How can I implement this Automaton in Java? - automaton

Question

I want to implement this deterministic finite automaton in Java and I want the program the program to recognize the language of the automaton.
Automaton
I already got this code, but I don´t no how to make the switch the best way :
int estado = 0;
char c = 0;
//else ir para erro
switch(aOpcao) {
case 1:
if(c == '/')
estado = 1;
break;
case 2:
if(c == '!')
estado = 7;
if(c == '#')
estado = 6;
break;
case 3:
if(c == 'a' || c == 'b' || c == 'c' || c == 'd' || c == 'e' || c == 'f'
|| c == 'g' || c == 'h' || c == 'i' || c == 'j' || c == 'k' ||
c == 'l' || c == 'm' || c == 'n' || c == 'o' || c == 'p' || c == 'q'
|| c == 'r' || c == 's' || c == 't' || c == 'u' || c == 'v' || c == 'w'
|| c == 'x' || c == 'y' || c == 'z' )
estado = 8;
if(c == '!')
estado = 7;
if(c == ',')
estado = 14;
if(c == 'a' || c == 'b' || c == 'c' || c == 'd' || c == 'e' || c == 'f'
|| c == 'g' || c == 'h' || c == 'i' || c == 'j' || c == 'k' ||
c == 'l' || c == 'm' || c == 'n' || c == 'o' || c == 'p' || c == 'q'
|| c == 'r' || c == 's' || c == 't' || c == 'u' || c == 'v' || c == 'w'
|| c == 'x' || c == 'y' || c == 'z' )
estado = 13;
break;

Answer 1

if you are looking for a better way to check if c is alphabet or not for those two long if statement.
then one simple way in java is to change it to
if( (c >= 'a' && c <= 'z') )
if you are talking about how to completely translate the above code into java. You have read java switch() statement and java documentation by yourself. Your question seems like a homework problem.