I get a input from uitextfield box. i can replace quotes("'") to empty(""). using
textfield.text.replacingOccurrences(of: "'", with: "")
is not working
textfield.text = "name's"
let trim = textfield.text?.replacingOccurrences(of: "'", with: "")
expected OUTPUT:
names
actual OUTPUT:
name's
text.replacingOccurrences can be used with regular expressions so using the group ['`´] could work here (I am not aware of any meta character for this). As #Rob mentioned in the comments it might be worth expanding the pattern further like [‘’'`´] or [‘’‛'′´`❛❜] or use "\p{Quotation_Mark}"
let trim = text.replacingOccurrences(of: "['`´]", with: "", options: .regularExpression)
It doesn't replace è or é which is good I suppose
let text = "name's are Josè and André, strings are `abc` and ´def´"
let trim = text.replacingOccurrences(of: "['`´]", with: "", options: .regularExpression)
print(trim)
yields
names are Josè and André, strings are abc and def
Related
Need to remove part of the string based on brackets.
For ex:
let str = "My Account (_1234)"
I wanted to remove inside brackets (_1234) and the result should be string My Account
Expected Output:
My Account
How can we achieve this with regex format or else using swift default class,need support on this.
Tried with separatedBy but it splits string into array but that is not the expected output.
str.components(separatedBy: "(")
Use replacingOccurrences(…)
let result = str.replacingOccurrences(of: #"\(.*\)"#,
with: "",
options: .regularExpression)
.trimmingCharacters(in: .whitespaces))
Regex ist not necessary. Just get the range of ( and extract the substring up to the lower bound of the range
let str = "My Account (_1234)"
if let range = str.range(of: " (") {
let account = String(str[..<range.lowerBound])
print(account)
}
I want to store float to CoreData and I want to convert every of the following inputs to 90.5:
90.5
90,5
90.5
90, 5
That means: Remove whitespace and convert , to .
Is this code best practice?
let str = " 90, 5 "
let converted = str.trimmingCharacters(in: .whitespacesAndNewlines)
let converted = strWithoutWithespace.replacingOccurrences(of: ",", with: ".")
No, it's not because it doesn't remove the space within the string.
The regex pattern "\\s+" removes all occurrences of one or more whitespace characters.
let str = " 90, 5 "
let strWithoutWhitespace = str.replacingOccurrences(of: "\\s+", with: "", options: .regularExpression)
let converted = strWithoutWhitespace.replacingOccurrences(of: ",", with: ".")
let's say I have a string
var a = "#bb #cccc #ddddd\u{ef}"
and i am setting it to textview like this
let text = a.trimmingCharacters(in: .whitespacesAndNewlines)
let textRemoved = text?.replacingOccurrences(of: "\u{ef}", with: "", options: NSString.CompareOptions.literal, range:nil)
textView.text = textRemove
I am trying to remove the \u{ef} character here. But in textRemoved it is not happening. Please help me how to do it.
I am using Xcode 10. Looks like below Xcode version than 10 is working
fine. is it a bug of Xcode 10?
This is a late answer but I struggled to replace "\u{ef}" in string as well. During debugging when hovered over string it showed presence of \u{ef} but when print in description it only showed space.
let str = "\u{ef} Some Title"
print(str) //" Some Title"
I tried replacingOccurrences(of: "\u{ef}", with: "", options: NSString.CompareOptions.literal, range: nil).trimmingCharacters(in: .whitespaces) but it failed as well.
So I used below snippet and it worked like wonder.
let modifiedStr = str.replacingOccurrences(of: "\u{fffc}", with: "", options: NSString.CompareOptions.literal, range: nil).trimmingCharacters(in: .whitespaces)
print(modifiedStr) //"Some Title"
Hope this helps someone!!
i also faced same issue for "\u{e2}". i have searched a lot but unable to find any answer. then i have tried below code , which works for me.
var newString = ""
for char in strMainString.unicodeScalars{
if char.isASCII{
newString += String(char)
}
}
Hope that will also work for you too.
In Xcode 10 Playground, string replaces for \u{00EF} is working.
var a = "#bb #cccc #ddddd\u{ef}"
a = a.replacingOccurrences(of: "\u{00EF}", with: "")
I hope that will work for you.
I tried the following and it worked like a charm:
replacingOccurrences(of: "�", with: " ", options: NSString.CompareOptions.literal, range: nil)
e.g. 1
let text = "\u{ef}\u{ef}\u{ef}\u{ef}😇哦哦哦"
let text1 = text.replacingOccurrences(of: "\u{fffc}", with: "", options: String.CompareOptions.literal, range: nil)
let text2 = text.replacingOccurrences(of: "\u{ef}", with: "", options: String.CompareOptions.literal, range: nil).trimmingCharacters(in: .whitespaces)
runnable
<img src="https://i.stack.imgur.com/styVo.png"/>
e.g. 2
let strBefore = textDocumentProxy.documentContextBeforeInput
let strAfter = textDocumentProxy.documentContextAfterInput
var textInput = strBefore + strAfter
let textInput2 = textInput.replacingOccurrences(of: "\u{ef}", with: "", options: String.CompareOptions.literal, range: nil)
let textInput1 = textInput.replacingOccurrences(of: "\u{fffc}", with: "", options: String.CompareOptions.literal, range: nil).trimmingCharacters(in: .whitespaces)
runnable
<img src="https://i.stack.imgur.com/xGHtW.png"/>
Similar to question but with \u{e2} symbol (fix is the same):
\u{e2} is not a character rather subset of UTF8 plane which starts with 0xE2 byte.
So look here, E2 are general punctuation symbols.
There many symbols actually which started with \u{e2} but not limited to it and full char can be represented f.e. with e2 80 a8 bytes (line separator).
That explains why shown in Xcode \u{e2} can't be replaced with replacingOccurrences... function. In order to filter out correct symbol you have to know what exact symbol it is, f.e. by using the snippet below:
"\u{2028}&😲".forEach { (char) in
print(Data(char.utf8).map { String(format: "%02x", $0) }.joined(separator: " "))
}
it prints to console:
e2 80 a8
26
f0 9f 98 b2
which are byte representation for each symbol.
Next step is to filter your string, go here and search in 3d column your bytes and unicode code point value is what you need (first column) and write it in swift code like "\u{2028}\u{206A}..." (depending on your sorting).
The final function may look like:
func removingE2Symbols() -> String {
let specialChars = "\u{202A}\u{202C}"
return filter { !specialChars.contains($0) }
}
Try this
extension String {
var asciiString: String {
return String(self.unicodeScalars.filter{ $0.isASCII })
}
}
It,s working Please check again:
let a = "#bb #cccc #ddddd\u{ef}"
let text = a.trimmingCharacters(in: .whitespacesAndNewlines)
let textRemoved = text.replacingOccurrences(of: "\u{ef}", with: "", options: NSString.CompareOptions.literal, range:nil)
print(textRemoved)
I simply need to replace:
<p>, <div>
with
\n<p>, \n<div>
in string with one single pattern replacing. Is it possible?
let string = "<p>hello</p> my <div>Doggy</div>"
let newString = string.replacingOccurrences(of: "<p>", with: "\n<p>").replacingOccurrences(of: "<div>", with: "\n<div>")
is there a better solution with regex?
You can do a regular expression search, with a template in the replacement
string:
let string = "<p>hello</p> my <div>Doggy</div>"
let newString = string.replacingOccurrences(of: "<p>|<div>", with: "\n$0", options: .regularExpression)
For each match, the $0 template is replaced by what actually matched the pattern.
I receive an NSAttributedString that contains a NSTextAttachment. I want to remove that attachment, and it looks like it is represented as "\u{ef}" in the string. Printing the unicode scalars of such string, it also seems that unicode scalar for the "\u{ef}" is U\0000fffc.
I tried to do this:
noAttachmentsText = text.replacingOccurrences(of: "\u{ef}", with: "")
with no success, so I'm trying by comparing unicode scalars:
var scalars = Array(text.unicodeScalars)
for scalar in scalars {
// compare `scalar` to `U\0000fffc`
}
but I'm not able either to succeed in the comparison.
How could I do this?
But this code works for me from How do I remove "\U0000fffc" from a string in Swift?
let original = "First part \u{ef} Last part"
let originalRange = Range<String.Index>(start: original.startIndex, end: original.endIndex)
let target = original.stringByReplacingOccurrencesOfString("\u{ef}", withString: "", options: NSStringCompareOptions.LiteralSearch, range: originalRange)
print(target)
Output :
"First part ï Last part"
to
First part Last part
U can use similar code for swift 3 just replace unicode using replacingOccurrences option for exapmle :
func stringTocleanup(str: String) -> String {
var result = str
result = result.replacingOccurrences(of: "\"", with: "\"")
.replacingOccurrences(of: "\u{10}", with: "")
return result
}