I'm relatively new to lua and programming in general (self taught), so please be gentle!
Anyway, I wrote a lua script to read a UDP message from a game. The structure of the message is:
DATAxXXXXaaaaBBBBccccDDDDeeeeFFFFggggHHHH
DATAx = 4 letter ID and x = control character
XXXX = integer shows the group of the data (groups are known)
aaaa...HHHHH = 8 single-precision floating point numbers
The last ones is those numbers I need to decode.
If I print the message as received, it's something like:
DATA*{V???A?A?...etc.
Using string.byte(), I'm getting a stream of bytes like this (I have "formatted" the bytes to reflect the structure above.
68 65 84 65/42/20 0 0 0/237 222 28 66/189 59 182 65/107 42 41 65/33 173 79 63/0 0 128 63/146 41 41 65/0 0 30 66/0 0 184 65
The first 5 bytes are of course the DATA*. The next 4 are the 20th group of data. The next bytes, the ones I need to decode, and are equal to those values:
237 222 28 66 = 39.218
189 59 182 65 = 22.779
107 42 41 65 = 10.573
33 173 79 63 = 0.8114
0 0 128 63 = 1.0000
146 41 41 65 = 10.573
0 0 30 66 = 39.500
0 0 184 65 = 23.000
I've found C# code that does the decode with BitConverter.ToSingle(), but I haven't found any like this for Lua.
Any idea?
What Lua version do you have?
This code works in Lua 5.3
local str = "DATA*\20\0\0\0\237\222\28\66\189\59\182\65..."
-- Read two float values starting from position 10 in the string
print(string.unpack("<ff", str, 10)) --> 39.217700958252 22.779169082642 18
-- 18 (third returned value) is the next position in the string
For Lua 5.1 you have to write special function (or steal it from François Perrad's git repo )
local function binary_to_float(str, pos)
local b1, b2, b3, b4 = str:byte(pos, pos+3)
local sign = b4 > 0x7F and -1 or 1
local expo = (b4 % 0x80) * 2 + math.floor(b3 / 0x80)
local mant = ((b3 % 0x80) * 0x100 + b2) * 0x100 + b1
local n
if mant + expo == 0 then
n = sign * 0.0
elseif expo == 0xFF then
n = (mant == 0 and sign or 0) / 0
else
n = sign * (1 + mant / 0x800000) * 2.0^(expo - 0x7F)
end
return n
end
local str = "DATA*\20\0\0\0\237\222\28\66\189\59\182\65..."
print(binary_to_float(str, 10)) --> 39.217700958252
print(binary_to_float(str, 14)) --> 22.779169082642
It’s little-endian byte-order of IEEE-754 single-precision binary:
E.g., 0 0 128 63 is:
00111111 10000000 00000000 00000000
(63) (128) (0) (0)
Why that equals 1 requires that you understand the very basics of IEEE-754 representation, namely its use of an exponent and mantissa. See here to start.
See #Egor‘s answer above for how to use string.unpack() in Lua 5.3 and one possible implementation you could use in earlier versions.
I'm trying to predict time series data for the next few days looking at past few days, using Keras. My label data is target values for multiple future days, regression model has multiple output neurons (the "direct approach" for time series).
Here is test data with predictions for 10 days, using 60 days history.
10 days prediction for test data
As you can see, future values for all days are about the same. I've spent quite some time on it, and must admit that I'm probably missing something with respect to LSTM...
Here is training data with prediction:
10 days prediction for training data
In order to confirm that I'm preparing data properly, I've created a "tracking data set" which I used to visualize data transformations. Here it is...
Data set:
Open,High,Low,Close,Volume,OpenInt
111,112,113,114,115,0
121,122,123,124,125,0
131,132,133,134,135,0
141,142,143,144,145,0
151,152,153,154,155,0
161,162,163,164,165,0
171,172,173,174,175,0
181,182,183,184,185,0
191,192,193,194,195,0
201,202,203,204,205,0
211,212,213,214,215,0
221,222,223,224,225,0
231,232,233,234,235,0
241,242,243,244,245,0
251,252,253,254,255,0
261,262,263,264,265,0
271,272,273,274,275,0
281,282,283,284,285,0
291,292,293,294,295,0
Training set using 2 days history, predicting 3 days future values (I used different values of history days and future days, and it all makes sense to me), without feature scaling in order to visualize data transformations:
X train (6, 2, 5)
[[[111 112 113 114 115]
[121 122 123 124 125]]
[[121 122 123 124 125]
[131 132 133 134 135]]
[[131 132 133 134 135]
[141 142 143 144 145]]
[[141 142 143 144 145]
[151 152 153 154 155]]
[[151 152 153 154 155]
[161 162 163 164 165]]
[[161 162 163 164 165]
[171 172 173 174 175]]]
Y train (6, 3)
[[131 141 151]
[141 151 161]
[151 161 171]
[161 171 181]
[171 181 191]
[181 191 201]]
Test set
X test (6, 2, 5)
[[[201 202 203 204 205]
[211 212 213 214 215]]
[[211 212 213 214 215]
[221 222 223 224 225]]
[[221 222 223 224 225]
[231 232 233 234 235]]
[[231 232 233 234 235]
[241 242 243 244 245]]
[[241 242 243 244 245]
[251 252 253 254 255]]
[[251 252 253 254 255]
[261 262 263 264 265]]]
Y test (6, 3)
[[221 231 241]
[231 241 251]
[241 251 261]
[251 261 271]
[261 271 281]
[271 281 291]]
Model:
def CreateRegressor(self,
optimizer='adam',
activation='tanh', # RNN activation
init_mode='glorot_uniform',
hidden_neurons=50,
dropout_rate=0.0,
weight_constraint=0,
stateful=False,
# SGD parameters
learn_rate=0.01,
momentum=0):
kernel_constraint = maxnorm(weight_constraint) if weight_constraint > 0 else None
model = Sequential()
model.add(LSTM(units=hidden_neurons, activation=activation, kernel_initializer=init_mode, kernel_constraint=kernel_constraint,
return_sequences=True, input_shape=(self.X_train.shape[1], self.X_train.shape[2]), stateful=stateful))
model.add(Dropout(dropout_rate))
model.add(LSTM(units=hidden_neurons, activation=activation, kernel_initializer=init_mode, kernel_constraint=kernel_constraint,
return_sequences=True, stateful=stateful))
model.add(Dropout(dropout_rate))
model.add(LSTM(units=hidden_neurons, activation=activation, kernel_initializer=init_mode, kernel_constraint=kernel_constraint,
return_sequences=True, stateful=stateful))
model.add(Dropout(dropout_rate))
model.add(LSTM(units=hidden_neurons, activation=activation, kernel_initializer=init_mode, kernel_constraint=kernel_constraint,
return_sequences=False, stateful=stateful))
model.add(Dropout(dropout_rate))
model.add(Dense(units=self.y_train.shape[1]))
if (optimizer == 'SGD'):
optimizer = SGD(lr=learn_rate, momentum=momentum)
model.compile(optimizer=optimizer, loss='mean_squared_error')
return model
...which I create with these params:
self.CreateRegressor(optimizer = 'adam', hidden_neurons = 100)
... and then fit like this:
self.regressor.fit(self.X_train, self.y_train, epochs=100, batch_size=32)
... and predict:
y_pred = self.regressor.predict(X_test)
... or
y_pred_train = self.regressor.predict(X_train)
What am I missing?
Using the Images package, I can open up a color image, convert it to Gray scale and then :
using Images
img_gld = imread("...path to some color jpg...")
img_gld_gs = convert(Image{Gray},img_gld)
#change from floats to Array of values between 0 and 255:
img_gld_gs = reinterpret(Uint8,data(img_gld_gs))
Now I've got a 1920X1080 array of Uint8's:
julia> img_gld_gs
1920x1080 Array{Uint8,2}
Now I want to get a histogram of the 2D array of Uint8 values:
julia> hist(img_gld_gs)
(0.0:50.0:300.0,
6x1080 Array{Int64,2}:
1302 1288 1293 1302 1297 1300 1257 1234 … 12 13 13 12 13 15 14
618 632 627 618 623 620 663 686 189 187 187 188 185 183 183
0 0 0 0 0 0 0 0 9 9 8 7 8 7 7
0 0 0 0 0 0 0 0 10 12 9 7 13 7 9
0 0 0 0 0 0 0 0 1238 1230 1236 1235 1230 1240 1234
0 0 0 0 0 0 0 0 … 462 469 467 471 471 468 473)
But, instead of 6x1080, I'd like 256 slots in the histogram to show total number of times each value has appeared. I tried:
julia> hist(img_gld_gs,256)
But that gives:
(2.0:1.0:252.0,
250x1080 Array{Int64,2}:
So instead of a 256x1080 Array, it's 250x1080. Is there any way to force it to have 256 bins (without resorting to writing my own hist function)? I want to be able to compare different images and I want the histogram for each image to have the same number of bins.
Assuming you want a histogram for the entire image (rather than one per row), you might want
hist(vec(img_gld_gs), -1:255)
which first converts the image to a 1-dimensional vector. (You can also use img_gld_gs[:], but that copies the data.)
Also note the range here: the hist function uses a left-open interval, so it will omit counting zeros unless you use something smaller than 0.
hist also accepts a vector (or range) as an optional argument that specifies the edge boundaries, so
hist(img_gld_gs, 0:256)
should work.
I am performing logistic regression using Vowpal Wabbit on a dataset with 25 features and 48 million instances. I have a question on current predict values. Should it be within 0 or 1.
average since example example current current current
loss last counter weight label predict features
0.693147 0.693147 1 1.0 -1.0000 0.0000 24
0.419189 0.145231 2 2.0 -1.0000 -1.8559 24
0.235457 0.051725 4 4.0 -1.0000 -2.7588 23
6.371911 12.508365 8 8.0 -1.0000 -3.7784 24
3.485084 0.598258 16 16.0 -1.0000 -2.2767 24
1.765249 0.045413 32 32.0 -1.0000 -2.8924 24
1.017911 0.270573 64 64.0 -1.0000 -3.0438 25
0.611419 0.204927 128 128.0 -1.0000 -3.1539 25
0.469127 0.326834 256 256.0 -1.0000 -1.6101 23
0.403473 0.337820 512 512.0 -1.0000 -2.8843 25
0.337348 0.271222 1024 1024.0 -1.0000 -2.5209 25
0.328909 0.320471 2048 2048.0 -1.0000 -2.0732 25
0.309401 0.289892 4096 4096.0 -1.0000 -2.7639 25
0.291447 0.273492 8192 8192.0 -1.0000 -2.5978 24
0.287428 0.283409 16384 16384.0 -1.0000 -3.1774 25
0.287249 0.287071 32768 32768.0 -1.0000 -2.7770 24
0.282737 0.278224 65536 65536.0 -1.0000 -1.9070 25
0.278517 0.274297 131072 131072.0 -1.0000 -3.3813 24
0.291475 0.304433 262144 262144.0 1.0000 -2.7975 23
0.324553 0.357630 524288 524288.0 -1.0000 -0.8995 24
0.373086 0.421619 1048576 1048576.0 -1.0000 -1.2076 24
0.422605 0.472125 2097152 2097152.0 1.0000 -1.4907 25
0.476046 0.529488 4194304 4194304.0 -1.0000 -1.8591 25
0.476627 0.477208 8388608 8388608.0 -1.0000 -2.0037 23
0.446556 0.416485 16777216 16777216.0 -1.0000 -0.9915 24
0.422831 0.399107 33554432 33554432.0 -1.0000 -1.9549 25
0.428316 0.433801 67108864 67108864.0 -1.0000 -0.6376 24
0.425511 0.422705 134217728 134217728.0 -1.0000 -0.4094 24
0.425185 0.424860 268435456 268435456.0 -1.0000 -1.1529 24
0.426747 0.428309 536870912 536870912.0 -1.0000 -2.7468 25
Predictions are in the range [-50, +50] (theoretically any real number, but Vowpal Wabbit truncates it to [-50, +50]).
To convert them to {-1, +1}, use --binary. Positive predictions are simply mapped to +1, negative to -1.
To convert them to [0, +1], use --link=logistic.
This uses the logistic function 1/(1 + exp(-x)).
You should also use --loss_function=logistic if you want to interpret the numbers as probabilities.
To convert them to [-1, +1], use --link=glf1.
This uses formula 2/(1 + exp(-x)) - 1 (generalized logistic function with limits of 1).
I tried to create a neural network to estimate y = x ^ 2. So I created a fitting neural network and gave it some samples for input and output. I tried to build this network in C++. But the result is different than I expected.
With the following inputs:
0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26
27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49
50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 -1
-2 -3 -4 -5 -6 -7 -8 -9 -10 -11 -12 -13 -14 -15 -16 -17 -18 -19 -20 -21 -22 -23 -24 -25 -26 -27 -28 -29 -30 -31 -32 -33 -34 -35 -36 -37 -38 -39 -40 -41 -42 -43 -44 -45 -46 -47 -48 -49 -50 -51 -52 -53 -54 -55 -56 -57 -58 -59 -60 -61 -62 -63 -64 -65 -66 -67 -68 -69 -70 -71
and the following outputs:
0 1 4 9 16 25 36 49 64 81 100 121 144 169 196 225 256 289 324 361 400
441 484 529 576 625 676 729 784 841 900 961 1024 1089 1156 1225 1296
1369 1444 1521 1600 1681 1764 1849 1936 2025 2116 2209 2304 2401 2500
2601 2704 2809 2916 3025 3136 3249 3364 3481 3600 3721 3844 3969 4096
4225 4356 4489 4624 4761 4900 5041 1 4 9 16 25 36 49 64 81 100 121 144
169 196 225 256 289 324 361 400 441 484 529 576 625 676 729 784 841
900 961 1024 1089 1156 1225 1296 1369 1444 1521 1600 1681 1764 1849
1936 2025 2116 2209 2304 2401 2500 2601 2704 2809 2916 3025 3136 3249
3364 3481 3600 3721 3844 3969 4096 4225 4356 4489 4624 4761 4900 5041
I used fitting tool network. with matrix rows. Training is 70%, validation is 15% and testing is 15% as well. The number of hidden neurons is two. Then in command lines I wrote this:
purelin(net.LW{2}*tansig(net.IW{1}*inputTest+net.b{1})+net.b{2})
Other information :
My net.b[1] is: -1.16610230053776 1.16667147712026
My net.b[2] is: 51.3266249426358
And net.IW(1) is: 0.344272596370387 0.344111217766824
net.LW(2) is: 31.7635369693519 -31.8082184881063
When my inputTest is 3, the result of this command is 16, while it should be about 9. Have I made an error somewhere?
I found the Stack Overflow post Neural network in MATLAB that contains a problem like my problem, but there is a little difference, and the differences is in that problem the ranges of input and output are same, but in my problem is no. That solution says I need to scale out the results, but how can I scale out my result?
You are right about scaling. As was mentioned in the linked answer, the neural network by default scales the input and output to the range [-1,1]. This can be seen in the network processing functions configuration:
>> net = fitnet(2);
>> net.inputs{1}.processFcns
ans =
'removeconstantrows' 'mapminmax'
>> net.outputs{2}.processFcns
ans =
'removeconstantrows' 'mapminmax'
The second preprocessing function applied to both input/output is mapminmax with the following parameters:
>> net.inputs{1}.processParams{2}
ans =
ymin: -1
ymax: 1
>> net.outputs{2}.processParams{2}
ans =
ymin: -1
ymax: 1
to map both into the range [-1,1] (prior to training).
This means that the trained network expects input values in this range, and outputs values also in the same range. If you want to manually feed input to the network, and compute the output yourself, you have to scale the data at input, and reverse the mapping at the output.
One last thing to remember is that each time you train the ANN, you will get different weights. If you want reproducible results, you need to fix the state of the random number generator (initialize it with the same seed each time). Read the documentation on functions like rng and RandStream.
You also have to pay attention that if you are dividing the data into training/testing/validation sets, you must use the same split each time (probably also affected by the randomness aspect I mentioned).
Here is an example to illustrate the idea (adapted from another post of mine):
%%# data
x = linspace(-71,71,200); %# 1D input
y_model = x.^2; %# model
y = y_model + 10*randn(size(x)).*x; %# add some noise
%%# create ANN, train, simulate
net = fitnet(2); %# one hidden layer with 2 nodes
net.divideFcn = 'dividerand';
net.trainParam.epochs = 50;
net = train(net,x,y);
y_hat = net(x);
%%# plot
plot(x, y, 'b.'), hold on
plot(x, x.^2, 'Color','g', 'LineWidth',2)
plot(x, y_hat, 'Color','r', 'LineWidth',2)
legend({'data (noisy)','model (x^2)','fitted'})
hold off, grid on
%%# manually simulate network
%# map input to [-1,1] range
[~,inMap] = mapminmax(x, -1, 1);
in = mapminmax('apply', x, inMap);
%# propagate values to get output (scaled to [-1,1])
hid = tansig( bsxfun(#plus, net.IW{1}*in, net.b{1}) ); %# hidden layer
outLayerOut = purelin( net.LW{2}*hid + net.b{2} ); %# output layer
%# reverse mapping from [-1,1] to original data scale
[~,outMap] = mapminmax(y, -1, 1);
out = mapminmax('reverse', outLayerOut, outMap);
%# compare against MATLAB output
max( abs(out - y_hat) ) %# this should be zero (or in the order of `eps`)
I opted to use the mapminmax function, but you could have done that manually as well. The formula is a pretty simply linear mapping:
y = (ymax-ymin)*(x-xmin)/(xmax-xmin) + ymin;