L1-regularization: Where to use penalized cost function? - machine-learning

L1 Regularization adds a penalty term to the cost function to limit the size of the weights. Do I understand correctly that this penalized cost function is only used in the optimization step and not to calculate the loss of the model? E.g. to calculate the loss of the model in the validation set the not-penalized loss function is to be used ?

Yes, you are right. Loss function measures the difference of model prediction with the target value. Penalty term is used to prevent from over-fitting.

Related

Does the Cost Function matter when CODING Logistic Regression

NOTE: when you see (0) in the functions it represents Theta not Zero
I've been studying Andrew Ng's Machine Learning Course, and I have the following inquery:
(Short Version: If one were to look at all the mathematical expressions/calculations used for both Forward AND Backward propagation, then it appears to me that we never use the Cost Function directly, but its Derivative , so what is the importance of the cost function and its choice anyway? is it purely to evaluate our system whenever we feel like it?)
Andrew mentioned that for Logistic Regression, using the MSE (Mean Squared Error) Cost function
wouldn't be good, because applying it to our Sigmoid function would yield a non-convex cost function that has a lot of Local Optima, so it is best that we use the following logistic cost function:
Which will have 2 graphs (one for y=0 and one for y=1), both of which are convex.
My question is the following, since it is our objective to minimize the cost function (aka have the Derivative reach 0), which we achieve by using Gradient Descent, updating our weights using the Derivative of the Cost Function, which in both cases (both cost functions) is the same derivative:
dJ = (h0(x(i)) - y(i)) . x(i)
So how did the different choice of cost function in this case effect our algorithm in any way? because in forward propagation, all we need is
h0(x(i)) = Sigmoid(0Tx)
which can be calculated without ever needing to calculate the cost function, then in backward propagation and in updating the weights, we always use the derivative of the cost function, so when does the Cost Function itself come into play? is it just necessary when we want an indication of how well our network is doing? (then why not just depend on the derivative to know that)
The forward propagation does not need the cost function in any way because you just applying all your learned weights to the corresponding input.
The cost function is generally used to measure how good your algorihm is by comparing your models outcome (therefore applying your current weights to your input) with the true label of the input (in supervised algorithms). The main objective is therefore to minimize the cost function error as (in most cases) you want the difference of the prediction and the true label as small as possible. In optimization it is pretty helpful if your function you want to optimize is convex because it guarantees that if you find a local minimum it is at the same time the global minimum.
For minimizing the cost function, gradient descent is used to iteratively update your weights to get closer to the minimum. This is done w.r.t to the learned weights such that you are able to update your weights of the model for achieving the lowest possible costs. The backpropagation algorithm is used to adjust the weights using the cost function in the backward pass.
Technically, you are correct: we do not explicitly use the cost function in any of the calculations for forward propagation and back propagation.
You asked 'what is the importance of the cost function and its choice anyway?'. I have two answers:
The cost function is incredibly important because its gradient is what allows us to update our weights. Although we are only actually computing the gradient of the cost function and not the cost function itself, choosing a different cost function would mean we would have a different gradient, thus changing how we update our weights.
The cost function allows us to evaluate our model performance. It is common practice to plot cost vs epoch to understand how the cost decreases over time.
Your answer indicted you essentially understood all of this already but I hoped to clarify it a bit. Thanks!

Understanding logic behind Sparse Autoencoders

I am currently going through a sparse autoencoder. What I understood is we don't need all hidden units to fire for every input rather some specific hidden units depending on the type of input. For this we are adding a sparse regularization term to the loss function. But I am unable to get how adding this regularization term to loss function helps us in stopping certain hidden units to fire up?sparse autoencoder
But I am unable to get how adding this regularization term to loss function helps us in stopping certain hidden units to fire up?
Because the this regularization term will precisely penalize excessive activations. As opposed to conventional regularization, in which re penalize the weights through the L1 or L2 norms, in this case we penalize the output of the activation functions by a scale factor. This method ensures only a subset of neurons in a hidden layer are activated for specific inputs, which overall yields better results, since you end up with more "specialized" neurons, that only fire for specific inputs, rather than all.
So just think of it in the way conventional regularization works. By adding a regularization term in the loss function in a Lasso regression, we are penalizing high coefficients through the L1 norm, and enforcing that when minimized, the loss function will yield smaller weights. Well in sparse regularization we are instead shrinking the activation vectors and reducing the subset of neurons that will fire for each input.

What is weight decay loss?

I have started recently with ML and TensorFlow. While going through the CIFAR10-tutorial on the website I came across a paragraph which is a bit confusing to me:
The usual method for training a network to perform N-way classification is multinomial logistic regression, aka. softmax regression. Softmax regression applies a softmax nonlinearity to the output of the network and calculates the cross-entropy between the normalized predictions and a 1-hot encoding of the label. For regularization, we also apply the usual weight decay losses to all learned variables. The objective function for the model is the sum of the cross entropy loss and all these weight decay terms, as returned by the loss() function.
I have read a few answers on what is weight decay on the forum and I can say that it is used for the purpose of regularization so that values of weights can be calculated to get the minimum losses and higher accuracy.
Now in the text above I understand that the loss() is made of cross-entropy loss(which is the difference in prediction and correct label values) and weight decay loss.
I am clear on cross entropy loss but what is this weight decay loss and why not just weight decay? How is this loss being calculated?
Weight decay is nothing but L2 regularisation of the weights, which can be achieved using tf.nn.l2_loss.
The loss function with regularisation is given by:
The second term of the above equation defines the L2-regularization of the weights (theta). It is generally added to avoid overfitting. This penalises peaky weights and makes sure that all the inputs are considered. (Few peaky weights means only those inputs connected to it are considered for decision making.)
During gradient descent parameter update, the above L2 regularization ultimately means that every weight is decayed linearly: W_new = (1 - lambda)* W_old + alpha*delta_J/delta_w. Thats why its generally called Weight decay.
Weight decay loss, because it adds to the cost function (the loss to be specific). Parameters are optimized from the loss. Using weight decay you want the effect to be visible to the entire network through the loss function.
TF L2 loss
Cost = Model_Loss(W) + decay_factor*L2_loss(W)
# In tensorflow it bascially computes half L2 norm
L2_loss = sum(W ** 2) / 2
What your tutorial is trying to say by "weight decay loss" is that compared to the cross-entropy cost you know from your unregularized models (i.e. how far off target were your model's predictions on training data), your new cost function penalizes not only prediction error but also the magnitude of the weights in your network. Whereas before you were optimizing only for correct prediction of the labels in your training set, now you are optimizing for correct label prediction as well as having small weights. The reason for this modification is that when a machine learning model trained by gradient descent yields large weights, it is likely they were arrived at in response to peculiarities (or, noise) in the training data. The model will not perform as well when exposed to held-out test data because it is overfit to the training set. The result of applying weight decay loss, more commonly called L2-regularization is that accuracy on training data will drop a bit but accuracy on test data can jump dramatically. And that's what you're after in the end: a model that generalizes well to data it did not see during training.
So you can get a firmer grasp on the mechanics of weight decay, let's look at the learning rule for weights in a L2-regularized network:
where eta and lambda are user-defined learning rate and regularization parameter, respectively and n is the number of training examples (you'll have to look up those Greek letters if you're not familiar). Since the values eta and (eta*lambda)/n both are constants for a given iteration of training, it's enough to interpret the learning rule for weight decay as "for a given weight, subract a small multiple of the derivative of the cost function with respect to that weight, and subtract a small multiple of the weight itself."
Let's look at four weights in an imaginary network and how the above learning rule affects them. As you can see, the regularization term shown in red pushes weights toward zero no matter what. It is designed to minimize the magnitude of the weight matrix, which it does by minimizing the absolute values of individual weights. Some key things to notice in these plots:
When the sign of the cost derivative and the sign are the weight are the same, the regularization term accelerates the weight's path to its optimum!
The amount that the regularization term affects the weight update is proportional to the current value of that weight. I've shown this in the plots with tiny red arrows showing contributions of weights with current values close to zero, and larger red arrows for weights with larger current magnitudes.

How does regularization parameter work in regularization?

In machine learning cost function, if we want to minimize the influence of two parameters, let's say theta3 and theta4, it seems like we have to give a large value of regularization parameter just like the equation below.
I am not quite sure why the bigger regularization parameter reduces the influence instead of increasing it. How does this function work?
It is because that the optimum values of thetas are found by minimizing the cost function.
As you increase the regularization parameter, optimization function will have to choose a smaller theta in order to minimize the total cost.
Quoting from similar question's answer:
At a high level you can think of regularization parameters as applying a kind of Occam's razor that favours simple solutions. The complexity of models is often measured by the size of the model w viewed as a vector. The overall loss function as in your example above consists of an error term and a regularization term that is weighted by λ, the regularization parameter. So the regularization term penalizes complexity (regularization is sometimes also called penalty). It is useful to think what happens if you are fitting a model by gradient descent. Initially your model is very bad and most of the loss comes from the error terms, so the model is adjusted to primarily to reduce the error term. Usually the magnitude of the model vector increases as the optimization progresses. As the model is improving and the model vector is growing the regularization term becomes a more significant part of the loss. Regularization prevents the model vector growing arbitrarily for negligible reductions in the error. λ just determines the relative importance of keeping the model simple relative to reducing training error.
There are different types of regularization terms in common use. The one you have, and most commonly used in SVMs, is L2 regularization. It has the side effect of spreading weight more evenly between the components of the model vector. The main alternative is L1 or lasso regularization which has the form λ∑i|wi|, ie it penalizes the sum absolute values of the model parameters. It favors concentrating the size of the model in only a few components, the opposite of L2 regularization. Generally L2 tends to be preferable for low dimensional models while lasso tends to work better for high dimensional models like text classification where it leads to sparse models, ie models with few non-zero parameters.
There is also elastic net regularization, which is just a weighted combination of L1 and L2 regularization. So you have 3 terms in your loss function: error term and the 2 regularization terms each with its own regularization parameter.
You said that you want to minimize the influence of two parameters, theta3 and theta4, meaning those two are both NOT important, so we are going to tell the model we want to fit by:
minimize the weights of theta3 and theta4 cause they don't really matter
And here is the learning process of the model:
Given theta3 and theta4 a really big parameter lambda , when theta3 or theta4 grows, your loss functions grows heavily relatively cause they(theta3 and theta4) both have a big multiplier(lambda), to minimize your object function(loss function), both theta3 and theta4 can only be chosen a very small value, saying that they are not important.
As regularization parameter increases from 0 to infinity, the residual sum of squares in linear regression decreases ,Variance of model decreases and Bias increases .
I will try it in most simple language. i think what you are asking is, how does adding a regularization term at the end deceases the value of parameters like theta3 and theta4 here.
So, lets first assume you added this to the end of your loss function which should massively increase the loss, making the function a bit more bias compared to before. Now we will use any optimization method, lets say gradient descent here and the job of gradient descent is to find all values of theta, now remember the fact that until this point we dont any value of theta and if you solve it you will realize the the values of theta are gonna be different if you hadnt used the regularization term at the end. To be exact, its gonna be less for theta3 and theta4.
So this will make sure your hypothesis has more bias and less variance. In simple term, it will make the equation is bit worse or not as exact as before but it will generalize the equation better.

What is a loss function in simple words?

Can anyone please explain in simple words and possibly with some examples what is a loss function in the field of machine learning/neural networks?
This came out while I was following a Tensorflow tutorial:
https://www.tensorflow.org/get_started/get_started
It describes how far off the result your network produced is from the expected result - it indicates the magnitude of error your model made on its prediciton.
You can then take that error and 'backpropagate' it through your model, adjusting its weights and making it get closer to the truth the next time around.
The loss function is how you're penalizing your output.
The following example is for a supervised setting i.e. when you know the correct result should be. Although loss functions can be applied even in unsupervised settings.
Suppose you have a model that always predicts 1. Just the scalar value 1.
You can have many loss functions applied to this model. L2 is the euclidean distance.
If I pass in some value say 2 and I want my model to learn the x**2 function then the result should be 4 (because 2*2 = 4). If we apply the L2 loss then its computed as ||4 - 1||^2 = 9.
We can also make up our own loss function. We can say the loss function is always 10. So no matter what our model outputs the loss will be constant.
Why do we care about loss functions? Well they determine how poorly the model did and in the context of backpropagation and neural networks. They also determine the gradients from the final layer to be propagated so the model can learn.
As other comments have suggested I think you should start with basic material. Here's a good link to start off with http://neuralnetworksanddeeplearning.com/
Worth to note we can speak of different kind of loss functions:
Regression loss functions and classification loss functions.
Regression loss function describes the difference between the values that a model is predicting and the actual values of the labels.
So the loss function has a meaning on a labeled data when we compare the prediction to the label at a single point of time.
This loss function is often called the error function or the error formula.
Typical error functions we use for regression models are L1 and L2, Huber loss, Quantile loss, log cosh loss.
Note: L1 loss is also know as Mean Absolute Error. L2 Loss is also know as Mean Square Error or Quadratic loss.
Loss functions for classification represent the price paid for inaccuracy of predictions in classification problems (problems of identifying which category a particular observation belongs to).
Name a few: log loss, focal loss, exponential loss, hinge loss, relative entropy loss and other.
Note: While more commonly used in regression, the square loss function can be re-written and utilized for classification.

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