my code not executing properly due to logical error - stack

Question

I'm working on a program to learn the concept of stack-array. I'm facing a error where the stack isn't displayed properly [display() function]. Where am i going wrong??
I tried checking the code twice. it doesn't display the output from display()
#include <iostream>
#include <conio.h>
#include <process.h>
using namespace std;
const int size =50;
int pop(int [] ,int&);
int push(int [] ,int , int);
void display(int [] ,int);
int main()
{
int s[size],item,top=-1,res;
char ch='y';
while (ch=='y'||ch=='Y')
{
cout<<"\n Enter the item for insertion: ";
cin>>item;
res=push(s,top,item);
if(res==-1)
{
cout<<"\nOVERFLOW!!!";
system("pause");
exit(1);
}
cout<<"\nThe stack is :"<<endl;
display(s,top);
cout<<"More elements??";
cin>>ch;
}
cout<<"Now deletion begins\n";
ch='y';
while(ch=='y'||ch=='Y')
{
res=pop(s,top);
if(res==-1)
{
cout<<"UNDERFLOW!!";
system("pause");
exit(1);
}
else
{
cout<<"\nElement deleted is: "<<res<<endl;
cout<<"\n The stack now is: "<<endl;
display(s,top);
}
cout<<"delete elements??";
cin>>ch;
}
getch();
return 0;
}
int push(int s[],int top,int ele)
{
if(top==size-1) return-1;
else
{
top++;
s[top]=ele;
}
return 0;
}
int pop (int s[],int &top)
{
int ret;
if(top==-1) return -1;
else
{
ret=s[top];
top--;
}
return ret;
}
void display (int s[], int top)
{
if(top==-1) return;
cout<< s[top]<<"<--"<<endl;
for(int i=top-1;i>=0;i--)
{
cout<<s[i]<<endl;
}
}
the display() function should display the array elements in form of a stack.