I wish to remove all intermediate spaces in s String.
Option 1:
func removingWhitespaces() -> String {
return replacingOccurrences(of: " ", with: "")
}
Option 2:
func removingWhitespaces() -> String {
return components(separatedBy: .whitespaces).joined()
}
Which is more performant ?
As per my point of view, I think option 1 is faster than the options 2.
Reason:
In option 2, you are chaining the return value of components(separatedBy:) to joined(). So ultimately the return value of the joined()` is used whereas in the option 1 you are directly calling the build-in function of the String.
As per my understanding, I would like to suggest Option 1
Because,
replacingOccurrences(of: " ", with: "")
will perform only single operation.
where,
components(separatedBy: .whitespaces).joined()
will perform two operation and taking more time. First it will separate elements by whitespace and create array then on array it will perform join operation and give you output.
Figure it out yourself. Basic performance testing is very simple in Xcode. In a XCTestCase class run these 2 tests
func testPerformance1() {
let string = "I wish to remove all intermediate spaces in a String"
self.measure {
for _ in 0..<10000 {
_ = string.replacingOccurrences(of: " ", with: "")
}
}
}
func testPerformance2() {
let string = "I wish to remove all intermediate spaces in a String"
self.measure {
for _ in 0..<10000 {
_ = string.components(separatedBy: .whitespaces).joined()
}
}
}
and read the result in the console. replacingOccurrences is much faster.
There is no big difference between components(separatedBy: " ") and components(separatedBy: .whitespaces)
Space
When talking about performance, one should take space complexity into account. What's meant by this term is how much memory will be needed to run this piece of code and describes the relationship between the number of elements in the input and the reserved memory. For example, we talk about:
O(n) space complexity when the reserved memory grows with the number of elements in the input.
O(1) space complexity when the reserved memory doesn't grow when the number of the input elements grows.
Between replacingOccurrences(of: " ", with: "") and components(separatedBy: .whitespaces).joined(), the former wins on space complexity since the latter creates an intermidiary array, and in performance, less is more.
Time
Given this string :
let str = "Lorem ipsum dolor sit amet, tempor nulla integer morbi, amet non amet pede quis enim, ipsum in a in congue etiam, aenean orci wisi, habitant ipsum magna auctor quo odio leo. Urna nunc. Semper mauris felis vivamus dictumst. Tortor volutpat fringilla sed, lorem dui bibendum ligula faucibus massa, dis metus volutpat nec ridiculus, ac vel vitae. At pellentesque, at sed, fringilla erat, justo eu at porttitor vestibulum hac, morbi in etiam sed nam. Elit consectetuer lorem feugiat, ante turpis elit et pellentesque erat nec, vitae a fermentum vivamus ut. Orci donec nulla justo non id quis, ante vestibulum nec, volutpat a egestas pretium aliquam non sed, eget vivamus vestibulum, ornare sed tempus. Suscipit laoreet vivamus congue, tempor amet erat nulla, nostrum justo, wisi cras ac tempor tincidunt eu, hac faucibus convallis. Ac massa aenean nunc est orci, erat facilisis. Aliquam donec. Ut blandit potenti quam quis pellentesque, cursus imperdiet morbi ea ut, non mauris consectetuer mauris risus vehicula in, sed rutrum pellentesque turpis. Eros gravida volutpat justo proin donec penatibus, suspendisse fermentum sed proin fringilla libero malesuada, nulla lectus ligula, aliquam amet, nemo quis est. Quis imperdiet, class leo, lobortis etiam volutpat lacus wisi. Vestibulum vitae, nibh sem molestie natoque. Elementum ornare, rutrum quisque ultrices odio mauris condimentum et, auctor elementum erat ultrices. Ex gravida libero molestie facilisi rutrum, wisi quam penatibus, dignissim elementum elit mi, mauris est elit convallis. Non etiam mauris pretium id, tempus neque magna, tincidunt odio metus habitasse in maecenas nonummy. Suspendisse eget neque, pretium fermentum elementum."
The benchmarking code is given below. Each code block will be run separately, while the others will be commented out. :
do {
let start = Date()
let result = str.components(separatedBy: " ").joined()
let end = Date()
print(result.count, end.timeIntervalSince(start))
}
do {
let start = Date()
let result = str.split(separator: " ").joined()
let end = Date()
print(result.count, end.timeIntervalSince(start))
}
do {
let start = Date()
let result = str.filter { !$0.isWhitespace }
let end = Date()
print(s.count, end.timeIntervalSince(start))
}
do {
let start = Date()
var s = str
s.removeAll { $0.isWhitespace }
let end = Date()
print(s.count, end.timeIntervalSince(start))
}
do {
let start = Date()
let result = str.components(separatedBy: .whitespaces).joined()
let end = Date()
print(result.count, end.timeIntervalSince(start))
}
do {
let start = Date()
var result = ""
for char in str where char != " " {
result.append(char)
}
let end = Date()
print(result.count, end.timeIntervalSince(start))
}
do {
let start = Date()
let result = str.replacingOccurrences(of: " ", with: "")
let end = Date()
print(result.count, end.timeIntervalSince(start))
}
do {
let start = Date()
var arr = str.utf8CString
arr.removeAll(where: { $0 != 32 })
var result = ""
arr.withUnsafeBufferPointer { ptr in
result = String(cString: ptr.baseAddress!)
}
let end = Date()
print(result.count, end.timeIntervalSince(start))
}
Compiled with optimization in the terminal using this command:
xcrun swiftc -O ReplaceStr.swift -o replaceStr
-O: with optimizations
ReplaceStr.swift: the name of the file containing the code. You should cd to the location of this file first.
-o: to specify the name of the output compiled file
replaceStr is an example name for the output file
And then run with ./replaceStr
After running each block multiple times, here are the best timings:
components(separatedBy: " ").joined() : 0.77ms
components(separatedBy: .whitespaces).joined() : 0.75ms
str.split(separator: " ").joined() : 0.54ms
filter { !$0.isWhitespace } : 0.52ms
removeAll { $0.isWhitespace } : 0.52ms
for char in str where char != " " : 0.26ms
replacingOccurrences(of: " ", with: "") : 0.23ms
str.utf8CString : 0.18ms
Comparable results were found with a shorter string :
let str = "Lorem ipsum dolor sit amet, tempor nulla integer morbi, amet non amet pede quis enim, ipsum in a in congue etiam, aenean orci wisi, habitant ipsum magna auctor quo odio leo."
Verdict
replacingOccurrences(of: " ", with: "") is better than components(separatedBy: .whitespaces).joined() in time complexity too. This is partially because replacingOccurrences(of:with:) is defined on NSString and not String. In a sense it's like comparing 🍏🍎 to 🍊🍊.
Manipulating the underlying CString beats them all 🥊 and is the overall best.
For more on benchmarking code, here is a good thread.
Using Split with joined is faster the other 2 options
class new: XCTestCase {
func testOption1() {
let string = String(repeating: "This is an example of a performance test case.", count: 10000)
self.measure {//0.0231s
_ = string.replacingOccurrences(of: " ", with: "")
}
}
func testOption2() {
let string = String(repeating: "This is an example of a performance test case.", count: 10000)
self.measure {//0.194s
_ = string.components(separatedBy: " ").joined()
}
}
func testOption3() {
let string = String(repeating: "This is an example of a performance test case.", count: 10000)
self.measure {//0.0184s
_ = string.split(separator: " ").joined()
}
}
}
Related
Here is a simple code that produces a strange top alignment and shrunk text of the second element inside ZStack.
BUT if you change the second text a bit (replace text2 by text2Alt1 or by text2Alt2) making it longer or shorter everything becomes correct.
What is the reason for this behavior?
struct VCardView: View {
let text: String
let color: UIColor
var body: some View {
VStack {
Rectangle()
.fill(Color(self.color))
.frame(idealWidth: 800, idealHeight: 500)
.aspectRatio(contentMode: .fit)
Text(self.text)
}
}
}
struct ContentView: View {
var body: some View {
ZStack(alignment: .topLeading) {
VCardView(text: text1, color: .blue)
.frame(width: 180, height: nil)
.alignmentGuide(.leading) { _ in 180 }
.alignmentGuide(.top) { _ in 0 }
//Replace text2 by text2Alt1 or text2Alt2 here:
VCardView(text: text2, color: .green)
.frame(width: 180, height: nil)
.alignmentGuide(.leading) { _ in 0 }
.alignmentGuide(.top) { _ in 0 }
}
}
let text1 = "1Lorem ipsum dolor sit amet, consectetuer adipiscing elit. Aenean commodo ligula eget dolor. Aenean massa. Cum sociis natoque penatibus et magnis dis parturient montes, nascetur ridiculus mus. Donec quam felis, ultricies nec, pellentesque eu, pretium quis, sem. Nulla consequat massa quis enim. Donec pede justo, fringilla vel, aliquet nec, vulputate eget, arcu. In enim justo, rhoncus ut, imperdiet a, venenatis vitae, justo. Nullam dictum felis eu pede mollis pretium. Integer tincidu!"
let text2 = "2Lorem ipsum dolor sit amet, consectetuer adipiscing elit. Aenean commodo ligula eget dolor. Aenean massa. Cum sociis nat!"
let text2Alt1 = "2Lorem ipsum dolor sit amet, consectetuer adipiscing elit. Aenean commodo ligula eget dolor. Aenean massa. C"
let text2Alt2 = "2Lorem ipsum dolor sit amet, consectetuer adipiscing elit. Aenean commodo ligula eget dolor. Aenean massa. Cum sociis nat! Cum sociis nat!"
}
Also, you could replace Rectangle() by Image() with appropriate proportions because it was the initial state. Rectangle with the ideal size is just for demonstration.
Here I use ZStack with explicit alignment guides (not HStack) because it's a part of another library. It is essential.
XCode 11.5
iOS 13.5 iPhone SE 2020
Bug looks like this:
Expected layout:
I've seen such Text truncation problems often in SwiftUI. The workaround which most of the time helps: ensure that Text is allowed to adjust it's font size automatically using the minimumScaleFactor modifier.
By modifying VCardView
Text(self.text)
.minimumScaleFactor(0.5)
The misalignment problem disappears for all possible text values (text1, text2, text2Alt1 and text2Alt2).
The resulting text does not look scaled at all. Everything fits nicely.
I do not have a good explanation, but I think if you tell SwiftUI that your Text is not 100% rigid/stiff, it performs better in calculating the elements extents.
Perhaps it is a SwiftUI bug, but I was always OK with this minimumScaleFactor workaround as it hadn't negatively impacted my results.
it doesn't look like a ZStack problem. Try to remove .aspectRatio(contentMode: .fit) from Rectangle() in VCardView.
For rectangle proportion check something like this.
I am trying to figure out how to use a progressView to show the progress of a something being downloaded using Realm. Through reading it seems that a Float called progress needs to be found, but I don't know how to find that in Realm. I have looked at the following questions, but I don't think that they are too helpful in this situation:
Swift: Realm - Update UI (Progress) while adding Data to DB
iOS-Swift How to update progressView
This is what I have at the moment:
ViewController:
import UIKit
import Realm
import RealmSwift
class ViewController: UIViewController {
var data = "Lorem ipsum dolor sit er elit lamet, consectetaur cillium adipisicing pecu, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua. Ut enim ad minim veniam, quis nostrud exercitation ullamco laboris nisi ut aliquip ex ea commodo consequat. Duis aute irure dolor in reprehenderit in voluptate velit esse cillum dolore eu fugiat nulla pariatur. Excepteur sint occaecat cupidatat non proident, sunt in culpa qui officia deserunt mollit anim id est laborum. Nam liber te conscient to factor tum poen legum odioque civiuda."
var realm: Realm!
#IBOutlet weak var saveBtn: UIButton!
#IBOutlet weak var progressView: UIProgressView!
override func viewDidLoad() {
super.viewDidLoad()
print("Hello")
print(Realm.Configuration.defaultConfiguration.fileURL!)
realm = try! Realm()
}
#IBAction func saveBtnPressed(_ sender: Any) {
saveToRealm(id: 1, name: "One", data: data)
let progress: Float = 0
progressView.setProgress(progress, animated: true)
}
func saveToRealm(id: Int, name: String, data: String) {
let realmSave = RealmSave()
realmSave.id = id
realmSave.name = name
realmSave.data = data
try? realm!.write {
realm.add(realmSave, update: true)
}
}
}
If there is anything that I can help with, please ask. Thank you
First: defining a let constant with a value of 0 will always stay 0. You can't dynamically change that to reflect the state of your download.
As a Realm engineer pointed out in this post "Realm has no way to know the total amount of data."
Estimating the progress should be done in your code.
You could try something like this:
func estimateProgress() {
let dataString = "Lorem ipsum dolor sit er elit lamet, consectetaur cillium adipisicing pecu, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua. Ut enim ad minim veniam, quis nostrud exercitation ullamco laboris nisi ut aliquip ex ea commodo consequat. Duis aute irure dolor in reprehenderit in voluptate velit esse cillum dolore eu fugiat nulla pariatur. Excepteur sint occaecat cupidatat non proident, sunt in culpa qui officia deserunt mollit anim id est laborum. Nam liber te conscient to factor tum poen legum odioque civiuda."
let data = dataString.data(using: .utf8)
let count = Float((data?.count)!)
let percentage: Float = count / 100
var progress: Float = 0
if progress < count {
progress += percentage
} else {
progress = count
}
progressView.setProgress(progress, animated: true)
print(progress)
}
Please note that this solution is for updating the UI and letting the user know that the saving to Realm is in progress. Since it uses the amount of bytes in the data, the larger the data, the longer it will take for the progress bar to fill. So it is good for UI, but it is not the actual state of progress.
And if you feel the progress bar is filling to slow/fast you can always tweak the percentage.
I have 40k strings in an array. I want to filter the array so that I'll get only the matched strings. I have some preconditions like it can have a separator in between, it should be a word search and the searches can have multiple words. So, I went with the regex and it's taking a lot of time.
The following is the code that I generated just for representation purpose here.
var arr = [String]()
for index in stride(from: 0, to: 40000, by: 1) {
arr.append("Lorem ipsum dolor sit er elit lamet, consectetaur cillium adipisicing pecu, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua. Ut enim ad minim veniam, quis nostrud exercitation ullamco laboris nisi ut aliquip ex ea commodo consequat. Duis aute irure dolor in reprehenderit in voluptate velit esse cillum dolore eu fugiat nulla pariatur. Excepteur sint occaecat cupidatat non proident, sunt in culpa qui officia deserunt mollit anim id est laborum. Nam liber te conscient to factor tum poen legum odioque civiuda.")
}
// We specify the words to be searched here
let searchTexts = ["aliqua", "Ut"]
// The time the execution started
print(Date().timeIntervalSince1970)
let predicate = NSPredicate(format: "SELF matches[cd] %#", ".*\\b\(searchTexts.joined(separator: "[ ,.!?;:\"(')-]*"))\\b.*")
let fil = arr.filter { (str) -> Bool in
return predicate.evaluate(with: str)
}
// The time the execution stopped
print(Date().timeIntervalSince1970)
The time taken is 2 seconds and in an iOS simulator. It takes more in devices.
How to improve the regex? I have searched a lot of sites but it didn't help me.
Edit:
The above question had been modified since it involved core data.
My actual question now is how do we apply the same logic to core data fetch?
Do not use a method that requires a whole string match if all you need is a partial match. NSPredicate with MATCHES requires a full string match and you have to use .* or similar to ensure that. However, the .* greedy dot pattern grabs the whole line and then backtracks to accommodate text for the subsequent patterns. The more patterns there are after .*, the less efficient the pattern is.
You need to use a method that will allow partial matches and thus will let you get rid of .*, e.g. a range(of:options:range:locale:) while passing the .regularExpression option.
In your scenario above, you may remove let predicate = NSPredicate(format: "SELF matches[cd] %#", ".*\\b\(searchTexts.joined(separator: "[ ,.!?;:\"(')-]*"))\\b.*" and replace return predicate.evaluate(with: str) with
return str.range(of: "\\b\(searchTexts.joined(separator: "[ ,.!?;:\"(')-]*"))\\b", options: .regularExpression) != nil
See the new regex demo (56 steps), and your regex demo (541 steps).
I want to make sure that my headerView inside a tableView is dynamically growing to account for the size of my attributed string.
This concept works fine with just autolayout for my cell-views without much work.
However I am having problems with the header (a UIView) and so I am trying to calculate it's height by hand but for some reason the height given by this code is too small?
func setupTableHeader () {
let str = "Sed ut perspiciatis unde omnis iste natus error sit voluptatem accusantium doloremque laudantium, totam rem aperiam, eaque ipsa quae ab illo inventore veritatis et quasi architecto beatae vitae dicta sunt explicabo. Nemo enim ipsam voluptatem quia voluptas sit aspernatur aut odit aut fugit, sed quia consequuntur magni dolores eos qui ratione voluptatem sequi nesciunt. Neque porro quisquam est, qui dolorem ipsum quia dolor sit amet, consectetur, adipisci velit, sed quia non numquam eius modi tempora incidunt ut labore et dolore magnam aliquam quaerat voluptatem. Ut enim ad minima veniam, quis nostrum exercitationem ullam corporis suscipit laboriosam, nisi ut aliquid ex ea commodi consequatur? Quis autem vel eum iure reprehenderit qui in ea voluptate velit esse quam nihil molestiae consequatur, vel illum qui dolorem eum fugiat quo voluptas nulla pariatur?"
let attributedStr = NSAttributedString(string: str)
headerViewLabel.attributedText = attributedStr
let rect = attributedStr.boundingRect(with: CGSize(width: view.frame.width, height: 100000000000000000), options: [.usesFontLeading, .usesLineFragmentOrigin], context: nil)
tableView.tableHeaderView = headerView
let height = rect.height
headerView.frame = CGRect(x: 0, y: 0, width: self.view.width, height: height + headerView.frame.height)
}
Create an extension on NSAttributedString that calculates a height based on a given width:
extension NSAttributedString {
func height(forConstantWidth width: CGFloat) -> CGFloat {
let constraintBox = CGSize(width: width, height: .greatestFiniteMagnitude)
let calculatedBox = boundingRect(with: constraintBox, options: .usesLineFragmentOrigin, context: nil)
return calculatedBox.height
}
}
You could call that and pass in the table view's width, like:
let height = myAttrString.height(forConstantWidth: tableView.frame.size.width)
You can make UITableView's header resize to account for size of its Sub Elements.
You can use following extension.
extension UITableView {
func automaticHeaderViewSize() {
if let headerView = self.tableHeaderView {
let height = headerView.systemLayoutSizeFitting(UILayoutFittingCompressedSize).height
var headerFrame = headerView.frame
//Comparison necessary to avoid infinite loop
if height != headerFrame.size.height {
headerFrame.size.height = height
headerView.frame = headerFrame
self.tableHeaderView = headerView
}
}
}
}
Just make sure, your label has numberOfLines = 0.
So, finally your code is going to be (according to your question).
func setupTableHeader () {
let str = "your long text..."
let attributedStr = NSAttributedString(string: str)
headerViewLabel.attributedText = attributedStr
tableView.tableHeaderView = headerView
tableView.automaticHeaderViewSize()
}
Hi I am using RedCloth, Rails 3.
Currently I splitling a long text based based on string "-BREAK-".
How do I split text based on character length without splitting in the middle of a sentence.
E.g.,
Lorem ipsum dolor sit amet, consectetur adipiscing elit. Maecenas at purus eu nisl consequat mattis. Morbi pretium eros eget erat ornare elementum.
Vivamus in dui sit amet tellus bibendum volutpat. Sed lorem sem, porttitor at mattis quis, volutpat sed quam. Vestibulum eu justo nec dui ullamcorper molestie. Sed eleifend malesuada mattis. Curabitur eleifend elit vitae justo feugiat iaculis. Etiam sed lectus eu quam suscipit fermentum id a sem.
Phasellus sed odio eu urna gravida venenatis venenatis non justo. Praesent tincidunt velit adipiscing ligula pretium commodo. Cras blandit, nibh ac sagittis egestas, enim odio rutrum metus, vel hendrerit felis urna cursus odio. Maecenas elementum erat et arcu vulputate eu fermentum orci semper. Proin luctus purus sit amet nibh blandit cursus.
That will be comprise one page. It's about 794 characters.
First you should split your text to single sentences.
Here's a simple, far-from-perfect way for doing this (I'm sure you could find plenty of more complete patterns elsewhere):
'Gsda asd. Gasd sasd. Tfed fdd.'.scan(/(.+?\.) ?/).map(&:first)
#=> ["Gsda asd.", "Gasd sasd.", "Tfed fdd."]
Then, you should join these sentences, keeping an eye of the paragraph length. You can use something like this:
# using words as units, but sentences are just the same:
s = ['foo', 'bar', 'beef', 'baz', 'hello', 'chunky', 'bacon']
LEN = 7 # minimum length of a paragraph
s.inject([]){|a,i|
if !a.last || a.last.length > LEN
a << i
else
a.last << " #{i}"
end
a
}
#=> ["foo bar beef", "baz hello", "chunky bacon"]
I don't think there's any built in logic for this, so you should just look for "." with a nice regex also specifying that it has to be straight after a word (not whitespace), followed by a space and a capital letter.
Edit: that should give you an array of occurrences from which you can pick the one closest to the character limit.