Question: How do I programmatically assign a class to a UIView created in Storyboard?
I have a UIView created in IB (graphView) in which I would like to display one of several graphs, their definitions created in their respective classes.
To do this, I created another view programmatically then assigned the class of the selected graph to that view, then added it to the original view:
#IBOutlet weak var graphView: UIView!
func displayGraph(choice: Int) {
var selectedGraphView = UIView()
switch choice {
case 1: selectedGraphView = class1()
case 2: selectedGraphView = class2()
case 3: selectedGraphView = class3()
default: selectedGraphView = class1()
}
selectedGraphView.frame = CGRect(x: 0, y: 0, width: graphView, height: graphView)
graphView.addSubview(selectedGraphView)
}
Things seem to work, but do I really need that second UIView (selectedGraphView)?
I tried changing it to:
func displayGraph2(choice: Int) {
switch choice {
case 1: graphView = class1()
case 2: graphView = class2()
case 3: graphView = class3()
default: graphView = class1()
}
}
but I don't know how to get the contents of the class to run.
Can I do it this way? If so, what is missing?
EDIT: Actually, there are 3 UIViews: the one in IB, the one to hold the graph, and the class itself creates one.
If, say class1 has nothing but print("entered class1"), in the first case (displayGraph), I see "entered class1" printed. In the second (displayGraph2), I get nothing.
EDIT2:
I can assign any of the classes to graphView in IB and get the print message from the class. How do I assign a class to graphView programmatically (since what I attempted in displayGraph2 doesn't work)?
When you add a UIView in Storyboard, you can assign its Custom Class. However, at run-time, you cannot change its class this way:
#IBOutlet var graphViewHolder: UIView!
override func viewDidLoad() {
super.viewDidLoad()
// cannot do this
let v = View2Class()
graphViewHolder = v
}
One common approach, as you've done, is to add a UIView in your Storyboard as a "holder" (or "container") view. Then, in code, instantiate an instance of your desired Custom Class and add it as a subview to the "holder" view.
However, if you do this:
selectedGraphView.frame = CGRect(x: 0, y: 0, width: graphView, height: graphView)
graphView.addSubview(selectedGraphView)
The newly added subview will have the size of the "holder" view, and you'll run into layout issues if / when the holder view changes size (such as on device rotation).
So, you can do it like this:
// let's name it "graphViewHolder" so we know we're using it as a "holder" view
#IBOutlet var graphViewHolder: UIView!
var currentChoice: Int = 1
override func viewDidLoad() {
super.viewDidLoad()
displayGraph(choice: 1)
}
func displayGraph(choice: Int) {
var selectedGraphView: UIView?
switch choice {
case 1: selectedGraphView = View1Class()
case 2: selectedGraphView = View2Class()
case 3: selectedGraphView = View3Class()
default: selectedGraphView = View1Class()
}
// unwrap optional
guard let sgv = selectedGraphView else { return }
// does the "holder" view already have any subviews?
// if so, remove them
graphViewHolder.subviews.forEach { v in
v.removeFromSuperview()
}
// add the new view as a subview of the "holder" view
graphViewHolder.addSubview(sgv)
// we need to give the new view auto-layout properties
sgv.translatesAutoresizingMaskIntoConstraints = false
NSLayoutConstraint.activate([
// constrain it to all 4 sides of the "holder" view
sgv.topAnchor.constraint(equalTo: graphViewHolder.topAnchor),
sgv.leadingAnchor.constraint(equalTo: graphViewHolder.leadingAnchor),
sgv.trailingAnchor.constraint(equalTo: graphViewHolder.trailingAnchor),
sgv.bottomAnchor.constraint(equalTo: graphViewHolder.bottomAnchor),
])
}
Now the subview will follow the "holder" view's constraints.
Note that if you want to do something to the loaded view, you'll have to make sure it's the right class.
So, for example, if we want to call a custom func in View2Class:
// make sure the "holder" view has a subview
guard let v = graphViewHolder.subviews.first else {
print("Graph View Holder has no subviews!")
return
}
// make sure the subview is a View2Class instance
guard let v2 = v as? View2Class else {
print("The Holder subview is not View2Class!")
return
}
// call a func in View2Class
v2.myFunc()
I hava a UIPageViewController that holds an array of ContentUIViewController, these have scrollviews in them.
When the scrollview scrolls I want to recognise this in the view controller that is the parent of the UIPageViewController (added as child)
What would be the best route to achieve this? as currently I tried delegating the didScroll back to the viewmodel for the ContentUIViewController then feeding that into the parent of the UIPageViewController to adjust header height that I want to collapse, but it doesn't work well / is very hacky
Is there a way to read delegate output in the a child vc to the parent vc without feeding it back through viewmodels? This is proving tricky due to the array nature of the UIPageViewController rather than a single child VC.
Updated:
private func generateContentControllers() -> [UIViewController] {
var viewControllers: [UIViewController] = []
viewControllers.append(ScrollableContentViewController(contentViews: infoViews))
viewControllers.append(reviewsVC)
viewControllers.append(ScrollableContentViewController(contentViews: helpViews))
}
return viewControllers
}
Provided via
var scrollingViewControllers: [UIViewController] { get }
Added with
if let firstViewController = self.viewModel.scrollingViewControllers.first {
pagingController.setViewControllers([firstViewController], direction: .forward, animated: false)
}
Here is how you can get that working.
1. Create a handler in ContentUIViewController that will be called in scrollViewDidScroll(_:) method for each contentOffset change.
class ContentUIViewController: UIViewController, UIScrollViewDelegate {
var handler: ((CGPoint)->())?
func scrollViewDidScroll(_ scrollView: UIScrollView) {
handler?(scrollView.contentOffset)
}
}
2. In ParentVC, create an instance of UIPageViewController and add it as a child to it. I think you did that already.
What you need to do next is create an array of ContentUIViewController and for each instance set the handler that we created earlier.
This handler will be called every time the scrollView is scrolled in that particular ContentUIViewController. We'll get the contentOffset of the scrollView here. Call updateHeaderHeight(for:) with the obtained contentOffset to adjust the header height.
class ViewModel {
private func generateContentControllers() -> [ContentUIViewController] {
var viewControllers: [ContentUIViewController] = []
//add your code here....
return viewControllers
}
lazy var scrollingViewControllers: [ContentUIViewController] = {
return self.generateContentControllers()
}()
}
class ParentVC: UIViewController {
let viewModel = ViewModel()
override func viewDidLoad() {
super.viewDidLoad()
self.viewModel.scrollingViewControllers.forEach {
$0.handler = {(offset) in
self.updateHeaderHeight(for: offset)
}
}
}
func updateHeaderHeight(for offset: CGPoint) {
//add the code to adjust header height here...
}
//add rest of the code for pageViewController here....
}
In Swift 3 (XCode 8.3.3) I have a control in a UIStackView. I have an array of UIImageViews, and loop through the array to populate the stack view at run time:
for voiceIcon in voiceIcons {
let voiceView = UIImageView(image: voiceIcon)
addArrangedSubview(voiceView)
}
These icons will sometimes become disabled (replaced with a new image), so in order to update the control, I have a function to remove all the icons so that I can re-add the appropriate ones (if there's a better way, I'm listening!):
private func resetIconsView() {
for subUIView in self.subviews as [UIView] {
removeArrangedSubview(subUIView)
subUIView.removeFromSuperview()
print("Removing")
}
}
I've also tried
for subUIView in self.subviews as! [UIImageView] { ... }
I get the debug line "Removing" for each of the icons, but they still remain in the control and the UI. I'm new to Swift, so I'm likely not understanding something, what approach should I take?
Try code below:
for view in arrangedSubviews {
view.removeFromSuperview()
}
I am assuming your UIStackView only contains some UIImageView. You can iterate through all the arranged subviews of your stack view and update your image of that imageView. A sample implementation could look like below:
func changeImage() {
for view in self.arrangedSubviews {
if let imgView = view as? UIImageView {
imgView.image = UIImage(named: "taka_icon.png")
}
}
}
I did it with an extension. You have also to remove Constraints if existing. Else this can cause some trouble.
USAGE: myStackView.removeAllArrangedSubviews()
public extension UIStackView {
func removeAllArrangedSubviews() {
let removedSubviews = arrangedSubviews.reduce([]) { (allSubviews, subview) -> [UIView] in
self.removeArrangedSubview(subview)
return allSubviews + [subview]
}
// Deactivate all constraints
NSLayoutConstraint.deactivate(removedSubviews.flatMap({ $0.constraints }))
// Remove the views from self
removedSubviews.forEach({ $0.removeFromSuperview() })
}
}
I'm trying to find my UILabels in my superview of my UIViewControllers.
This is my code:
func watch(startTime:String, endTime:String) {
if superview == nil {println("NightWatcher: No viewcontroller specified");return}
listSubviewsOfView(self.superview!)
}
func listSubviewsOfView(view: UIView) {
var subviews = view.subviews
if (subviews.count == 0) { return }
view.backgroundColor = UIColor.blackColor()
for subview in subviews {
if subview.isKindOfClass(UILabel) {
// do something with label..
}
self.listSubviewsOfView(subview as UIView)
}
}
This is how it is recommended to in Objective-C, but in Swift I get nothing but UIViews and CALayer. I definitely have UILabels in the view that is supplied to this method. What am I missing?
The call in my UIViewController:
NightWatcher(view: self.view).watch("21:00", endTime: "08:30") // still working on
Here's a version that will return an Array of all the UILabel views in whatever view you pass in:
func getLabelsInView(view: UIView) -> [UILabel] {
var results = [UILabel]()
for subview in view.subviews as [UIView] {
if let labelView = subview as? UILabel {
results += [labelView]
} else {
results += getLabelsInView(view: subview)
}
}
return results
}
Then you can iterate over them to do whatever you'd like:
override func viewDidLoad() {
super.viewDidLoad()
let labels = getLabelsInView(self.view)
for label in labels {
println(label.text)
}
}
Using functional programming concepts you can achieve this much easier.
let labels = self.view.subviews.flatMap { $0 as? UILabel }
for label in labels {
//Do something with label
}
Swift 4
Adepting mKane's answer you can use this code:
let labels = self.view.subviews.compactMap { $0 as? UILabel }
for label in labels {
// do whatever
}
You could set a tag to your UILabel in the Storyboard or programmatically using:
myLabel.tag = 1234
Then, to find it use:
let myLabel = view.viewWithTag(1234)
I have a UIView which is placed on the screen via several constraints. Some of the constraints are owned by the superview, others are owned by other ancestors (e.g. perhaps the view property of a UIViewController).
I want to remove all of these old constraints, and place it somewhere new using new constraints.
How can I do this without creating an IBOutlet for every single constraint and having to remember which view owns said constraint?
To elaborate, the naive approach would be to create a bunch of IBOutlets for each of the constraints, and would then involve calling code such as:
[viewA removeConstraint:self.myViewsLeftConstraint];
[viewB removeConstraint:self.myViewsTopConstraint];
[viewB removeConstraint:self.myViewsBottomConstraint];
[self.view removeConstraint:self.myViewsRightConstraint];
The problem with this code is that even in the simplest case, I would need to create 2 IBOutlets. For complex layouts, this could easily reach 4 or 8 required IBOutlets. Furthermore, I would need to ensure that my call to remove the constraint is being called on the proper view. For example, imagine that myViewsLeftConstraint is owned by viewA. If I were to accidentally call [self.view removeConstraint:self.myViewsLeftConstraint], nothing would happen.
Note: The method constraintsAffectingLayoutForAxis looks promising, but is intended for debugging purposes only.
Update: Many of the answers I am receiving deal with self.constraints, self.superview.constraints, or some variant of those. These solutions won't work since those methods return only the constraints owned by the view, not the ones affecting the view.
To clarify the problem with these solutions, consider this view hierarchy:
Grandfather
Father
Me
Son
Daughter
Brother
Uncle
Now imagine we create the following constraints, and always attach them to their nearest common ancestor:
C0: Me: same top as Son (owned by Me)
C1: Me: width = 100 (owned by Me)
C2: Me: same height as Brother (owned by Father)
C3: Me: same top as Uncle (owned by Grandfather)
C4: Me: same left as Grandfather (owned by Grandfather)
C5: Brother: same left as Father (owned by Father)
C6: Uncle: same left as Grandfather (owned by Grandfather)
C7: Son: same left as Daughter (owned by Me)
Now imagine we want to remove all constraints affecting Me. Any proper solution should remove [C0,C1,C2,C3,C4] and nothing else.
If I use self.constraints (where self is Me), I will get [C0,C1,C7], since those are the only constraints owned by Me. Obviously it wouldn't be enough to remove this since it is missing [C2,C3,C4]. Furthermore, it is removing C7 unnecessarily.
If I use self.superview.constraints (where self is Me), I will get [C2,C5], since those are the constraints owned by Father. Obviously we cannot remove all these since C5 is completely unrelated to Me.
If I use grandfather.constraints, I will get [C3,C4,C6]. Again, we cannot remove all of these since C6 should remain intact.
The brute force approach is to loop over each of the view's ancestors (including itself), and seeing if firstItem or secondItem are the view itself; if so, remove that constraint. This will lead to a correct solution, returning [C0,C1,C2,C3,C4], and only those constraints.
However, I'm hoping there is a more elegant solution than having to loop through the entire list of ancestors.
This approach worked for me:
#interface UIView (RemoveConstraints)
- (void)removeAllConstraints;
#end
#implementation UIView (RemoveConstraints)
- (void)removeAllConstraints
{
UIView *superview = self.superview;
while (superview != nil) {
for (NSLayoutConstraint *c in superview.constraints) {
if (c.firstItem == self || c.secondItem == self) {
[superview removeConstraint:c];
}
}
superview = superview.superview;
}
[self removeConstraints:self.constraints];
self.translatesAutoresizingMaskIntoConstraints = YES;
}
#end
After it's done executing your view remains where it was because it creates autoresizing constraints. When I don't do this the view usually disappears. Additionally, it doesn't just remove constraints from superview but traversing all the way up as there may be constraints affecting it in ancestor views.
Swift 4 Version
extension UIView {
public func removeAllConstraints() {
var _superview = self.superview
while let superview = _superview {
for constraint in superview.constraints {
if let first = constraint.firstItem as? UIView, first == self {
superview.removeConstraint(constraint)
}
if let second = constraint.secondItem as? UIView, second == self {
superview.removeConstraint(constraint)
}
}
_superview = superview.superview
}
self.removeConstraints(self.constraints)
self.translatesAutoresizingMaskIntoConstraints = true
}
}
The only solution I have found so far is to remove the view from its superview:
[view removeFromSuperview]
This looks like it removes all constraints affecting its layout and is ready to be added to a superview and have new constraints attached. However, it will incorrectly remove any subviews from the hierarchy as well, and get rid of [C7] incorrectly.
You can remove all constraints in a view by doing this:
self.removeConstraints(self.constraints)
EDIT: To remove the constraints of all subviews, use the following extension in Swift:
extension UIView {
func clearConstraints() {
for subview in self.subviews {
subview.clearConstraints()
}
self.removeConstraints(self.constraints)
}
}
There are two ways of on how to achieve that according to Apple Developer Documentation
1. NSLayoutConstraint.deactivateConstraints
This is a convenience method that provides an easy way to deactivate a
set of constraints with one call. The effect of this method is the
same as setting the isActive property of each constraint to false.
Typically, using this method is more efficient than deactivating each
constraint individually.
// Declaration
class func deactivate(_ constraints: [NSLayoutConstraint])
// Usage
NSLayoutConstraint.deactivate(yourView.constraints)
2. UIView.removeConstraints (Deprecated for >= iOS 8.0)
When developing for iOS 8.0 or later, use the NSLayoutConstraint
class’s deactivateConstraints: method instead of calling the
removeConstraints: method directly. The deactivateConstraints: method
automatically removes the constraints from the correct views.
// Declaration
func removeConstraints(_ constraints: [NSLayoutConstraint])`
// Usage
yourView.removeConstraints(yourView.constraints)
Tips
Using Storyboards or XIBs can be such a pain at configuring the constraints as mentioned on your scenario, you have to create IBOutlets for each ones you want to remove. Even so, most of the time Interface Builder creates more trouble than it solves.
Therefore when having very dynamic content and different states of the view, I would suggest:
Creating your views programmatically
Layout them and using NSLayoutAnchor
Append each constraint that might get removed later to an array
Clear them every time before applying the new state
Simple Code
private var customConstraints = [NSLayoutConstraint]()
private func activate(constraints: [NSLayoutConstraint]) {
customConstraints.append(contentsOf: constraints)
customConstraints.forEach { $0.isActive = true }
}
private func clearConstraints() {
customConstraints.forEach { $0.isActive = false }
customConstraints.removeAll()
}
private func updateViewState() {
clearConstraints()
let constraints = [
view.leadingAnchor.constraint(equalTo: parentView.leadingAnchor),
view.trailingAnchor.constraint(equalTo: parentView.trailingAnchor),
view.topAnchor.constraint(equalTo: parentView.topAnchor),
view.bottomAnchor.constraint(equalTo: parentView.bottomAnchor)
]
activate(constraints: constraints)
view.layoutIfNeeded()
}
References
NSLayoutConstraint
UIView
In Swift:
import UIKit
extension UIView {
/**
Removes all constrains for this view
*/
func removeConstraints() {
let constraints = self.superview?.constraints.filter{
$0.firstItem as? UIView == self || $0.secondItem as? UIView == self
} ?? []
self.superview?.removeConstraints(constraints)
self.removeConstraints(self.constraints)
}
}
Details
Xcode 10.2.1 (10E1001), Swift 5
Solution
import UIKit
extension UIView {
func removeConstraints() { removeConstraints(constraints) }
func deactivateAllConstraints() { NSLayoutConstraint.deactivate(getAllConstraints()) }
func getAllSubviews() -> [UIView] { return UIView.getAllSubviews(view: self) }
func getAllConstraints() -> [NSLayoutConstraint] {
var subviewsConstraints = getAllSubviews().flatMap { $0.constraints }
if let superview = self.superview {
subviewsConstraints += superview.constraints.compactMap { (constraint) -> NSLayoutConstraint? in
if let view = constraint.firstItem as? UIView, view == self { return constraint }
return nil
}
}
return subviewsConstraints + constraints
}
class func getAllSubviews(view: UIView) -> [UIView] {
return view.subviews.flatMap { [$0] + getAllSubviews(view: $0) }
}
}
Usage
print("constraints: \(view.getAllConstraints().count), subviews: \(view.getAllSubviews().count)")
view.deactivateAllConstraints()
The easier and efficient approach is to remove the view from superView and re add as subview again.
this causes all the subview constraints get removed automagically.😉
Swift
Following UIView Extension will remove all Edge constraints of a view:
extension UIView {
func removeAllConstraints() {
if let _superview = self.superview {
self.removeFromSuperview()
_superview.addSubview(self)
}
}
}
A Swift solution:
extension UIView {
func removeAllConstraints() {
var view: UIView? = self
while let currentView = view {
currentView.removeConstraints(currentView.constraints.filter {
return $0.firstItem as? UIView == self || $0.secondItem as? UIView == self
})
view = view?.superview
}
}
}
It's important to go through all the parents, since the constraints between two elements are holds by the common ancestors, so just clearing the superview as detailed in this answer is not good enough, and you might end up having bad surprise later on.
Based on previous answers (swift 4)
You can use immediateConstraints when you don't want to crawl entire hierarchies.
extension UIView {
/**
* Deactivates immediate constraints that target this view (self + superview)
*/
func deactivateImmediateConstraints(){
NSLayoutConstraint.deactivate(self.immediateConstraints)
}
/**
* Deactivates all constrains that target this view
*/
func deactiveAllConstraints(){
NSLayoutConstraint.deactivate(self.allConstraints)
}
/**
* Gets self.constraints + superview?.constraints for this particular view
*/
var immediateConstraints:[NSLayoutConstraint]{
let constraints = self.superview?.constraints.filter{
$0.firstItem as? UIView === self || $0.secondItem as? UIView === self
} ?? []
return self.constraints + constraints
}
/**
* Crawls up superview hierarchy and gets all constraints that affect this view
*/
var allConstraints:[NSLayoutConstraint] {
var view: UIView? = self
var constraints:[NSLayoutConstraint] = []
while let currentView = view {
constraints += currentView.constraints.filter {
return $0.firstItem as? UIView === self || $0.secondItem as? UIView === self
}
view = view?.superview
}
return constraints
}
}
I use the following method to remove all constraints from a view:
.h file:
+ (void)RemoveContraintsFromView:(UIView*)view
removeParentConstraints:(bool)parent
removeChildConstraints:(bool)child;
.m file:
+ (void)RemoveContraintsFromView:(UIView *)view
removeParentConstraints:(bool)parent
removeChildConstraints:(bool)child
{
if (parent) {
// Remove constraints between view and its parent.
UIView *superview = view.superview;
[view removeFromSuperview];
[superview addSubview:view];
}
if (child) {
// Remove constraints between view and its children.
[view removeConstraints:[view constraints]];
}
}
You can also read this post on my blog to better understand how it works behind the hood.
If you need more granular control, I'd strongly advise switching to Masonry, a powerful framework class you could use whenever you need to properly handle constraints programmatically.
With objectiveC
[self.superview.constraints enumerateObjectsUsingBlock:^(__kindof NSLayoutConstraint * _Nonnull obj, NSUInteger idx, BOOL * _Nonnull stop) {
NSLayoutConstraint *constraint = (NSLayoutConstraint *)obj;
if (constraint.firstItem == self || constraint.secondItem == self) {
[self.superview removeConstraint:constraint];
}
}];
[self removeConstraints:self.constraints];
}
You could use something like this:
[viewA.superview.constraints enumerateObjectsUsingBlock:^(id obj, NSUInteger idx, BOOL *stop) {
NSLayoutConstraint *constraint = (NSLayoutConstraint *)obj;
if (constraint.firstItem == viewA || constraint.secondItem == viewA) {
[viewA.superview removeConstraint:constraint];
}
}];
[viewA removeConstraints:viewA.constraints];
Basically, this is enumerates over all the constraints on the superview of viewA and removes all of the constraints that are related to viewA.
Then, the second part removes the constraints from viewA using the array of viewA's constraints.
(As of July 31, 2017)
SWIFT 3
self.yourCustomView.removeFromSuperview()
self.yourCustomViewParentView.addSubview(self.yourCustomView)
Objective C
[self.yourCustomView removeFromSuperview];
[self.yourCustomViewParentView addSubview:self.yourCustomView];
This is the easiest way to quickly remove all constraints that exist on a UIView. Just be sure to add the UIView back with it's new constraints or new frame afterwards =)
Using a Reusable Sequence
I decided to approach this in a more 'reusable' way. Since finding all constraints affecting a view is the basis for all of the above, I decided to implement a custom sequence that returns them all for me, along with the owning views.
First thing to do is define an extension on Arrays of NSLayoutConstraint that returns all elements affecting a specific view.
public extension Array where Element == NSLayoutConstraint {
func affectingView(_ targetView:UIView) -> [NSLayoutConstraint] {
return self.filter{
if let firstView = $0.firstItem as? UIView,
firstView == targetView {
return true
}
if let secondView = $0.secondItem as? UIView,
secondView == targetView {
return true
}
return false
}
}
}
We then use that extension in a custom sequence that returns all constraints affecting that view, along with the views that actually own them (which can be anywhere up the view hierarchy)
public struct AllConstraintsSequence : Sequence {
public init(view:UIView){
self.view = view
}
public let view:UIView
public func makeIterator() -> Iterator {
return Iterator(view:view)
}
public struct Iterator : IteratorProtocol {
public typealias Element = (constraint:NSLayoutConstraint, owningView:UIView)
init(view:UIView){
targetView = view
currentView = view
currentViewConstraintsAffectingTargetView = currentView.constraints.affectingView(targetView)
}
private let targetView : UIView
private var currentView : UIView
private var currentViewConstraintsAffectingTargetView:[NSLayoutConstraint] = []
private var nextConstraintIndex = 0
mutating public func next() -> Element? {
while(true){
if nextConstraintIndex < currentViewConstraintsAffectingTargetView.count {
defer{nextConstraintIndex += 1}
return (currentViewConstraintsAffectingTargetView[nextConstraintIndex], currentView)
}
nextConstraintIndex = 0
guard let superview = currentView.superview else { return nil }
self.currentView = superview
self.currentViewConstraintsAffectingTargetView = currentView.constraints.affectingView(targetView)
}
}
}
}
Finally we declare an extension on UIView to expose all the constraints affecting it in a simple property that you can access with a simple for-each syntax.
extension UIView {
var constraintsAffectingView:AllConstraintsSequence {
return AllConstraintsSequence(view:self)
}
}
Now we can iterate all constraints affecting a view and do what we want with them...
List their identifiers...
for (constraint, _) in someView.constraintsAffectingView{
print(constraint.identifier ?? "No identifier")
}
Deactivate them...
for (constraint, _) in someView.constraintsAffectingView{
constraint.isActive = false
}
Or remove them entirely...
for (constraint, owningView) in someView.constraintsAffectingView{
owningView.removeConstraints([constraint])
}
Enjoy!
This is the way to disable all constraints from a specific view
NSLayoutConstraint.deactivate(myView.constraints)