Boost documents in search results which are matched to array - ruby-on-rails

Question

I have this relatively complex search query that's already being built and working with perfect sorting.
But I think here searching is slow just because of script so all I want to remove script and write query accordingly.
current code :-
"sort": [
{
"_script": {
"type": "number",
"script": {
"lang": "painless",
"source": "double pscore = 0;for(id in params.boost_ids){if(params._source.midoffice_master_id == id){pscore = -999999999;}}return pscore;",
"params": {
"boost_ids": [
3,
4,
5
]
}
}
}
}]
Above code explaination:-
For example, if a match query would give a result like:
[{m_id: 1, name: A}, {m_id: 2, name: B}, {m_id: 3, name: C}, {m_id: 4, name: D}, ...]
So I want to boost document with m_id array [3, 4, 5] which would then transform the result into:
[{m_id: 3, name: C}, {m_id: 4, name: D}, {m_id: 1, name: A}, {m_id: 2, name: B}, ...]

Answer 1

You can make use of the below query using Function Score Query(for boosting) and Terms Query (used to query array of values)
Note that the logic I've mentioned is in the should clause of the bool query.
POST <your_index_name>/_search
{
"query": {
"bool": {
"must": [
{
"match_all": {} //just a sample must clause to retrieve all docs
}
],
"should": [
{
"function_score": { <---- Function Score Query
"query": {
"terms": { <---- Terms Query
"m_id": [
3,4,5
]
}
},
"boost": 100 <---- Boosting value
}
}
]
}
}
}
So basically, you can remove the sort logic completely and add the above function query in your should clause, which would give you the results in the order you are looking for.
Note that you'd have to find a way to add the logic correctly in case if you have much complex query, and if you are struggling with anything, do let me know. I'd be happy to help!!
Hope this helps!