I want to assign a value to an existing variable, but the name of the variable is dynamic. How do I do that
def a1 = 0;
def b = 1;
eval("a${b} =1;");
print a1
No need for javascript here:
def name = 'someName';
def value = 'someValue';
new GroovyShell(this.binding).evaluate("${name} = '${value}'")
assert someName == value;
Though this doesn't answer your question exactly, an easy way around this is to drop your dynamic variables as map keys instead... avoid needing to eval them
def b = 1
def map = [:]
map."a${b}" = 1
assert map."a${b}" == 1
println(map) // result is [a1:1]
Related
I have a properties file which I call inside my Jenkins Pipeline Script to get multiple variables.
BuildCounter = n
BuildName1 = Name 1
BuildName2 = Name 2
...
Buildnamen = Name n
I call my properties file with: def props = readProperties file: Path
Now I want to create a loop to print all my BuildNames
for (i = 0; i < BuildJobCounterInt; i++){
tmp = 'BuildName' + i+1
println props.tmp
}
But of course this is not working. ne last println call is searching for a variable called tmp in my properties file. Is there a way to perform this or am I completely wrong?
EDIT:
This is my .properties file:
BuildJobCounter = 1
BuildName1 = 'Win32'
BuildPath1 = '_Build/MBE3_Win32'
BuildName2 = 'empty'
BuildPath2 = 'empty'
TestJobCounter = '0'
TestName1 = 'empty'
TestPath1 = 'empty'
TestName2 = 'empty'
TestPath2 = 'empty'
In my Jenkins pipeline I want to have the possibility to check the ammount of Build/TestJobs and automatically calle the Jobs (each BuildName and BuildPath is a Freestyle Job) To call all these Job I thought of calling the variables inside a for loop. So for every istep I have the Name/Path pair.
Try the below:
Change from:
println props.tmp
To:
println props[tmp]
or
println props."$tmp"
EDIT : based on OP comment
change from:
tmp = 'BuildName' + i+1
To:
def tmp = "BuildName${(i+1).toString()}"
Since Bazel does not provide a way to map labels to strings, I am wondering how to work around this via Skylark.
Following my partial horrible "workaround".
First the statics:
_INDEX_COUNT = 50
def _build_label_mapping():
lmap = {}
for i in range(_INDEX_COUNT):
lmap ["map_name%s" % i] = attr.string()
lmap ["map_label%s" % i] = attr.label(allow_files = True)
return lmap
_LABEL_MAPPING = _build_label_mapping()
And in the implementation:
item_pairs = {}
for i in range(_INDEX_COUNT):
id = getattr(ctx.attr, "map_name%s" % i)
if not id:
continue
mapl = getattr(ctx.attr, "map_label%s" % i)
if len(mapl.files):
item_pairs[id] = list(mapl.files)[0].path
else:
item_pairs[id] = ""
if item_pairs:
arguments += [
"--map", str(item_pairs), # Pass json data
]
And then the rule:
_foo = rule(
implementation = _impl,
attrs = dict({
"srcs": attr.label_list(allow_files = True, mandatory = True),
}.items() + _LABEL_MAPPING.items()),
Which needs to be wrapped like:
def foo(map={}, **kwargs):
map_args = {}
# TODO: Check whether order of items is defined
for i, item in enumerate(textures.items()):
key, value = item
map_args["map_name%s" % i] = key
map_args["map_label%s" % i] = value
return _foo(
**dict(map_args.items() + kwargs.items())
)
Is there a better way of doing that in Skylark?
To rephrase your question, you want to create a rule attribute mapping from string to label?
This is currently not supported (see list of attributes), but you can file a feature request for this.
Do you think using "label_keyed_string_dict" is a reasonable workaround? (it won't work if you have duplicated keys)
I have a string which consists of numbers:
str = "1234567892"
And I want to iterate individual characters in it and get indices of specific numbers (for example, "2"). As I've learned, I can use gmatch and create a special iterator to store the indices (because, as I know, I just can't get indices with gmatch):
local indices = {}
local counter = 0
for c in str:gmatch"." do
counter = counter + 1
if c == "2" then
table.insert(indices, counter)
end
end
But, I guess, this is not the most efficient decision. I also can convert string to table and iterate table, but it seems to be even more inefficient. So what is the best way to solve the task?
Simply loop over the string! You're overcomplicating it :)
local indices = {[0]={},{},{},{},{},{},{},{},{},{}} --Remove [0] = {}, if there's no chance of a 0 appearing in your string :)
local str = "26842170434179427"
local container
for i = 1,#str do
container = indices[str:sub(i, i)]
container[#container+1] = i
end
container = nil
To find all indices and also do not use regexp but just plain text search
local i = 0
while true do
i = string.find(str, '2', i+1, true)
if not i then break end
indices[#indices + 1] = i
end
What am I looking for is a code like that.
local sometable = {
[1] = [2] = "abc",
}
So this is surely a wrong way to set 2 keys. ( returned an error )
You received an error because Lua doesn't have a syntax for setting multiple keys to a single value in a table constructor.
You have a few options, when using tables as arrays (sequences) you can omit the key:
local t = {'abc', 'abc'}
If you don't want to repeat the value, use a variable:
local init = 'abc'
local t = {init, init}
Or, write a function to do the initialization:
local function initialize(t, v, first, last)
first = first or 1
last = last or first
assert(first <= last, 'invalid first/last')
for i = first, last do
t[i] = v
end
return t
end
local t = initialize({}, 'abc', 1, 2)
How can I get variables that not declared yet?
Here are simple example:
a = b
b = 123
What I want from these 2 lines is a << 123. But obv it doesn't work.
I know the easy way to get the answer a = 123 is cut 1st line and paste it to lower than 2nd line.
But I'm in some problem. I need some function like 'WillDeclaredVar()' that I can use in like this:
a = WillDeclaredVar(b)
sheepCount = 123
b = sheepCount
print(a)
so I can get the answer '123'.
Or there are any built-in functions that will allows me to do similar thing?
===
I think the link given by timrau is not telling my case. the key point is how to get Variables 'that not declared yet'.
===
Adding actual Code:
triggerCount = 0 -- Counting number of 'Trigger' function
local Trigger = function (t)
triggerCount = triggerCount + 1
return Trigger (t)
end
-- following Triggers are same as while statement.
-- following Triggers doing: Add 1 MarineCount until get 64000 MarineCount
Trigger { -- Here the Trigger function. Now triggerCount = 1.
players = {P1}
actions = {
SetDeaths(P1, Add, 1, "Terran Marine")
},
flag = {preserved},
}
Portal(LoopStart);
-- function Portal(VariableName) returns VariableName = triggerCount. So LoopStart = 1.
Trigger { -- Now triggerCount = 2.
players = {P1}
actions = {
LinkList(LoopEnd, LoopStart);
-- function LinkList(From, To) changes 'From' Trigger's next pointer to the 'To' Trigger.
-- But now the problem happens. Because 'LoopEnd' is not declared yet.
},
flag = {preserved},
}
Trigger { -- Now triggerCount = 3.
players = {P1}
conditions = {
Deaths(P1, Exactly, 64000, "Terran Marine");
}
actions = {
_LinkList(LoopEnd);
-- Reset LoopEnd's next pointer(= LoopEscape) if MarineCount hits 64000
},
flag = {preserved},
}
Portal(LoopEnd); -- LoopEnd = 3.
Changing Order of Triggers will break the Trigger logic(while statement).
All i want is get easy to coding. To put in bluntly, I don't need to solve this problem(get undeclared var). I can imagine a few ways to avoid it. But if i using these ways then the coding work will be very complicated and the difficulty of coding will increases greatly. The difficulty made me stop coding in recent months.
How can I get variables that not declared yet?
Short of time travel, you can't.
Your example code doesn't explain the motivation for the question, because this:
a = WillDeclaredVar(b)
sheepCount = 123
b = sheepCount
print(a)
Can trivially be rearranged into this:
sheepCount = 123
b = sheepCount
a = WillDeclaredVar(b)
print(a)
It would be easier to answer your question if you showed the actual problem you're trying to solve (to avoid an XY problem).
However, as stated there are few things we can note.
First, you need to distinguish between declaring a variable and giving it a value. In Lua you can say:
local b
To declare b as a local variable, which presumably will make a slot for it in the stack frame and let you bind closures to it, before you give it a value. However, the line:
a = WillDeclaredVar(b)
Will pass WillDeclaredVar the value that b currently has, and there's no way for a to change retroactively as a result of b being assigned a new value. That's simply not going to happen, ever. Neither a nor WillDeclaredVar are even aware that b exists, they are receive the value it contains at the point of call.
You could however bind the variable b to a closure which will fetch b's current value when needed.
-- declare b before giving it a value, aka "forward reference"
local b
a = function() return b end
sheepCount = 123
b = sheepCount
print(a()) -- call a to get b's current value
Another way to do that would be to make b a global variable, which is really just a key into your environment table, so you could say:
a = WillDeclaredVar('b')
And have a be some object that can fetch the current value of __ENV['b'] when required.
However, neither of these will support this syntax:
print(a)
a needs to be a function, something that looks up the value of b when needed rather than simply holding a previously computed value. You could do it in this particular instance (i.e. a needs to be convertable to a string), by creating a proxy object that implements __tostring.
function WillDeclaredVar(variableName)
local proxy = { environment = _ENV or _G, variableName = variableName }
return setmetatable(proxy, {
__tostring = function(proxy)
return proxy.environment[proxy.variableName]
end
})
end
-- a will compute a value based on the current value of b when needed
a = WillDeclaredVar('b')
sheepCount = 123
b = sheepCount
print(a)
Output:
123
To make var1 be a reference for var2 write var1 = ReferenceF or var2 (please note a space inside "ReferenceFor"!)
do
local values, references, reference_flag = {}, {}
setmetatable(_G, {
__index = function (_, name)
if name == 'ReferenceF' then
reference_flag = true
elseif reference_flag then
reference_flag = false
return {[references] = name}
elseif references[name] then
return _G[references[name]]
else
return values[name]
end
end,
__newindex = function (_, name, val)
if type(val) == 'table' and val[references] then
references[name] = val[references]
else
values[name] = val
end
end
})
end
a = ReferenceF or b -- a is Reference For b
b = ReferenceF or c -- b is Reference For c
sheepCount = 123
c = sheepCount
print(a, b, c) --> 123 123 123