I have a loop that adds numbers in groups of a certain number which can be inputted by the user.
no_reps = #trial.number_of_repetitions
I'm looking to input a random number between one and the no_reps variable in groups of no_reps variable.
Current the r.treatment_index = SecureRandom.random_number(1..no_reps) isn't putting in unique numbers. The values match the range, but aren't unique per in_groups_of.
#trial.repetitions.in_groups_of(no_reps).each_with_index do |a, i|
a.each do |r|
r.repetition_index = i + 1
r.treatment_index = SecureRandom.random_number(1..no_reps)
end
end
Try to #shuffle prepopulated array:
#trial.repetitions.in_groups_of(no_reps).each_with_index do |a, i|
treatment_indexes = (1..no_reps).to_a.shuffle
a.each_with_index do |r, j|
r.repetition_index = i + 1
r.treatment_index = treatment_indexes[j]
end
end
UPD: If you take care about speed:
treatment_indexes = (1..no_reps).to_a
#trial.repetitions.in_groups_of(no_reps).each_with_index do |a, i|
treatment_indexes.shuffle!
...
Related
I am working on a kind of order where I have multiple amount in different currencies in just one attribute. So am trying to make sum on different currencies inside that attribute using other attributes in the table, which works fine but outputs the result as a count of all the rows instead of just showing the sum of the random values calculated.
orders_controller.rb
module Admin
module Statistic
class OrdersController < BaseController
def show
#orders_grid = ::Statistic::OrdersGrid.new(params[:statistic_orders_grid]) do |value|
value.page(params[:page]).per(20)
end
#assets = #orders_grid.assets
##fee_groups = {:fee => #assets.sum(:fee)}
#fee_groups = {
:fee => #assets.sum{|t|
olaoa = t.type
market_string = t.currency
base_currency = market_string.slice(0..2)
quote_currency = market_string.slice(3..5)
if olaoa == 'OrderBid' and base_currency == 'btc'
"#{ t.fee.to_s + ' ' + base_currency.upcase }"
elsif olaoa == 'OrderAsk' and quote_currency == 'ngn'
"#{ t.fee.to_s + ' ' + quote_currency.upcase }"
end
}
}
#orders_filter = true
#orders_group = true
end
end
end
end
summary.htm.slim
.panel.panel-default
.panel-heading
h4.panel-title.row
a data-parent="#filter-accordion" data-toggle="collapse" href="#summary"
span.col-xs-8.text-muted = t('admin.statistic.summary')
span.col-xs-4.text-right.text-muted = t('admin.statistic.click-to-expand')
#summary.panel-collapse.collapse
.panel-body
.datagrid-groups
- if !#orders_group
- if groups
- groups.each do |key, val|
.datagrid.group.row
span.col-xs-2.title = t("admin.statistic.#{controller_name}.#{controller.action_name}.#{key}")
span.col-xs-10.value = val
- if #orders_group
/ Summary Count Loop
- if groups
- groups.each do |key, val|
.datagrid.group.row
span.col-xs-2.title = t("admin.statistic.#{controller_name}.#{controller.action_name}.#{key}")
span.col-xs-10.value = pluralize(val, 'Order')
/ Summary Fees Loop. This is the Fee loop causing problem if am rigth and I dont know how to fix this.
- if #fee_groups
- #fee_groups.each do |key, val|
.datagrid.group.row
span.col-xs-2.title = t("admin.statistic.#{controller_name}.#{controller.action_name}.#{key}")
span.col-xs-10.value = val
The result of the code
So as you can see it renders 0.0BTC 5 times because the filter only has 5 orders. How do i deal with this. I want just the sum of all BTCs to show in the result instead of showing it 5 times.
Any help will be appreciated.
Because you sum strings in you're #fee_groups query that will results in putting strings next to each other instead of a total amount.
If you call it like this
#fee_groups = { fee: #assets.sum{|t| t.fee}}
You will get the total sum of you're assets.
I have an array PARTITION which stores days.
I want to group_by my posts (ActiveRecord::Relation) according to how old are they and in which partition they lie.
Example: PARTITION = [0, 40, 60, 90]
I want to group posts which are 0 to 40 days old, 40 to 60 days old, 60 to 90 days old and older than 90 days.
Please note that I will get array data from an external source and I don't want to use a where clause because I am using includes and where fires db query making includes useless.
How can I do this?
Here's a simple approach:
posts.each_with_object(Hash.new { |h, k| h[k] = [] }) do |post, hash|
days_old = (Date.today - post.created_at.to_date).to_i
case days_old
when 0..39
hash[0] << post
when 40..59
hash[40] << post
when 60..89
hash[60] << post
when 90..Float::INFINITY # or 90.. in the newest Ruby versions
hash[90] << post
end
end
This iterates through the posts, along with a hash which has a default value of an empty array.
Then, we simply check how many days ago a post was created and add it to relevant key of the hash.
This hash is then returned when all posts have been processed.
You can use whatever you want for the keys (e.g. hash["< 40"]), though I've used your partitions for illustrative purposes.
The result will be something akin to the following:
{ 0: [post_1, post_3, etc],
40: [etc],
60: [etc],
90: [etc] }
Hope this helps - let me know if you've got any questions.
Edit: it's a little trickier if your PARTITIONS are coming from an external source, though the following would work:
# transform the PARTITIONS into an array of ranges
ranges = PARTITIONS.map.with_index do |p, i|
return 0..(p - 1) if i == 0 # first range is 0..partition minus 1
return i..Float::INFINITY if i + 1 == PARTITIONS.length # last range is partition to infinity
p..(PARTITIONS[i + 1] - 1)
end
# loop through the posts with a hash with arrays as the default value
posts.each_with_object(Hash.new { |h, k| h[k] = [] }) do |post, hash|
# loop through the new ranges
ranges.each do |range|
days_old = Date.today - post.created_at.to_date
hash[range] << post if range.include?(days_old) # add the post to the hash key for the range if it's present within the range
end
end
A final edit:
Bit silly using each_with_object when group_by will handle this perfectly. Example below:
posts.group_by |post|
days_old = (Date.today - post.created_at.to_date).to_i
case days_old
when 0..39
0
when 40..59
40
when 60..89
60
when 90..Float::INFINITY # or 90.. in the newest Ruby versions
90
end
end
Assumptions:
This partitioning is for display purposes.
The attribute you want to group by is days
You want to the result a hash
{ 0 => [<Post1>], 40 => [<Post12>], 60 => [<Post41>], 90 => [<Post101>] }
add these methods to your model
# post.rb
def self.age_partitioned
group_by(&:age_partition)
end
def age_partition
[90, 60, 40, 0].find(days) # replace days by the correct attribute name
end
# Now to use it
Post.where(filters).includes(:all_what_you_want).age_partitioned
As per the description given in the post, something done as below could help you group the data:
result_array_0_40 = [];result_array_40_60 = [];result_array_60_90 = [];result_array_90 = [];
result_json = {}
Now, we need to iterate over values and manually group them into dynamic key value pairs
PARTITION.each do |x|
result_array_0_40.push(x) if (0..40).include?(x)
result_array_40_60.push(x) if (40..60).include?(x)
result_array_60_90.push(x) if (60..90).include?(x)
result_array_90.push(x) if x > 90
result_json["0..40"] = result_array_0_40
result_json["40..60"] = result_array_40_60
result_json["60..90"] = result_array_60_90
result_json["90+"] = result_array_90
end
Hope it Helps!!
I have an array of hashes lets say offers = {offer1,...,offer6}. Each offer is a hash.
Each offer has various keys one of which is a price hash:
offer1 = {..., :price => {:amount => 400, :amount2 => 300, :currency => "INR",...}
Now I want to return a hash with only the unique hashes/offers. Also, I want :price hash to have the values averaged.
So, the final offers array will have:
offers=[offer1, offer2,...]
offer1[:price] will have values equal to average of the values of each key from duplicated offer hashes and same with offer2[:price] and so on so that in end I end with an hash with only unique offers.
offers1..6 can be duplicate with same id and price hash different. If they are duplicate we need to do the averaging otherwise not.
Is there an elegant way to do all of this?
I have tried grouping the hashes with a unique key and merging the price hashes of each. But am unable to reach the final solution.
my attempt:
rooms_hash = rooms.map do |room|
unless room[:offers].uniq.count == room[:offers].count
grouped_offers = room[:offers].group_by{|x| x[:room_category_id]}
offer_values = grouped_offers.values
price_array = offer_values.map do |v|
v.inject do |k, v|
k.merge!(price: k[:price].merge(v[:price]){|_, a, b| [a, b].flatten })
end
end
price_array.map do |o|
o[:price] = {}.tap{ |h| o[:price].each {|k, list| h[k] = list.all?{|e| [Fixnum, NilClass].include? e.class} ? list.map(&:to_i).sum/list.size : list.compact.first ; h } }
end
price_array
end
end
rooms.zip(rooms_hash).map do |room,averaged_offers|
if room[:offers].count > 1
room[:offers] = averaged_offers.select{|offer| offer[:room_category_id] == room[:room_category_id]}
room
end
end
This code actually fails when I don't get any duplicates. So how can I check for that as well?
Edit:
Yes offers is an array and offers1..6 are hashes.
offer1..._hash = {:offer_id=>"uuid", :price=>{:amount=>4422380, :gross_amount=>4422380, :currency=>"INR", :tax=>434318, :hotel_fees=>0, :base_fare=>3988062}, .....}
Let's say i have two relation arrays of a user's daily buy and sell.
how do i iterate through both of them using .each and still let the the longer array run independently once the shorter one is exhaused. Below i want to find the ratio of someone's daily buys and sells. But can't get the ratio because it's always 1 as i'm iterating through the longer array once for each item of the shorter array.
users = User.all
ratios = Hash.new
users.each do |user|
if user.buys.count > 0 && user.sells.count > 0
ratios[user.name] = Hash.new
buy_array = []
sell_array = []
date = ""
daily_buy = user.buys.group_by(&:created_at)
daily_sell = user.sells.group_by(&:created_at)
daily_buy.each do |buy|
daily_sell.each do |sell|
if buy[0].to_date == sell[0].to_date
date = buy[0].to_date
buy_array << buy[1]
sell_array << sell[1]
end
end
end
ratio_hash[user.name][date] = (buy_array.length.round(2)/sell_array.length)
end
end
Thanks!
You could concat both arrays and get rid of duplicated elements by doing:
(a_array + b_array).uniq.each do |num|
# code goes here
end
Uniq method API
daily_buy = user.buys.group_by(&:created_at)
daily_sell = user.sells.group_by(&:created_at
buys_and_sells = daily_buy + daily_sell
totals = buys_and_sells.inject({}) do |hsh, transaction|
hsh['buys'] ||= 0;
hsh['sells'] ||= 0;
hsh['buys'] += 1 if transaction.is_a?(Buy)
hsh['sells'] += 1 if transaction.is_a?(Sell)
hsh
end
hsh['buys']/hsh['sells']
I think the above might do it...rather than collecting each thing in to separate arrays, concat them together, then run through each item in the combined array, increasing the count in the appropriate key of the hash returned by the inject.
In this case you can't loop them with each use for loop
this code will give you a hint
ar = [1,2,3,4,5]
br = [1,2,3]
array_l = (ar.length > br.length) ? ar.length : br.length
for i in 0..array_l
if ar[i] and br[i]
puts ar[i].to_s + " " + br[i].to_s
elsif ar[i]
puts ar[i].to_s
elsif br[i]
puts br[i].to_s
end
end
I want to make a loop on a variable that can be altered inside of the loop.
first_var.sort.each do |first_id, first_value|
second_var.sort.each do |second_id, second_value_value|
difference = first_value - second_value
if difference >= 0
second_var.delete(second_id)
else
second_var[second_id] += first_value
if second_var[second_id] == 0
second_var.delete(second_id)
end
first_var.delete(first_id)
end
end
end
The idea behind this code is that I want to use it for calculating how much money a certain user is going to give some other user. Both of the variables contain hashes. The first_var is containing the users that will get money, and the second_var is containing the users that are going to pay. The loop is supposed to "fill up" a user that should get money, and when a user gets full, or a user is out of money, to just take it out of the loop, and continue filling up the rest of the users.
How do I do this, because this doesn't work?
Okay. What it looks like you have is two hashes, hence the "id, value" split.
If you are looping through arrays and you want to use the index of the array, you would want to use Array.each_index.
If you are looping through an Array of objects, and 'id' and 'value' are attributes, you only need to call some arbitrary block variable, not two.
Lets assume these are two hashes, H1 and H2, of equal length, with common keys. You want to do the following: if H1[key]value is > than H2[key]:value, remove key from H2, else, sum H1:value to H2:value and put the result in H2[key].
H1.each_key do |k|
if H1[k] > H2[k] then
H2.delete(k)
else
H2[k] = H2[k]+H1[k]
end
end
Assume you are looping through two arrays, and you want to sort them by value, and then if the value in A1[x] is greater than the value in A2[x], remove A2[x]. Else, sum A1[x] with A2[x].
b = a2.sort
a1.sort.each_index do |k|
if a1[k] > b[k]
b[k] = nil
else
b[k] = a1[k] + b[k]
end
end
a2 = b.compact
Based on the new info: you have a hash for payees and a hash for payers. Lets call them ees and ers just for convenience. The difficult part of this is that as you modify the ers hash, you might confuse the loop. One way to do this--poorly--is as follows.
e_keys = ees.keys
r_keys = ers.keys
e = 0
r = 0
until e == e_keys.length or r == r_keys.length
ees[e_keys[e]] = ees[e_keys[e]] + ers[r_keys[r]]
x = max_value - ees[e_keys[e]]
ers[r_keys[r]] = x >= 0 ? 0 : x.abs
ees[e_keys[e]] = [ees[e_keys[e]], max_value].min
if ers[r_keys[r]] == 0 then r+= 1 end
if ees[e_keys[e]] == max_value then e+=1 end
end
The reason I say that this is not a great solution is that I think there is a more "ruby" way to do this, but I'm not sure what it is. This does avoid any problems that modifying the hash you are iterating through might cause, however.
Do you mean?
some_value = 5
arrarr = [[],[1,2,5],[5,3],[2,5,7],[5,6,2,5]]
arrarr.each do |a|
a.delete(some_value)
end
arrarr now has the value [[], [1, 2], [3], [2, 7], [6, 2]]
I think you can sort of alter a variable inside such a loop but I would highly recommend against it. I'm guessing it's undefined behaviour.
here is what happened when I tried it
a.each do |x|
p x
a = []
end
prints
1
2
3
4
5
and a is [] at the end
while
a.each do |x|
p x
a = []
end
prints nothing
and a is [] at the end
If you can I'd try using
each/map/filter/select.ect. otherwise make a new array and looping through list a normally.
Or loop over numbers from x to y
1.upto(5).each do |n|
do_stuff_with(arr[n])
end
Assuming:
some_var = [1,2,3,4]
delete_if sounds like a viable candidate for this:
some_var.delete_if { |a| a == 1 }
p some_var
=> [2,3,4]