Function only available for parameter property - ios

Is it possible to have a function available only when the property of a parameter meets a certain condition? For example, by using the where keyword? I gave an example of the idea below.
struct ASN1 {
enum Types: UInt8 {
case constructed
case primitive
}
class Tag {
let type: Types
}
class Encoder {
func enter(tag: ASN1.Tag) where tag.type == .constructed {
// Function only available when tag property type is .constructed
}
}
}

Related

Create a protocol with default implementation that gives name/title/self of Enum as string

I am trying to create a protocol with default implementation that returns enum itself as string. But not able to find the correct syntax.
This is the code I tried so far, but it is not taking default implementation
protocol TestSelf {
static var desc: String { get set }
}
extension TestSelf {
get {
static var desc: String {
String(describing: self)
}
set {
print(\(new value))
}
}
enum Test: TestSelf { }
Access
print(Test.desc)
Asking me to implement the desc in the enum saying 'static var' declaration requires an initializer expression or an explicitly stated getter. I don't want to initialize it again. It should work with Default Implementation.
Ask:
At all places I don't need to write
String(describing: Test.self)
instead I can directly use
Test.desc
I think you want something like this (this is playground code):
protocol SelfDescriber {
static var descriptionOfSelf: String {get}
}
extension SelfDescriber {
static var descriptionOfSelf: String {
String(describing: Self.self)
}
}
enum Test: SelfDescriber {}
print(Test.descriptionOfSelf) // "Test"

How to declare optional class property with generic `Results`

I have a lot of Object subclasses which all of them conforms to some protocol (Transport for ex.) and I don't know which type of objects (Car or Bus for ex.) will be displayed, it depends on some parameters and therefore I want to have some generic computed value which can return Results of Objects based on Type enum value. Can I do that without casting Results to array?
protocol Transport { }
class Car: Object, Transport { }
class Bus: Object, Transport { }
// #1
var array: Array<Transport>? {
return [Car(), Bus()]
}
// #2
var results: Results<Object>? {
if displayCars {
realm?.objects(Car.self)
} else {
realm?.objects(Bus.self)
}
}
№1 will be fine but №2 will not compile because:
Cannot convert return expression of type 'Results<Car>?' to return type 'Results<Object>?'
Update
// Another example.
var objects: Results<Object>?
override func viewDidLoad() {
super.viewDidLoad()
if displayCars {
objects = realm.objects(Car.self)
}
}
Compile error: Cannot assign value of type 'Results<Car>?' to type 'Results<Object>?'
Unfortunately, you will probably have to turn Results<Car> into [Car] in order for this to work. The built-in Swift collections are covariant, but any user-defined Swift generic type (including user-defined collections) is invariant. There's no way right now to specify otherwise.

Swift Type Erasure with Generic Enum and Generic Protocol

I have had to use type erasure in Swift a few times however it always involved a generic protocol. In this case, it involves both a generic enum and and generic protocol and I'm stumped.
Here is my generic enum and generic protocol with the necessary extension:
enum UIState<T> {
case Loading
case Success([T])
case Failure(ErrorType)
}
protocol ModelsDelegate: class {
associatedtype Model
var state: UIState<[Model]> { get set }
}
extension ModelsDelegate {
func getNewState(state: UIState<[Model]>) -> UIState<[Model]> {
return state
}
func setNewState(models: UIState<[Model]>) {
state = models
}
}
And here is my type erased generic class:
class AnyModelsDelegate<T>: ModelsDelegate {
var state: UIState<[T]> {
get { return _getNewState(UIState<[T]>) } // Error #1
set { _setNewState(newValue) }
}
private let _getNewState: ((UIState<[T]>) -> UIState<[T]>)
private let _setNewState: (UIState<[T]> -> Void)
required init<U: ModelsDelegate where U.Model == T>(_ models: U) {
_getNewState = models.getNewState
_setNewState = models.setNewState
}
}
I'm getting the following errors (they are marked in the code sample):
Error #1:
Cannot convert value of type '(UIState<[T]>).Type' (aka 'UIState<Array<T>>.Type') to expected argument type 'UIState<[_]>' (aka 'UIState<Array<_>>')
I have been working on this for awhile and there have been quite a few variations on this code that "almost worked". The error always has to do with the getter.
The problem that causes this error, as #dan has pointed out, is that on this line you're trying to pass a type as an argument, instead of an instance of that type:
get { return _getNewState(UIState<[T]>) }
However, I would question your use of an argument to this function in the first place, surely a getting function should have no argument at all? In this case you'll simply want your _getNewState function to have the signature () -> UIState<[T]>, and call it like so:
get { return _getNewState() }
Also, if your getNewState and setNewState(_:) functions in your protocol extension only exist in order to forward the getting and setting of your state property to the type-erasure – you can simplify your code by getting rid of them entirely and use closure expressions in the type-erasure's init instead:
_getNewState = { models.state }
_setNewState = { models.state = $0 }
(These work by capturing a reference to the models argument, for more info see Closures: Capturing Values)
Finally, I suspect that you mean to refer to UIState<T> rather than UIState<[T]> throughout your code, as T in this case refers to an element in the array that your .Success case has as an associated value (unless you want a 2D array here).
All in all, with the above proposed changes, you'll want your code to look something like this:
enum UIState<T> {
case Loading
case Success([T])
case Failure(ErrorType)
}
protocol ModelsDelegate: class {
associatedtype Model
var state: UIState<Model> { get set }
}
class AnyModelsDelegate<T>: ModelsDelegate {
var state: UIState<T> {
get { return _getNewState() }
set { _setNewState(newValue) }
}
private let _getNewState: () -> UIState<T>
private let _setNewState: (UIState<T>) -> Void
required init<U: ModelsDelegate where U.Model == T>(_ models: U) {
_getNewState = { models.state }
_setNewState = { models.state = $0 }
}
}

How do I add different types conforming to a protocol with an associated type to a collection?

As an exercise in learning I'm rewriting my validation library in Swift.
I have a ValidationRule protocol that defines what individual rules should look like:
protocol ValidationRule {
typealias InputType
func validateInput(input: InputType) -> Bool
//...
}
The associated type InputType defines the type of input to be validated (e.g String). It can be explicit or generic.
Here are two rules:
struct ValidationRuleLength: ValidationRule {
typealias InputType = String
//...
}
struct ValidationRuleCondition<T>: ValidationRule {
typealias InputType = T
// ...
}
Elsewhere, I have a function that validates an input with a collection of ValidationRules:
static func validate<R: ValidationRule>(input i: R.InputType, rules rs: [R]) -> ValidationResult {
let errors = rs.filter { !$0.validateInput(i) }.map { $0.failureMessage }
return errors.isEmpty ? .Valid : .Invalid(errors)
}
I thought this was going to work but the compiler disagrees.
In the following example, even though the input is a String, rule1's InputType is a String, and rule2s InputType is a String...
func testThatItCanEvaluateMultipleRules() {
let rule1 = ValidationRuleCondition<String>(failureMessage: "message1") { $0.characters.count > 0 }
let rule2 = ValidationRuleLength(min: 1, failureMessage: "message2")
let invalid = Validator.validate(input: "", rules: [rule1, rule2])
XCTAssertEqual(invalid, .Invalid(["message1", "message2"]))
}
... I'm getting extremely helpful error message:
_ is not convertible to ValidationRuleLength
which is cryptic but suggests that the types should be exactly equal?
So my question is... how do I append different types that all conform to a protocol with an associated type into a collection?
Unsure how to achieve what I'm attempting, or if it's even possible?
EDIT
Here's it is without context:
protocol Foo {
typealias FooType
func doSomething(thing: FooType)
}
class Bar<T>: Foo {
typealias FooType = T
func doSomething(thing: T) {
print(thing)
}
}
class Baz: Foo {
typealias FooType = String
func doSomething(thing: String) {
print(thing)
}
}
func doSomethingWithFoos<F: Foo>(thing: [F]) {
print(thing)
}
let bar = Bar<String>()
let baz = Baz()
let foos: [Foo] = [bar, baz]
doSomethingWithFoos(foos)
Here we get:
Protocol Foo can only be used as a generic constraint because it has
Self or associated type requirements.
I understand that. What I need to say is something like:
doSomethingWithFoos<F: Foo where F.FooType == F.FooType>(thing: [F]) {
}
Protocols with type aliases cannot be used this way. Swift doesn't have a way to talk directly about meta-types like ValidationRule or Array. You can only deal with instantiations like ValidationRule where... or Array<String>. With typealiases, there's no way to get there directly. So we have to get there indirectly with type erasure.
Swift has several type-erasers. AnySequence, AnyGenerator, AnyForwardIndex, etc. These are generic versions of protocols. We can build our own AnyValidationRule:
struct AnyValidationRule<InputType>: ValidationRule {
private let validator: (InputType) -> Bool
init<Base: ValidationRule where Base.InputType == InputType>(_ base: Base) {
validator = base.validate
}
func validate(input: InputType) -> Bool { return validator(input) }
}
The deep magic here is validator. It's possible that there's some other way to do type erasure without a closure, but that's the best way I know. (I also hate the fact that Swift cannot handle validate being a closure property. In Swift, property getters aren't proper methods. So you need the extra indirection layer of validator.)
With that in place, you can make the kinds of arrays you wanted:
let len = ValidationRuleLength()
len.validate("stuff")
let cond = ValidationRuleCondition<String>()
cond.validate("otherstuff")
let rules = [AnyValidationRule(len), AnyValidationRule(cond)]
let passed = rules.reduce(true) { $0 && $1.validate("combined") }
Note that type erasure doesn't throw away type safety. It just "erases" a layer of implementation detail. AnyValidationRule<String> is still different from AnyValidationRule<Int>, so this will fail:
let len = ValidationRuleLength()
let condInt = ValidationRuleCondition<Int>()
let badRules = [AnyValidationRule(len), AnyValidationRule(condInt)]
// error: type of expression is ambiguous without more context

Cannot invoke 'handler' with argument list of type '([Post])'

I both do, and don't get why the last line of this playground throws a compiler error:
protocol Model { }
struct Post: Model {
var content = "Hello"
}
struct Posts: Model {
var allPosts: [Post] = [Post(), Post(), Post()]
}
func handler(items: [Model]) { }
var posts = Posts()
handler(posts.posts)
If you're reading between the lines, my goal is to be able to invoke a function with an argument that is an array of structs that conform to a protocol. The function should be able to deal with arrays of different types of structs. Would love to know what I'm missing, and if you have a suggestion for a better solution.
Thanks!
It seems to be Swift limitations. But you can do some workaround like this using Generics:
func handler<T: Model>(items: [T]) { }
or else make your protocol a #objc protocol which you can only apply to class type:
#objc protocol Model { }
class Post: Model {
var content = "Hello"
}

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