in advance.
For ranges that contain strings, I have used a formula like below, which counts any value that starts with one character (the ?) followed by 0 or more characters (the *). I haven't tested on ranges that contain numbers.
=COUNTIF(range,"=?*")
To do this in one cell, without needing to create a separate column or use arrayformula{}, you can use sumproduct.
=SUMPRODUCT(LEN(XXX1:XXX30)>1)
If you have an array of True/False values then you can use -- to force them to be converted to numeric values like this:
=SUMPRODUCT(--(LEN(XXX1:XXX30)>1))
Credit to #greg who posted this in the comments - I think it is arguably the best answer and should be displayed as such. Sumproduct is a powerful function that can often to be used to get around shortcomings in countif type formulae.
Create another list using an =ARRAYFORMULA(len(XXX1:XXX30)>1) and then do a COUNTIF based on that new list: =countif(XXY1:XXY30,true()).
A simple formula that works for my needs is =ROWS(FILTER(range,LEN(range)>X))
The Google Sheets criteria syntax seems inconsistent, because the expression that works fine with FILTER() gives an erroneous zero result with COUNTIF().
Here's a demo worksheet
Another approach is to use the QUERY function.
This way you can write a simple SQL like statement to achieve this.
For example:
=QUERY(XXX1:XXX30,"SELECT COUNT(X) WHERE X MATCHES '.{1,}'")
To explain the MATCHES criteria:
It is a regex that matches every cell that contains 1 or more characters.
The . operator matches any character.
The {1,} qualifies that you only want to match cells that have at 1 or more characters in them.
Here is a link to another SO question that describes this method.