I'm currently trying to run Export to PDF script, however when I try running it in DOORS ver 9.6.1, I get a couple of errors.
Line 8: char c = str[i]; contains a syntax error
Any thoughts on how I can resolve this issue?
string makeCaption(Buffer& str)
{
setempty(tempBuf);
int i = 0;
{
for(i = 0; i < length(str); ++i)
char c = str[i];
if('\n' != c) && '\\' != c)
{
tempBuf += c;
}
}
escapeSpecialLaTeXCharacters(tempBuf);
return stringOf(tempBuf);
}
Seems to me like copy/paste problems. When you compare your code with the original you might notice that you moved line 6 with the sole { one line up. If you put it back where it belongs i.e. after the line "for(...)", the code works
Related
I am looking at some Flutter projects and I notice this codes:
#override
int get hashCode => todos.hashCode ^ isLoading.hashCode;
What is this ^ sign doing here? This line of code is found in the AppState of Flutter projects. Is this used to compare the before and after State?
It is the bitwise XOR operator
https://www.dartlang.org/guides/language/language-tour#operators
Below is the way to use XOR operator. I think this is not useful to you but it is helpful to some one who searching for XOR operation
Call below method encryptDecrypt("123456") . you will get output as abcdef
String encryptDecrypt(String input) {
int xorKey = "P".codeUnitAt(0);
String output = "";
int length = input.length;
for (int i = 0; i < length; i++) {
output = (output + String.fromCharCode((input[i].codeUnitAt(0) ^ xorKey)));
}
return output;
}
This is my function. It's working absolutely fine; I just can't get one more thing working.
Instead of the static fopen paths, I need the user to write the path for the files. I tried several things but I can't get it working. Please help
int FileToFile() {
FILE *fp;
FILE *fp_write;
char line[128];
int max=0;
int countFor=0;
int countWhile=0;
int countDo = 0;
fp = fopen("d:\\text.txt", "r+");
fp_write = fopen("d:\\results.txt", "w+");
if (!fp) {
perror("Greshka");
}
else {
while (fgets(line, sizeof line, fp) != NULL) {
countFor = 0;
countWhile = 0;
countDo = 0;
fputs(line, stdout);
if (line[strlen(line)-1] = "\n") if (max < (strlen(line) -1)) max = strlen(line) -1;
else if (max < strlen(line)) max = strlen(line);
char *tmp = line;
while (tmp = strstr(tmp, "for")){
countFor++;
tmp++;
}
tmp = line;
while (tmp = strstr(tmp, "while")){
countWhile++;
tmp++;
}
tmp = line;
while (tmp = strstr(tmp, "do")){
countDo++;
tmp++;
}
fprintf(fp_write, "Na tozi red operatora for go ima: %d pyti\n", countFor);
fprintf(fp_write, "Na tozi red operatora for/while go ima: %d pyti\n", countWhile - countDo);
fprintf(fp_write, "Na tozi red operatora do go ima: %d pyti\n", countDo);
}
fprintf(fp_write, "Maximalen broi simvoli e:%d\n", max);
fclose(fp_write);
fclose(fp);
}
}
Have a look at argc and argv. They are used for command-line arguments passed to a program. This requires that your main function be revised as follows:
int main(int argc, char *argv[])
The argc is an integer that represents the number of command-like arguments, and argv is an array of char* that contain the arguments themselves. Note that for both, the program name itself counts as an argument.
So if you invoke your program like this:
myprog c:\temp
Then argc will be 2, argv[0] will be myprog, and argv[1] will be c:\temp. Now you can just pass the strings to your function. If you pass more arguments, they will be argv[2], etc.
Keep in mind if your path contains spaces, you must enclose it in double quotes for it to be considered one argument, because space is used as a delimiter:
myprog "c:\path with spaces"
I am trying to learn the Dart language, by transposing the exercices given by my school for C programming.
The very first exercice in our C pool is to write a function print_alphabet() that prints the alphabet in lowercase; it is forbidden to print the alphabet directly.
In POSIX C, the straightforward solution would be:
#include <unistd.h>
void print_alphabet(void)
{
char c;
c = 'a';
while (c <= 'z')
{
write(STDOUT_FILENO, &c, 1);
c++;
}
}
int main(void)
{
print_alphabet();
return (0);
}
However, as far as I know, the current version of Dart (1.1.1) does not have an easy way of dealing with characters. The farthest I came up with (for my very first version) is this:
void print_alphabet()
{
var c = "a".codeUnits.first;
var i = 0;
while (++i <= 26)
{
print(c.toString());
c++;
}
}
void main() {
print_alphabet();
}
Which prints the ASCII value of each character, one per line, as a string ("97" ... "122"). Not really what I intended…
I am trying to search for a proper way of doing this. But the lack of a char type like the one in C is giving me a bit of a hard time, as a beginner!
Dart does not have character types.
To convert a code point to a string, you use the String constructor String.fromCharCode:
int c = "a".codeUnitAt(0);
int end = "z".codeUnitAt(0);
while (c <= end) {
print(String.fromCharCode(c));
c++;
}
For simple stuff like this, I'd use "print" instead of "stdout", if you don't mind the newlines.
There is also:
int char_a = 'a'.codeUnitAt(0);
print(String.fromCharCodes(new Iterable.generate(26, (x) => char_a + x)));
or, using newer list literal syntax:
int char_a = 'a'.codeUnitAt(0);
int char_z = 'z'.codeUnitAt(0);
print(String.fromCharCodes([for (var i = char_a; i <= char_z; i++) i]));
As I was finalizing my post and rephrasing my question’s title, I am no longer barking up the wrong tree thanks to this question about stdout.
It seems that one proper way of writing characters is to use stdout.writeCharCode from the dart:io library.
import 'dart:io';
void ft_print_alphabet()
{
var c = "a".codeUnits.first;
while (c <= "z".codeUnits.first)
stdout.writeCharCode(c++);
}
void main() {
ft_print_alphabet();
}
I still have no clue about how to manipulate character types, but at least I can print them.
I have one script behind one spreedsheet and I'm trying to export some cell values to document, and than email the pdv version of temp document..(trash it latter). I have problem with value I get or in the way I'm getting the value from spreedsheet to doc.. I can't manipulate the decimal point..
// fix the price currency display and alignment in GOOGLE DOCUMENT TABLE!
for (var i = 0; i < price.getNumRows(); i++){
for (var j = 0; j < price.getRow(i).getNumCells(); j++){
var temp = price.getCell(i, j);
temp.getChild(0).asParagraph().setSpacingAfter(0);
if((j == 6 || j == 7) && !temp.getText() == "" ) {
(i > 0) ? temp.replaceText(temp.getText(), temp.getText() + " kn") : void false; // skip the first line with header titles...
temp.getChild(0).asParagraph().setAlignment(DocumentApp.HorizontalAlignment.RIGHT);
}
}
}
after (i > 0) there is temp.getText() value.. that sometimes is like: 55,987654 and I would like that to round to two digits.. but can't :(
Thanks for help!
I have found solution..
it's very simple but did take me some time.. hope that can help someone else with similar situation
parseFloat(temp.getText()).toFixed(2) + " kn")
this did the trick and the output is something like: 55,99 kn!
I am writing code to ingest the IOR file generated by the team responsible for the server and use it to bind my client to their object. Sounds easy, right?
For some reason a bit beyond my grasp (having to do with firewalls, DMZs, etc.), the value for the server inside the IOR file is not something we can use. We have to modify it. However, the IOR string is encoded.
What does Visibroker provide that will let me decode the IOR string, change one or more values, then re-encode it and continue on as normal?
I've already looked into IORInterceptors and URL Naming but I don't think either will do the trick.
Thanks in advance!
When you feel like you need to hack an IOR, resist the urge to do so by writing code and whatnot to mangle it to your liking. IORs are meant to be created and dictated by the server that contains the referenced objects, so the moment you start mucking around in there, you're kinda "voiding your warranty".
Instead, spend your time finding the right way to make the IOR usable in your environment by having the server use an alternative hostname when it generates them. Most ORBs offer such a feature. I don't know Visibroker's particular configuration options at all, but a quick Google search revealed this page that shows a promising value:
vbroker.se.iiop_ts.host
Specifies the host name used by this server engine.
The default value, null, means use the host name from the system.
Hope that helps.
Long time ago I wrote IorParser for GNU Classpath, the code is available. It is a normal parser written being aware about the format, should not "void a warranty" I think. IOR contains multiple tagged profiles that are encapsulated very much like XML so we could parse/modify profiles that we need and understand and leave the rest untouched.
The profile we need to parse is TAG_INTERNET_IOP. It contains version number, host, port and object key. Code that reads and writes this profile can be found in gnu.IOR class. I am sorry this is part of the system library and not a nice piece of code to copy paste here but it should not be very difficult to rip it out with a couple of dependent classes.
This question has been repeatedly asked as CORBA :: Get the client ORB address and port with use of IIOP
Use the FixIOR tool (binary) from jacORB to patch the address and port of an IOR. Download the binary (unzip it) and run:
fixior <new-address> <new-port> <ior-file>
The tool will override the content of the IOR file with the 'patched' IOR
You can use IOR Parser to check the resulting IOR and compare it to your original IOR
Use this function to change the IOR. pass stringified IOR as first argument.
void hackIOR(const char* str, char* newIOR )
{
size_t s = (str ? strlen(str) : 0);
char temp[1000];
strcpy(newIOR,"IOR:");
const char *p = str;
s = (s-4)/2; // how many octets are there in the string
p += 4;
int i;
for (i=0; i<(int)s; i++) {
int j = i*2;
char v=0;
if (p[j] >= '0' && p[j] <= '9') {
v = ((p[j] - '0') << 4);
}
else if (p[j] >= 'a' && p[j] <= 'f') {
v = ((p[j] - 'a' + 10) << 4);
}
else if (p[j] >= 'A' && p[j] <= 'F') {
v = ((p[j] - 'A' + 10) << 4);
}
else
cout <<"invalid octet"<<endl;
if (p[j+1] >= '0' && p[j+1] <= '9') {
v += (p[j+1] - '0');
}
else if (p[j+1] >= 'a' && p[j+1] <= 'f') {
v += (p[j+1] - 'a' + 10);
}
else if (p[j+1] >= 'A' && p[j+1] <= 'F') {
v += (p[j+1] - 'A' + 10);
}
else
cout <<"invalid octet"<<endl;
temp[i]=v;
}
temp[i] = 0;
// Now temp has decoded IOR string. print it.
// Replace the object ID in temp.
// Encoded it back, with following code.
int temp1,temp2;
int l,k;
for(k = 0, l = 4 ; k < s ; k++)
{
temp1=temp2=temp[k];
temp1 &= 0x0F;
temp2 = temp2 & 0xF0;
temp2 = temp2 >> 4;
if(temp2 >=0 && temp2 <=9)
{
newIOR[l++] = temp2+'0';
}
else if(temp2 >=10 && temp2 <=15)
{
newIOR[l++] = temp2+'A'-10;
}
if(temp1 >=0 && temp1 <=9)
{
newIOR[l++] = temp1+'0';
}
else if(temp1 >=10 && temp1 <=15)
{
newIOR[l++] = temp1+'A'-10;
}
}
newIOR[l] = 0;
//new IOR is present in new variable newIOR.
}
Hope this works for you.