Seque order for selection lists - ios

Question

I am implementing the following. I have a view controller and I have buttons that open a table view controller with selection items. when I then select an item in a cell and go back to the view controller, previous values are blank (looks like it opens a new instance). The code I am using to go back is as follows:
override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
if segue.identifier == "playerselected" {
let cell = sender as! UITableViewCell
let indexPath = tableView.indexPath(for: cell)
let itemController : GameViewController = segue.destination as! GameViewController
let item : Player = frc.object(at: indexPath!) as! Player
itemController.item2 = item
}

Answer 1

Yes, you're right, if you have segue from VC1 (GameViewController) to VC2 (SomeTableViewController) and then from VC2 to VC1, it's not the same instance of VC1.
If you don't use UINavigationController, you can simply "go" from VC2 back to VC1 by dismissing your VC2 using
dismiss(animated: true)
But how can you now pass data back to your previous controller? Start with this: in VC2 create closure variable which takes parameter of type Player. Then before you dismiss VC2, call this closure
class SomeTableViewController: UITableViewController {
var callback: ( (Player) -> Void )?
func playerSelected(_ player: Player) {
callback?(player)
dismiss(animated: true)
}
}
But will happen after callback is called? Nothing, you have to assign what will happen before you present VC2. So you can override prepare(for:sender:) inside VC1 and assign destination's callback closure variable (when callback will be called, you need to change VC1's item2)
override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
if segue.identifier == "segueToTableViewController" {
let tableViewController = segue.destination as! SomeTableViewController
tableViewController.callback = { player in
self.item2 = player
}
}
}