My docker sometimes create randomw container name based on my docker image e.g. yeeyi
How to docker rm all off the containers where the image is yeeyi?
is there something like? docker rm all --image yeeyi in a single command line?
You can do this using this command:
docker rm $(docker ps -a -q --filter "ancestor=ubuntu")
replace ubuntu with your image name.
This basically gets all the container ids (running or otherwise) that use the image ubuntu and then removes them.
Try the below workaround(update the grep string according to your need);
docker ps --filter "status=exited" | grep yeeyi
Check the output of above command, if you have the correct list, then use the below command;
docker rm (docker ps --filter "status=exited" | grep yeeyi | awk '{print $1}')
Another option is to check the exit code of such randomly created container. If that code is different then rest you can use the below command to get list of such containers;
docker ps -a --filter "exited=<status code>"
I am basically looking to achieve this 2 steps:
1. Run the docker image:
docker run -p 80:80 some-image-name:25
2. Now "docker ps" returns whole data about the container but I was looking for just the container ID to
3. run some test on it.. ex.
docker exec -it /usr/bin/npm run test
So my question is how I can get just the container id from step 2.
Note: I need this flow for my pipeline script in Jenkins.
docker ps -a -q
This will give you only container's id
You could use awk to get the container ID's as follows:
docker ps | awk 'NR > 1 {print $1}'
This one-liner outputs all the container ID's printed by docker ps. To get only the first one you would use:
docker ps | awk 'NR > 1 {print $1; exit}'
Even though that answers your question I recommend that you use container names instead of relying on container ID's.
P.S.: This solution is on average 1 millisecond slower than docker ps -q, but it is significantly more flexible.
docker ps --format {{.ID}}
Will return only the ids of running containers.
you can use docker functionality to get this done:
docker ps --filter volume=remote-volume --format "table {{.ID}}\t{{.Mounts}}"
with --format "{{.ID}}" you'd get the ids only. You can also filter. Read the documentation of docker ps for more details
All the below command give you container id's
docker ps -aqf "name=containername"
docker ps --no-trunc -aqf name=containername
docker container ls | grep 'container-name' | awk '{print $1}'```
You can get container ID using following command:
docker ps -q
how to find which docker container is using/referencing a particular image?
To give more detail, say I have some 10 docker images and there are some 30 docker containers.. How can find which containers are created using docker image ID XXXXX using a simple command?
You need to dig through the docker history output for other images to see what is linked back. There's an image out there that automates much of this that you can run with the following:
docker run -it --rm -v /var/run/docker.sock:/var/run/docker.sock \
nate/dockviz images -t -l
More details on the above command can be found on this github repo.
Here you go:
docker ps -a | awk '{ print $1,$2 }' | grep $(docker images | grep *image-id* | awk '{ print $1}')
On Ubuntu 14.04 (Trusty Tahr) I'm looking for a way to stop a running container and the only information I have is the image name that was used in the Docker run command.
Is there a command to find all the matching running containers that match that image name and stop them?
If you know the image:tag exact container version
Following issue 8959, a good start would be:
docker ps -a -q --filter="name=<containerName>"
Since name refers to the container and not the image name, you would need to use the more recent Docker 1.9 filter ancestor, mentioned in koekiebox's answer.
docker ps -a -q --filter ancestor=<image-name>
As commented below by kiril, to remove those containers:
stop returns the containers as well.
So chaining stop and rm will do the job:
docker rm $(docker stop $(docker ps -a -q --filter ancestor=<image-name> --format="{{.ID}}"))
If you know only the image name (not image:tag)
As Alex Jansen points out in the comments:
The ancestor option does not support wildcard matching.
Alex proposes a solution, but the one I managed to run, when you have multiple containers running from the same image is (in your ~/.bashrc for instance):
dsi() { docker stop $(docker ps -a | awk -v i="^$1.*" '{if($2~i){print$1}}'); }
Then I just call in my bash session (after sourcing ~/.bashrc):
dsi alpine
And any container running from alpine.*:xxx would stop.
Meaning: any image whose name is starting with alpine.
You might need to tweak the awk -v i="^$1.*" if you want ^$1.* to be more precise.
From there, of course:
drmi() { docker rm $(dsi $1 | tr '\n' ' '); }
And a drmi alpine would stop and remove any alpine:xxx container.
The previous answers did not work for me, but this did:
docker stop $(docker ps -q --filter ancestor=<image-name> )
You could start the container setting a container name:
docker run -d --name <container-name> <image-name>
The same image could be used to spin up multiple containers, so this is a good way to start a container. Then you could use this container-name to stop, attach... the container:
docker exec -it <container-name> bash
docker stop <container-name>
docker rm <container-name>
This code will stop all containers with the image centos:6. I couldn't find an easier solution for that.
docker ps | grep centos:6 | awk '{print $1}' | xargs docker stop
Or even shorter:
docker stop $(docker ps -a | grep centos:6 | awk '{print $1}')
Two ways to stop running a container:
1. $docker stop container_ID
2. $docker kill container_ID
You can get running containers using the following command:
$docker ps
Following links for more information:
https://docs.docker.com/engine/reference/commandline/stop/
https://docs.docker.com/v1.8/reference/commandline/kill/
This will only stop all containers with image = "yourImgName" :
sudo docker stop $(sudo docker ps | grep "yourImgName" | cut -d " " -f 1)
This will stop and remove all containers with image = "yourImgName" :
sudo docker rm $(sudo docker stop $(sudo docker ps -a | grep "yourImgName" | cut -d " " -f 1))
I made a /usr/local/bin/docker.stop that takes in the image name (assumes you only have one running).
docker stop $(docker ps -q -f "name=$1")
Stop docker container by image name:
imagename='mydockerimage'
docker stop $(docker ps | awk '{split($2,image,":"); print $1, image[1]}' | awk -v image=$imagename '$2 == image {print $1}')
Stop docker container by image name and tag:
imagename='mydockerimage:latest'
docker stop $(docker ps | awk -v image=$imagename '$2 == image {print $1}')
If you created the image, you can add a label to it and filter running containers by label
docker ps -q --filter "label=image=$image"
Unreliable methods
docker ps -a -q --filter ancestor=<image-name>
does not always work
docker ps -a -q --filter="name=<containerName>"
filters by container name, not image name
docker ps | grep <image-name> | awk '{print $1}'
is problematic since the image name may appear in other columns for other images
list all containers with info and ID
docker ps
docker stop CONTAINER ID
For Docker version 18.09.0
I found that format flag won't be needed
docker rm $(docker stop $(docker ps -a -q -f ancestor=<image-name>))
I was trying to wrap my Docker commands in gulp tasks and realised that you can do the following:
docker stop container-name
docker rm container-name
This might not work for scenarios where you have multiple containers with the same name (if that's possible), but for my use case it was perfect.
In my case --filter ancestor=<image-name> was not working, so the following command cleaned up the Docker container for me:
docker rm $(docker stop $(docker ps -a -q --filter "name=container_name_here" --format="{{.ID}}"))
Adding on top of #VonC superb answer, here is a ZSH function that you can add into your .zshrc file:
dockstop() {
docker rm $(docker stop $(docker ps -a -q --filter ancestor="$1" --format="{{.ID}}"))
}
Then in your command line, simply do dockstop myImageName and it will stop and remove all containers that were started from an image called myImageName.
use: docker container stop $(docker container ls -q --filter ancestor=mongo)
(base) :~ user$ docker ps
CONTAINER ID IMAGE COMMAND CREATED STATUS PORTS NAMES
d394144acf3a mongo "docker-entrypoint.s…" 15 seconds ago Up 14 seconds 0.0.0.0:27017->27017/tcp magical_nobel
(base) :~ user$ docker container stop $(docker container ls -q --filter ancestor=mongo)
d394144acf3a
(base) :~ user$ docker ps
CONTAINER ID IMAGE COMMAND CREATED STATUS PORTS NAMES
(base) :~ user$
This is my script to rebuild docker container, stop and start it again
docker pull [registry]/[image]:latest
docker build --no-cache -t [localregistry]/[localimagename]:latest -f compose.yaml context/
docker ps --no-trunc | grep [localimagename] | awk '{print $1}' | xargs docker stop
docker run -d -p 8111:80 [localregistry]/[localimagename]:latest
note --no-trunc argument which shows the image name or other info in full lenght in the output
Here's a concise command which doesn't require you to specify the image tag (as most of these answers do):
docker stop $(docker ps -a | awk -v i="^${image_name}.*" '{if($2~i){print$1}}')
docker stop $(docker ps -a | grep "zalenium")
docker rm $(docker ps -a | grep "zalenium")
This should be enough.
If you want to prefer a simple AWK approach, here Is my take:
docker rm -f $(docker ps | awk '{ if($2 == "<your image name>") { print $NF}}')
$(docker ps | awk '{ if($2 == "<your image name>") { print $NF}}') - prints the docker container names based on input image
docker ps - list all containers
awk '{ if($2 == "<your-image-name>") { print $NF}}' - The second parsed column of docker ps gives the image name. Comparing it with your image name will execute print $NF which prints the container name.
docker rm -f removes the containers
For example, removing all running containers of ubuntu image, can be done simply as:
docker rm -f $(docker ps | awk '{ if($2 == "ubuntu:latest") { print $NF}}')
PS: Remember to include the image tag in AWK, since it's a equal comparator.
if you know a part of the container name you can use AWK with docker as following :
CONTAINER_IDS=$(docker ps -a | awk '($2 ~ /container.*/) {print $1}')
if [ -z "$CONTAINER_IDS" -o "$CONTAINER_IDS" == " " ]; then
echo "No containers available for deletion"
else
docker rm -f $CONTAINER_IDS
fi
image: docker
services:
- docker:dind
stages:
- deploy
step-deploy-prod:
stage: deploy
tags:
- docker
script:
- container_id=$(docker ps -q -a -f status=running --filter name=todoapp)
- if [ -n "$container_id" ]; then
docker stop $container_id;
docker rm -f $container_id;
fi
- container_id=$(docker ps -q -a -f status=exited --filter name=todoapp)
- if [ -n "$container_id" ]; then
docker rm -f $container_id;
fi
- docker build -t app/creative .
- docker run -d -p 8081:80 --name todoapp app/creative
First, check for a running container with the command docker ps -q -a -f status=running --filter name=todoapp , if it finds one it stops and deletes the running container then check for any containers that are stopped and have the name todoapp using the command docker ps -q -a -f status=exited --filter name=todoapp, then it will remove the container if it's found.
Then it will build a new image and start a new container with the new build image.
As I have found out, if you stop the container, it can't be found with docker rm just incase anyone stumbles across this if you are wanting to replace a newly deployed image via gitlab-ci
There is an option in docker ps command -f status=exited which shows all the containers which are in stopped state.
container_id=$(docker ps -q -a -f status=exited --filter name=todoapp)
This command would only return container ids that are stopped and has name todoapp
Also, a better way to remove the stopped container is by using the -f or --force option with the docker rm command. This option will remove the container even if it is in a stopped state.
You can use the ps command to take a look at the running containers:
docker ps -a
From there you should see the name of your container along with the container ID that you're looking for. Here's more information about docker ps.
Supposed I have an image that I want to tag as 0.10.24 (in my case it's an image containing Node.js 0.10.24). I built that image using a Dockerfile and executing docker build and by providing a tag using the -t parameter.
I expect that one day I will have additional versions of that image, so I will rerun the process, just with another tag name.
So far, so good. This works great and fine and all is well.
But, and this is where problems start, I also want to always have the newest image tagged ad latest additionally. So I guess I need to give two names to the very same image.
How do I do this? Do I really need to re-run docker build on the exact same version again, but this time use another tag, is is there a better option?
You can have multiple tags when building the image:
$ docker build -t whenry/fedora-jboss:latest -t whenry/fedora-jboss:v2.1 .
Reference: https://docs.docker.com/engine/reference/commandline/build/#tag-image-t
Once you have your image, you can use
$ docker tag <image> <newName>/<repoName>:<tagName>
Build and tag the image with creack/node:latest
$ ID=$(docker build -q -t creack/node .)
Add a new tag
$ docker tag $ID creack/node:0.10.24
You can use this and skip the -t part from build
$ docker tag $ID creack/node:latest
Here is my bash script
docker build -t ${IMAGE}:${VERSION} .
docker tag ${IMAGE}:${VERSION} ${IMAGE}:latest
You can then remove untagged images if you rebuilt the same version with
docker rmi $(docker images | grep "^<none>" | awk "{print $3}")
link
or
docker rmi $(docker images | grep "^<none>" | tr -s " " | cut -d' ' -f3 | tr '\n' ' ')
or
Clean up commands:
Docker 1.13 introduces clean-up commands. To remove all unused containers, images, networks and volumes:
docker system prune
or individually:
docker container prune
docker image prune
docker network prune
docker volume prune
ID=$(docker build -t creack/node .) doesn't work for me since ID will contain the output from the build.
SO I'm using this small BASH script:
#!/bin/bash
set -o pipefail
IMAGE=...your image name...
VERSION=...the version...
docker build -t ${IMAGE}:${VERSION} . | tee build.log || exit 1
ID=$(tail -1 build.log | awk '{print $3;}')
docker tag $ID ${IMAGE}:latest
docker images | grep ${IMAGE}
docker run --rm ${IMAGE}:latest /opt/java7/bin/java -version
Just grep the ID from docker images:
docker build -t creack/node:latest .
ID="$(docker images | grep 'creak/node' | head -n 1 | awk '{print $3}')"
docker tag "$ID" creack/node:0.10.24
docker tag "$ID" creack/node:latest
Needs no temporary file and gives full build output. You still can redirect it to /dev/null or a log file.
Variation of Aaron's answer.
Using sed without temporary files
#!/bin/bash
VERSION=1.0.0
IMAGE=company/image
ID=$(docker build -t ${IMAGE} . | tail -1 | sed 's/.*Successfully built \(.*\)$/\1/')
docker tag ${ID} ${IMAGE}:${VERSION}
docker tag -f ${ID} ${IMAGE}:latest
To give tag to a docker file during build command:
docker build -t image_name:tag_name .
otherwise it will give latest tag to your docker image automatically.
Hye it's very easy you just need to follow the below steps -
So, to create and tagging an image in Docker we can use the following commands
First take out your Docker id by running the below command
docker ps
Copy -> Names
docker build -t dockerId/Name of your image you want:latest .
For me I use
docker build -t condescending_greider/newdoc:latest .
Thanks for your time