Playing with Dart, is it possible to create a delay constructing a Future?:
Future<String>.value("Hello").then((newsDigest) {
print(newsDigest);
}) // .delayed(Duration(seconds: 5))
Yes, this is possible:
factory Future.delayed(Duration duration, [FutureOr<T> computation()]) {
_Future<T> result = new _Future<T>();
new Timer(duration, () {
try {
result._complete(computation?.call());
} catch (e, s) {
_completeWithErrorCallback(result, e, s);
}
});
return result;
}
As you have already discovered Future.delayed constructor creates a future that runs after a delay:
From the docs:
Future<T>.delayed(
Duration duration,
[ FutureOr<T> computation()
])
The computation will be executed after the given duration has passed, and the future is completed with the result of the computation.
If computation returns a future, the future returned by this constructor will complete with the value or error of that future.
For the sake of simplicity, taking a future that complete immediately with a value, this snippet creates a delayed future that complete after 3 seconds:
import 'dart:async';
main() {
var future = Future<String>.value("Hello");
var delayedFuture = Future.delayed(Duration(seconds: 3), () => future);
delayedFuture.then((value) {
print("Done: $value");
});
}
Related
I am failing to understand, why the error thrown from addItem method in below code is not caught in the try-catch block
void main() async {
var executor = Executor();
var stream = Stream.fromIterable([0, 1, 2, 3, 4, 5, 6, 7]);
try {
await for (var _ in stream) {
executor.submit(() => demoMethod());
}
await executor.execute();
} catch (e) {
print(e);
}
}
Future<void> demoMethod() async {
var list = [1, 2, 3, 1, 4, 5];
var executor = Executor();
var test = Test();
for (var element in list) {
executor.submit(() => test.addItem(element));
}
await executor.execute();
test.list.forEach(print);
}
class Test {
var list = <int>[];
Future<void> addItem(int i) async {
if (list.contains(i)) {
throw Exception('Item exists');
}
list.add(i);
}
}
class Executor {
final List<Future<void>> _futures = [];
bool _disposed = false;
void submit(Future<void> Function() computation) {
if (!_disposed) {
_futures.add(computation());
} else {
throw Exception('Executor is already disposed');
}
}
Future<void> execute() async {
await Future.wait(_futures, eagerError: true);
_disposed = true;
}
}
but below code is able to catch the error properly
void main() async {
var executor = Executor();
try {
for (var i = 0; i < 10; i++) {
executor.submit(() => demoMethod());
}
await executor.execute();
} catch (e) {
print(e);
}
}
I am guessing it has something to do with the stream processing.
It's the stream.
In your other examples, you synchronously run through a loop a and call Executor.submit with all the computations, then immediately call executor.execute().
There is no asychronous gap between calling the function which returns a future, and Future.wait starting to wait for that future.
In the stream code, each stream events starts an asynchronous computation by calling Executor.submit. That creates a future, stores it in a list, and goes back to waiting for the stream.
If that future completes, with an error, before the stream ends and Future.wait gets called, then there is no error handler attached to the future yet. The error is then considered unhandled, and is reported to the current Zone's uncaught error handler. Here that's the root zone, which means it's a global uncaught error, which may crash your entire program.
You need to make sure the future doesn't consider its error unhandled.
The easiest way to do that is to change submit to:
void submit(Future<void> Function() computation) {
if (!_disposed) {
_futures.add(computation()..ignore());
} else {
throw StateError('Executor is already disposed');
}
}
The ..ignore() tells the future that it's OK to not have an error handler.
You know, because the code will later come back and call executor.execute, that any errors will still be reported, so it should be safe to just postpone them a little. That's what Future.ignore is for.
(Also changed Exception to StateError, because that's what you should use to report people using objects that have been disposed or otherwise decommissioned.)
When I try to run the below code, it completes in a little more than 4 seconds. I couldn't understand why it finishes in that time. I thought it would complete in 14 seconds(4sec in declaring order variable,10sec in for loop). Don't Future.delayed() stop all the progress in program?
Future<void> printOrderMessage() async {
print("Awaiting user order ...");
var order = await fetchUserOrder(); //I couldn't understand here.
print('Your order is: $order');
}
Future<String> fetchUserOrder() {
return Future.delayed(const Duration(seconds: 4), () => 'Large Latte');
}
void main() async {
countSeconds(4); //Başlama yeri
await printOrderMessage();
}
void countSeconds(int s) {
for (var i = 1; i <= s; i++) {
Future.delayed(Duration(seconds: i), () => print(i)); //Also here
}
}
Output:
Awaiting user order ...
1
2
3
4
Your order is: Large Latte
I am learning Dart. Here is my code:
class MyClass {
MyClass() {
stream = Stream<int>.periodic(Duration(seconds: 1), (t) => t + 1).take(3);
myStreamController.addStream(stream);
Future.delayed(Duration(seconds: 2), () {
myStreamController.addStream(42); // but 42 is digit, not stream!
});
}
}
Working code:
class MyClass {
MyClass() {
stream = Stream<int>.periodic(Duration(seconds: 1), (t) => t + 1).take(3);
myStreamController.addStream(stream).then(
(done) {
Future.delayed(Duration(seconds: 2), () {
myStreamController.addStream( Stream.value(42) );
});
}
);
}
}
How I can add value to Stream?
Look at the Stream.value constructor:
Creates a stream which emits a single data event before completing.
This stream emits a single data event of value and then completes with
a done event.
https://api.dart.dev/stable/2.5.0/dart-async/Stream/Stream.value.html
This is related to is there any way to cancel a dart Future?
In my case, there are no HTTP, just expensive calculations. I have a table/list which I scroll through. As the elements become visible, I generate futures to show the calculation results. But if I (the end user) scroll quickly, some results will have "scrolled out of view" and will no longer required. This could be a large number, and would seriously delay the return of futures (results) that are to be usefully :-) displayed in currently visible elements. Can something be done about that? cheers, Steve
You could just set a flag which indicates to the delayed code (run from futures) that the result isn't needed anymore.
When the delayed code is called it just returns.
library cancel_future;
import 'dart:async' show Future, Timer;
import 'dart:math' show Random;
typedef void TaskFunction(Task task);
// Container for a task
class Task {
// an assigned task id
final id;
// data to process
int data;
// Indicate to the task function, that it should stop processing
bool isCanceled = false;
// The task function must set this flat to true when all work is done.
bool isFinished = false;
// The task function which processed the data and sets the result.
TaskFunction fn;
// The result set by the task function when it finished processing.
int result;
Task(this.id, this.data, this.fn);
// Start processing the task.
void execute() => fn(this);
}
final rnd = new Random();
void main(List<String> args) {
// create tasks
final tasks = new List<Task>.from(generate());
// start all tasks
tasks.forEach((t) => t.execute());
// after random delay cancel all unfinished tasks
new Future.delayed(new Duration(seconds: rnd.nextInt(10)), () {
tasks.forEach((t) {
if (!t.isFinished) {
t.isCanceled = true;
}
});
}).then((_) {
// check results
int done = 0;
int canceled = 0;
tasks.forEach((t) {
print(
'Task id: ${t.id}; isCanceled: ${t.isCanceled}; isFinished: ${t.isFinished}; data: ${t.data}; result: ${t.result}');
if (t.isFinished) {
done++;
}
if (t.isCanceled) {
canceled++;
}
});
print('Canceled: $canceled.');
print('Done: $done.');
});
}
// geneator for job 100 jobs
Iterable<Task> generate() sync* {
int i = 0;
while (i++ < 100) {
yield new Task(i, rnd.nextInt(100), calc);
}
}
// job function
void calc(Task t) {
// do a bit of work every 100ms to simulate longer processing
new Timer.periodic(new Duration(milliseconds: 100), (timer) {
var result = 0;
// check if jost was canceled and stop processing in case it was.
if (t.isCanceled) {
timer.cancel();
return;
}
// while not finished do a chunk of work
if (result < t.data) {
result++;
} else {
// finished - clean up and store result
t.isFinished = true;
t.result = result;
timer.cancel();
}
});
}
I launch a request to a server with a future "requestServer".
I would like to poll a system for a specific value (passed from false to true, when request is done) and return when finished.
Code could be like that, but "while" synchronous and "checkOperation" is asynchronous?
return requestServer().then((operation) {
var done = false;
while (done)
return checkOperation(operation).then((result) {
done = (result == true);
});
sleep(10);
}
});
Any ideas ?
I guess this is not exactly what you want but as far as I know there is no way to block execution so you have to use callbacks.
void main(List<String> args) {
// polling
new Timer.periodic(new Duration(microseconds: 100), (t) {
if(isDone) {
t.cancel();
someCallback();
}
});
// set isDone to true sometimes in the future
new Future.delayed(new Duration(seconds: 10), () => isDone = true);
}
bool isDone = false;
void someCallback() {
print('isDone: $isDone');
// continue processing
}
You can of course pass the callback as parameter instead of hardcode it, because functions are first class members in Dart.
Polling doesn't work very well for async. It is better to wait for a signal from the thing that must complete.
Günter Zöchbauer's answer shows you how to poll anyway, by sampling with a timer.
As an alternative, it would be better to not have a boolean done, but instead complete another future when you are ready. This is busy-polling, which polls again as soon as a result comes back, which may be more intensive than you need. Using timer based polling can be more efficient if you don't need the result as soon as possible.
return requestServer().then((operation) {
var completer = new Completer();
void poll(result) {
if (!result) {
operation.then(poll, onError: completer.completeError);
} else {
completer.complete();
}
}
poll(false);
return completer.future;
});
(Code not really tested, since I don't have your requestServer).
When you want build functions that return Futures, it is sometimes useful to use Completers. Think that requestServer() is living in the Future too, so you will have threat the result as a Future.
return requestServer().then((operation) {
// This is necessary then you want to control async
// funcions.
Completer completer = new Completer();
//
new Timer.periodic(const Duration(seconds: 10), (_) {
checkOperation(operation).then((result) {
// Only when the result is true, you pass the signal
// that the operation has finished.
// You can alse use `completer.complete(result)` if you want
// to pass data inside of the future.
if (result == true) completer.complete();
});
});
// You return the future straight away.
// It will be returned by requestServer();
return completer.future;
});
I use a function like this in a TestUtil library:
static Future<bool> waitUntilTrue(bool Function() callback,
{Duration timeout: const Duration(seconds: 2),
Duration pollInterval: const Duration(milliseconds: 50)}) {
var completer = new Completer<bool>();
var started = DateTime.now();
poll() {
var now = DateTime.now();
if (now.difference(started) >= timeout) {
completer.completeError(Exception('timed out in waitUntilTrue'));
return;
}
if (callback()) {
completer.complete(true);
} else {
new Timer(Duration(milliseconds: 100), () {
poll();
});
}
}
poll();
return completer.future;
}
And then in my test code I'll do something like:
await TestUtil.waitUntilTrue(() => someObj.isDone);
Edit:
Note that if you're using this in a testWidgets test, you have to do a little extra, since it relies on real async work happening:
await tester.runAsync<bool>(
() => TestUtil.waitUntilTrue(() => myObj.isLoaded),
additionalTime: Duration(seconds: 5));