Converting strings to numbers
prise = "1200$"
print(tonumber( prise))
prise = "1$20das0$"
print(tonumber( prise))
tell me how to get only numbers from a string
You can use pattern matching. The pattern [^%d] matches everything that is not a digits and we replace it with nothing.
local prise = "1$20das0$"
local onlydigits = string.gsub(prise, "[^%d]", "")
print(tonumber(onlydigits))
Live example on Wandbox
Related
I was wondering if I could make an app in which time is display in words instead of conventional numbers. Do you think that there is any package for dart to convert time or numbers to words?
For example
1:30 AM will be One : Thirty AM
Thanks for reading this question. Have a wonderful day.
You can use any of available package to convert from number to words example
package: https://pub.dev/packages/number_to_words
import 'package:number_to_words/number_to_words.dart';
main(){
String input = '1:30 AM';
var s1 = input.split(':');
var s2 = s1[1].split(' ');
String hour = s1[0];
String minute = s2[0];
String hourWord = NumberToWord().convert('en-in',int.parse(hour));
String minuteWord = NumberToWord().convert('en-in',int.parse(minute));
print('$hourWord:$minuteWork ${s2[1]}');
}
Code:
path5 = '2.Project\WP101 (237641784)\QR2\5.Project\\'
print ('path5 =',path5)
I get:
path5 = 2.Project\WP101 (237641784)\QR2.Project\
What can I do to stop getting the weird sign after QR2 in the path name?
You need to ignore escape chars.
#ignoring escape sequences
#ignoring single quote escape sequences
str1 = r"Hi, I\'m IncludeHelp"
#ignoring double quotes escape sequences
str2 = r"\"Hello world\""
#ignoring path escape sequences
str3 = r"D:\\work_folder\\python_works"
#ignoring hexadecimal values escape sequences
str4 = r"This is \x49\x6E\x63\x6C\x75\x64\x65\x48\x65\x6C\x70"
print(str1);
print(str2);
print(str3);
print(str4);
Just put an r infront of your string and you are good to go.
In your case:
path5 = r'2.Project\WP101 (237641784)\QR2\5.Project\'
print ('path5 =',path5)
My case is a little special, I need to insert space or comma for every 4 digits.
Example:
18686305
1868,6305 or 1868 6305
How can I do in swift 4?
A NumberFormatter is designed to convert numerical values to String values based on a pre-defined format. In your case, the following will insert grouping separators every four digits:
import Foundation
let groupingSeparator = "," // determined based on user input, as per the question
let formatter = NumberFormatter()
formatter.positiveFormat = "####,####"
formatter.negativeFormat = "-####,####"
formatter.groupingSeparator = groupingSeparator
if let string = formatter.string(from: 18686305) {
print(string) // prints "1868,6305"
}
The positiveFormat and negativeFormat variables follow the Unicode Technical Standard #35.
Is there a function to capitalize each word in a string or is this a manual process?
For e.g. "bob is tall"
And I would like "Bob Is Tall"
Surely there is something and none of the Swift IOS answers I have found seemed to cover this.
Are you looking for capitalizedString
Discussion
A string with the first character in each word changed to its corresponding uppercase value, and all remaining characters set to their corresponding lowercase values.
and/or capitalizedStringWithLocale(_:)
Returns a capitalized representation of the receiver using the specified locale.
For strings presented to users, pass the current locale ([NSLocale currentLocale]). To use the system locale, pass nil.
Swift 3:
var lowercased = "hello there"
var stringCapitalized = lowercased.capitalized
//prints: "Hello There"
Since iOS 9 a localised capitalization function is available as capitalised letters may differ in languages.
if #available(iOS 9.0, *) {
"istanbul".localizedCapitalizedString
// In Turkish: "İstanbul"
}
An example of the answer provided above.
var sentenceToCap = "this is a sentence."
println(sentenceToCap.capitalizedStringWithLocale(NSLocale.currentLocale()) )
End result is a string "This Is A Sentence"
For Swift 3 it has been changed to capitalized .
Discussion
This property performs the canonical (non-localized) mapping. It is suitable for programming operations that require stable results not depending on the current locale.
A capitalized string is a string with the first character in each word changed to its corresponding uppercase value, and all remaining characters set to their corresponding lowercase values. A “word” is any sequence of characters delimited by spaces, tabs, or line terminators (listed under getLineStart(_:end:contentsEnd:for:)). Some common word delimiting punctuation isn’t considered, so this property may not generally produce the desired results for multiword strings.
Case transformations aren’t guaranteed to be symmetrical or to produce strings of the same lengths as the originals. See lowercased for an example.
There is a built in function for that
nameOfString.capitalizedString
This will capitalize every word of string. To capitalize only the first letter you can use:
nameOfString.replaceRange(nameOfString.startIndex...nameOfString.startIndex, with: String(nameOfString[nameOfString.startIndex]).capitalizedString)
Older Thread
Here is what I came up with that seems to work but I am open to anything that is better.
func firstCharacterUpperCase(sentenceToCap:String) -> String {
//break it into an array by delimiting the sentence using a space
var breakupSentence = sentenceToCap.componentsSeparatedByString(" ")
var newSentence = ""
//Loop the array and concatinate the capitalized word into a variable.
for wordInSentence in breakupSentence {
newSentence = "\(newSentence) \(wordInSentence.capitalizedString)"
}
// send it back up.
return newSentence
}
or if I want to use this as an extension of the string class.
extension String {
var capitalizeEachWord:String {
//break it into an array by delimiting the sentence using a space
var breakupSentence = self.componentsSeparatedByString(" ")
var newSentence = ""
//Loop the array and concatinate the capitalized word into a variable.
for wordInSentence in breakupSentence {
newSentence = "\(newSentence) \(wordInSentence.capitalizedString)"
}
// send it back up.
return newSentence
}
}
Again, anything better is welcome.
Swift 5 version of Christopher Wade's answer
let str = "my string"
let result = str.capitalized(with: NSLocale.current)
print(result) // prints My String
I wanted to know how does writeInt treat a 32 bit unsigned or a signed integer passed to it?
It is easy to understand that how it works with a hexadecimal number. Util.Print will print the corresponding ASCII Characters.
0x41424344 will be broken down into 4 1 byte characters, A, B, C and D.
It seems like its different when an integer is passed to writeInt.
for instance,
var test: ByteArray = new ByteArray();
test.writeInt(0x41424344); // prints ABCD
test.writeInt(2590463591); // prints gVg
test.writeInt(1119885898); // prints BÀJ
I am unclear how the Util.Print function treats the integers written into the ByteArray by writeInt.
The characters, gVg do not correspond to the integer number, 2590463591
According to the definition of writeInt here:
http://livedocs.adobe.com/livecycle/es/sdkHelp/common/langref/flash/utils/ByteArray.html#writeInt%28%29
It states that it works with a 32 Bit Signed Integer.
If someone can elaborate over how it translates the integers to characters, it would be helpful.
EDIT: And how does it handle negative integers?
For instance,
test.writeInt(-11338743); // prints ÿRü
So,
-11338743 = 0xFF52FC09
is that correct?
Thanks.
If you interpret encoded bytes as ASCII
dec hex ascii
1094861636 = 0x41424344 = ABCD
2590463591 = 0x9A675667 = gVg
1119885898 = 0x42C01A4A = BÀJ
Also, note that int vs unsigned int would implement different functions:
var test:ByteArray = new ByteArray();
test.writeInt(0x41424344);
test.writeUnsignedInt(0x41424344);