Related
I want a regular expression to check that:
A password contains at least eight characters, including at least one number and includes both lower and uppercase letters and special characters, for example #, ?, !.
It cannot be your old password or contain your username, "password", or "websitename"
And here is my validation expression which is for eight characters including one uppercase letter, one lowercase letter, and one number or special character.
(?=^.{8,}$)((?=.*\d)|(?=.*\W+))(?![.\n])(?=.*[A-Z])(?=.*[a-z]).*$"
How can I write it for a password must be eight characters including one uppercase letter, one special character and alphanumeric characters?
Minimum eight characters, at least one letter and one number:
"^(?=.*[A-Za-z])(?=.*\d)[A-Za-z\d]{8,}$"
Minimum eight characters, at least one letter, one number and one special character:
"^(?=.*[A-Za-z])(?=.*\d)(?=.*[#$!%*#?&])[A-Za-z\d#$!%*#?&]{8,}$"
Minimum eight characters, at least one uppercase letter, one lowercase letter and one number:
"^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)[a-zA-Z\d]{8,}$"
Minimum eight characters, at least one uppercase letter, one lowercase letter, one number and one special character:
"^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)(?=.*[#$!%*?&])[A-Za-z\d#$!%*?&]{8,}$"
Minimum eight and maximum 10 characters, at least one uppercase letter, one lowercase letter, one number and one special character:
"^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)(?=.*[#$!%*?&])[A-Za-z\d#$!%*?&]{8,10}$"
You may use this regex with multiple lookahead assertions (conditions):
^(?=.*?[A-Z])(?=.*?[a-z])(?=.*?[0-9])(?=.*?[#?!#$%^&*-]).{8,}$
This regex will enforce these rules:
At least one upper case English letter, (?=.*?[A-Z])
At least one lower case English letter, (?=.*?[a-z])
At least one digit, (?=.*?[0-9])
At least one special character, (?=.*?[#?!#$%^&*-])
Minimum eight in length .{8,} (with the anchors)
Regular expressions don't have an AND operator, so it's pretty hard to write a regex that matches valid passwords, when validity is defined by something AND something else AND something else...
But, regular expressions do have an OR operator, so just apply DeMorgan's theorem, and write a regex that matches invalid passwords:
Anything with less than eight characters OR anything with no numbers OR anything with no uppercase OR or anything with no lowercase OR anything with no special characters.
So:
^(.{0,7}|[^0-9]*|[^A-Z]*|[^a-z]*|[a-zA-Z0-9]*)$
If anything matches that, then it's an invalid password.
Use the following Regex to satisfy the below conditions:
Conditions:
Min 1 uppercase letter.
Min 1 lowercase letter.
Min 1 special character.
Min 1 number.
Min 8 characters.
Max 30 characters.
Regex:
/^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)(?=.*[#$#!%&*?])[A-Za-z\d#$#!%&*?]{8,30}$/
Just a small improvement for #anubhava's answer: Since special character are limited to the ones in the keyboard, use this for any special character:
^(?=.*?[A-Z])(?=(.*[a-z]){1,})(?=(.*[\d]){1,})(?=(.*[\W]){1,})(?!.*\s).{8,}$
This regex will enforce these rules:
At least one upper case English letter
At least one lower case English letter
At least one digit
At least one special character
Minimum eight in length
I had some difficulty following the most popular answer for my circumstances. For example, my validation was failing with characters such as ; or [. I was not interested in white-listing my special characters, so I instead leveraged [^\w\s] as a test - simply put - match non word characters (including numeric) and non white space characters. To summarize, here is what worked for me...
at least 8 characters
at least 1 numeric character
at least 1 lowercase letter
at least 1 uppercase letter
at least 1 special character
/^(?=.*?[A-Z])(?=.*?[a-z])(?=.*?[0-9])(?=.*?[^\w\s]).{8,}$/
JSFiddle Link - simple demo covering various cases
✅ The following 4 regex patterns can help you to write almost any password validation
Pattern 1:
Password must contain one digit from 1 to 9, one lowercase letter, one uppercase letter, one special character, no space, and it must be 8-16 characters long.
/^(?=.*[0-9])(?=.*[a-z])(?=.*[A-Z])(?=.*\W)(?!.* ).{8,16}$/
Explanation:
(?=.*[0-9]) means that the password must contain a single digit from 1 to 9.
(?=.*[a-z]) means that the password must contain one lowercase letter.
(?=.*[A-Z]) means that the password must contain one uppercase letter.
(?=.*\W) means that the password must contain one special character.
.{8,16} means that the password must be 8-16 characters long. We must use this at the end of the regex, just before the $ symbol.
What are ^ and $:
^ indicates the beginning of the string. $ indicates the end of the string.
If we don't use these ^ & $, the regex will not be able to determine the maximum length of the password. In the above example, we have a condition that the password can't be longer than 16 characters, to make that condition work, we have used these ^ & $
Remove maximum length restriction:
Instead of .{8,16}, if we used .{8,}, it would mean that the password must be at least 8 characters long. So, there will not be any condition for checking the maximum length of the password.
Don't accept any number(digit):
Instead of (?=.*[0-9]), if we used (?!.*[0-9]), it would mean that the password must not contain any digit from 1-9 (Difference with the (?=.*[0-9]) is the use of ! instead of =)
Don't accept any spcecial character:
Instead of (?=.*\W), if we used (?!.*\W), it would mean that the password must not contain any special characters (The difference with the (?=.*\W) is the use of ! instead of =)
Alternative Syntax for number(digit):
Instead of (?=.*[0-9]), we could have used (?=.*\d). (?=.*\d) also means that the password must contain a single digit from 1 to 9.
Pattern 2:
Password must contain one digit from 1 to 9, one lowercase letter, one uppercase letter, one underscore but no other special character, no space and it must be 8-16 characters long.
/^(?=.*[0-9])(?=.*[a-z])(?=.*[A-Z])(?=.*_)(?!.*\W)(?!.* ).{8,16}$/
Difference with the Pattern 1
Here, we have used (?=.*_) which wasn't on the Pattern 1.
(?=.*_)(?!.*\W) means that the password must contain an underscore but can not contain any other special character.
Pattern 3:
Password must contain one digit from 1 to 9, one lowercase letter, one uppercase letter, one underscore, no space and it must be 8-16 characters long. Usage of any other special character other than underscore is optional.
/^(?=.*[0-9])(?=.*[a-z])(?=.*[A-Z])(?=.*_)(?!.* ).{8,16}$/
Difference with the Pattern 2
Here, we have not used (?!.*\W) what was on the Pattern 2.
But it still has the (?=.*_)
By just removing the (?!.*\W), special characters have become optional. Now, one underscore is required but any other special character can be used or not as it's optional.
Pattern 4:
Password must contain one digit from 1 to 9, one lowercase letter, one uppercase letter, and one underscore, and it must be 8-16 characters long. Usage of any other special character and usage of space is optional.
/^(?=.*[0-9])(?=.*[a-z])(?=.*[A-Z]).{8,16}$/
Difference with the Pattern 3
Here, we have not used (?=.*_) & (?!.* ) which was on the Pattern 3.
By removing (?=.*_), it's no longer mandatory to pass one underscore. Now, passing special characters is optional.
By removing the (?!.* ), usage of space has become optional too.
I would reply to Peter Mortensen, but I don't have enough reputation.
His expressions are perfect for each of the specified minimum requirements. The problem with his expressions that don't require special characters is that they also don't ALLOW special characters, so they also enforce maximum requirements, which I don't believe the OP requested. Normally you want to allow your users to make their password as strong as they want; why restrict strong passwords?
So, his "minimum eight characters, at least one letter and one number" expression:
^(?=.*[A-Za-z])(?=.*\d)[A-Za-z\d]{8,}$
achieves the minimum requirement, but the remaining characters can only be letter and numbers. To allow (but not require) special characters, you should use something like:
^(?=.*[A-Za-z])(?=.*\d).{8,}$ to allow any characters
or
^(?=.*[A-Za-z])(?=.*\d)[A-Za-z\d$#$!%*#?&]{8,}$ to allow specific special characters
Likewise, "minimum eight characters, at least one uppercase letter, one lowercase letter and one number:"
^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)[a-zA-Z\d]{8,}$
meets that minimum requirement, but only allows letters and numbers. Use:
^(?=.*[a-z])(?=.*[A-Z])(?=.*\d).{8,}$ to allow any characters
or
^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)[A-Za-z\d$#$!%*?&]{8,} to allow specific special characters.
A more "generic" version(?), allowing none English letters as special characters.
^(?=\S*[a-z])(?=\S*[A-Z])(?=\S*\d)(?=\S*[^\w\s])\S{8,}$
var pwdList = [
'##V4-\3Z`zTzM{>k',
'12qw!"QW12',
'123qweASD!"#',
'1qA!"#$%&',
'Günther32',
'123456789',
'qweASD123',
'qweqQWEQWEqw',
'12qwAS!'
],
re = /^(?=\S*[a-z])(?=\S*[A-Z])(?=\S*\d)(?=\S*[^\w\s])\S{8,}$/;
pwdList.forEach(function (pw) {
document.write('<span style="color:'+ (re.test(pw) ? 'green':'red') + '">' + pw + '</span><br/>');
});
Import the JavaScript file jquery.validate.min.js.
You can use this method:
$.validator.addMethod("pwcheck", function (value) {
return /[\#\#\$\%\^\&\*\(\)\_\+\!]/.test(value) && /[a-z]/.test(value) && /[0-9]/.test(value) && /[A-Z]/.test(value)
});
At least one upper case English letter
At least one lower case English letter
At least one digit
At least one special character
For standard password requirements I found this to be useful:
At least 1 alphabet
At least 1 digit
Contains no space
Optional special characters e.g. #$!%*#?&^_-
Minimum 8 characters long
/^(?=.*[A-Za-z])(?=.*\d)[A-Za-z\d#$!%*#?&^_-]{8,}$/
You can also set the upper limit for example {8,32} up to 32 characters long.
Try this one:
Minimum six characters
At least one uppercase character
At least one lowercase character
At least one special character
Expression:
"/^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)(?=.*[$#$!%*?&.])[A-Za-z\d$#$!%*?&.]{6, 20}/"
Optional Special Characters:
At least one special character
At least one number
Special characters are optional
Minimum six characters and maximum 16 characters
Expression:
"/^(?=.*\d)(?=.*[a-zA-Z]).{6,20}$/"
If the min and max condition is not required then remove .{6, 16}
6 is minimum character limit
20 is maximum character limit
?= means match expression
This worked for me:
^(?=.*[0-9])(?=.*[a-z])(?=.*[A-Z])(?=.*[#$!%*?&])([a-zA-Z0-9#$!%*?&]{8,})$
At least 8 characters long;
One lowercase, one uppercase, one number and one special character;
No whitespaces.
Not directly answering the question, but does it really have to be a regex?
I used to do lots of Perl, and got used to solving problems with regexes. However, when they get more complicated with all the look-aheads and other quirks, you need to write dozens of unit tests to kill all those little bugs.
Furthermore, a regex is typically a few times slower than an imperative or a functional solution.
For example, the following (not very FP) Scala function solves the original question about three times faster than the regex of the most popular answer. What it does is also so clear that you don't need a unit test at all:
def validatePassword(password: String): Boolean = {
if (password.length < 8)
return false
var lower = false
var upper = false
var numbers = false
var special = false
password.foreach { c =>
if (c.isDigit) numbers = true
else if (c.isLower) lower = true
else if (c.isUpper) upper = true
else special = true
}
lower && upper && numbers && special
}
For a more strict validation where the following is required:
At least One Upper Case Character
At least one Lower Case character
At least one digit
At least one symbol/special character #$!%*#?&^_-
Minimum 8 characters/digits
Regex:
/(?=.*\d)(?=.*[a-z])(?=.*[A-Z])(?=.*[#$!%*#?&^_-]).{8,}/
I hope it helps someone with a more stringent.
What about considering the following regex solution:
^(?=.*[\w])(?=.*[\W])[\w\W]{8,}$
Which validates the following:
At least one lowercase
At least one uppercase
At least one digit
At least one special character
At least it should have 8 characters long.
Check it out working at the following link https://regex101.com/r/qPmC06/4/
^(?=.*[A-Z])(?=.*[a-z])(?=.*[0-9])(?=.*[!##$%^&*()_+,.\\\/;':"-]).{8,}$
Another option is to make use of contrast in the lookahead assertions using a negated character class, optionally matching any character except that is listed before matching the character that should be matched.
^(?=[^A-Z\n]*[A-Z])(?=[^a-z\n]*[a-z])(?=[^0-9\n]*[0-9])(?=[^#?!#$%^&*\n-]*[#?!#$%^&*-]).{8,}$
See a regex demo
In parts, the pattern matches:
^ Start of string
(?=[^A-Z\n]*[A-Z]) Positive lookahead, assert 0+ times any char except A-Z or a newline. Then match a char A-Z
(?=[^a-z\n]*[a-z]) The same approach for a char a-z
(?=[^0-9\n]*[0-9]) The same approach for a digit 0-9
(?=[^#?!#$%^&*\n-]*[#?!#$%^&*-]) The same approach for a char that you would consider special
.{8,} Match 8 or more times any character except a newline
$ End of string
Notes
A dot can also match a space. If you do not want to allow matching a space, then .{8,} can be changed to \S{8,} to match 8 or more non whitespace characters
Using either . or \S can match more characters than are specified in the lookahead assertions. If you only want to match the characters that are used in the assertions, you can change .{8,} to match only the allowed characters [#?!#$%^&*A-Za-z0-9-]{8,} using a character class
const regex = /^(?=[^A-Z\n]*[A-Z])(?=[^a-z\n]*[a-z])(?=[^0-9\n]*[0-9])(?=[^#?!#$%^&*\n-]*[#?!#$%^&*-]).{8,}$/;
[
"abcA1#!A",
"#!asdfSFD1;",
"# a f F1 ;",
"1111111111",
"aaaaaaaa",
"11111111",
"AAAAAAAA",
"########",
"aA1#"
].forEach(s =>
console.log(regex.test(s) ? `Match --> ${s}` : `No match --> ${s}`)
);
/^(?=.*[A-Z])(?=.*[a-z])(?=.*[0-9]).*$/
this the simple way to use it while validate atleast 1 uppercase 1 lowercase and 1 number
and this is the example while I use in express validation
check('password')
.notEmpty()
.withMessage('Password cannot be null')
.bail()
.isLength({ min: 6 })
.withMessage('Password must be at least 6 characters')
.bail()
.matches(/^(?=.*[A-Z])(?=.*[a-z])(?=.*[0-9]).*$/)
.withMessage(
'Must have atleast 1 uppercase, 1 lowercase letter and 1 number'
),
Testing this one in 2020:
^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)(?=.*[#$!%*?&])[A-Za-z\d#$!%*?&]{8,}$
Verify yourself
const regex = /^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)(?=.*[#$!%*?&])[A-Za-z\d#$!%*?&]{8,}$/;
const str = `some12*Nuts`;
let m;
if ((m = regex.exec(str)) !== null) {
// The result can be accessed through the `m`-variable.
m.forEach((match, groupIndex) => {
console.log(`Found match, group ${groupIndex}: ${match}`);
});
}
#ClasG has already suggested:
^(?=\S*[a-z])(?=\S*[A-Z])(?=\S*\d)(?=\S*[^\w\s])\S{8,}$
but it does not accept _(underscore) as a special character (eg. Aa12345_).
An improved one is:
^(?=\S*[a-z])(?=\S*[A-Z])(?=\S*\d)(?=\S*([^\w\s]|[_]))\S{8,}$
I've found many problems here, so I made my own.
Here it is in all it's glory, with tests:
^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)(?=.*([^a-zA-Z\d\s])).{9,}$
https://regex101.com/r/DCRR65/4/tests
Things to look out for:
doesn't use \w because that includes _, which I'm testing for.
I've had lots of troubles matching symbols, without matching the end of the line.
Doesn't specify symbols specifically, this is also because different locales may have different symbols on their keyboards that they may want to use.
Demo:
function password_check() {
pass = document.getElementById("password").value;
console.log(pass);
regex = /^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)(?=.*[#$!%*?&])[A-Za-z\d#$!%*?&]{8,}$/;
if (regex.exec(pass) == null) {
alert('invalid password!')
}
else {
console.log("valid");
}
}
<input type="text" id="password" value="Sample#1">
<input type="button" id="submit" onclick="password_check()" value="submit">
var strongRegex = new RegExp("^(?=.*[a-z])(?=.*[A-Z])(?=.*[0-9])(?=.*[!##\$%\^&\*])(?=.{8,})");
var mediumRegex = new RegExp("^(((?=.*[a-z])(?=.*[A-Z]))|((?=.*[a-z])(?=.*[0-9]))|((?=.*[A-Z])(?=.*[0-9])))(?=.{6,})");
Best For javascript
Keep it simple stupid:
This should do the trick for you, always.
Regex: ^(.{0,7}|[^a-z]{1,}|[^A-Z]{1,}|[^\d]{1,}|[^\W]{1,})$|[\s]
If your password matches the regex above, it is invalid.
If there's no match, your password is valid and contains has at least 8 characters, one upper case letter, one lower case letter and one symbol or special character. And it also contains no spaces, tabs or line breaks.
Breakdown of Regex
.{0,7} - matches if password has between 0 to 7 characters.
[^a-z]{1,} - matches if no lower case is found
[^A-Z]{1,} - matches if no upper case is found
[^\d]{1,} - matches if no number (between [0-9]) is found
[\s] - matches if a white space, tab or line break is found.
With this approach there's no limit or restriction in terms of symbols allowed. If you want to limit to few symbols allowable, just change [^\W] with [^YourSymbols].
(?=.*[0-9])(?=.*[a-z])(?=.*[A-Z])(?=.*[##$%^&+-]).{6}
According to your need this pattern should work just fine. Try this,
^(?=(.*\d){1})(.*\S)(?=.*[a-zA-Z\S])[0-9a-zA-Z\S]{8,}
Just create a string variable, assign the pattern, and create a boolean method which returns true if the pattern is correct, else false.
Sample:
String pattern = "^(?=(.*\d){1})(.*\S)(?=.*[a-zA-Z\S])[0-9a-zA-Z\S]{8,}";
String password_string = "Type the password here"
private boolean isValidPassword(String password_string) {
return password_string.matches(Constants.passwordPattern);
}
Use the following Regex to satisfy the below conditions:
Conditions: 1] Min 1 special character.
2] Min 1 number.
3] Min 8 characters or More
Regex: ^(?=.*\d)(?=.*[#$#!%&*?])[A-Za-z\d#$#!%&*?]{8,}$
Can Test Online: https://regex101.com
Just we can do this by using HTML5.
Use below code in pattern attribute,
pattern="(?=^.{8,}$)((?=.*\d)(?=.*\W+))(?![.\n])(?=.*[A-Z])(?=.*[a-z]).*$"
It will work perfectly.
You can use the below regular expression pattern to check the password whether it matches your expectations or not.
((?=.*\\d)(?=.*[a-z])(?=.*[A-Z])(?=.*[~!##$%^&*()]).{8,20})
I have two regular expressions: ^(\\p{L}|[0-9]|_)+$ and #[^[:punct:][:space:]]+ (the first is used in Java, the second on iOS). I want to combine these into one expression, to match either one or the other in iOS.
The first one is for a username so I also need to add a # character to the start of that one. What would that look like?
The ^(\\p{L}|[0-9]|_)+$ pattern in Java matches the same way as in ICU library used in iOS (they are very similar): a whole string consisting of 1 or more Unicode letters, ASCII digits or _. It is poorly written as the alternation group is quantified and that is much less efficient than a character class based solution, ^[\\p{L}0-9_]+$.
The #[^[:punct:][:space:]]+ pattern matches a # followed with 1 or more chars other than punctuation/symbols and whitespace chars (that is, 1 or more letters or digits, or alphanumeric chars).
What you seek can be writtern as
#[\\p{L}0-9_]+|[^[:punct:][:space:]]+
or
#[\\p{L}0-9_]+|#[[:alnum:]]+
or if you want to limit to ASCII digits and not match Unicode digits:
#[\\p{L}0-9_]+|#[\\p{L}0-9]+
It matches
# - a # symbol
[\\p{L}0-9_]+ - 1 or more Unicode letters, ASCII diigts, _
| - or
# - a # char
[[:alnum:]]+ - 1 or more letters or digits.
[^[:punct:][:space:]]+ - any 1+ chars other than punctuation/symbols and whitespace.
Basically, all these expressions match strings like this.
If you want to match #SomeThing_123 in full, just use [##]\\w+, a # or # and then 1 or more letters, digits or _, or to only allow ASCII digits, [##][\\p{L}0-9_]+.
A word boundary may be required at the end of the pattern, [##][\\p{L}0-9_]+\\b.
I want a regular expression to check that:
A password contains at least eight characters, including at least one number and includes both lower and uppercase letters and special characters, for example #, ?, !.
It cannot be your old password or contain your username, "password", or "websitename"
And here is my validation expression which is for eight characters including one uppercase letter, one lowercase letter, and one number or special character.
(?=^.{8,}$)((?=.*\d)|(?=.*\W+))(?![.\n])(?=.*[A-Z])(?=.*[a-z]).*$"
How can I write it for a password must be eight characters including one uppercase letter, one special character and alphanumeric characters?
Minimum eight characters, at least one letter and one number:
"^(?=.*[A-Za-z])(?=.*\d)[A-Za-z\d]{8,}$"
Minimum eight characters, at least one letter, one number and one special character:
"^(?=.*[A-Za-z])(?=.*\d)(?=.*[#$!%*#?&])[A-Za-z\d#$!%*#?&]{8,}$"
Minimum eight characters, at least one uppercase letter, one lowercase letter and one number:
"^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)[a-zA-Z\d]{8,}$"
Minimum eight characters, at least one uppercase letter, one lowercase letter, one number and one special character:
"^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)(?=.*[#$!%*?&])[A-Za-z\d#$!%*?&]{8,}$"
Minimum eight and maximum 10 characters, at least one uppercase letter, one lowercase letter, one number and one special character:
"^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)(?=.*[#$!%*?&])[A-Za-z\d#$!%*?&]{8,10}$"
You may use this regex with multiple lookahead assertions (conditions):
^(?=.*?[A-Z])(?=.*?[a-z])(?=.*?[0-9])(?=.*?[#?!#$%^&*-]).{8,}$
This regex will enforce these rules:
At least one upper case English letter, (?=.*?[A-Z])
At least one lower case English letter, (?=.*?[a-z])
At least one digit, (?=.*?[0-9])
At least one special character, (?=.*?[#?!#$%^&*-])
Minimum eight in length .{8,} (with the anchors)
Regular expressions don't have an AND operator, so it's pretty hard to write a regex that matches valid passwords, when validity is defined by something AND something else AND something else...
But, regular expressions do have an OR operator, so just apply DeMorgan's theorem, and write a regex that matches invalid passwords:
Anything with less than eight characters OR anything with no numbers OR anything with no uppercase OR or anything with no lowercase OR anything with no special characters.
So:
^(.{0,7}|[^0-9]*|[^A-Z]*|[^a-z]*|[a-zA-Z0-9]*)$
If anything matches that, then it's an invalid password.
Use the following Regex to satisfy the below conditions:
Conditions:
Min 1 uppercase letter.
Min 1 lowercase letter.
Min 1 special character.
Min 1 number.
Min 8 characters.
Max 30 characters.
Regex:
/^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)(?=.*[#$#!%&*?])[A-Za-z\d#$#!%&*?]{8,30}$/
Just a small improvement for #anubhava's answer: Since special character are limited to the ones in the keyboard, use this for any special character:
^(?=.*?[A-Z])(?=(.*[a-z]){1,})(?=(.*[\d]){1,})(?=(.*[\W]){1,})(?!.*\s).{8,}$
This regex will enforce these rules:
At least one upper case English letter
At least one lower case English letter
At least one digit
At least one special character
Minimum eight in length
I had some difficulty following the most popular answer for my circumstances. For example, my validation was failing with characters such as ; or [. I was not interested in white-listing my special characters, so I instead leveraged [^\w\s] as a test - simply put - match non word characters (including numeric) and non white space characters. To summarize, here is what worked for me...
at least 8 characters
at least 1 numeric character
at least 1 lowercase letter
at least 1 uppercase letter
at least 1 special character
/^(?=.*?[A-Z])(?=.*?[a-z])(?=.*?[0-9])(?=.*?[^\w\s]).{8,}$/
JSFiddle Link - simple demo covering various cases
✅ The following 4 regex patterns can help you to write almost any password validation
Pattern 1:
Password must contain one digit from 1 to 9, one lowercase letter, one uppercase letter, one special character, no space, and it must be 8-16 characters long.
/^(?=.*[0-9])(?=.*[a-z])(?=.*[A-Z])(?=.*\W)(?!.* ).{8,16}$/
Explanation:
(?=.*[0-9]) means that the password must contain a single digit from 1 to 9.
(?=.*[a-z]) means that the password must contain one lowercase letter.
(?=.*[A-Z]) means that the password must contain one uppercase letter.
(?=.*\W) means that the password must contain one special character.
.{8,16} means that the password must be 8-16 characters long. We must use this at the end of the regex, just before the $ symbol.
What are ^ and $:
^ indicates the beginning of the string. $ indicates the end of the string.
If we don't use these ^ & $, the regex will not be able to determine the maximum length of the password. In the above example, we have a condition that the password can't be longer than 16 characters, to make that condition work, we have used these ^ & $
Remove maximum length restriction:
Instead of .{8,16}, if we used .{8,}, it would mean that the password must be at least 8 characters long. So, there will not be any condition for checking the maximum length of the password.
Don't accept any number(digit):
Instead of (?=.*[0-9]), if we used (?!.*[0-9]), it would mean that the password must not contain any digit from 1-9 (Difference with the (?=.*[0-9]) is the use of ! instead of =)
Don't accept any spcecial character:
Instead of (?=.*\W), if we used (?!.*\W), it would mean that the password must not contain any special characters (The difference with the (?=.*\W) is the use of ! instead of =)
Alternative Syntax for number(digit):
Instead of (?=.*[0-9]), we could have used (?=.*\d). (?=.*\d) also means that the password must contain a single digit from 1 to 9.
Pattern 2:
Password must contain one digit from 1 to 9, one lowercase letter, one uppercase letter, one underscore but no other special character, no space and it must be 8-16 characters long.
/^(?=.*[0-9])(?=.*[a-z])(?=.*[A-Z])(?=.*_)(?!.*\W)(?!.* ).{8,16}$/
Difference with the Pattern 1
Here, we have used (?=.*_) which wasn't on the Pattern 1.
(?=.*_)(?!.*\W) means that the password must contain an underscore but can not contain any other special character.
Pattern 3:
Password must contain one digit from 1 to 9, one lowercase letter, one uppercase letter, one underscore, no space and it must be 8-16 characters long. Usage of any other special character other than underscore is optional.
/^(?=.*[0-9])(?=.*[a-z])(?=.*[A-Z])(?=.*_)(?!.* ).{8,16}$/
Difference with the Pattern 2
Here, we have not used (?!.*\W) what was on the Pattern 2.
But it still has the (?=.*_)
By just removing the (?!.*\W), special characters have become optional. Now, one underscore is required but any other special character can be used or not as it's optional.
Pattern 4:
Password must contain one digit from 1 to 9, one lowercase letter, one uppercase letter, and one underscore, and it must be 8-16 characters long. Usage of any other special character and usage of space is optional.
/^(?=.*[0-9])(?=.*[a-z])(?=.*[A-Z]).{8,16}$/
Difference with the Pattern 3
Here, we have not used (?=.*_) & (?!.* ) which was on the Pattern 3.
By removing (?=.*_), it's no longer mandatory to pass one underscore. Now, passing special characters is optional.
By removing the (?!.* ), usage of space has become optional too.
I would reply to Peter Mortensen, but I don't have enough reputation.
His expressions are perfect for each of the specified minimum requirements. The problem with his expressions that don't require special characters is that they also don't ALLOW special characters, so they also enforce maximum requirements, which I don't believe the OP requested. Normally you want to allow your users to make their password as strong as they want; why restrict strong passwords?
So, his "minimum eight characters, at least one letter and one number" expression:
^(?=.*[A-Za-z])(?=.*\d)[A-Za-z\d]{8,}$
achieves the minimum requirement, but the remaining characters can only be letter and numbers. To allow (but not require) special characters, you should use something like:
^(?=.*[A-Za-z])(?=.*\d).{8,}$ to allow any characters
or
^(?=.*[A-Za-z])(?=.*\d)[A-Za-z\d$#$!%*#?&]{8,}$ to allow specific special characters
Likewise, "minimum eight characters, at least one uppercase letter, one lowercase letter and one number:"
^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)[a-zA-Z\d]{8,}$
meets that minimum requirement, but only allows letters and numbers. Use:
^(?=.*[a-z])(?=.*[A-Z])(?=.*\d).{8,}$ to allow any characters
or
^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)[A-Za-z\d$#$!%*?&]{8,} to allow specific special characters.
A more "generic" version(?), allowing none English letters as special characters.
^(?=\S*[a-z])(?=\S*[A-Z])(?=\S*\d)(?=\S*[^\w\s])\S{8,}$
var pwdList = [
'##V4-\3Z`zTzM{>k',
'12qw!"QW12',
'123qweASD!"#',
'1qA!"#$%&',
'Günther32',
'123456789',
'qweASD123',
'qweqQWEQWEqw',
'12qwAS!'
],
re = /^(?=\S*[a-z])(?=\S*[A-Z])(?=\S*\d)(?=\S*[^\w\s])\S{8,}$/;
pwdList.forEach(function (pw) {
document.write('<span style="color:'+ (re.test(pw) ? 'green':'red') + '">' + pw + '</span><br/>');
});
Import the JavaScript file jquery.validate.min.js.
You can use this method:
$.validator.addMethod("pwcheck", function (value) {
return /[\#\#\$\%\^\&\*\(\)\_\+\!]/.test(value) && /[a-z]/.test(value) && /[0-9]/.test(value) && /[A-Z]/.test(value)
});
At least one upper case English letter
At least one lower case English letter
At least one digit
At least one special character
For standard password requirements I found this to be useful:
At least 1 alphabet
At least 1 digit
Contains no space
Optional special characters e.g. #$!%*#?&^_-
Minimum 8 characters long
/^(?=.*[A-Za-z])(?=.*\d)[A-Za-z\d#$!%*#?&^_-]{8,}$/
You can also set the upper limit for example {8,32} up to 32 characters long.
Try this one:
Minimum six characters
At least one uppercase character
At least one lowercase character
At least one special character
Expression:
"/^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)(?=.*[$#$!%*?&.])[A-Za-z\d$#$!%*?&.]{6, 20}/"
Optional Special Characters:
At least one special character
At least one number
Special characters are optional
Minimum six characters and maximum 16 characters
Expression:
"/^(?=.*\d)(?=.*[a-zA-Z]).{6,20}$/"
If the min and max condition is not required then remove .{6, 16}
6 is minimum character limit
20 is maximum character limit
?= means match expression
This worked for me:
^(?=.*[0-9])(?=.*[a-z])(?=.*[A-Z])(?=.*[#$!%*?&])([a-zA-Z0-9#$!%*?&]{8,})$
At least 8 characters long;
One lowercase, one uppercase, one number and one special character;
No whitespaces.
Not directly answering the question, but does it really have to be a regex?
I used to do lots of Perl, and got used to solving problems with regexes. However, when they get more complicated with all the look-aheads and other quirks, you need to write dozens of unit tests to kill all those little bugs.
Furthermore, a regex is typically a few times slower than an imperative or a functional solution.
For example, the following (not very FP) Scala function solves the original question about three times faster than the regex of the most popular answer. What it does is also so clear that you don't need a unit test at all:
def validatePassword(password: String): Boolean = {
if (password.length < 8)
return false
var lower = false
var upper = false
var numbers = false
var special = false
password.foreach { c =>
if (c.isDigit) numbers = true
else if (c.isLower) lower = true
else if (c.isUpper) upper = true
else special = true
}
lower && upper && numbers && special
}
For a more strict validation where the following is required:
At least One Upper Case Character
At least one Lower Case character
At least one digit
At least one symbol/special character #$!%*#?&^_-
Minimum 8 characters/digits
Regex:
/(?=.*\d)(?=.*[a-z])(?=.*[A-Z])(?=.*[#$!%*#?&^_-]).{8,}/
I hope it helps someone with a more stringent.
What about considering the following regex solution:
^(?=.*[\w])(?=.*[\W])[\w\W]{8,}$
Which validates the following:
At least one lowercase
At least one uppercase
At least one digit
At least one special character
At least it should have 8 characters long.
Check it out working at the following link https://regex101.com/r/qPmC06/4/
^(?=.*[A-Z])(?=.*[a-z])(?=.*[0-9])(?=.*[!##$%^&*()_+,.\\\/;':"-]).{8,}$
Another option is to make use of contrast in the lookahead assertions using a negated character class, optionally matching any character except that is listed before matching the character that should be matched.
^(?=[^A-Z\n]*[A-Z])(?=[^a-z\n]*[a-z])(?=[^0-9\n]*[0-9])(?=[^#?!#$%^&*\n-]*[#?!#$%^&*-]).{8,}$
See a regex demo
In parts, the pattern matches:
^ Start of string
(?=[^A-Z\n]*[A-Z]) Positive lookahead, assert 0+ times any char except A-Z or a newline. Then match a char A-Z
(?=[^a-z\n]*[a-z]) The same approach for a char a-z
(?=[^0-9\n]*[0-9]) The same approach for a digit 0-9
(?=[^#?!#$%^&*\n-]*[#?!#$%^&*-]) The same approach for a char that you would consider special
.{8,} Match 8 or more times any character except a newline
$ End of string
Notes
A dot can also match a space. If you do not want to allow matching a space, then .{8,} can be changed to \S{8,} to match 8 or more non whitespace characters
Using either . or \S can match more characters than are specified in the lookahead assertions. If you only want to match the characters that are used in the assertions, you can change .{8,} to match only the allowed characters [#?!#$%^&*A-Za-z0-9-]{8,} using a character class
const regex = /^(?=[^A-Z\n]*[A-Z])(?=[^a-z\n]*[a-z])(?=[^0-9\n]*[0-9])(?=[^#?!#$%^&*\n-]*[#?!#$%^&*-]).{8,}$/;
[
"abcA1#!A",
"#!asdfSFD1;",
"# a f F1 ;",
"1111111111",
"aaaaaaaa",
"11111111",
"AAAAAAAA",
"########",
"aA1#"
].forEach(s =>
console.log(regex.test(s) ? `Match --> ${s}` : `No match --> ${s}`)
);
/^(?=.*[A-Z])(?=.*[a-z])(?=.*[0-9]).*$/
this the simple way to use it while validate atleast 1 uppercase 1 lowercase and 1 number
and this is the example while I use in express validation
check('password')
.notEmpty()
.withMessage('Password cannot be null')
.bail()
.isLength({ min: 6 })
.withMessage('Password must be at least 6 characters')
.bail()
.matches(/^(?=.*[A-Z])(?=.*[a-z])(?=.*[0-9]).*$/)
.withMessage(
'Must have atleast 1 uppercase, 1 lowercase letter and 1 number'
),
Testing this one in 2020:
^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)(?=.*[#$!%*?&])[A-Za-z\d#$!%*?&]{8,}$
Verify yourself
const regex = /^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)(?=.*[#$!%*?&])[A-Za-z\d#$!%*?&]{8,}$/;
const str = `some12*Nuts`;
let m;
if ((m = regex.exec(str)) !== null) {
// The result can be accessed through the `m`-variable.
m.forEach((match, groupIndex) => {
console.log(`Found match, group ${groupIndex}: ${match}`);
});
}
#ClasG has already suggested:
^(?=\S*[a-z])(?=\S*[A-Z])(?=\S*\d)(?=\S*[^\w\s])\S{8,}$
but it does not accept _(underscore) as a special character (eg. Aa12345_).
An improved one is:
^(?=\S*[a-z])(?=\S*[A-Z])(?=\S*\d)(?=\S*([^\w\s]|[_]))\S{8,}$
I've found many problems here, so I made my own.
Here it is in all it's glory, with tests:
^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)(?=.*([^a-zA-Z\d\s])).{9,}$
https://regex101.com/r/DCRR65/4/tests
Things to look out for:
doesn't use \w because that includes _, which I'm testing for.
I've had lots of troubles matching symbols, without matching the end of the line.
Doesn't specify symbols specifically, this is also because different locales may have different symbols on their keyboards that they may want to use.
Demo:
function password_check() {
pass = document.getElementById("password").value;
console.log(pass);
regex = /^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)(?=.*[#$!%*?&])[A-Za-z\d#$!%*?&]{8,}$/;
if (regex.exec(pass) == null) {
alert('invalid password!')
}
else {
console.log("valid");
}
}
<input type="text" id="password" value="Sample#1">
<input type="button" id="submit" onclick="password_check()" value="submit">
var strongRegex = new RegExp("^(?=.*[a-z])(?=.*[A-Z])(?=.*[0-9])(?=.*[!##\$%\^&\*])(?=.{8,})");
var mediumRegex = new RegExp("^(((?=.*[a-z])(?=.*[A-Z]))|((?=.*[a-z])(?=.*[0-9]))|((?=.*[A-Z])(?=.*[0-9])))(?=.{6,})");
Best For javascript
Keep it simple stupid:
This should do the trick for you, always.
Regex: ^(.{0,7}|[^a-z]{1,}|[^A-Z]{1,}|[^\d]{1,}|[^\W]{1,})$|[\s]
If your password matches the regex above, it is invalid.
If there's no match, your password is valid and contains has at least 8 characters, one upper case letter, one lower case letter and one symbol or special character. And it also contains no spaces, tabs or line breaks.
Breakdown of Regex
.{0,7} - matches if password has between 0 to 7 characters.
[^a-z]{1,} - matches if no lower case is found
[^A-Z]{1,} - matches if no upper case is found
[^\d]{1,} - matches if no number (between [0-9]) is found
[\s] - matches if a white space, tab or line break is found.
With this approach there's no limit or restriction in terms of symbols allowed. If you want to limit to few symbols allowable, just change [^\W] with [^YourSymbols].
(?=.*[0-9])(?=.*[a-z])(?=.*[A-Z])(?=.*[##$%^&+-]).{6}
According to your need this pattern should work just fine. Try this,
^(?=(.*\d){1})(.*\S)(?=.*[a-zA-Z\S])[0-9a-zA-Z\S]{8,}
Just create a string variable, assign the pattern, and create a boolean method which returns true if the pattern is correct, else false.
Sample:
String pattern = "^(?=(.*\d){1})(.*\S)(?=.*[a-zA-Z\S])[0-9a-zA-Z\S]{8,}";
String password_string = "Type the password here"
private boolean isValidPassword(String password_string) {
return password_string.matches(Constants.passwordPattern);
}
Use the following Regex to satisfy the below conditions:
Conditions: 1] Min 1 special character.
2] Min 1 number.
3] Min 8 characters or More
Regex: ^(?=.*\d)(?=.*[#$#!%&*?])[A-Za-z\d#$#!%&*?]{8,}$
Can Test Online: https://regex101.com
Just we can do this by using HTML5.
Use below code in pattern attribute,
pattern="(?=^.{8,}$)((?=.*\d)(?=.*\W+))(?![.\n])(?=.*[A-Z])(?=.*[a-z]).*$"
It will work perfectly.
You can use the below regular expression pattern to check the password whether it matches your expectations or not.
((?=.*\\d)(?=.*[a-z])(?=.*[A-Z])(?=.*[~!##$%^&*()]).{8,20})
Just came across this pattern, which I really don't understand:
^[%w-.]+$
And could you give me some examples to match this expression?
Valid in Lua, where %w is (almost) the equivalent of \w in other languages
^[%w-.]+$ means match a string that is entirely composed of alphanumeric characters (letters and digits), dashes or dots.
Explanation
The ^ anchor asserts that we are at the beginning of the string
The character class [%w-.] matches one character that is a letter or digit (the meaning of %w), or a dash, or a period. This would be the equivalent of [\w-.] in JavaScript
The + quantifier matches such a character one or more times
The $ anchor asserts that we are at the end of the string
Reference
Lua Patterns
Actually it will match nothing. Because there is an error: w- this is a start of a text range and it is out of order. So it should be %w\- instead.
^[%w\-.]+$
Means:
^ assert position at start of the string
[%w\-.]+ match a single character present in the list below
+ Quantifier: Between one and unlimited times, as many times as possible, giving back as needed [greedy]
%w a single character in the list %w literally (case sensitive)
\- matches the character - literally
. the literal character .
$ assert position at end of the string
Edit
As the OP changed the question and the tags this answer no longer fits as a proper answer. It is POSIX based answer.
As #zx81 comment:
%w is \w in Lua which means any alphanumeric characters plus "_"
I am writing a parse for a script language.
I need to recognize strings, integers and floats.
I successfully recognize strings with the rule:
[a-zA-Z0-9_]+ {return STRING;}
But I have problem recognizing Integers and Floats. These are the (wrong) rules I wrote:
["+"|"-"][1-9]{DIGIT}* { return INTEGER;}
["+"|"-"]["0." | [1-9]{DIGIT}*"."]{DIGIT}+ {return FLOAT;}
How can I fix them?
Furthermore, since a "abc123" is a valid string, how can I make sure that it is recognized as a string and not as the concatenation of a string ("abc") and an Integer ("123") ?
First problem: There's a difference between (...) and [...]. Your regular expressions don't do what you think they do because you're using the wrong punctuation.
Beyond that:
No numeric rule recognizes 0.
Both numeric rules require an explicit sign.
Your STRING rule recognizes integers.
So, to start:
[...] encloses a set of individual characters or character ranges. It matches a single character which is a member of the set.
(...) encloses a regular expression. The parentheses are used for grouping, as in mathematics.
"..." encloses a sequence of individual characters, and matches exactly those characters.
With that in mind, let's look at
["+"|"-"][1-9]{DIGIT}*
The first bracket expression ["+"|"-"] is a set of individual characters or ranges. In this case, the set contains: ", +, " (again, which has no effect because a set contains zero or one instances of each member), |, and the range "-", which is a range whose endpoints are the same character, and consequently only includes that character, ", which is already in the set. In short, that was equivalent to ["+|]. It will match one of those three characters. It requires one of those three characters, in fact.
The second bracket expression [1-9] matches one character in the range 1-9, so it probably does what you expected. Again, it matches exactly one character.
Finally, {DIGIT} matches the expansion of the name DIGIT. I'll assume that you have the definition:
DIGIT [0-9]
somewhere in your definitions section. (In passing, I note that you could have just used the character class [:digit:], which would have been unambiguous, and you would not have needed to define it.) It's followed by a *, which means that it will match zero or more repetitions of the {DIGIT} definition.
Now, an example of a string which matches that pattern:
|42
And some examples of strings which don't match that pattern:
-7 # The pattern must start with |, + or "
42 # Again, the pattern must start with |, + or "
+0 # The character following the + must be in the range [0-9]
Similarly, your float pattern, once the [...] expressions are simplified, becomes (writing out the individual pieces one per line, to make it more obvious):
["+|] # i.e. the set " + |
["0.|[1-9] # i.e. the set " 0 | [ 1 2 3 4 5 6 7 8 9
{DIGIT}* # Any number of digits
"." # A single period
] # A single ]
{DIGIT}+ # one or more digits
So here's a possible match:
"..]3
I'll skip over writing out the solution because I think you'll benefit more from doing it yourself.
Now, the other issues:
Some rule should match 0. If you don't want to allow leading zeros, you'll need to just a it as a separate rule.
Use the optional operator (?) to indicate that the preceding object is optional. eg. "foo"? matches either the three characters f, o, o (in order) or matches the empty string. You can use that to make the sign optional.
The problem is not the matching of abc123, as in your question. (F)lex always gives you the longest possible match, and the only rule which could match the starting character a is the string rule, so it will allow the string rule to continue as long as it can. It will always match all of abc123. However, it will also match 123, which you would probably prefer to be matched by your numeric rule. Here, the other (f)lex matching criterion comes into play: when there are two or more rules which could match exactly the same string, and none of the rules can match a longer string, (f)lex chooses the first rule in the file. So if you want to give numbers priority over strings, you have to put the number rule earlier in your (f)lex file than the string rule.
I hope that gives you some ideas about how to fix things.