I have to select the value of v1 which has match as V0 and (Need to make a 13 digit number , also remove the decimal point)
I am getting NaN.
Please guide.
XSLT:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema" >
<xsl:output method="text" encoding="utf-8" />
<xsl:output omit-xml-declaration="yes" />
<xsl:param name="break" select="'
'" />
<xsl:template match="A">
<xsl:value-of select="format-number(B[match = V0]/v1 * 100,'0000000000000')"/>
</xsl:template>
INPUT:
<A>
<B>
<match>V0</match>
<v1>34.56</v1>
</B>
<B>
<match>V1</match>
<v1>34.54</v1>
</B>
Expected - 0000000003456
Actual - NaN
Just change
<xsl:value-of select="format-number(B[match = V0]/v1 * 100,'0000000000000')"/>
to
<xsl:value-of select="format-number(B[match = 'V0']/v1 * 100,'0000000000000')"/>
And the rest will follow.
Output is:
000000003456
You forgot to put your element value into single quotes.
Related
We have a requirement in which need to convert XML into Fixed Length File. First record is as header and after that we have actual records..From 2 record onwards we need to apply the logic which is mentioned below:
After length 45, consider 10 numbers 0000001000, what ever be the last digit we need to check and replace by following the below table.
Same logic we need to repeat at position 59th to 74th.
77th to 80th we need to get the value 5152 and store into one variable
I had asked the question with 1st logic and got the awesome response, now I am left with 2nd and 3rd logic
For Positive: (0000001000) - (000000100{)
{= 0
A = 1
B = 2
c = 3
D = 4
E = 5
F = 6
G = 7
H = 8
I = 9
Request anyone to help me to achieve the same, I have mentioned the XSLT which I got from previous answers.Thanks
Input:
<ZR>
<INPUT>
<I_FIL>ERES</I_FIL>
</INPUT>
<TABLES>
<T_ER>
<item>
<DATA> HEADER1111111122222222333333344456</DATA>
</item>
<item>
<DATA>778944 D4E2 EA 1234567891 2018-11-060000001000EA 0000000000000100005152D04YA30TRE0000000XXXYYY 800{ Q 2018-11-05</DATA>
</item>
<item>
<DATA>987654 D4E2 EA 1987654321 2018-11-060000002001EA 0000000000000100005152D04YA30UUU0000000XXXLRB 100{ Q 2018-11-05</DATA>
</item>
.
.
.
.
.
.
.
.
<item>
<DATA>12345678912345678934562754378909726533297TRAILER</DATA>
</item>
</T_ER>
</TABLES>
</ZR>
XSLT:
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:fn="http://www.w3.org/2005/xpath-functions">
<xsl:output omit-xml-declaration="yes" />
<xsl:param name="break" select="'
'" />
<xsl:template match="/">
<xsl:value-of select="ZR/TABLES/T_ER/item[1]/DATA" />
<xsl:value-of select="$break" />
<xsl:for-each select="ZR/TABLES/T_ER/item[position() != 1]">
<xsl:variable name="length" select="string-length(substring(DATA,0,46))" />
<xsl:variable name="tenNumbers" select="substring(DATA, ($length + 1),
10)"/>
<xsl:variable name="charToReplace" select="translate(substring($tenNumbers, string-length($tenNumbers), 1),'0123456789','{ABCDEFGHI')" />
<xsl:value-of select="concat(substring(DATA,0,46), substring(DATA, ($length + 1), 9), $charToReplace, substring(DATA,($length+11),(string-length(DATA) + 1)))"/>
<xsl:value-of select="$break" />
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
OR
<xsl:template match="/">
<xsl:value-of select="
ZR/TABLES/T_ER/item[1]/DATA,
ZR/TABLES/T_ER/item[position() > 1]/DATA/concat(
substring(., 1, 54),
substring('{ABCDEFGHI', number(substring(., 55, 1)) + 1, 1),
substring(., 56)
)" separator="
" />
</xsl:template>
Expected Output:
HEADER1111111122222222333333344456
778944 D4E2 EA 1234567891 2018-11-06000000100{EA
000000000000010{005152D04YA30TRE0000000XXXYYY 800{ Q 2018-11-05
987654 D4E2 EA 1987654321 2018-11-06000000200AEA
000000000000010{005152D04YA30UUU0000000XXXLRB 100{ Q 2018-11-05
.
.
.
.
12345678912345678934562754378909726533297TRAILER
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:fn="http://www.w3.org/2005/xpath-functions">
<xsl:output omit-xml-declaration="yes" />
<xsl:param name="break" select="'
'" />
<xsl:template match="/">
<xsl:value-of select="ZR/TABLES/T_ER/item[1]/DATA" />
<xsl:value-of select="$break" />
<xsl:for-each select="ZR/TABLES/T_ER/item[position() != 1]">
<xsl:variable name="length" select="string-length(substring(DATA,0,46))" />
<xsl:variable name="tenNumbers" select="substring(DATA, ($length + 1), 10)" />
<xsl:variable name="sixteenNumbers" select="substring(DATA, (string-length(substring(DATA,0,59)) + 1), 16)" />
<xsl:variable name="firstCharToReplace" select="translate(substring($tenNumbers, string-length($tenNumbers), 1),'0123456789','{ABCDEFGHI')" />
<xsl:variable name="secondCharToReplace" select="translate(substring($sixteenNumbers, string-length($sixteenNumbers), 1),'0123456789','{ABCDEFGHI')" />
<xsl:choose>
<xsl:when test="string-length($tenNumbers) != 10">
<xsl:value-of select="concat(substring(DATA,0,46), substring(DATA, ($length + 1), 9))" />
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="concat(substring(DATA,0,46),
substring(DATA, ($length + 1), 9),
$firstCharToReplace,
substring(DATA,($length+11), 18),
$secondCharToReplace,
substring(DATA,($length+30),(string-length(DATA) + 1)))" />
</xsl:otherwise>
</xsl:choose>
<xsl:value-of select="$break" />
<xsl:variable name="temp" select="substring(DATA,77,4)" />
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
It depends on what condition you want to replace the char.
If it is based on after EA (as per comment) the solution would be different.
For now, I have implemented it solely length based with both points 2 & 3 covered.
http://xsltfiddle.liberty-development.net/6r5Gh38/1
EDIT:
http://xsltfiddle.liberty-development.net/6r5Gh38/2
EDIT 2:
Brief about the points mentioned in comment:
1. <xsl:when test="string-length($tenNumbers) != 10"> This condition is added to remove that extra R appearing for last <item> .
It means if the 10 numbers we are taking in variable is actually having 10 numbers or not.
In the last case,
<item>
<DATA>12345678912345678934562754378909726533297TRAILER</DATA>
</item>
We don't get 10 numbers after 46th character. We get less than that. That's the reason the output has been separated out for two different cases.
2. substring(DATA,0,46) --> which will take first 45 characters to match 778944 D4E2 EA 1234567891 2018-11-06
substring(DATA, ($length + 1), 9) --> which will take 9 characters from index 46th to match 000000100
$firstCharToReplace --> This will replace 10th character as your requirement of 1st question i.e. {
substring(DATA,($length+11), 18) --> It will start remaining string from index (45+11)th to 18 characters that matches EA 000000000000010
$secondCharToReplace --> This will replace (45+11+18)= 74th character as your requirement of 2nd question i.e. {
substring(DATA,($length+30),(string-length(DATA) + 1)) --> It starts from (45+30)= 75th character to last index and gives 005152D04YA30TRE0000000XXXYYY 800{ Q 2018-11-05
Note: In your case, there are extra tabs and white-spaces exist in between the string. That's why the index number has been changed to match your expected output.
I would like to check if given comma separated value is ascending numeric sequence.
Input XML:
<?xml version="1.0" encoding="UTF-8"?>
<root>
<isSequence>
<seq name="a" value="1, 2, 3"/>
<seq name="b" value="3, 1, 5, 6"/>
<seq name="c" value="15, 16, 18, 0"/>
<seq name="d" value="21, 22, 23, 24, 25"/>
<seq name="e" value="A, B, C"/>
</isSequence>
</root>
I have tried below code
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="xs"
version="2.0">
<xsl:template match="/">
<xsl:for-each select="root/isSequence/seq">
<xsl:if test="subsequence(#value, 0)">
<xsl:value-of select="#name"/> is an ascending numeric sequence
</xsl:if>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
Expected Result
a is an ascending numeric sequence
d is an ascending numeric sequence
Assuming you are looking for an integer sequence then I think (in XSLT 3) this can be expressed as
<xsl:template match="seq[let $items := tokenize(#value, ',\s+')!xs:integer(.) return every $p in 1 to count($items) satisfies $items[$p] = $items[1] + ($p - 1)]">
<xsl:value-of select="#name"/><xsl:text> is an ascending numeric sequence
</xsl:text>
</xsl:template>
Full example (https://xsltfiddle.liberty-development.net/6r5Gh2H)
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="#all"
expand-text="yes"
version="3.0">
<xsl:mode on-no-match="shallow-skip"/>
<xsl:strip-space elements="*"/>
<xsl:output method="text"/>
<xsl:template match="seq[let $items := tokenize(#value, ',\s+')!xs:integer(.) return every $p in 1 to count($items) satisfies $items[$p] = $items[1] + ($p - 1)]">
<xsl:value-of select="#name"/><xsl:text> is an ascending numeric sequence
</xsl:text>
</xsl:template>
</xsl:stylesheet>
In XSLT 2 with XPath 2 I don't think you have let to express that compactly in a match pattern but you can of course use a variable at XSLT level:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="#all"
version="2.0">
<xsl:strip-space elements="*"/>
<xsl:output method="text"/>
<xsl:template match="seq[every $i in tokenize(#value, ',\s+') satisfies $i castable as xs:integer]">
<xsl:variable name="items" select="for $item in tokenize(#value, ',\s+') return xs:integer($item)"/>
<xsl:if test="every $p in 1 to count($items) satisfies $items[$p] = $items[1] + ($p - 1)">
<xsl:value-of select="#name"/><xsl:text> is an ascending numeric sequence
</xsl:text>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
http://xsltransform.hikmatu.com/bFDb2BU
My requirement is to concatenate values coming at run time in the ref element. I could get separate values for each element and the concatenate it but still i will miss out text in between.
I have edited my questions as per suggestion made by Martin.
Here is my input XML:
<?xml version="1.0" encoding="UTF-8"?><rootelement>
<nref ref="f1"/> <nref ref="f2"/> <nref ref="f3"/>
<nref ref="f4"/> <nref ref="f5"/>
<pnotes>
<pnote id="f1">
<p>Some Text.</p>
</pnote>
<pnote id="f2">
<p><ref><year>1812</year>, <vol>3</vol><series>F. &
F.</series><pages>22</pages></ref>, at p. 27.</p>
</pnote>
<pnote id="f3">
<p><ref>[<year>1914</year>],
<vol>2</vol><series>A.B.C.</series><pages>94</pages></ref>.</p>
</pnote>
<pnote id="f4">
<p><ref><year>1955</year>,
<vol>2</vol><series>A.B.C</series><pages>509</pages></ref>.</p>
</pnote>
<pnote id="f5">
<p><ref>[<year>1805</year>], <series>A.C.</series><pages>21</pages> </ref>.</p>
</pnote>
</pnotes></rootelement>
I have tried following XSLT
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="xs"
version="2.0">
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="nref">
<xsl:variable name="ref" select="#ref"/>
<noteref>
<xsl:for-each select="//pnotes/pnote">
<xsl:if test="#id = $ref">
<xsl:value-of select="."/>
</xsl:if>
</xsl:for-each>
</noteref>
</xsl:template>
<xsl:template match="//pnotes[not(pnotes)]"/>
</xsl:stylesheet>
The result i get is not correct.
I need spaces in between the text.
Result :
<?xml version="1.0" encoding="UTF-8"?>
<rootelement>
<noteref> Some Text. </noteref>
<noteref> 1812, 3F. & F.22, at p. 27. </noteref>
<noteref> [1914], 2A.B.C.94. </noteref>
<noteref> 1955, 2A.B.C509. </noteref>
<noteref> [1805], A.C.21. </noteref>
</rootelement>
Required Result is:
<?xml version="1.0" encoding="UTF-8"?>
<rootelement>
<noteref> Some Text. </noteref>
<noteref> 1812, 3 F. & F. 22, at p. 27. </noteref>
<noteref> [1914], 2 A.B.C. 94. </noteref>
<noteref> 1955, 2 A.B.C 509. </noteref>
<noteref> [1805], A.C.21. </noteref>
</rootelement>
Can somebody help me please? Thanks in advance.
You are iterating over elemnts and anyone of them have square brackets:
When you make your first iteration, you get the element <year> and its value is 1902, not [1902]. Your square brackets are in the element <noteref>.
Change your XML to store the year as [1902] or change your for-each to print the square brackets manually.
Simply output the string value of the element to get all text, if you don't want the line breaks the also normalize the string:
<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="ref">
<noteref>
<xsl:value-of select="normalize-space()"/>
</noteref>
</xsl:template>
</xsl:transform>
Result is
<rootelement>
<pnote>
<P>
<noteref>[1902], A.C. 12</noteref>.</P>
</pnote>
<pnote>
<P>
<noteref>1902 B.A. 98</noteref>.</P>
</pnote>
<pnote>
<P> This is a text </P>
</pnote>
<pnote>
<P>
<noteref>[1912], 1 R.B. 160</noteref>, at pp. 165, 169.</P>
</pnote>
</rootelement>
Online at http://xsltransform.hikmatu.com/b4GWV2.
I think I'm missing something simple here. I have a source XML file
<Inventory Division="B" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<StackGroup name="Warehouse">
<Stack>
<Mainstack name="PRIMARY">
<MainstackGroup name="GROUP_PRIMARY">
<MainstackLayer sequence="1">
<StackLayerRef id="LAYER_1"/>
</MainstackLayer>
</MainstackGroup>
</Mainstack>
<Mainstack name="SECONDARY">
<MainstackGroup name="GROUP_SECONDARY">
<MainstackLayer sequence="2">
<StackLayerRef id="LAYER_2"/>
</MainstackLayer>
</MainstackGroup>
</Mainstack>
</Stack>
</StackGroup>
</Inventory>
I'm applying a stylesheet:
<?xml version="1.0" encoding="iso-8859-1"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="/">
<Mainstack>
<NumberOfStacks>
<xsl:value-of select="count(/Inventory/StackGroup/Stack/Mainstack)"/>
</NumberOfStacks>
<StackDisplayOrder>
<xsl:apply-templates select="/Inventory/StackGroup/Stack/Mainstack" mode="order"/>
</StackDisplayOrder>
<xsl:apply-templates select="/Inventory/StackGroup/Stack/Mainstack" mode="stacklist"/>
</Mainstack>
</xsl:template>
<xsl:template match="/Inventory/StackGroup/Stack/Mainstack" mode="order">
<Index><xsl:value-of select="position() - 1" /></Index>
</xsl:template>
<xsl:template match="/Inventory/StackGroup/Stack/Mainstack" mode="stacklist">
<Stack>
<Index><xsl:value-of select="position() - 1" /></Index>
<Name>
<xsl:value-of select="/Inventory/StackGroup/Stack/Mainstack/#name"/>
</Name>
<GroupName>
<xsl:value-of select="/Inventory/StackGroup/Stack/Mainstack/MainstackGroup/#name"/>
</GroupName>
<SequenceNo>
<xsl:value-of select="/Inventory/StackGroup/Stack/Mainstack/MainstackGroup/MainstackLayer/#sequence"/>
</SequenceNo>
<LayerNo>
<xsl:value-of select="/Inventory/StackGroup/Stack/Mainstack/MainstackGroup/MainstackLayer/StackLayerRef/#id"/>
</LayerNo>
</Stack>
</xsl:template>
</xsl:stylesheet>
I get the following output:
<?xml version="1.0" encoding="UTF-8"?>
<Mainstack>
<NumberOfStacks>2</NumberOfStacks>
<StackDisplayOrder>
<Index>0</I`enter code here`ndex>
<Index>1</Index>
</StackDisplayOrder>
<Stack>
<Index>0</Index>
<Name>PRIMARY SECONDARY</Name>
<GroupName>GROUP_PRIMARY GROUP_SECONDARY</GroupName>
<SequenceNo>1 2</SequenceNo>
<LayerNo>LAYER_1 LAYER_2</LayerNo>
</Stack>
<Stack>
<Index>1</Index>
<Name>PRIMARY SECONDARY</Name>
<GroupName>GROUP_PRIMARY GROUP_SECONDARY</GroupName>
<SequenceNo>1 2</SequenceNo>
<LayerNo>LAYER_1 LAYER_2</LayerNo>
</Stack>
</Mainstack>
The template obviously finds two matches and concatenates the data from both. How can I separate them?
Thanks in advance!
Use relative paths so change e.g.
<Name>
<xsl:value-of select="/Inventory/StackGroup/Stack/Mainstack/#name"/>
</Name>
to
<Name>
<xsl:value-of select="#name"/>
</Name>
and so on for all the paths in the template.
I have a list of node ids. I want to append "-Selected" to all the text nodes within the given set of node ids. Please let me know how we can achieve the same using XSL?
Input:
<node1 id="a">
<node2 id="b">
<node3 id="c">Text node0</node3>
<node4 id="d">
<node5 id="e">Text node1</node5>
<node6 id="f">Text node2</node6>
</node4>
</node2>
<node7 id="g">Text node3
<node8 id="h" align="center">Text node4</node8>
<node9 id="i">Text node5</node9>
</node7>
<node10 id="j">Text node6
</node10>
<node11 id="h">Text node7
</node11>
</node1>
Input Param: List of node ids
<nodes>
<node>b</node>
<node>g</node>
<node>h</node>
</nodes>
If the input param has node 'a' then i need all the text nodes to be appended with selected.
Expected output:
<node1 id="a">
<node2 id="b">
<node3 id="c">Text node0 - Selected<node3/>
<node4 id="d">
<node5 id="e">Text node1 - Selected</node5>
<node6 id="f">Text node2 - Selected</node6>
</node4>
</node2>
<node7 id="g">Text node3 - Selected
<node8 id="h" align="center">Text node4 - Selected</node8>
<node9 id="i">Text node5 - Selected</node9>
</node7>
<node10 id="j">Text node6
</node10>
<node11 id="h">Text node7 - Selected
</node11>
</node1>
This transformation:
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
>
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:param name="pNodes">
<nodes>
<node>b</node>
<node>g</node>
<node>h</node>
</nodes>
</xsl:param>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="*[#id = $pNodes/*/*]//text()">
<xsl:value-of select="concat(., ' Selected')"/>
</xsl:template>
</xsl:stylesheet>
when applied on the provided XML Document, produces the wanted, correct result.
This XSLT 2.0 stylesheet:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:param name="pNodes">
<nodes>
<node>b</node>
<node>g</node>
<node>h</node>
</nodes>
</xsl:param>
<xsl:template match="text()" >
<xsl:value-of select="." />
<xsl:if test="ancestor::*[#id = $pNodes/*/*] and normalize-space()!=''">
<xsl:text> - Selected</xsl:text>
</xsl:if>
</xsl:template>
<xsl:template match="#* | * | comment() | processing-instruction()">
<xsl:copy>
<xsl:apply-templates select="#* | node()" />
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Uses a modified identity transform. The template match on text() has an if statement that evaluates whether the text node is a descendant of an element with an #id who's value matches one of the specified nodes, and that the text node is not all whitespace(you can adjust that as necessary, but otherwise). If it meets those criteria, it outputs " - selected".
Applied to the sample input it produces this output:
<?xml version="1.0" encoding="UTF-8"?><node1 id="a">
<node2 id="b">
<node3 id="c"/>
<node4 id="d">
<node5 id="e">Text node1 - Selected</node5>
<node6 id="f">Text node2 - Selected</node6>
</node4>
</node2>
<node7 id="g">Text node3
- Selected<node8 id="h" align="center">Text node4 - Selected</node8>
<node9 id="i">Text node5 - Selected</node9>
</node7>
<node10 id="j">Text node6
</node10>
<node11 id="h">Text node7
- Selected</node11>
</node1>