Ruby on Rails beginner question : equality - ruby-on-rails

I'm starting to know ROR and I was doing a kind of blog with articles, etc...
I did this code :
def show
id = params[:id]
list = Article.all
is_valid = false
list.all.each do |article|
if article.id == id
#is_valid = true
break
end
end
As you can see, this code just wants to check if the article ID exists or not. So I'm testing equality between id and article.id (which's a model linked to the appropriated table in the database) BUT when I try to use or display #is_valid boolean I saw that article.id == id is FALSE every time, even if article.id = 2 and id = 2. I tried to think about everything that can make this occuring, but I admit I still misunderstand this.
Then I ask you if you know why this is occuring. Of course, an equality like 2 == 2 will change #is_valid to true.
Thank you for your help !

Maybe its because params[:id] it's a string and article.id it's an Integer
(byebug) params
{"controller"=>"admin/my_controller", "action"=>"edit", "id"=>"1"}
And yes it is... "id" is a string "1", so you may try this:
def show
id = params[:id].to_i
list = Article.all
is_valid = false
list.all.each do |article|
if article.id == id
#is_valid = true
break
end
end
end
And maybe could work.
This is the answer to your question,
But if you want to learn a little more about Activerecord you can do this
Article.exists?(params[:id])
and that will do what you are trying to do just with a query against db.
and if you want to get just a simple article
record = Article.find_by(id: params[:id]) #return nil when not exist
if record # if nil will threat like false on ruby
#my code when exist
else
#my code when not exist
end
will work (you also can use find but find will throw an exception ActiveRecord::RecordNotFound when not exists so you have to catch that exception.
Activerecord has many ways to check this you dont need to do it by hand.

def show
#article = Article.find(params[:id])
end
This will create a database query which returns a single row. .find raises a ActiveRecord::NotFound exception if the record is not found. Rails catches this error and shows a 404 page. Article.find_by(id: params[:id]) is the "safe" alternative that does not raise.
Your code is problematic since list = Article.all will load all the records out of the database which is slow and will exhaust the memory on the server if you have enough articles. Its the least effective way possible to solve the task.
If you want to just test for existence use .exists? or .any?. This creates a COUNT query instead of selecting the rows.
Article.where(title: 'Hello World').exists?

Related

Problem with selecting elements with the same params

What i do wrong? I want to return every products which pass condition:
def show
products = Product.select{|x| x[:category_id] == params[:id]}
render json: products
end
When i write
def show
products = Product.select{|x| x[:category_id] == 1}
render json: products
end
it works why the first example doesn't work?
I am pretty sure that there is mismatch in data type.
1=='1' #will be always false
1==1 #will be true
'1'=='1' #will be true as well
And also check for nil value from params[:id]
Please make sure to change as follows
def show
products = Product.select{|x| x.category_id == params[:id].to_i}
render json: products
end
OR
The best solution as suggested by #Eyeslandic is to use .where as it will not check for mismatch in data type. And also you don't have to take care of nil value from params[:id].
You should really be using a where to stop sql from loading all your products.
#products = Product.where('category_is = ?', params[:id])
The being said, if you are sticking to rails restful conventions, the fact you have a param called :id that is the category_id suggests you are on the category controller. So maybe consider changing your logic to:
#category = Category.includes(:products).find(params[:id])
you can then access products via
#category.products
or if your not interested in the category too much maybe
#products = Category.includes(:products).find(params[:id])&.products

removing objects from an array during a loop

I am trying to filter the results of an user search in my app to only show users who are NOT friends. My friends table has 3 columns; f1 (userid of person who sent request), f2 (userid of friend who received request), and confirmed (boolean of true or false). As you can see, #usersfiltered is the result of the search. Then the definition of the current user's friend is established. Then I am trying to remove the friends from the search results. This does not seem to be working but should be pretty straight forward. I've tried delete (not good) and destroy.
def index
#THIS IS THE SEARCH RESULT
#usersfiltered = User.where("first_name LIKE?", "%#{params[:first_name]}%" )
#THIS IS DEFINING ROWS ON THE FRIEND TABLE THAT BELONG TO CURRENT USER
#confirmedfriends = Friend.where(:confirmed => true)
friendsapproved = #confirmedfriends.where(:f2 => current_user.id)
friendsrequestedapproved = #confirmedfriends.where(:f1 => current_user.id)
#GOING THROUGH SEARCH RESULTS
#usersfiltered.each do |usersfiltered|
if friendsapproved.present?
friendsapproved.each do |fa|
if usersfiltered.id == fa.f1
#NEED TO REMOVE THIS FROM RESULTS HERE SOMEHOW
usersfiltered.remove
end
end
end
#SAME LOGIC
if friendsrequestedapproved.present?
friendsrequestedapproved.each do |fra|
if usersfiltered.id == fra.f2
usersfiltered.remove
end
end
end
end
end
I would flip it around the other way. Take the logic that is loop-invariant out of the loop, which gives a good first-order simplification:
approved_ids = []
approved_ids = friendsapproved.map { |fa| fa.f1 } if friendsapproved.present?
approved_ids += friendsrequestedapproved.map { |fra| fra.f2 } if friendsrequestedapproved.present?
approved_ids.uniq! # (May not be needed)
#usersfiltered.delete_if { |user| approved_ids.include? user.id }
This could probably be simplified further if friendsapproved and friendsrequestedapproved have been created separately strictly for the purpose of the deletions. You could generate a single friendsapproval list consisting of both and avoid unioning id sets above.
While I agree that there may be better ways to implement what you're doing, I think the specific problem you're facing is that in Rails 4, the where method returns an ActiveRecord::Relation not an Array. While you can use each on a Relation, you cannot in general perform array operations.
However, you can convert a Relation to an Array with the to_a method as in:
#usersfiltered = User.where("first_name LIKE?", "%#{params[:first_name]}%" ).to_a
This would then allow you to do the following within your loop:
usersfiltered.delete(fa)

assigning values to model

I'm kinda new to coding on rails. It would be great if you could help me out with what I think might be noob question.Here's my code:
def create
#project = Project.new(params[:project])
if #project.save
redirect_to new_project_path
end
student=#project.student_str.split(";")
#users = User.where(:code => student)
#users.each do |c|
puts c.email
end
#users.each do |c|
puts "I'm here"
c.projects = "#{c.projects};#{#project.id}"
end
end
So, in the create method, Each time a new project is created a string called student_str is stored where the ID number of each student is seperated by a ";". I split that string to an array using the split function to get an array of student ID's. I have the puts c.email and puts "I'm here" to make sure the loops are working fine. I get the proper outputs on terminal.
The problem here is the
c.projects = "#{c.projects};#{#project.id}"
That simply does not seem to be working.
My model is not updated when this line is executed. I get no errors though.
Can you tell me what I might have to do to fix this?
thanks!
You have to call c.save after you updated the projects attribute. Otherwise the object is updated but not the database so the next time you load it the changes are gone.

Iterating through every record in a database - Ruby on Rails / ActiveRecord

n00b question. I'm trying to loop through every User record in my database. The pseudo code might look a little something like this:
def send_notifications
render :nothing => true
# Randomly select Message record from DB
#message = Message.offset(rand(Message.count)).first
random_message = #message.content
#user = User.all.entries.each do
#user = User.find(:id)
number_to_text = ""
#user.number = number_to_text #number is a User's phone number
puts #user.number
end
end
Can someone fill me in on the best approach for doing this? A little help with the syntax would be great too :)
Here is the correct syntax to iterate over all User :
User.all.each do |user|
#the code here is called once for each user
# user is accessible by 'user' variable
# WARNING: User.all performs poorly with large datasets
end
To improve performance and decrease load, use User.find_each (see doc) instead of User.all. Note that using find_each loses the ability to sort.
Also a possible one-liner for same purpose:
User.all.map { |u| u.number = ""; puts u.number }

How to store the result of my algorithm?

I have an algorithm that searches through all of my sites users, finding those which share a common property with the user using the algorithm (by going to a certain page). It can find multiple users, each can have multiple shared properties. The algorithm works fine, in terms of finding the matches, but I'm having trouble working out how to store the data so that later I'll be able to use each unit of information. I need to be able to access both the found users, and each of the respective shared properties, so I can't just build a string. This is an example of the output, being run from the perspective of user 1:
user 4
sharedproperty3
sharedproperty6
user 6
sharedproperty6
sharedproperty10
shareproperty11
What do I need to do to be able to store this data, and have access to any bit of it for further manipulation? I was thinking of a hash of a hash, but I can't really wrap my head around it. I'm pretty new to programming, and Ruby in particular. Thanks for reading!
EDIT - Here's the code. I'm fully expecting this to be the most incorrect way to do this, but it's my first try so be gentle :)
So if I'm understanding you guys correctly, instead of adding the interests to a string, I should be creating an array or a hash, adding each interest as I find it, then storing each of these in an array or hash? Thanks so much for the help.
def getMatchedUsers
matched_user_html = nil
combined_properties = nil
online_user_list = User.logged_in.all
shared_interest = false
online_user_list.each do |n| # for every online user
combined_properties = nil
if n.email != current_user.email # that is not the current user
current_user.properties.each do |o| # go through all of the current users properties
n.properties.each do |p| # go through the online users properties
if p.interestname.eql?(o.interestname) # if the online users property matches the current user
shared_interest = true
if combined_properties == nil
combined_properties = o.interestname
else
combined_properties = combined_properties + ", " + o.interestname
end
end
end
if shared_interest == true
matched_user_html = n.actualname + ": " + combined_properties
end
end
end
end
return matched_user_html
render :nothing => true
end
This returns an array of hashes with all users and their corresponding sharedproperties.
class User
def find_matching_users
returning Array.new do |matching_users|
self.logged_in.each do |other_user|
next if current_user == other_user # jump if current_user
# see http://ruby-doc.org/core/classes/Array.html#M002212 for more details on the & opreator
unless (common_properties = current_user.properties & other_user.properties).empty?
matching_users << { :user => other_user, :common_properties => common_properties }
end
end
end
end
end
In your view you can do something like this:
<%- current_user.find_matching_users.each do |matching_user| -%>
<%-# you can acccess the user with matching_user[:user] -%>
<%-# you can acccess the common properties with matching_user[:common_properties] -%>
<%- end -%>
You can use a hash table with the key being the user object and the value being an array of the shared properties . This is assuming that you first need to do a lookup based on the user .
Something like this :
#user_results = { user1 => [sharedproperty3,sharedproperty7] , user2 => [sharedproperty10,sharedproperty11,sharedproperty12]}
You can then acces the values like :
#user_results[user1]
or you can also iterate over all the keys using #user_results.keys

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