Newbie on coding and don't know how to make it work: Have the equation and need to change 3 variables depending on the situation.
Tried to Google but I guess I don't know what I'm exactly looking for as English isn't my first language
https://docs.google.com/spreadsheets/d/1HUw724okFB94GpeYmF3sacQBgQRnpnTSvgMMSk6RX4Y/edit?usp=sharing
=B4+(((B3/100)*280.059565*(B2^-0.412565956)-B3))
Related
I have been trying to extract the required data from a single cell and I have tried using some common formulas but its not working for all the cells exactly.
I would appreciate your help in this regards.
Google Sheet
Formula 1
=LEFT(A2,FIND(C2,A2)-1)
Formula 2
=SUBSTITUTE(TRIM(SUBSTITUTE(SUBSTITUTE(LEFT(RIGHT(A2,len(A2)-FIND(") ",A2)),6),")",""),"(","")),"|","")
I duplicated your tab and entered the following formula in cell E2:
=ArrayFormula(ifna(regexextract(A2:A,"\[\s\]\s(.+)?\s\((.+)\)")))
Explanation
\[\s\]\s - find [ ]
(.+)?\s\( - extract everything after it until the next occurence of (
(.+)\) - extract everything after the above ( and before the next occurence of )
EDIT: The first time I've tried #ztiaa answer it didn't work... don't know why. I kept investigating REGEX and gave it another try, and it did... You'd probably prefer that. I leave my answer just as a memory, and if it's useful for someone else in another scenario
Honestly, I don't handle regex as #ztiaa, but what I've found difficult about your example is that there are sometimes more than one opening parenthesis... that's why I looked for a way of finding the last appearance of "(". You can learn more about this workaround here
I changed "#" with "CUT HERE" in my example, just in case "#" may appear in your example. With that in mind, you can set these two formulas:
=ArrayFormula(IF(A3:A="","",MID(A3:A,5,FIND("CUT HERE",SUBSTITUTE(A3:A,"(","CUT
HERE",LEN(A3:A)-LEN(SUBSTITUTE(A3:A,"(",""))))-5)))
=arrayformula(if(A3:A="","",mid(A3:A,FIND("CUT HERE",SUBSTITUTE(A3:A,"(","CUT
HERE",LEN(A3:A)-LEN(SUBSTITUTE(A3:A,"(",""))))+1,FIND(")",A3:A,FIND("CUT
HERE",SUBSTITUTE(A3:A,"(","CUT
HERE",LEN(A3:A)-LEN(SUBSTITUTE(A3:A,"(",""))))+1)-FIND("CUT
HERE",SUBSTITUTE(A3:A,"(","CUT
HERE",LEN(A3:A)-LEN(SUBSTITUTE(A3:A,"(",""))))-1)))
The second one is really long because it has to find the amount of characters in between brackets. But it appears to work. Probably there's a more ellegant way with Regex, I repeat :)
Look in J and K of your example:
Does anyone know how I can deobfuscate a lua script that uses xfuscator to hide it? The obfuscation looks like this. If anyone could give me a point into the right direction on how I can get this done that would bne awesome! I didnt share the source because I wanted help figuring out how to deobfusate myself and didnt want the answer!
https://gyazo.com/d2a9a2bcc602d1a1146491158271e3e6
See that long table? That's the real code. It's a pattern you see quite often with obfuscators. Other than that, keep in mind that _, __0 and such are all valid Lua identifiers, to you can have variables named like that.
_ is a function that turns a number into a character; __0 is a table that contains some standard functions. There's nothing special going on beyond that. If you see a __0[1]("Hello"), that'd be the same as print("Hello"); it just looks weird, because they put print into the __0 table at index 1.
Ultimately, the obfuscator just makes use of Lua features that people often don't understand well enough to understand what's going on. If you know the language though, it's all just smoke and mirrors.
So i have this column of numbers and i wish to extract only the numbers before the "HE" text for example, this is what i need, and i don't really know how to achieve this.
Maybe there is a way to use a formula or command to do this, i've been trying to use power tools add-on but to no avail i did not get it.
Maybe for clarification in each cell there are 2 lines, using alt+enter.
REGEXEXTRACT() is suitable in this case.
=REGEXEXTRACT(A1,"(.+) HE")
Few good tips here about REGEXEXTRACT().
For array approach use below formula-
=ArrayFormula(IF(A1:A="","",REGEXEXTRACT(A1:A,"(.+) HE")))
EZ stuff but after an hour.. =filter(May15!A:S , May15!E:E="Authorization") is yielding a rich populated sheet. However I can't get OR working! Despite it working elsewhere in the sheet. I'd like other possibilities via the same filter. I tried several including the OR this way
=filter(May15!A:S , OR(May15!E:E="Authorization" , May15!E:E="bigwhale", May15!E:E="hi"))
.. to no avail. Any help appreciated. Also, I read somewhere the OR could be accessed using a "+" and that sounded like a neat method.. Thanks!
One possible way is to use RegEx:
=filter(H:H , REGEXMATCH(E:E,JOIN("|",A1:A3)))
put in A1:A3:
Authorization
bigwhale
hi
This trick is useful when you need to add conditions, just paste one more value in cell A4 and use range A1:A4
Another way is to use plus sign:
=FILTER(H:H,(E:E="Authorization")+(E:E="bigwhale")+(E:E="hi"))
First time questioner and extremely new LaTeX user here. I'm trying to get equations to line up according to the arrow symbol used in my linear rules for a Phonology paper.
\begin{align}
\text{/b'al/} &\arrow\ \text{[b\super{j}\textipa{A}l]}\\
\text{/luna/} &\arrow\ \text{[wu.n\textipa{A}]}\\
\end{align}
For this I made \newcommand{\arrow}[0]{$\rightarrow$} to avoivd swapping in and out of mathmode.The format I'm trying to get is that it would have the first and second lines match up according to the arrow. However, I keep getting a "Missing } inserted. } l.38 \end{align}".
Sorry for the possibly dumb question, but can anyone help?
If you are using \arrow in both math and text mode, then you can use
\newcommand{\arrow}{\ensuremath{\rightarrow}}
which will ensure it be typeset in math-mode, regardless of the context. Note that there are some problems with using \ensuremath. However, they may not pertain to your situation.
It looks like the problem is that the align environment already defines math mode, and because your \arrow definition includes the math mode delimiters it breaks the whole thing. You just have to write \rightarrow without the $ ... $ around it.
If you want, define another command \marrow[0]{\rightarrow} to use within math mode.
If this answered your question, please mark it as such so that others know that it worked for you.