Start second while loop only after first is finished - lua

Question

I'm trying to write a function that puts the remaining seconds into a human readable format. The problem I'm having(I think) is that my second while loop is trying to do it's job before the first is finished. I'll end up with "1 hour, 271 minutes and 37 seconds. In my latest attempt, I tried to use minNeeded but that doesn't work either because it's checking for it's existence prior to the first loop being finished. How can I manage this?
function prettyTime(secs)
local hr = 0
local hrDisplay = ''
local min = 0
local minDislplay = ''
local minNeeded = 0
if(secs >= 3600) then
while secs >= 3600 do
secs = secs - 3600
hr = hr + 1
if secs < 3600 then
secsRemaining = secs
minNeeded = 1
end
end
else
minNeeded = 1
end
while true do
if(minNeeded == 1){
while secsRemaining >= 60 do
secsRemaining = secsRemaining - 60
min = min + 1
end
end
end
if hr > 1 then
hrDisplay = hr .. ' hours, '
elseif hr == 1 then
hrDisplay = '1 hour, '
end
if min > 1 then
minDisplay = min .. ' minutes and '
elseif min == 1 then
minDisplay = '1 minute and '
else
minDisplay = ''
end
return hrDisplay .. minDisplay .. secs .. ' seconds'
end

Answer 1

your Code has few bugs, if(minNeeded == 1){ is syntax error, while true do will never break.
Here is the simple converter,
function prettyTime(sec)
local sec = tonumber(sec)
if sec <= 0 then
return "00.00.00";
else
h = tonumber(string.format("%02.f", math.floor(sec/3600)))
m = tonumber(string.format("%02.f", math.floor(sec/60 - (h*60))))
s = tonumber(string.format("%02.f", math.floor(sec - h*3600 - m*60)))
-- return h.."."..m.."."..s
end
local res = ''
if h == 1 then
res = res ..h .. ' hour, '
elseif h > 1 then
res = res ..h .. ' hours, '
end
if m <= 1 then
res = res ..m .. ' minute, '
elseif m > 1 then
res = res ..m .. ' minute, '
end
if s <= 1 then
res = res ..s .. ' second, '
elseif s > 1 then
res = res ..s .. ' seconds '
end
return res
end
print(prettyTime(3670)) -- 1 hour, 1 minute, 10 seconds