I cant seem to figure out how to write this query using the Neo4jClient
MATCH (n)
WHERE (n.Id="1ef17d65-492e-4c0d-aa79-13065edd37f2" AND n.CaseType="NaturalPerson") OR (n.Id="a5c143d4-0306-4057-a96f-e39c5c50eb22" AND n.CaseType="NaturalPerson")
RETURN n
If i write the query like this
this.client.Cypher.Match("(n)")
.Where("f.Id=\"1ef17d65-492e-4c0d-aa79-13065edd37f2\"")
.AndWhere("n.CaseType=\"NaturalPerson\"")
.OrWhere("f.Id=\"1ef17d65-492e-4c0d-aa79-13065edd37f2\"")
.AndWhere("n.CaseType=\"NaturalPerson\"")
.Return((n, r) => n.As<T>());
The following query is generated, but it does not have the parentheses '(' ')' which logicly group the two and clauses
MATCH (n)
WHERE f.Id="1ef17d65-492e-4c0d-aa79-13065edd37f2"
AND n.CaseType="NaturalPerson"
OR f.Id="1ef17d65-492e-4c0d-aa79-13065edd37f2"
AND n.CaseType="NaturalPerson"
RETURN n AS Node, r AS Metadata
You either do:
.Where("n.Id='1ef17d65-492e-4c0d-aa79-13065edd37f2' AND n.CaseType='NaturalPerson')
.OrWhere("n.Id='a5c143d4-0306-4057-a96f-e39c5c50eb22' AND n.CaseType='NaturalPerson'")
or, you could put it all in one .Where
But, if it was me, I would do:
.Where("n.CaseType = 'NaturalPerson')
.AndWhere("n.Id IN ['1ef17d65-492e-4c0d-aa79-13065edd37f2','a5c143d4-0306-4057-a96f-e39c5c50eb22']
And I would definitely be using parameters like so:
var ids = new [] {'a5c143d4-0306-4057-a96f-e39c5c50eb22', '1ef17d65-492e-4c0d-aa79-13065edd37f2'};
var caseType = "NaturalPerson";
this.client.Cypher.Match("(n)")
.Where("n.CaseType = $caseTypeParam")
.AndWhere("n.Id IN $idsParam")
.WithParam("caseTypeParam", caseType)
.WithParam("idsParam", ids")
/*.. etc..*/
Related
I have the following params in my Neo4J:
{
"lists": [
{
"from": "someone",
"to": "somebody"
}
]
}
And the following query:
MATCH (c:Concept{name:'infranodus'}) WITH c, $lists AS list
UNWIND CASE WHEN list = [{}] THEN [null] ELSE list END AS l
WITH l
MATCH (cp1:Concept{name:l.from})
WITH cp1
MATCH (cp2:Concept{name:'somebody'})
RETURN cp1,cp2;
The query above will work.
However, if I replace l.from with a non-existent parameter, e.g. l.about, then — as the match doesn't happen — the second cp2 match doesn't fire.
How can I change this behavior and continue executing this query even if cp1 is not found? Maybe there's a way to pass on a dummy variable as a result?
MATCH (c:Concept{name:'infranodus'}) WITH c, $lists AS list
UNWIND CASE WHEN list = [{}] THEN [null] ELSE list END AS l
WITH l
MATCH (cp1:Concept{name:l.about})
WITH cp1
MATCH (cp2:Concept{name:'somebody'})
RETURN cp1,cp2;
Use OPTIONAL MATCH. If there is no match is found, then it will use NULL for the missing part of the pattern. It is similar to outer join in SQL.
NEW:
OPTIONAL MATCH (cp1:Concept{name:l.about})
OLD:
MATCH (cp1:Concept{name:l.about})
You can maybe replace it with an IN predicate ?
For eg :
WITH {from: 'Matt Olg', about: 'Matthew Olg'}
AS l
MATCH (n:Person)
WHERE n.name IN [l.from, l.to]
RETURN n.name
╒══════════╕
│"n.name" │
╞══════════╡
│"Matt Olg"│
└──────────┘
I am new with Neo4j and I am stucked trying to get a query with two conditions, where I want to get all the "Autors" related to "Pixar" and "Fox". So far I have tried the following two ways:
MATCH (a:Autor)- [:AUTOR_DE]-> (t:Título) -[:PRODUCIDO_POR] ->( p:Productora {Nombre: "Pixar"}),
and
MATCH (a:Autor)- [:AUTOR_DE]-> (t:Título) -[:PRODUCIDO_POR] ->( p:Productora {Nombre: "Fox"}),
return a,p
and
MATCH (a:Autor)- [:AUTOR_DE]-> (t:Título) -[:PRODUCIDO_POR] ->( p:Productora)
WHERE ( (p:Productora) = "Fox" OR (p:Productora) = "Pixar")
return a,p
Thanks in advance
Assuming that a Productora node stores its name in a name property, and that every Productora node has a unique name, this should work:
MATCH (a:Autor)-[:AUTOR_DE]->(:Título)-[:PRODUCIDO_POR]->(p:Productora)
WHERE p.name = "Fox" OR p.name = "Pixar"
WITH a, COLLECT(DISTINCT p) AS ps
WHERE SIZE(ps) = 2
return a, ps
And this should also work:
MATCH (fox:Productora), (pixar:Productora), (a:Autor)
WHERE fox.name = "Fox" AND pixar.name = "Pixar" AND
(a)-[:AUTOR_DE]->(:Título)-[:PRODUCIDO_POR]->(fox) AND
(a)-[:AUTOR_DE]->(:Título)-[:PRODUCIDO_POR]->(pixar)
return a, fox, pixar
I'm trying to get Total(Sum) of a property of "df" object.I have attached screen shot of sample database I'm using
I tried to get the graph using following query
MATCH P= (n:Org)-[:O_CH*0..]->()-[:LEAF*0..]->()-[:CH*0..]->()-[:FOR*0..]->() RETURN P
To create objects
create(n:Org{name:'Root',id:1})
create(n:Org{name:'L1.1',id:2,parent:1})
create(n:Org{name:'L1.2',id:3,parent:1})
create(n:Org{name:'L1.3',id:4,parent:1})
create(n:Org{name:'L2.1',id:5,parent:3})
create(n:Org{name:'L2.2',id:6,parent:4})
create(n:Op{name:'CH1',id:7,orgId:5})
create(n:Op{name:'CH2',id:8,orgId:5 ,parent:'CH1'})
create(n:Proj{name:'P1',id:9,opp:'CH2'})
create(n:Proj{name:'P2',id:10,opp:'CH1'})
create(n:R{name:'R1',id:200,orgId:2 })
create (n:df{id:100,map:8,forecast:toFloat(10)})
create (n:df{id:101,map:7,forecast:toFloat(10)})
create (n:df{id:102,map:9,forecast:toFloat(10)})
create (n:df{id:103,map:10,forecast:toFloat(10)})
create (n:df{id:104,map:200,forecast:toFloat(10)})
To Crate relationships
MATCH (c:Org),(p:Org) WHERE c.parent = p.id create (p)-[:O_CH]->(c)
MATCH (c:Op),(p:Op) WHERE c.parent = p.name create (p)-[:CH]->(c)
MATCH (c:Op),(p:Org) WHERE c.orgId = p.id create (p)-[:LEAF]->(c)
MATCH (c:Proj),(p:Op) WHERE c.opp = p.name create (p)-[:CH]->(c)
MATCH (c:R),(p:Org) WHERE c.orgId = p.id create (p)-[:LEAF]->(c)
MATCH (c:df),(p:) WHERE c.map = p.id create (p)-[:FOR]->(c)
I'm expecting 60 as total where I get 260 as total. Please let me know where I'm wrong . Need your help to figure out.
I'm trying to get Total(Sum) of a property of "df" object.
I believe you needs a simple query that match all nodes with label :df and return the sum of node.forecast. Try it:
// Match all nodes with :df label
MATCH(n:df)
// Return the sum of the property 'forecast' of each matched node
RETURN sum(n.forecast)
From comments:
Thank you Bruno.But the thing i need to get the aggregated value as a
example if i select L2.1 , i need to get the sum of df objects which
are under that node
This should work:
MATCH({name:'L2.1'})-[*]->(n)
RETURN SUM(n.forecast)
This is in continuation of Neo4j: Listing node labels
I am constructing a dynamic MATCH statement to return the hierarchy structure & use the output as a Neo4j JDBC input to query the data from a java method:
MATCH p=(:Service)<-[*]-(:Anomaly)
WITH head(nodes(p)) AS Service, p, count(p) AS cnt
RETURN DISTINCT Service.company_id, Service.company_site_id,
"MATCH srvhier=(" +
reduce(labels = "", n IN nodes(p) | labels + labels(n)[0] +
"<-[:BELONGS_TO]-") + ") WHERE Service.company_id = {1} AND
Service.company_site_id = {2} AND Anomaly.name={3} RETURN " +
reduce(labels = "", n IN nodes(p) | labels + labels(n)[0] + ".name,");
The output is as follows:
MATCH srvhier=(Service<-[:BELONGS_TO]-Category<-[:BELONGS_TO]-SubService<-
[:BELONGS_TO]-Assets<-[:BELONGS_TO]-Anomaly<-[:BELONGS_TO]-) WHERE
Service.company_id = {1} and Service.company_site_id = {21} and
Anomaly.name={3} RETURN Service.name, Category.name, SubService.name,
Assets.name, Anomaly.name,
The problem I am seeing:
The "BELONGS_TO" gets appended to my last node
Line 2: Assets<-[:BELONGS_TO]-Anomaly**<-[:BELONGS_TO]-**
Are there string functions (I have looked at Substring..) that can be used to remove it? Or can I use a CASE statement with condition n=cnt to append "BELONGS_TO"?
The same problem persists with my last line:
Line 5: Assets.name,Anomaly.name**,** - the additional "," that I need to eliminate.
Thanks.
I think you need to introduce a case statement into the reduce clause something like this snippet below. If the node isn't the last element of the collection then append the "<-[:BELONGS_TO]-" relationship. If it is the last element then don't append it.
...
reduce(labels = "", n IN nodes(p) |
CASE
WHEN n <> nodes(p)[length(nodes(p))-1] THEN
labels + labels(n)[0] + "<-[:BELONGS_TO]-"
ELSE
labels + labels(n)[0]
END
...
Cypher has a substring function that works basically like you'd expect. An example: here's how you'd return everything but the last three characters of a string:
return substring("hello", 0, length("hello")-3);
(That returns "he")
So you could use substring to trim the last separator off of your query that you don't want.
But I don't understand why you're building your query in such a complex way; you're using cypher to write cypher (which is OK) but (and I don't understand your data model 100%) it seems to me like there's probably an easier way to write this query.
My Cypher looks like this:
START source=node(16822), target=node(12449)
MATCH p = allShortestPaths(source-[*]-target)
return p
And I want to write equivalent C# code for this. This is what I've come up till now
var query = client.Cypher
.Start(new { source = sourceNode.Reference, target = targetNode.Reference })
.Match("p = allShortestPaths(source-[*]-target)")
.Return<Node<Data>>("x");
Where Data is the class which has a string property(string ID).
What should i put in place of x to get my result as a list of concatenated IDs which comprises the path.
Cypher 2.0
START source=node(16822), target=node(12449)
MATCH p = allShortestPaths(source-[*]-target)
return nodes(p)
Good old way of executing query was the last resort which i used
CypherQuery query1 = new CypherQuery(#"START m=node(" + sourceNode.Reference.Id.ToString() + "), n=node(" + targetNode.Reference.Id.ToString() + #")
match p = allshortestpaths(m-[*]-n)
return distinct Extract(x in NODES(p): x.NodeId) as paths", paramCollection, CypherResultMode.Set);
var paths = ((IRawGraphClient)client).ExecuteGetCypherResults<List<string>>(query1);