iOS binary search code crash above 256 items - ios

I've used iOS default code to search string in custom dictionary object which exist in array, Means array of dictionary items.
NSRange searchRange = NSMakeRange(0, artistThumbnail.count);
index = [artistThumbnail indexOfObject:artist
inSortedRange:searchRange
options:NSBinarySearchingLastEqual
usingComparator:^NSComparisonResult(id _Nonnull obj1, id _Nonnull obj2) {
NSString *artistName = (NSString *)obj2;
NSDictionary *artistThumbnail = (NSDictionary *)obj1;
NSString *artistToCompare = artistThumbnail[_artist_thumb];
NSComparisonResult result = [artistToCompare compare:artistName];
return result;
}];
When I used same code with less then equal to 256 objects code work fine no crash, both Obj1 and Obj2 have the dictionary object, but when array have >256 items then it crash and I've noticed that obj1 and obj2 not the same as the previously always come in NSDictionary format.

The problem is that your comparison object is of a different type than your array elements. If you type the array properly as NSArray<NSDictionary *> * you get a warning saying that parameter indexOfObject should be of type NSDictionary *.
Furthermore, you cannot rely on the artist object always is passed as obj2 to the comparison function. The documentation does not say anything about this, so you should assume that it can be passed as obj1 sometimes and obj2 other times.
To solve it you can embed the artist in a dictionary to make it the same format as an array element like this #{ _artist_thumb: artist }. Then you retrieve the name from both parameters the same way.
NSRange searchRange = NSMakeRange(0, artistThumbnail.count);
index = [artistThumbnail indexOfObject:#{ _artist_thumb: artist }
inSortedRange:searchRange
options:NSBinarySearchingLastEqual
usingComparator:^NSComparisonResult(id _Nonnull obj1, id _Nonnull obj2) {
NSString *artistName = ((NSDictionary *)obj2)[_artist_thumb];
NSDictionary *artistThumbnail = (NSDictionary *)obj1;
NSString *artistToCompare = artistThumbnail[_artist_thumb];
NSComparisonResult result = [artistToCompare compare:artistName];
return result;
}];

Related

ordering array with another array

I have the following categoryNames array.
And now, I have categoryTempElements and it has cName property. I need to know how to order categoryTempElements with a order of categoryNames.
UPDATE: I have added sortOrder property to Category object and tried the following but order does not change.
for (Category* a in categoryTempElements) {
int index = (int)[categoryNames indexOfObject:a.cName];
a.sortOrder = index;
}
NSSortDescriptor *sortDescriptor = [[NSSortDescriptor alloc] initWithKey:#"sortOrder" ascending:YES];
NSArray *sortDescriptors = [NSArray arrayWithObject:sortDescriptor];
NSArray *sortedArray = [categoryTempElements sortedArrayUsingDescriptors:sortDescriptors];
Another way could be without using sortedArrayUsingComparator, using two for-loops. Declare a new Mutable array called sortedCategoryElements and compare the categoryNames in categoryTempElements, If matches add it to a new array sortedCategoryElements:
NSMutableArray *sortedCategoryElements = [NSMutableArray new];
for (NSString *name in categoryNames) {
for (Category *category in categoryTempElements) {
if (name == category.cName) {
[sortedCategoryElements addObject:category];
break;
}
}
}
I tried with your set of data, it worked for me.
Hope it helps!
You need first convert your categoryNames array into dictionary with NSString key and NSNumber int value, the value will be the order in the array
//this is example code, this will be your first array (reference value array)
NSArray * array = #[#"prueba",#"prueba2",#"prueba3"];
//first you need convert this array in NSDictionary
NSMutableDictionary * arrayDict = [NSMutableDictionary dictionary];
int counter = 0;
for (NSString * value in array) {
if(arrayDict[value] == nil)
{
arrayDict[value] = [NSNumber numberWithInt:counter];
}
counter++;
}
After that then you can get the value and order with sortedArrayUsingComparator method, something like this
//this is an example of your second array categoryTempElements
NSArray * arrayOfObjs = #[[testObject testObjectWithName:#"prueba3"],[testObject testObjectWithName:#"prueba"],[testObject testObjectWithName:#"prueba2"]];
NSArray * sorted = [arrayOfObjs sortedArrayUsingComparator:^NSComparisonResult(testObject * _Nonnull obj1, testObject * _Nonnull obj2) {
if([((NSNumber*)arrayDict[obj1.cName]) intValue] < [((NSNumber*)arrayDict[obj2.cName]) intValue]){
return NSOrderedAscending;
}
if([((NSNumber*)arrayDict[obj1.cName]) intValue] > [((NSNumber*)arrayDict[obj2.cName]) intValue]){
return NSOrderedDescending;
}
return NSOrderedSame;
}];
for (testObject * obj in sorted) {
NSLog(#"%#",obj.cName);
}
And voila in sorted you will have your array of object sorted by your first array NSString order
Hope this helps
Create a dictionary with cName as the key and the Category object as the value. Then iterate over the categoryNames array, and build another array by using each item in categoryNames as the key. The resulting array should be sorted in the same order as categoryNames.
NSArray has a method sortedArrayUsingComparator: which sorts an array using the ordering implemented by the block you pass. This block, of type NSComparator, is passed references to two elements of your array and you must return the order of those two elements.
And now, I have categoryTempElements and it has cName property.
So your block will be passed two categoryTempElements, you need to access the cName property of each, and compare the resulting two values...
I need to know how to order categoryTempElements with a order of categoryNames
by the position, i.e. the index, of those values in your categoryNames array. The method indexOfObject: provides that index for you.
So put that together and your problem is solved.
HTH

Comparing two NSDictionaries and Find Difference

I am working on an iOS app, where I will be getting a JSON Object from server, which will be populated on a UITableView.
User can change values on tableview, Hence resulting in a new JSON.
Now I want to send only delta (Difference of Two JSON Objects) back to server.
I know I can traverse both Objects for finding delta. But just wish to know is there any easy solution for this problem.
Ex:
NSDictionary *dict1 = {#"Name" : "John", #"Deptt" : #"IT"};
NSDictionary *dict2 = {#"Name" : "Mary", #"Deptt" : #"IT"};
Delta = {#"Name" : "Mary"}
Considering new value is Mary for key name;
Thanks In Advance
isEqualToDictionary: Returns a Boolean value that indicates whether the contents of the receiving dictionary are equal to the contents of another given dictionary.
if ([NSDictionary1 isEqualToDictionary:NSDictionary2) {
NSLog(#"The two dictionaries are equal.");
}
Two dictionaries have equal contents if they each hold the same number of entries and, for a given key, the corresponding value objects in each dictionary satisfy the isEqual: test.
Here's how to get all the keys with non-matching values. What to do with those keys is app level question, but the most informative structure would include an array of mismatched values from both dictionaries, as well has handle keys from one that are not present in the other:
NSMutableDictionary *result = [#{} mutableCopy];
// notice that this will neglect keys in dict2 which are not in dict1
for (NSString *key in [dict1 allKeys]) {
id value1 = dict1[key];
id value2 = dict2[key];
if (![value1 equals:value2]) {
// since the values might be mismatched because value2 is nil
value2 = (value2)? value2 : [NSNull null];
result[key] = #[value1, value2];
}
}
// for keys in dict2 that we didn't check because they're not in dict1
NSMutableSet *set1 = [NSMutableSet setWithArray:[dict1 allKeys]];
NSMutableSet *set2 = [NSMutableSet setWithArray:[dict2 allKeys]];
[set2 minusSet:set1]
for (NSString *key in set2) {
result[key] = #[[NSNull null], dict2[key]];
}
There are certainly more economical ways to do it, but this code is optimized for instruction.
Just enumerate through and compare the dictionaries key-by-key. This will output any differences as well as any unmatched keys on either side, you can tweak the logic depending on exactly what you want to include.
- (NSDictionary *)delta:(NSDictionary *)dictionary
{
NSMutableDictionary *result = NSMutableDictionary.dictionary;
// Find objects in self that don't exist or are different in the other dictionary
[self enumerateKeysAndObjectsUsingBlock:^(id _Nonnull key, id _Nonnull obj, BOOL * _Nonnull stop) {
id otherObj = dictionary[key];
if (![obj isEqual:otherObj]) {
result[key] = obj;
}
}];
// Find objects in the other dictionary that don't exist in self
[dictionary enumerateKeysAndObjectsUsingBlock:^(id _Nonnull key, id _Nonnull obj, BOOL * _Nonnull stop) {
id selfObj = self[key];
if (!selfObj) {
result[key] = obj;
}
}];
return result;
}

Search element in nsdictionary by value

I have nsdictionary which contains elements with following structure
name --> value
email--> key
I get value(of above structure) from user,
now I want to search element in nsdictionary by value(entered by user) not by key, whether it is present in nsdictionary or not and also want to get index of that element if present.
How to do this?
The best to do so would propably be
- (NSArray *)allKeysForObject:(id)anObject
This method of NSDictionary gives you back all the keys having anObject as their value. If you only have each object once in the whole dictionary it will logically return an array with only one key in it.
NSArray * users = ...; //your array of NSDictionary objects
NSPredicate *filter = [NSPredicate predicateWithFormat:#"email = test#gmail.com"];
NSArray *filteredContacts = [contacts filteredArrayUsingPredicate:filter];
for more than one value of email, then use an OR in the predicate:
filter = [NSPredicate predicateWithFormat:#"contact_type = 42 OR contact_type = 23"];
The dictionary data structure has no 'order', so you'd have to search for your key by iterating the collection and looking for the desired value.
Example:
NSString *targetKey = nil;
NSArray *allKeys = [collection allKeys];
for (int i = 0; i < [allKeys count]; ++i) {
NSString *key = [allKeys objectAtIndex:i];
NSString *obj = [collection objectForKey:key];
if ([obj isEqualToString:searchedString]) { // searchedString is what you're looking for
targetKey = key;
break;
}
}
// check if key was found (not nil) & proceed
// ...
You can search the entered value in NSDictionary , but you can't get an index of value , as NSDictionary has no order of key value pair.
NSArray *array = [yourDictionaryObject allValues];
if ([array containsObject:#"userEnteredValue"]) {
<#statements#>
}
You need to iterate through the Dictionary for the keys has the Value of your need:
Try this:
NSArray *keys= [json allKeys];
for (NSString *keysV in keys){
NSLog(#"Keys are %#", keysV);
if([Your_Dict objectForKey: keysV] isEqual:#"string to Match"){
//Do your stuff here
}
}

getting the object value in key in dictionary

I have a dictionary with key-value pair populated from JSON returned data.What I wish to do is use the dictionary to populate UITableView.
I have this structure for table:
[Product Name]
By [Manufacturer Name]
What this means is that key is Product Name and Value is Manufacturer Name. I need to get the name of the key and the name of the value. How can this be done? and is it possible without for-loop?
I'd use the enumerateKeysAndObjectsUsingBlock: method. The following code builds a list of the strings you require.
NSMutableArray *names = [NSMutableArray array];
[dictionary enumerateKeysAndObjectsUsingBlock: ^(NSString *key, NSString *object, BOOL *stop) {
[names addObject[NSString stringWithFormat:#"%# By %#",key, object]];
}];
You can use the keyEnumerator of NSDictionary and for each key look up the value. This could look something like this:
for (NSString *p in dict)
{
NSString *m = [dict objectForKey:p];
// do something with (p,m)
}
You should not be concerned with avoiding for-loops. After all, something like a for loop will always happen somewhere underneath.
If your keys are dynamic from json then you can use
NSArray *keys = [dictionary allkeys];
Then in the table View Cell for row at index path method you can populate the table view with the corresponding keys and their values.
NSArray * keys = [results allKeys];
for (int i = 0;i<[keys count];c++){
NSString* productName = [key objectAtIndex:i];
NSString* manufacturerName = [results objectForKey:productName];
}
Hope this helps...
I have assumed the name as strings, you can change the type according to your situation..

Sort NSArray of NSStrings based on a super set of ordered Strings

I have an NSArray which contains some NSString objects. For example:
NSArray *objects = #[#"Stin",#"Foo",#"Ray",#"Space"];
Now I need to sort this array based on following order of Strings.
NSArray *sortOrder = #[#"John",#"Foo",#"Space",#"Star",#"Ray",#"Stin"];
So the answer should be
NSArray *sorted = #[#"Foo",#"Space",#"Ray",#"Stin"];
How can I achieve this?
ANSWER:
Based on Accepted answer of dasblinkenlight, I did following and it worked to charm.
NSMutableArray *objects = #[#"Star",#"Stin",#"Foo",#"Ray",#"Space",#"John"];
NSArray *sortOrder = #[#"John",#"Foo",#"Space",#"Star",#"Ray",#"Stin"];
[objects sortUsingComparator:^NSComparisonResult(id obj1, id obj2) {
int index1 = [sortOrder indexOfObject:obj1];
int index2 = [sortOrder indexOfObject:obj2];
if (index1 > index2)
return NSOrderedDescending;
if (index1 < index2)
return NSOrderedAscending;
return NSOrderedSame;
}];
Create NSComparator that holds a reference to the superset array, and decides the relative order of strings by comparing the results of calling [superset indexOfObject:str] on both strings. Call sortedArrayUsingComparator: passing an instance of NSComparator to get the desired ordering.
dasblinkenlight's solution would work, but like most programming problems there are multiple ways to go about it. Here is one such alternative:
NSMutableArray *sorted = [NSMutableArray arrayWithCapacity:0];
[sortOrder enumerateObjectsUsingBlock:^(NSString *sortedString, NSUInteger idx, BOOL *stop) {
if ([objects containsObject:sortedString]) {
[sorted addObject:sortedString];
}
}];
The variable names correspond to the variable names used in the original question.
This works because the enumeration happens in order. Therefore, what takes place is, essentially, a cull of the objects that exist in both arrays in the order as specified by sortOrder.

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