Predictive tableView swift 4 - ios

Question

I have 2 tableView with 2 tableView first to display data & sec for predictive texts and I'm using textField as searchBar so when I set the cell for the sec tableView is give me that error when I try to return the cell at cellForRowAt method
Cannot convert return expression of type UITableViewCell.Type to return type UITableViewCell
and that's my code
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
if tableView == tableView {
let cell = tableView.dequeueReusableCell(withIdentifier: "SearchCell", for: indexPath) as! searchCell
//cell.pics = receiveData[indexPath.item]
cell.titleCell.text = receiveData[indexPath.row].adeTitle
cell.cityCell.text = receiveData[indexPath.row].city
cell.dateCell.text = receiveData[indexPath.row].date
cell.distanceCell.text = receiveData[indexPath.row].distance
cell.priceCell.text = receiveData[indexPath.row].adePrice
if receiveData[indexPath.row].typ == "2" {
cell.kindCell.text = "used"
cell.kindCell.backgroundColor = UIColor.darkGray
cell.kindCell.textColor = UIColor.white
} else if receiveData[indexPath.row].typ == "1" {
cell.kindCell.text = "New"
} else {
cell.kindCell.text = "none"
cell.kindCell.backgroundColor = UIColor.darkGray
cell.kindCell.textColor = UIColor.white
}
} else {
var cell = searchTableView.dequeueReusableCell(withIdentifier: "Cell" )
if cell == nil {
cell = UITableViewCell(style: .default, reuseIdentifier: "Cell")
}
cell?.textLabel?.text = inputs[indexPath.row]
}
return UITableViewCell
}

Answer 1

Looks like UITableViewCell's instance is not returned in your cellForRowAt method,
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
if tableView == tableView {
let cell = tableView.dequeueReusableCell(withIdentifier: "SearchCell", for: indexPath) as! searchCell
...
// do your stuffs with cell
...
return cell
}
return UITableViewCell()
}