Google SpreadSheet Query - Merge queries results into one - google-sheets

Let's take this data in a Google sheet:
| Product | Green | Red | Date |
| A | 1 | 0 | 1/1/2020 |
| A | 1 | 0 | 2/1/2020 |
| B | 0 | 1 | 2/25/2020 |
| C | 1 | 0 | 2/28/2020 |
| A | 0 | 1 | 3/1/2020 |
My goal would be to display the sum of Green / Red for each product:
From the beginning of the year,
For the current month.
I created this Google Query to get the results for all the year:
=QUERY(DATA!A:D,"select A, sum(B), sum(C) where D >= date '2020-01-01' and D <= date '2020-12-31' group by A")
I get this result:
| Product | sum Green | sum Red |
| A | 2 | 1 |
| B | 0 | 1 |
| C | 1 | 0 |
And this query for the given month (I simplified the query, but I have a Settings sheet to specify the month to query):
=QUERY(DATA!A:D,"select A, sum(B), sum(C) where D >= date '2020-01-01' and D <= date '2020-01-31' group by A")
And get this result:
| Product | sum Green | sum Red |
| A | 1 | 0 |
Now I'm stuck in joining the two results into one, like this:
| Product | Year sum Green | Year sum Red | Jan sum Green | Jan sum Red |
| A | 2 | 1 | 1 | 0 |
| B | 0 | 1 | | |
| C | 1 | 0 | | |
How can I achieve this ?
Thanks a lot for your help!


try:
=ARRAYFORMULA(IFNA(VLOOKUP(F2:F, QUERY(DATA!A:D,
"select A,sum(B),sum(C)
where month(D)+1 = 1
group by A
label sum(B)'Jan sum Green',sum(C)'Jan sum Red'"), {2,3}, 0)))

Related

Cypher query aggregate sum of values

I have a Cypher query that shows the following output:
+----------------
| usid | count |
+----------------
| "000" | 1 |
| "000" | 0 |
| "000" | 0 |
| "001" | 1 |
| "001" | 1 |
| "001" | 0 |
| "002" | 2 |
| "002" | 2 |
| "002" | 0 |
| "003" | 4 |
| "003" | 2 |
| "003" | 2 |
| "004" | 4 |
| "004" | 4 |
| "004" | 4 |
+----------------
How can I get the below result with the condition SUM(count) <= 9.
+----------------
| usid | count |
+----------------
| "000" | 1 |
| "001" | 2 |
| "002" | 4 |
| "003" | 8 |
+----------------
Note: I have used the below query to get the 1st table data.
MATCH (us:USER)
WITH us
WHERE us.count <= 4
RETURN us.id as usid, us.count as count;

I don't know how you get your original data, so I will just use a WITH clause and assume the data is there:
// original data
WITH usid, count
// aggregate and filter
WITH usid, sum(count) as new_count
WHERE new_count <= 9
RETURN usid, new_count
Based on the updated question, the new query would look like:
MATCH (us:USER)
WHERE us.count <= 4
WITH us.id as usid, sum(us.count) as count
WHERE new_count <= 9
RETURN usid, count
˙˙˙

Compare each cell in two rows, but with an exception

I have a table that keeps track of scores from a test. It compares the row with someone's answers to the row with the correct data:
A B C D E
+--------------+-----+-----+-----+-------+
1 | | Q1 | Q2 | Q3 | Score |
+--------------+-----+-----+-----+-------+
2 | Answers | C | B | A | |
+--------------+-----+-----+-----+-------+
3 | George | C | A | B | 1 |
4 | Judith | C | C | A | 2 |
5 | James | A | B | C | 1 |
+--------------+-----+-----+-----+-------+
The formula behind the Score column is:
=arrayformula(sumproduct(($B$2:$D$2=B3:D3)))
The first part of sumproduct is a static reference to the Answers row. The second part is comparing it against the row it's on. However I want to add an exception: if the Answers row contains an asterisk it should consider all answers correct:
A B C D E
+--------------+-----+-----+-----+-------+
1 | | Q1 | Q2 | Q3 | Score |
+--------------+-----+-----+-----+-------+
2 | Answers | C | * | A | |
+--------------+-----+-----+-----+-------+
3 | George | C | A | B | 2 |
4 | Judith | C | C | A | 3 |
5 | James | A | B | C | 1 |
+--------------+-----+-----+-----+-------+
How would I be able to do this?

Please try:
=arrayformula(sumproduct(($B$2:$D$2=B3:D3)+($B$2:$D$2="*")))

=IF(OR($B$2=B3, $B$2="*"), 1, )+
IF(OR($C$2=C3, $C$2="*"), 1, )+
IF(OR($D$2=D3, $D$2="*"), 1, )
this will cover up to 51 questions (columns / range of B:AZ)
=IF(LEN($B$2),IF(OR($B$2=B3,$B$2="*"),1,),)+
IF(LEN($C$2),IF(OR($C$2=C3,$C$2="*"),1,),)+
IF(LEN($D$2),IF(OR($D$2=D3,$D$2="*"),1,),)+
IF(LEN($E$2),IF(OR($E$2=E3,$E$2="*"),1,),)+
IF(LEN($F$2),IF(OR($F$2=F3,$F$2="*"),1,),)+
IF(LEN($G$2),IF(OR($G$2=G3,$G$2="*"),1,),)+
IF(LEN($H$2),IF(OR($H$2=H3,$H$2="*"),1,),)+
IF(LEN($I$2),IF(OR($I$2=I3,$I$2="*"),1,),)+
IF(LEN($J$2),IF(OR($J$2=J3,$J$2="*"),1,),)+
IF(LEN($K$2),IF(OR($K$2=K3,$K$2="*"),1,),)+
IF(LEN($L$2),IF(OR($L$2=L3,$L$2="*"),1,),)+
IF(LEN($M$2),IF(OR($M$2=M3,$M$2="*"),1,),)+
IF(LEN($N$2),IF(OR($N$2=N3,$N$2="*"),1,),)+
IF(LEN($O$2),IF(OR($O$2=O3,$O$2="*"),1,),)+
IF(LEN($P$2),IF(OR($P$2=P3,$P$2="*"),1,),)+
IF(LEN($Q$2),IF(OR($Q$2=Q3,$Q$2="*"),1,),)+
IF(LEN($R$2),IF(OR($R$2=R3,$R$2="*"),1,),)+
IF(LEN($S$2),IF(OR($S$2=S3,$S$2="*"),1,),)+
IF(LEN($T$2),IF(OR($T$2=T3,$T$2="*"),1,),)+
IF(LEN($U$2),IF(OR($U$2=U3,$U$2="*"),1,),)+
IF(LEN($V$2),IF(OR($V$2=V3,$V$2="*"),1,),)+
IF(LEN($W$2),IF(OR($W$2=W3,$W$2="*"),1,),)+
IF(LEN($X$2),IF(OR($X$2=X3,$X$2="*"),1,),)+
IF(LEN($Y$2),IF(OR($Y$2=Y3,$Y$2="*"),1,),)+
IF(LEN($Z$2),IF(OR($Z$2=Z3,$Z$2="*"),1,),)+
IF(LEN($AA$2),IF(OR($AA$2=AA3,$AA$2="*"),1,),)+
IF(LEN($AB$2),IF(OR($AB$2=AB3,$AB$2="*"),1,),)+
IF(LEN($AC$2),IF(OR($AC$2=AC3,$AC$2="*"),1,),)+
IF(LEN($AD$2),IF(OR($AD$2=AD3,$AD$2="*"),1,),)+
IF(LEN($AE$2),IF(OR($AE$2=AE3,$AE$2="*"),1,),)+
IF(LEN($AF$2),IF(OR($AF$2=AF3,$AF$2="*"),1,),)+
IF(LEN($AG$2),IF(OR($AG$2=AG3,$AG$2="*"),1,),)+
IF(LEN($AH$2),IF(OR($AH$2=AH3,$AH$2="*"),1,),)+
IF(LEN($AI$2),IF(OR($AI$2=AI3,$AI$2="*"),1,),)+
IF(LEN($AJ$2),IF(OR($AJ$2=AJ3,$AJ$2="*"),1,),)+
IF(LEN($AK$2),IF(OR($AK$2=AK3,$AK$2="*"),1,),)+
IF(LEN($AL$2),IF(OR($AL$2=AL3,$AL$2="*"),1,),)+
IF(LEN($AM$2),IF(OR($AM$2=AM3,$AM$2="*"),1,),)+
IF(LEN($AN$2),IF(OR($AN$2=AN3,$AN$2="*"),1,),)+
IF(LEN($AO$2),IF(OR($AO$2=AO3,$AO$2="*"),1,),)+
IF(LEN($AP$2),IF(OR($AP$2=AP3,$AP$2="*"),1,),)+
IF(LEN($AQ$2),IF(OR($AQ$2=AQ3,$AQ$2="*"),1,),)+
IF(LEN($AR$2),IF(OR($AR$2=AR3,$AR$2="*"),1,),)+
IF(LEN($AS$2),IF(OR($AS$2=AS3,$AS$2="*"),1,),)+
IF(LEN($AT$2),IF(OR($AT$2=AT3,$AT$2="*"),1,),)+
IF(LEN($AU$2),IF(OR($AU$2=AU3,$AU$2="*"),1,),)+
IF(LEN($AV$2),IF(OR($AV$2=AV3,$AV$2="*"),1,),)+
IF(LEN($AW$2),IF(OR($AW$2=AW3,$AW$2="*"),1,),)+
IF(LEN($AX$2),IF(OR($AX$2=AX3,$AX$2="*"),1,),)+
IF(LEN($AY$2),IF(OR($AY$2=AY3,$AY$2="*"),1,),)+
IF(LEN($AZ$2),IF(OR($AZ$2=AZ3,$AZ$2="*"),1,),)
and here is "Formula Generator" sheet for that

googlesheet - Call month API in query statement not work as expected

To summarize each month's balance, I try to call month API in query statement. but sounds like the month API always return (month - 1) but not month.
Example data:
| Type | TransDate | Amount |
|---------+------------+---------|
| Sale | 08/13/2017 | -40.97 |
| Return | 08/10/2017 | 127.48 |
| Payment | 08/07/2017 | 2194.45 |
| Sale | 08/07/2017 | -100.97 |
| Sale | 08/06/2017 | -143.44 |
| Sale | 07/02/2017 | -143.44 |
| Sale | 07/03/2017 | -7.55 |
| Sale | 08/04/2017 | -8.03 |
I use below formula:
=query(A:C,"select MONTH(B),sum(C) where A = 'Sale' or A = 'Return' group by MONTH(B) label MONTH(B) 'Month',sum(C) 'Total'")
The result table:
| Month | Total |
|-------+---------|
| 6 | -150.99 |
| 7 | -165.93 |
The month should be 7 and 8, but actually it return 6 and 7.

As the documentation says:
Returns the zero-based month value from a date or datetime value. For example: month(date "2009-02-05") returns 1. Note: the months are 0-based, so the function returns 0 for January, 1 for February, etc.

As #puts said, the index is start from 0, fix that with a offset:
=query(A:E,"select MONTH(B)+1,sum(E) where A = 'Sale' or A = 'Return' group by MONTH(B) label MONTH(B)+1 'Month',sum(E) 'Total'")

Finding root of a tree in a directed graph

I have a tree structure like node(1)->node(2)->node(3). I have name as an property used to retrieve a node.
Given a node say node(3), i wanna retrieve node(1).
Query tried :
MATCH (p:Node)-[:HAS*]->(c:Node) WHERE c.name = "node 3" RETURN p LIMIT 5
But, not able to get node 1.

Your query will not only return "node 1", but it should at least include one path containing it. It's possible to filter the paths to only get the one traversing all the way to the root, however:
MATCH (c:Node {name: "node 3"})<-[:HAS*0..]-(p:Node)
// The root does not have any incoming relationship
WHERE NOT (p)<-[:HAS]-()
RETURN p
Note the use of the 0 length, which matches all cases, including the one where the start node is the root.
Fun fact: even if you have an index on Node:name, it won't be used (unless you're using Neo4j 3.1, where it seems to be fixed since 3.1 Beta2 at least) and you have to explicitly specify it.
MATCH (c:Node {name: "node 3"})<-[:HAS*0..]-(p:Node)
USING INDEX c:Node(name)
WHERE NOT (p)<-[:HAS]-()
RETURN p
Using PROFILE on the first query (with a numerical id property instead of name):
+-----------------------+----------------+------+---------+-------------------------+----------------------+
| Operator | Estimated Rows | Rows | DB Hits | Variables | Other |
+-----------------------+----------------+------+---------+-------------------------+----------------------+
| +ProduceResults | 0 | 1 | 0 | p | p |
| | +----------------+------+---------+-------------------------+----------------------+
| +AntiSemiApply | 0 | 1 | 0 | anon[23], c -- p | |
| |\ +----------------+------+---------+-------------------------+----------------------+
| | +Expand(All) | 1 | 0 | 3 | anon[58], anon[67] -- p | (p)<-[:HAS]-() |
| | | +----------------+------+---------+-------------------------+----------------------+
| | +Argument | 1 | 3 | 0 | p | |
| | +----------------+------+---------+-------------------------+----------------------+
| +Filter | 1 | 3 | 3 | anon[23], c, p | p:Node |
| | +----------------+------+---------+-------------------------+----------------------+
| +VarLengthExpand(All) | 1 | 3 | 5 | anon[23], p -- c | (c)<-[:HAS*]-(p) |
| | +----------------+------+---------+-------------------------+----------------------+
| +Filter | 1 | 1 | 3 | c | c.id == { AUTOINT0} |
| | +----------------+------+---------+-------------------------+----------------------+
| +NodeByLabelScan | 3 | 3 | 4 | c | :Node |
+-----------------------+----------------+------+---------+-------------------------+----------------------+
Total database accesses: 18
and on the second one:
+-----------------------+----------------+------+---------+-------------------------+------------------+
| Operator | Estimated Rows | Rows | DB Hits | Variables | Other |
+-----------------------+----------------+------+---------+-------------------------+------------------+
| +ProduceResults | 0 | 1 | 0 | p | p |
| | +----------------+------+---------+-------------------------+------------------+
| +AntiSemiApply | 0 | 1 | 0 | anon[23], c -- p | |
| |\ +----------------+------+---------+-------------------------+------------------+
| | +Expand(All) | 1 | 0 | 3 | anon[81], anon[90] -- p | (p)<-[:HAS]-() |
| | | +----------------+------+---------+-------------------------+------------------+
| | +Argument | 1 | 3 | 0 | p | |
| | +----------------+------+---------+-------------------------+------------------+
| +Filter | 1 | 3 | 3 | anon[23], c, p | p:Node |
| | +----------------+------+---------+-------------------------+------------------+
| +VarLengthExpand(All) | 1 | 3 | 5 | anon[23], p -- c | (c)<-[:HAS*]-(p) |
| | +----------------+------+---------+-------------------------+------------------+
| +NodeUniqueIndexSeek | 1 | 1 | 2 | c | :Node(id) |
+-----------------------+----------------+------+---------+-------------------------+------------------+
Total database accesses: 13

Counting unique values in Google Spreadsheet based on multiple columns

Let's take this spreadsheet for example:
ID | StoreName | StoreID | CheckinTime | User
0 | w1 | 1 | 10:00 | user1
1 | w5 | 1 | 10:01 | user2
2 | w2 | 1 | 10:01 | user1
3 | w1 | 1 | 10:01 | user4
4 | w5 | 1 | 10:05 | user1
5 | w3 | 1 | 10:05 | user6
6 | w1 | 1 | 10:05 | user1
7 | w1 | 1 | 10:05 | user1
Is there a way to create a new column/tab/sheet to count all the unique checkins for a store. So let's say; StoreName "w1" is visited by "user1" 3 times and 1 time by "user4". The expected output will be 2 (2 unique visitors for "w1"). This is the output I would like to have:
ID | StoreName | uniqueCheckins
0 | w1 | 2
1 | w2 | 1
2 | w3 | 1
3 | w4 | 0
4 | w5 | 2

To produce the StoreName and uniqueCheckins output columns:
=QUERY(QUERY(B:E,"select B, E, count(C) group by B, E",1),"select Col1, count(Col2) group by Col1 label count(Col2) 'uniqueCheckins'",1)
However this will omit any StoreName that doesn't appear in the raw data (in your example, w4). Would this be OK?

Updated my answer
=({FILTER(SORT(UNIQUE(Index(UNIQUE({B2:B,E2:E}),,1))),SORT(UNIQUE(Index(UNIQUE({B2:B,E2:E}),,1)))<>""),ARRAYFORMULA(COUNTIF(INDEX(UNIQUE({B2:B,E2:E}),,1),"="&FILTER(SORT(UNIQUE(Index(UNIQUE({B2:B,E2:E}),,1))),SORT(UNIQUE(Index(UNIQUE({B2:B,E2:E}),,1)))<>"")))})

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