Parse string between " characters ANTLR4 - parsing

Question

My task is to write grammar for custom query language, where users can write some basic queries.
My grammar so far:
grammar EAQL;
prog: cond;
cond: cond logical_operator cond | elexpr comparison_operator VALUE;
elexpr: ELSTEREOTYPE '.' eattribute;
conexpr: CSTEREOTYPE '.' cattribute;
eattribute: 'Name' | 'Path' | 'GUID' | conexpr;
cattribute: 'Name' | 'GUID' | elexpr;
VALUE: QUOTATION ( ~([QUOTATION]) | ~('\n'))+ QUOTATION;
ELSTEREOTYPE: 'EG_ApplicationComponent' | 'EG_ApplicationFunction';
CSTEREOTYPE: 'EG_Flow';
SPACE: ' ';
QUOTATION: '"';
EOL: '\n';
WS : (' ' | '\t')+ -> channel(HIDDEN);
AND: 'AND';
OR: 'OR';
logical_operator: AND | OR;
EQUALS: '=';
GREATER_THAN: '>';
SMALLER_THAN: '<';
comparison_operator: GREATER_THAN | SMALLER_THAN | EQUALS;
When i try to parse this string
EG_ApplicationComponent.Name= "name1" AND EG_ApplicationFunction.Name="name2"
ANTLR will create following children in tree:
'EG_ApplicationComponent'
'.'
'Name'
'='
'"name1" AND EG_ApplicationFunction.Name= "name2"'
I am absolute beginner in creating parsers, but i still do not understand why it does greedy matching until end of string in VALUE, when I specified that matching should end when QUOTATION is found. I expect, that if would match 'name1' as VALUE in first branch of tree and then create another branch with EG_ApplicationFunction.Name= "name2" parsed as previous branch.
This would be my expected result:
'EG_ApplicationComponent'
'.'
'Name'
'='
'"name1"'
AND
EG_ApplicationFunction
'.'
'Name'
'='
'"name2"'

Answer 1

~[QUOTATION] matches any character other than Q, U, O, T, A, T, I, O and N. What you need to do is ~["].
Your VALUE rule could look like this:
VALUE
: QUOTATION ~["\r\n]* QUOTATION
;