How can I \label \subsection in \intertext inside flalign? (LATEX) - latex

I have one flalign environment, so columns are aligned same way whole page. I need \subsections inside this flalign, so I used \intertext. And I need \label these \subsections. And thats where I failed. It \label first equation after \subsection but not \subsection itself or error occurs.
Image:
When I tried to use more flalign environments and place subsections between them they were not aligned same way and it looked terible.
Thanks for help.
\begin{flalign}
&\text{Značení: } &&X\sim \text{Exp($\lambda$)} &&
\\
&\text{Parametry: } &&\lambda > 0 &&
\\
&\text{Nosič: } &&X \in (0,\infty) &&
\\
&\text{Hustota: } &&f(x)=
\begin{cases}
\lambda e^{-\lambda x} & x>0
\\
0 & x\leq 0
\end{cases}
\\
&\text{Distribuční funkce: } &&F(x)=
\begin{cases}
1-e^{-\lambda x} & x>0
\\
0 & x\leq 0
\end{cases} &&
\\
&\text{Střední hodnota: } && \E X = \frac{1}{\lambda} &&
\\
&\text{Rozptyl: } && \var X = \frac{1}{\lambda^2} &&
\\
\intertext{\subsection{Weibullovo rozdělení}}\label{priloha:weibdist}
&\text{Značení: } &&X\sim \text{Weib($\alpha$, $\beta$)}&&
\\
&\text{Parametry: } &&\text{$\alpha$, $\beta>0$}&&
\\
&\text{Nosič: } &&X \in \langle 0,\infty)&&
\\
&\text{Hustota: } &&f(x)=
\begin{cases}
\alpha \beta^\alpha x^{\alpha-1} e^{-(\beta x)^\alpha} & x\geq 0
\\
0 & x< 0
\end{cases}&&
\\
&\text{Distribuční funkce: } &&F(x)=
\begin{cases}
1-e^{-(\beta x)^\alpha} & x\geq 0
\\
0 & x< 0
\end{cases}
\\
&\text{Střední hodnota: } &&\E X = \frac{1}{\beta} \Gamma\left(1+\frac{1}{\alpha}\right)
\\
&\text{Rozptyl: } &&\var X = \frac{1}{\beta^2} \left\lbrace\Gamma \left(1+\frac{2}{\alpha}\right)-\left[\Gamma\left(1+\frac{1}{\alpha}\right)\right]^2\right\rbrace
\\
\intertext{\subsection{Gama rozdělení}}\label{priloha:gammadist}
&\text{Značení: } &&X\sim \Gamma(\alpha,\;\beta)&&
\\
&\text{Parametry: } &&\alpha,\; \beta > 0
\\
&\text{Nosič: } &&X \in (0,\infty)
\\
&\text{Hustota: } &&f(x)=
\begin{cases}
\frac{\alpha^\beta}{\Gamma(\beta)}x^{\beta-1}e^{-\alpha x} & x>0
\\
0 & x\leq 0
\end{cases}
\\
&\text{Střední hodnota: } && \E X = \frac{\beta}{\alpha}
\\
&\text{Rozptyl: } && \var X = \frac{\beta}{\alpha^2}
\end{flalign}

From the images you show, I would suggest to use a tabular with a fixed width instead. This will allow you to break for things like subsections:
\documentclass[12pt,fleqn]{article}
\usepackage{amsmath}
\usepackage{array}
\begin{document}
\subsection{First part}
\noindent%
{%
\abovedisplayskip=-\baselineskip
\belowdisplayskip=-.5\baselineskip
\begin{tabular}{#{}p{.3\textwidth}#{}p{.7\textwidth}#{}}
First equation: & \begin{equation} a+b+c=d \end{equation}\\
Second equation: & \begin{equation} a+b+c=d \end{equation}\\
\end{tabular}
}
\subsection{Second part}
\label{sub:1}
\noindent%
{%
\abovedisplayskip=-\baselineskip
\belowdisplayskip=-.5\baselineskip
\begin{tabular}{#{}m{.3\textwidth}#{}m{.7\textwidth}#{}}
Next equation: & \begin{equation} a+b+c+45867+ddlk=d \end{equation}\\
Another equation: & \begin{equation} a+b+c+sdfsdf+565=d \end{equation}\\
\end{tabular}
}
Here alignment is working, but labeling not. Second part is \ref{sub:1}. It referes to 3th equation instead of subsection.
\end{document}

Related

What's the meaning of "double superscript" in overleaf?

I wrote a wrapped equation in overleaf:
\begin{equation}
\begin{aligned}
\y & = \argmin_{\y'} \sum_{i,j}\W_{ij}||\y'_i - \y'_j||_2^2 \\
& = \argmin_{\y'} \sum_{i,j}(\y'_i - \y'_j)^2\W_{ij} \\
& = \argmin_{\y'} \sum_{i,j}(\y'_i^2 + \y'_j^2 - 2\y'_i\y'_j)\W_{ij} \\
& = \argmin_{\y'} \sum_{i,j}\y'_i^2\W_{ij} + \sum_{i,j}\y'_j^2\W_{ij} - 2\sum_{i,j}\y'_i\y'_j\W_{ij} \\ & = \argmin_{\y'} \sum_{i}\y'_i^2D_{ii} + \sum_{j}\y'_j^2D_{jj} - 2\sum_{i,j}\y'_i\y'_j\W_{ij} \\ & = \argmin_{\y'} 2 (\sum_{i}\y'_i^2D_{ii} - \sum_{i,j}\y'_i\y'_j\W_{ij}) \\
& = \argmin_{\y'} 2 {\y'}^\top \L{\y'} \\
\end{aligned}
\end{equation}
The overleaf shows that there are three "double superscript" error in this code, what is that and how can I fix this (although I can compile it successfully)?
I expect to find the solution to this problem.
A double sub-/superscript error occurs when you have more than one sub-/superscript associated with an element. An example is $x^2^2$ which can be interpreted in two ways: ${x^2}^2$ or $x^{2^2}$. Mathematically they mean the same, but from a typesetting point of view they are interpreted differently:
The first - ${x^2}^2$ - sets both exponents in \scriptstyle (so they're the same size) while the second sets the exponents in staggering (reducing) sizes (first one uses \scriptstyle while the second uses \scriptscriptstyle). This difference in typesetting is rather pushed to the user to fix to avoid confusion or misinterpreting what the result should look like. A similar concept holds for subscripts (like $x_2_2$) and combinations of scripts (like `$x_2^2_2$).
What is hidden in your is the use of a prime (like $y'$) which is similar to $y^\prime$:
$x' = x^\prime \neq x\prime$
As such, $y'^2$ is similar to $y^\prime^2$ which is interpreted as a double superscript, causing the error you see.
The way around it is to appropriately group the elements to denote the way you want it represented in output. In your case, this is most likely ${y'}^2$. I've done that below, with some adjustments to other elements:
\documentclass{article}
\usepackage{mathtools}
% https://tex.stackexchange.com/q/5223/5764
\DeclareMathOperator*{\argmax}{arg\,max}
\DeclareMathOperator*{\argmin}{arg\,min}
\DeclarePairedDelimiter{\norm}{\|}{\|}
\newcommand{\y}{\mathcal{Y}}
\newcommand{\W}{\mathcal{W}}
\begin{document}
\begin{equation}
\begin{aligned}
\y & = \argmin_{\y'} \sum_{i, j} \W_{ij} \norm[\big]{ \y'_i - \y'_j }_2^2 \\
& = \argmin_{\y'} \sum_{i, j} \bigl(\y'_i - \y'_j \bigr)^2 \W_{ij} \\
& = \argmin_{\y'} \sum_{i, j} \bigl( {\y'}_i^2 + {\y'}_j^2 - 2 \y'_i \y'_j \bigr) \W_{ij} \\
& = \argmin_{\y'} \sum_{i, j}{\y'}_i^2 \W_{ij} + \sum_{i, j} {\y'}_j^2 \W_{ij} - 2\sum_{i, j} \y'_i \y'_j \W_{ij} \\
& = \argmin_{\y'} \sum_i {\y'}_i^2 D_{ii} + \sum_j {\y'}_j^2 D_{jj} - 2 \sum_{i, j} \y'_i \y'_j \W_{ij} \\
& = \argmin_{\y'} 2 \biggl( \sum_i {\y'}_i^2 D_{ii} - \sum_{i, j} \y'_i \y'_j \W_{ij} \biggr) \\
& = \argmin_{\y'} 2 {\y'}^\top \L \y'
\end{aligned}
\end{equation}
\end{document}

Line cut in \tabularx{}

I have a code below. I would like to remove the white space before the highlighted part.
\documentclass[10pt,english,8pt]{beamer}
\usetheme{default}
\usepackage{booktabs}
\usepackage{tabularx}
%\newcommand{\iid}{\stackrel{\mathrm{iid}}{\sim}}
\newcolumntype{C}{>{\centering\arraybackslash}X}
\newcolumntype{R}{>{\raggedright\arraybackslash}X}
\newcolumntype{L}{>{\raggedleft\arraybackslash}X}
\title{Beamer Template}
\author{TeXstudio Team}
\begin{document}
\begin{frame}{Frame Title}
\begin{table}[htbp]
%\begin{table}[!ht]
\centering
\scriptsize
%\caption{Title }
\label{tab:5}
\begin{tabularx}{1\textwidth}
{>{\raggedright\arraybackslash}p{2cm}
>{\centering\arraybackslash}p{1.75cm}
>{\centering\arraybackslash}p{1.75cm}
>{\centering\arraybackslash}p{1.75cm}
>{\centering\arraybackslash}p{1.75cm}
}
%\multicolumn{11}{#{}p{1\textwidth}#{}}{\footnotesize
% Caption }\\
\toprule
& Log Probability of Default & Log Recovery Rate
& Log Spread & Log Leverage \\ [0.5ex]
& (1) & (2) & (3) & (4) \\
\midrule
Log Damage
&0.017** &-0.003*** & 0.002 & -0.157 \\
&(0.0008) &(0.003) & (0.075) & (0.178) \\
Log Adaptation
&-0.157*** &0.012 &-0.463** & 0.514*** \\
&(0.021) &(0.007) &(0.182) &(0.193)\\
Log Damage X Log Adaptation
&0.006 &0.018* &-0.398 &0.535 \\
&(0.030) &(0.011) &(0.249) &(0.513)\\
Constant
&-1.227***&-0.117***&2.244***&0.101\\
&(0.026)&(0.009)&(0.187)&(0.237)\\
\midrule
Observations &926 &925 &458 &177 \\
$R^2$ &41\% &19\% &8\% &38\%\\
Adjusted $R^2$ &40\%&17\%&4\%&32\%\\
Residual Std. Error
& 0.071 & 0.025 & 0.373 & 0.264 \\
& (df = 907) & (df = 906) & (df = 439) & (df = 159)\\
F Statistic
& 35.253*** & 11.455*** & 2.104***  & 5.811***  \\
& (df = 18; 907)& (df = 18; 906)& (df = 18; 439)& (df = 17; 159)\\
\bottomrule
\addlinespace
\multicolumn{4}{#{}p{0.8\textwidth}#{}}{\footnotesize \tiny{Note: *p<0.1; **p<0.05; ***p<0.01 }} \\
\end{tabularx}
%\end{table}
\end{table}
\end{frame}
\end{document}
Log Damage X Log Adaptation is too long to fit into a single cell. The easiest fix is to manually move the second part of the phrase into the next line.
If you are using a tabularx, you should use at least one X column to make sure the table can adapt to the available space
I would use #{} in front and after the other columns to get rid of the extra space
To make reading the table easier, I would add some additional vertical space between the blocks
Are you abusing the poor X as multiplication sign? Don't!
the syntax \tiny{...} is wrong. It is a switch and does not take an argument. Use {\tiny ...} instead.
Missing math mode around the < signs
most of your table should be in math mode to get correct minus sign and proper spacing around operators, but I'm too lazy to add this in the example below...
\documentclass[10pt,english,8pt]{beamer}
\usetheme{default}
\usepackage{booktabs}
\usepackage{tabularx}
%\newcommand{\iid}{\stackrel{\mathrm{iid}}{\sim}}
\newcolumntype{C}{>{\centering\arraybackslash}X}
\newcolumntype{R}{>{\raggedright\arraybackslash}X}
\newcolumntype{L}{>{\raggedleft\arraybackslash}X}
\title{Beamer Template}
\author{TeXstudio Team}
\begin{document}
\begin{frame}{Frame Title}
\begin{table}[htbp]
%\begin{table}[!ht]
\centering
\scriptsize
%\caption{Title }
\label{tab:5}
\begin{tabularx}{1\textwidth}
{
#{}
>{\raggedright\arraybackslash}X
>{\centering\arraybackslash}p{1.75cm}
>{\centering\arraybackslash}p{1.75cm}
>{\centering\arraybackslash}p{1.75cm}
>{\centering\arraybackslash}p{1.75cm}
#{}
}
%\multicolumn{11}{#{}p{1\textwidth}#{}}{\footnotesize
% Caption }\\
\toprule
& Log Probability of Default & Log Recovery Rate
& Log Spread & Log Leverage \\ [0.5ex]
& (1) & (2) & (3) & (4) \\
\midrule
Log Damage
&0.017** &-0.003*** & 0.002 & -0.157 \\
&(0.0008) &(0.003) & (0.075) & (0.178) \\\addlinespace
Log Adaptation
&-0.157*** &0.012 &-0.463** & 0.514*** \\
&(0.021) &(0.007) &(0.182) &(0.193)\\\addlinespace
Log Damage $\times$
&0.006 &0.018* &-0.398 &0.535 \\
Log Adaptation &(0.030) &(0.011) &(0.249) &(0.513)\\\addlinespace
Constant
&-1.227***&-0.117***&2.244***&0.101\\
&(0.026)&(0.009)&(0.187)&(0.237)\\
\midrule
Observations &926 &925 &458 &177 \\
$R^2$ &41\% &19\% &8\% &38\%\\
Adjusted $R^2$ &40\%&17\%&4\%&32\%\\\addlinespace
Residual Std. Error
& 0.071 & 0.025 & 0.373 & 0.264 \\
& (df = 907) & (df = 906) & (df = 439) & (df = 159)\\\addlinespace
F Statistic
& 35.253*** & 11.455*** & 2.104*** & 5.811*** \\
& (df = 18; 907)& (df = 18; 906)& (df = 18; 439)& (df = 17; 159)\\
\bottomrule
\addlinespace
\multicolumn{4}{#{}p{0.8\textwidth}#{}}{\footnotesize {\tiny Note: *$p<0.1$; **$p<0.05$; ***$p<0.01$ }} \\
\end{tabularx}
%\end{table}
\end{table}
\end{frame}
\end{document}

How to align math equations even when some variables are missing?

I want the variables and signs aligned in a set of equations.
Desired output:
What I am trying in Mathjax:
\[
\begin{align}
2&x_1 - x_2 &+ 1.5&x_3 &= 8 \\
&x_1 &- 4&x_3 &= -1
\end{align}
\]
What I got:
So, what do I have to do to have the same alignment as in the "desired output" image?
There are a number of ways to achieve this. Below I use an array (with appropriate stretch and spacing), alignat and align coupled with eqparbox for measuring similarly-tagged boxes (this latter approach requires two compilations with every change in the largest element associated with every <tag>):
\documentclass{article}
\usepackage{amsmath,eqparbox}
%\usepackage{xparse}% If you have LaTeX2e < 2020-10-01
% https://tex.stackexchange.com/a/34412/5764
\makeatletter
% \eqmathbox[<tag>][<align>]{<math>}
\NewDocumentCommand{\eqmathbox}{o O{c} m}{%
\IfValueTF{#1}
{\def\eqmathbox###1##2{\eqmakebox[#1][#2]{$##1##2$}}}
{\def\eqmathbox###1##2{\eqmakebox{$##1##2$}}}
\mathpalette\eqmathbox#{#3}
}
\makeatother
\begin{document}
\[
\renewcommand{\arraystretch}{1.2}
\setlength{\arraycolsep}{0pt}
\begin{array}{ r c r c r c r }
2 x_1 & {}-{} & x_2 & {}+{} & 1.5 x_3 & {}={} & 8 \\
x_1 & & & {}-{} & 4 x_3 & {}={} & -7
\end{array}
\]
\begin{alignat*}{4}
2 x_1 & {}-{} & x_2 & {}+{} & 1.5 x_3 = {} && 8 \\
x_1 & & & {}-{} & 4 x_3 = {} && -7
\end{alignat*}
\begin{align*}
\eqmathbox[x1][r]{2 x_1} - \eqmathbox[x2][r]{x_2} + \eqmathbox[x3][r]{1.5 x_3} &= \eqmathbox[c][r]{8} \\
\eqmathbox[x1][r]{ x_1} \phantom{{}-{}} \eqmathbox[x2][r]{} - \eqmathbox[x3][r]{4 x_3} &= \eqmathbox[c][r]{-7}
\end{align*}
\end{document}
All yield similar output:

Vertical lines and width table latex

I'm replicating a table of an article, I need the table is the width of the text of the sheet and add a vertical lines below the word for, I attach my code.
% Please add the following required packages to your document preamble:
% \usepackage{booktabs}
\begin{table}[h]
\centering
\label{my-label}
\begin{tabular}{#{}l#{}}
\toprule
\textbf{Algorithm 2:} The Forward algorithm \\ \midrule
\textbf{Initialization:} \\
\ $\alpha_1(i) = \pi_i bi(O_1), \ 1 \leq i \leq K$ \\
\\
\textbf{Recursion:} \\
\textbf{for} t = 1,..., T-1 \textbf{do} \\
\ \ \ \textbf{for} j = 1,..., K do \\
\ \ \ \ \ \ \ $\alpha_{t+1}(j) = \left [\sum_{i=1}^{k} \alpha_t (i) \alpha_{ij},\right ] b_j(O_{t+1})$ \\
\ \ \ \textbf{end} \\
\textbf{end} \\
\\
\textbf{Result:} $P(O_{1:T}) = \sum_{i=1}^N \alpha_T (i)$ \\ \bottomrule
\end{tabular}
\end{table}
The result I expect is the one in the superior image. Any idea.
Add \vline and usepackage{tabularx} for width text.
\begin{table}[h]
\centering
\label{my-label}
\begin{tabularx}{\textwidth}{X}
\toprule
\textbf{Algorithm 2:} The Forward algorithm \\ \midrule
\textbf{Initialization:} \\
\ $\alpha_1(i) = \pi_i bi(O_1), \ 1 \leq i \leq K$ \\
\\
\textbf{Recursion:} \\
\textbf{for} $t = 1,..., T-1$ \textbf{do} \\
\ \ \vline \ \ \textbf{for} $j = 1,..., K$ \textbf{do} \\
\ \ \vline \ \ \ \ \vline \ \ $\alpha_{t+1}(j) = \left [\sum_{i=1}^{k} \alpha_t (i) \alpha_{ij},\right ] b_j(O_{t+1})$ \\
\ \ \vline \ \ \textbf{end} \\
\textbf{end} \\
\\
\textbf{Result:} $P(O_{1:T}) = \sum_{i=1}^N \alpha_T (i)$ \\ \bottomrule
\end{tabularx}
\end{table}
If you just want to replicate the algorithm display, a table would probably suffice:
\documentclass{article}
\usepackage{float,tabularx,booktabs,amsmath,mleftright}
\usepackage{lipsum}
\begin{document}
\sloppy % Just for this example
\lipsum[1]
\begin{table}[H]
\begin{tabularx}{\textwidth}{ #{} X #{} }
\toprule
\textbf{Algorithm 2:} The Forward algorithm \\
\midrule
\textbf{Initialization:} \\
\ $\alpha_1(i) = \pi_i b_i(O_1), \ 1 \leq i \leq K$ \\
\\
\textbf{Recursion:} \\
\textbf{for} $t = 1, \dots, T - 1$ \textbf{do} \\
\begin{tabular}{ #{\hspace{\tabcolsep}} | l }
\textbf{for} $j = 1, \dots, K$ \textbf{do} \\
\begin{tabular}{ #{\hspace{\tabcolsep}} | l }
$\displaystyle \alpha_{t + 1}(j) = \mleft[ \sum_{i = 1}^k \alpha_t (i) \alpha_{i j} \mright] b_j(O_{t + 1})$ \\
\end{tabular} \\
\textbf{end}
\end{tabular} \\
\textbf{end} \\
\\
\textbf{Result:} $\displaystyle P(O_{1:T}) = \sum_{i = 1}^N \alpha_T(i)$ \\
\bottomrule
\end{tabularx}
\end{table}
\lipsum[2]
\end{document}
Some considerations:
Used the [H]ere float specifier to maintain the position of the algorithm in-line with the code. This effectively removes the floating capability. Needs the float package.
tabularx stretches the table to a specified width using an X-column. Also removed the space around the X-column using #{} so the algorithm is flush with the column edges.
booktabs provides a neat layout of the lines and vertical spacing.
amsmath's \dots provides the best spacing around \dots, depending on the instance it's used in. Avoid using ... to denote ellipses.
Stretching of the display operator within a text-style use of math mode is achieved via \displaystyle. It does stretch the line height though.
mleftright's \mleft...\mright pairs provide better spacing around the delimiters than the traditional \left...\right.
Vertical rules stem from nested tabulars using a natural column widths and a forced indentation of width \tabcolsep.

How to display two-rows bracket in Latex?

Does anyone know how to modify the following string in order to display the two-lines bracket?
str = '$$c_i =\{\begin{array}{l l} 1 \quad L\left(Q_i\right) < 0 \\ 0 \quad L\left(Q_i\right) \geq 0 \\ \end{array}$$';
The current output is the following:
The sign '{' has to embrace both rows (1 and 0).
$$c_i =\begin{cases} 1 & L\left(Q_i\right) < 0 \\
0 & L\left(Q_i\right) \geq 0
\end{cases}$$
The tex file should have \usepackage{amsmath} in the preamble.
This is derived from Niall Murphy's answer, "tidied up" a bit:
\[
c_i =
\begin{cases}
1 & L (Q_i) < 0 \\
0 & L (Q_i) \geq 0
\end{cases}
\]
Note that the "\" becomes "\\", and I've removed the \left and \right parenthesis modifiers, which introduce unwanted (I think) space between L and (.
Try add \left before \{ and \rigth. at the end.
It should look like
$$\alpha_t = \left \{ {{\sqrt{\frac1N},\; t = 0 } \atop {\sqrt{\frac2N},\; t \ne 0 } } \right.$$
or
$$
\left\{\begin{tabular}{l} \textbf{Y} = 0,299\textbf{R} + 0,587\textbf{G} + 0,114\textbf{B} \\ \textbf{Cb} = 128 + 0,5\textbf{R} - 0,418688\textbf{G} - 0,081312\textbf{B} \\ \textbf{Cr} = 128 - 0,168736\textbf{R} - 0,331264\textbf{G} - 0,53\textbf{B} \end{tabular} \right.
$$

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