How to convert my stringArray to int8Array. Please give me any solution to convert this.
I want below type of array
let int8Array:[UInt8] = [ox55,0x55,0xff,0x01,0x0B,0x00,0x0B,0x03,0x07,0x12,0x0E,0x0C,0x10,0x09,0x12,0x0C,0x19,0x09,0xFF,0x14]
Below is my ViewController:
class ViewController:UIViewController {
var checkSum:UInt8 = 0
override func viewDidLoad() {
super.viewDidLoad()
let stringArray:[String] = ["0x55", "0x55", "0xff", "0x01", "0x0B", "0x38", "0x18", "0x31", "0x10", "0x18", "0x0E", "0x16", "0x31", "0x10", "0x18", "0x16", "0x30", "0x11", "0x18", "0x20", "0xE1"]
var int8Array:[UInt8] = stringArray.map{ UInt8($0.dropFirst(2), radix: 16)! }
int8Array.removeFirst()
int8Array.removeFirst()
int8Array.removeFirst()
print(int8Array)
for item in int8Array {
checkSum = calculateCheckSum(crc: checkSum, byteValue: UInt8(item))
}
print(checkSum)
}
func calculateCheckSum(crc:UInt8, byteValue: UInt8) -> UInt8 {
let generator: UInt8 = 0x1D
var newCrc = crc ^ byteValue
for _ in 1...8 {
if (newCrc & 0x80 != 0) {
newCrc = (newCrc << 1) ^ generator
}
else {
newCrc <<= 1
}
}
return newCrc
}
}
If it is an option you could switch it around to specify the UInt8 array and derive the String array from that.
let int8Array: [UInt8] = [0x55, 0x55, 0xa5, 0x3f]
var stringArray: [String] {
return int8Array.map { String(format: "0x%02X", $0) }
}
print(stringArray)
// ["0x55", "0x55", "0xA5", "0x3F"]
Just map the stuff, you have to remove 0x to make the UInt8(_:radix:) initializer work.
let uint8Array = stringArray.map{ UInt8($0.dropFirst(2), radix: 16)! }
First take your string array and call map on it then map it to a [UInt8] (where the total result will be [[UInt8]] and call flatMap on the result to get an array of [UInt8].. then you can do forEach on it to calculate your checksum or w/e..
[String].init().map({
[UInt8]($0.utf8)
}).flatMap({ $0 }).forEach({
print($0) //Print each byte or convert to hex or w/e..
})
Related
I'm was trying to convert hexString to Array of Bytes([UInt8]) I searched everywhere but couldn't find a solution. Below is my swift 2 code
func stringToBytes(_ string: String) -> [UInt8]? {
let chars = Array(string)
let length = chars.count
if length & 1 != 0 {
return nil
}
var bytes = [UInt8]()
bytes.reserveCapacity(length/2)
for var i = 0; i < length; i += 2 {
if let a = find(hexChars, chars[i]),
let b = find(hexChars, chars[i+1]) {
bytes.append(UInt8(a << 4) + UInt8(b))
} else {
return nil
}
}
return bytes
}
Example Hex
Hex : "7661706f72"
expectedOutput : "vapor"
This code can generate the same output as your swift 2 code.
func stringToBytes(_ string: String) -> [UInt8]? {
let length = string.characters.count
if length & 1 != 0 {
return nil
}
var bytes = [UInt8]()
bytes.reserveCapacity(length/2)
var index = string.startIndex
for _ in 0..<length/2 {
let nextIndex = string.index(index, offsetBy: 2)
if let b = UInt8(string[index..<nextIndex], radix: 16) {
bytes.append(b)
} else {
return nil
}
index = nextIndex
}
return bytes
}
let bytes = stringToBytes("7661706f72")
print(String(bytes: bytes!, encoding: .utf8)) //->Optional("vapor")
Here is a sketch of how I'd do it in a more idiomatic Swift style (this might be Swift 4 only):
func toPairsOfChars(pairs: [String], string: String) -> [String] {
if string.count == 0 {
return pairs
}
var pairsMod = pairs
pairsMod.append(String(string.prefix(2)))
return toPairsOfChars(pairs: pairsMod, string: String(string.dropFirst(2)))
}
func stringToBytes(_ string: String) -> [UInt8]? {
// omit error checking: remove '0x', make sure even, valid chars
let pairs = toPairsOfChars(pairs: [], string: string)
return pairs.map { UInt8($0, radix: 16)! }
}
Following code may be help for you
extension String {
/// Create `Data` from hexadecimal string representation
///
/// This takes a hexadecimal representation and creates a `Data` object. Note, if the string has any spaces or non-hex characters (e.g. starts with '<' and with a '>'), those are ignored and only hex characters are processed.
///
/// - returns: Data represented by this hexadecimal string.
func hexadecimal() -> Data? {
var data = Data(capacity: characters.count / 2)
let regex = try! NSRegularExpression(pattern: "[0-9a-f]{1,2}", options: .caseInsensitive)
regex.enumerateMatches(in: self, options: [], range: NSMakeRange(0, characters.count)) { match, flags, stop in
let byteString = (self as NSString).substring(with: match!.range)
var num = UInt8(byteString, radix: 16)!
data.append(&num, count: 1)
}
guard data.count > 0 else {
return nil
}
return data
}
}
extension String {
/// Create `String` representation of `Data` created from hexadecimal string representation
///
/// This takes a hexadecimal representation and creates a String object from that. Note, if the string has any spaces, those are removed. Also if the string started with a `<` or ended with a `>`, those are removed, too.
init?(hexadecimal string: String) {
guard let data = string.hexadecimal() else {
return nil
}
self.init(data: data, encoding: .utf8)
}
/// - parameter encoding: The `NSStringCoding` that indicates how the string should be converted to `NSData` before performing the hexadecimal conversion.
/// - returns: `String` representation of this String object.
func hexadecimalString() -> String? {
return data(using: .utf8)?
.hexadecimal()
}
}
extension Data {
/// Create hexadecimal string representation of `Data` object.
/// - returns: `String` representation of this `Data` object.
func hexadecimal() -> String {
return map { String(format: "%02x", $0) }
.joined(separator: "")
}
}
Use like this :
let hexString = "68656c6c 6f2c2077 6f726c64"
print(String(hexadecimalString: hexString))
Or
let originalString = "hello, world"
print(originalString.hexadecimalString())
After lot searching and thinking here is how you do it
func toByteArray( _ hex:String ) -> [UInt8] {
// remove "-" from Hexadecimal
var hexString = hex.removeWord( "-" )
let size = hexString.characters.count / 2
var result:[UInt8] = [UInt8]( repeating: 0, count: size ) // array with length = size
// for ( int i = 0; i < hexString.length; i += 2 )
for i in stride( from: 0, to: hexString.characters.count, by: 2 ) {
let subHexStr = hexString.subString( i, length: 2 )
result[ i / 2 ] = UInt8( subHexStr, radix: 16 )! // ! - because could be null
}
return result
}
extension String {
func subString( _ from: Int, length: Int ) -> String {
let size = self.characters.count
let to = length + from
if from < 0 || to > size {
return ""
}
var result = ""
for ( idx, char ) in self.characters.enumerated() {
if idx >= from && idx < to {
result.append( char )
}
}
return result
}
func removeWord( _ word:String ) -> String {
var result = ""
let textCharArr = Array( self.characters )
let wordCharArr = Array( word.characters )
var possibleMatch = ""
var i = 0, j = 0
while i < textCharArr.count {
if textCharArr[ i ] == wordCharArr[ j ] {
if j == wordCharArr.count - 1 {
possibleMatch = ""
j = 0
}
else {
possibleMatch.append( textCharArr[ i ] )
j += 1
}
}
else {
result.append( possibleMatch )
possibleMatch = ""
if j == 0 {
result.append( textCharArr[ i ] )
}
else {
j = 0
i -= 1
}
}
i += 1
}
return result
}
}
Refer this video to know how I did it.
Credit : AllTech
Conversion of String to Data with nicer syntax.
static func hexStringToData(string: String) -> Data {
let stringArray = Array(string)
var data: Data = Data()
for i in stride(from: 0, to: string.count, by: 2) {
let pair: String = String(stringArray[i]) + String(stringArray[i+1])
if let byteNum = UInt8(pair, radix: 16) {
let byte = Data([byteNum])
data.append(byte)
}
else{
fatalError()
}
}
return data
}
This is my code to convert byte data to float. I tried every answers given in this site. I am getting exponential value for this "<44fa0000>" byte data
static func returnFloatValue(mutableData:NSMutableData)->Float
{
let qtyRange = mutableData.subdataWithRange(NSMakeRange(0, 4))
let qtyString = String(qtyRange)
let qtyTrimString = qtyString.stringByTrimmingCharactersInSet(NSCharacterSet(charactersInString: "<>"))
let qtyValue = Float(strtoul(qtyTrimString, nil, 16)/10)
return qtyValue
}
Thanks
<44fa0000> is the big-endian memory representation of the
binary floating point number 2000.0. To get the number back from
the data, you have to read it into an UInt32 first, convert from
big-endian to host byteorder, and then cast the result to
a Float.
In Swift 2 that would be
func floatValueFromData(data: NSData) -> Float {
return unsafeBitCast(UInt32(bigEndian: UnsafePointer(data.bytes).memory), Float.self)
}
Example:
let bytes: [UInt8] = [0x44, 0xFA, 0x00, 0x00]
let data = NSData(bytes: bytes, length: 4)
print(data) // <44fa0000>
let f = floatValueFromData(data)
print(f) // 2000.0
In Swift 3 you would use Data instead of NSData, and the
unsafeBitCast can be replaced by the Float(bitPattern:)
initializer:
func floatValue(data: Data) -> Float {
return Float(bitPattern: UInt32(bigEndian: data.withUnsafeBytes { $0.pointee } ))
}
In Swift 5 the withUnsafeBytes() method of Data calls the closure with an (untyped) UnsafeRawBufferPointer, and you can load() the value from the raw memory:
func floatValue(data: Data) -> Float {
return Float(bitPattern: UInt32(bigEndian: data.withUnsafeBytes { $0.load(as: UInt32.self) }))
}
Here is some swift 5:
let data = Data([0x44, 0xfa, 0x00, 0x00]) // 0x44fa0000
let floatNb:Float = data.withUnsafeBytes { $0.load(as: Float.self) }
// note that depending on the input endianess, you could add .reversed() to data
let floatNb:Float = data.reversed().withUnsafeBytes { $0.load(as: Float.self) }
WARNING: this sample throws if your Data is under 4 bytes..
.
Safe Data extension:
extension Data {
enum Endianess {
case little
case big
}
func toFloat(endianess: Endianess = .little) -> Float? {
guard self.count <= 4 else { return nil }
switch endianess {
case .big:
let data = [UInt8](repeating: 0x00, count: 4-self.count) + self
return data.withUnsafeBytes { $0.load(as: Float.self) }
case .little:
let data = self + [UInt8](repeating: 0x00, count: 4-self.count)
return data.reversed().withUnsafeBytes { $0.load(as: Float.self) }
}
}
}
Tests:
let opData = Data([0x44, 0xFA, 0x00, 0x00])
let nb42 = Data([0x42, 0x28])
let nb42bigEndian = Data([0x28, 0x42])
let tooBig = Data([0x44, 0xFA, 0x00, 0x00, 0x00])
print("opData: \(opData.toFloat())")
print("nb42: \(nb42.toFloat())")
print("nb42bigEndian: \(nb42bigEndian.toFloat(endianess: .big))")
print("tooBig: \(tooBig.toFloat())")
you may find a faster way but this was good enough for my needs
Use this function:
static func returnFloatValue(data: NSMutableData) -> Float {
let bytes = [UInt8](data as Data)
var f: Float = 0
memcpy(&f, bytes, 4)
return f
}
And you can see it in action here:
var initialValue: Float = 19.200
let data = NSMutableData(bytes: &initialValue, length: 4)
func returnFloatValue(data: NSMutableData) -> Float {
let bytes = [UInt8](data as Data)
var f: Float = 0
memcpy(&f, bytes, 4)
return f
}
var result:Float = returnFloatValue(data: data)
print("f=\(result)")// f=19.2
For 64 bit values the code is:
static func longBitsToDouble(x : Int64) -> Float64
{ return Float64(bitPattern: UInt64(x)) }
Swift 4+.
extension String {
var masked: String {
// some logic which I have to write to mask string.
// I tried following and just shows x 🤦♂️
// replacingOccurrences(
// of: ".(.+).",
// with: "x",
// options: .regularExpression,
// range: nil
//)
}
}
let helloWorld = "Hello World"
print("Masked string is - \(helloWorld.masked)")
Expected output is - "Hxxxxxxxxxd"
There is a Regular Expression way with lookaround
extension String {
var masked: String {
replacingOccurrences(
of: "(?!^).(?!$)", // RegEx
with: "x", // Replacement
options: .regularExpression // Option to set RegEx
)
}
}
You can enumerate the string and apply map transform to get the expected output:
extension String {
var masked: String {
self.enumerated().map({ (index, ch) in
if index == 0
|| index == self.count - 1 {
return String(ch)
}
return "x"
}).joined()
}
}
let str = "hello"
print("after masking \(str.masked)") // Output - hxxxo
The map transform will return an array, so use joined() to convert the array back to String. Also, note that you have to typecast ch to String as String(ch) because the type of ch is 'String.Element' (aka 'Character').
extension Sequence {
func replacingEachInteriorElement(with replacement: Element) -> [Element] {
let prefix = dropLast()
return
prefix.prefix(1)
+ prefix.dropFirst().map { _ in replacement }
+ suffix(1)
}
}
extension String {
var masked: Self {
.init( replacingEachInteriorElement(with: "x") )
}
}
"Hello World".masked == "Hxxxxxxxxxd" // true
"H🦾👄🐺🥻🐸🦈🏄♂️🍯🪐d".masked == "Hello World".masked // true
"🥮".masked // 🥮
"🥶😎".masked // 🥶😎
[].replacingEachInteriorElement(with: 500) // []
My solution without using Regular Expression:
extension String {
var masked: String {
if self.count < 2 { return self }
var output = self
let range = self.index(after: self.startIndex)..<self.index(before: endIndex)
let replacement = String.init(repeating: "x", count: output.count - 2)
output.replaceSubrange(range, with: replacement)
return output
}
}
So far, I've found following solution.
extension String {
var masked: String {
var newString = ""
for index in 0..<count {
if index != 0 && index != count-1 {
newString.append(contentsOf: "x")
} else {
let array = Array(self)
let char = array[index]
let string = String(char)
newString.append(string)
}
}
return newString
}
}
If you want to leave first and last letters you can use this ->
public extension String {
var masked: String {
return prefix(1) + String(repeating: "x", count: Swift.max(0, count-2)) + suffix(1)
}
}
USAGE
let hello = "Hello"
hello.masked
// Hxxxo
OR
you can pass unmasked character count ->
public extension String {
func masked(with unmaskedCount: Int) -> String {
let unmaskedPrefix = unmaskedCount/2
return prefix(unmaskedPrefix) + String(repeating: "x", count: Swift.max(0, count-unmaskedPrefix)) + suffix(unmaskedPrefix)
}
}
USAGE
let hello = "Hello"
hello.masked(with: 2)
// Hxxxo
let number = "5555555555"
number.masked(with: 4)
// 55xxxxxx55
I have successfully scan and read the stringValue from QR.But couldn't convert the stringValue to readable format.
https://uidai.gov.in/images/resource/User_manulal_QR_Code_15032019.pdf
I have tried to convert using the above procedure but couldn't succeed.
1) I have tried library to convert to BigInt and converted to binary value
let str = String(self.metadataStringValue, radix: 2)
print(str)
2)Convert the Big Integer into byte array successfully
let byteArray = Array(BigUInt(str)!.serialize())
print(byteArray)
3) Used Apple's decompression algorithm (zlib)
4) Read the value of byte array from index 0 to till first delimiter value“255” and convert this byte array value into string with encoding “ISO-8859-1”.
var firstDelimiter = ArraySlice<UInt8>()
var firstDelimiterArray = [UInt8]()
var delimiterIndex:Int = 0
for index in 0..<byteArray.count {
if byteArray[index] == 255 {
firstDelimiter = byteArray[delimiterIndex...index]
delimiterIndex = index + 1
firstDelimiterArray = firstDelimiter.map { $0 }
let data2 = Data(bytes: firstDelimiterArray, count: firstDelimiterArray.count)
print(data2 as NSData)
}
}
5)“ISO-8859-1” encoding
Couldn't convert to readbale format(I have used .isolatin1)
For swift 5,
I have decoded aadhar's secure QR Code and fetched name, DOB and gender
Referred: https://uidai.gov.in/images/resource/User_manulal_QR_Code_15032019.pdf
Install these pods
pod 'BigInt'
pod 'GzipSwift'
Import these pods
import BigInt
import Gzip
After scanning QR Code call the below function
func scannedData(code: String) {
print(code)
//Convert to BigInt
let bInt = BigInt(code, radix: 10)
//Convert to bytes
let byteData = bInt?.serialize() ?? Data()
//Convert to byte array
var data = Array(bInt?.serialize() ?? Data())
// Decompress
let decompressedData: Data
if byteData.isGzipped {
decompressedData = try! byteData.gunzipped()
data = [UInt8](decompressedData)
} else {
decompressedData = byteData
}
var firstDelimiter = ArraySlice<UInt8>()
var firstDelimiterArray = [UInt8]()
var delimiterIndex:Int = 0
var set:Int = 0
for index in 0..<data.count {
if data[index] == 255 {
set = set + 1
firstDelimiter = data[delimiterIndex..<index]
delimiterIndex = index + 1
firstDelimiterArray = firstDelimiter.map { $0 }
let sepData = Data(bytes: firstDelimiterArray, count: firstDelimiterArray.count)
// name
if set == 3 {
let name = convertString(data: sepData)
}
// DOB
if set == 4 {
let dob = convertString(data: sepData)
}
// Gender
if set == 5 {
let gender = convertString(data: sepData)
}
}
}
}
To encode the separated bytes use this function
private func convertString(data: Data) -> String {
return String(data: data, encoding: .windowsCP1250) ?? ""
}
Use this extension
extension BigInt {
public func serialize() -> Data {
var array = Array(BigUInt.init(self.magnitude).serialize())
if array.count > 0 {
if self.sign == BigInt.Sign.plus {
if array[0] >= 128 {
array.insert(0, at: 0)
}
} else if self.sign == BigInt.Sign.minus {
if array[0] <= 127 {
array.insert(255, at: 0)
}
}
}
return Data.init(bytes: array)
}
public init(_ data: Data) {
var dataArray = Array(data)
var sign: BigInt.Sign = BigInt.Sign.plus
if dataArray.count > 0 {
if dataArray[0] >= 128 {
sign = BigInt.Sign.minus
if dataArray.count > 1 {
if dataArray[0] == 255, dataArray.count > 1 {
dataArray.remove(at: 0)
} else {
dataArray[0] = UInt8(256 - Int(dataArray[0]))
}
}
}
}
let magnitude = BigUInt.init(Data.init(bytes: dataArray))
self .init(sign: sign, magnitude: magnitude)
}
}
I got the code to convert String to HEX-String in Objective-C:
- (NSString *) CreateDataWithHexString:(NSString*)inputString {
NSUInteger inLength = [inputString length];
unichar *inCharacters = alloca(sizeof(unichar) * inLength);
[inputString getCharacters:inCharacters range:NSMakeRange(0, inLength)];
UInt8 *outBytes = malloc(sizeof(UInt8) * ((inLength / 2) + 1));
NSInteger i, o = 0;
UInt8 outByte = 0;
for (i = 0; i < inLength; i++) {
UInt8 c = inCharacters[i];
SInt8 value = -1;
if (c >= '0' && c <= '9') value = (c - '0');
else if (c >= 'A' && c <= 'F') value = 10 + (c - 'A');
else if (c >= 'a' && c <= 'f') value = 10 + (c - 'a');
if (value >= 0) {
if (i % 2 == 1) {
outBytes[o++] = (outByte << 4) | value;
outByte = 0;
} else {
outByte = value;
}
} else {
if (o != 0) break;
}
}
NSData *a = [[NSData alloc] initWithBytesNoCopy:outBytes length:o freeWhenDone:YES];
NSString* newStr = [NSString stringWithUTF8String:[a bytes]];
return newStr;
}
I want the same in Swift. Can anybody translate this code in Swift, or is there any easy way to do this in Swift?
This is my hex string to Data routine:
extension String {
/// Create `Data` from hexadecimal string representation
///
/// This creates a `Data` object from hex string. Note, if the string has any spaces or non-hex characters (e.g. starts with '<' and with a '>'), those are ignored and only hex characters are processed.
///
/// - returns: Data represented by this hexadecimal string.
var hexadecimal: Data? {
var data = Data(capacity: count / 2)
let regex = try! NSRegularExpression(pattern: "[0-9a-f]{1,2}", options: .caseInsensitive)
regex.enumerateMatches(in: self, range: NSRange(startIndex..., in: self)) { match, _, _ in
let byteString = (self as NSString).substring(with: match!.range)
let num = UInt8(byteString, radix: 16)!
data.append(num)
}
guard data.count > 0 else { return nil }
return data
}
}
And for the sake of completeness, this is my Data to hex string routine:
extension Data {
/// Hexadecimal string representation of `Data` object.
var hexadecimal: String {
return map { String(format: "%02x", $0) }
.joined()
}
}
Note, as shown in the above, I generally only convert between hexadecimal representations and NSData instances (because if the information could have been represented as a string you probably wouldn't have created a hexadecimal representation in the first place). But your original question wanted to convert between hexadecimal representations and String objects, and that might look like so:
extension String {
/// Create `String` representation of `Data` created from hexadecimal string representation
///
/// This takes a hexadecimal representation and creates a String object from that. Note, if the string has any spaces, those are removed. Also if the string started with a `<` or ended with a `>`, those are removed, too.
///
/// For example,
///
/// String(hexadecimal: "<666f6f>")
///
/// is
///
/// Optional("foo")
///
/// - returns: `String` represented by this hexadecimal string.
init?(hexadecimal string: String, encoding: String.Encoding = .utf8) {
guard let data = string.hexadecimal() else {
return nil
}
self.init(data: data, encoding: encoding)
}
/// Create hexadecimal string representation of `String` object.
///
/// For example,
///
/// "foo".hexadecimalString()
///
/// is
///
/// Optional("666f6f")
///
/// - parameter encoding: The `String.Encoding` that indicates how the string should be converted to `Data` before performing the hexadecimal conversion.
///
/// - returns: `String` representation of this String object.
func hexadecimalString(encoding: String.Encoding = .utf8) -> String? {
return data(using: encoding)?
.hexadecimal
}
}
You could then use the above like so:
let hexString = "68656c6c 6f2c2077 6f726c64"
print(String(hexadecimal: hexString))
Or,
let originalString = "hello, world"
print(originalString.hexadecimalString())
For permutations of the above for earlier Swift versions, see the revision history of this question.
convert hex string to data and string:
Swift1
func dataWithHexString(hex: String) -> NSData {
var hex = hex
let data = NSMutableData()
while(countElements(hex) > 0) {
var c: String = hex.substringToIndex(advance(hex.startIndex, 2))
hex = hex.substringFromIndex(advance(hex.startIndex, 2))
var ch: UInt32 = 0
NSScanner(string: c).scanHexInt(&ch)
data.appendBytes(&ch, length: 1)
}
return data
}
use:
let data = dataWithHexString("68656c6c6f2c20776f726c64") // <68656c6c 6f2c2077 6f726c64>
if let string = NSString(data: data, encoding: 1) {
print(string) // hello, world
}
Swift2
func dataWithHexString(hex: String) -> NSData {
var hex = hex
let data = NSMutableData()
while(hex.characters.count > 0) {
let c: String = hex.substringToIndex(hex.startIndex.advancedBy(2))
hex = hex.substringFromIndex(hex.startIndex.advancedBy(2))
var ch: UInt32 = 0
NSScanner(string: c).scanHexInt(&ch)
data.appendBytes(&ch, length: 1)
}
return data
}
use:
let data = dataWithHexString("68656c6c6f2c20776f726c64") // <68656c6c 6f2c2077 6f726c64>
if let string = String(data: data, encoding: NSUTF8StringEncoding) {
print(string) //"hello, world"
}
Swift3
func dataWithHexString(hex: String) -> Data {
var hex = hex
var data = Data()
while(hex.characters.count > 0) {
let c: String = hex.substring(to: hex.index(hex.startIndex, offsetBy: 2))
hex = hex.substring(from: hex.index(hex.startIndex, offsetBy: 2))
var ch: UInt32 = 0
Scanner(string: c).scanHexInt32(&ch)
var char = UInt8(ch)
data.append(&char, count: 1)
}
return data
}
use:
let data = dataWithHexString(hex: "68656c6c6f2c20776f726c64") // <68656c6c 6f2c2077 6f726c64>
let string = String(data: data, encoding: .utf8) // "hello, world"
Swift4
func dataWithHexString(hex: String) -> Data {
var hex = hex
var data = Data()
while(hex.count > 0) {
let subIndex = hex.index(hex.startIndex, offsetBy: 2)
let c = String(hex[..<subIndex])
hex = String(hex[subIndex...])
var ch: UInt32 = 0
Scanner(string: c).scanHexInt32(&ch)
var char = UInt8(ch)
data.append(&char, count: 1)
}
return data
}
use:
let data = dataWithHexString(hex: "68656c6c6f2c20776f726c64") // <68656c6c 6f2c2077 6f726c64>
let string = String(data: data, encoding: .utf8) // "hello, world"
Swift 4 & Swift 5 implementation:
init?(hexString: String) {
let len = hexString.count / 2
var data = Data(capacity: len)
var i = hexString.startIndex
for _ in 0..<len {
let j = hexString.index(i, offsetBy: 2)
let bytes = hexString[i..<j]
if var num = UInt8(bytes, radix: 16) {
data.append(&num, count: 1)
} else {
return nil
}
i = j
}
self = data
}
Usage:
let data = Data(hexString: "0a1b3c4d")
Swift 5
extension Data {
init?(hex: String) {
guard hex.count.isMultiple(of: 2) else {
return nil
}
let chars = hex.map { $0 }
let bytes = stride(from: 0, to: chars.count, by: 2)
.map { String(chars[$0]) + String(chars[$0 + 1]) }
.compactMap { UInt8($0, radix: 16) }
guard hex.count / bytes.count == 2 else { return nil }
self.init(bytes)
}
}
Here is my Swift 5 way to do it:
does take care of "0x" prefixes
use subscript instead of allocated Array(), no C style [i+1] too
add .hexadecimal to String.data(using encoding:) -> Data?
.
String Extension:
extension String {
enum ExtendedEncoding {
case hexadecimal
}
func data(using encoding:ExtendedEncoding) -> Data? {
let hexStr = self.dropFirst(self.hasPrefix("0x") ? 2 : 0)
guard hexStr.count % 2 == 0 else { return nil }
var newData = Data(capacity: hexStr.count/2)
var indexIsEven = true
for i in hexStr.indices {
if indexIsEven {
let byteRange = i...hexStr.index(after: i)
guard let byte = UInt8(hexStr[byteRange], radix: 16) else { return nil }
newData.append(byte)
}
indexIsEven.toggle()
}
return newData
}
}
Usage:
"5413".data(using: .hexadecimal)
"0x1234FF".data(using: .hexadecimal)
Tests:
extension Data {
var bytes:[UInt8] { // fancy pretty call: myData.bytes -> [UInt8]
return [UInt8](self)
}
// Could make a more optimized one~
func hexa(prefixed isPrefixed:Bool = true) -> String {
return self.bytes.reduce(isPrefixed ? "0x" : "") { $0 + String(format: "%02X", $1) }
}
}
print("000204ff5400".data(using: .hexadecimal)?.hexa() ?? "failed") // OK
print("0x000204ff5400".data(using: .hexadecimal)?.hexa() ?? "failed") // OK
print("541".data(using: .hexadecimal)?.hexa() ?? "failed") // fails
print("5413".data(using: .hexadecimal)?.hexa() ?? "failed") // OK
Here's a simple solution I settled on:
extension NSData {
public convenience init(hexString: String) {
var index = hexString.startIndex
var bytes: [UInt8] = []
repeat {
bytes.append(hexString[index...index.advancedBy(1)].withCString {
return UInt8(strtoul($0, nil, 16))
})
index = index.advancedBy(2)
} while index.distanceTo(hexString.endIndex) != 0
self.init(bytes: &bytes, length: bytes.count)
}
}
Usage:
let data = NSData(hexString: "b8dfb080bc33fb564249e34252bf143d88fc018f")
Output:
print(data)
>>> <b8dfb080 bc33fb56 4249e342 52bf143d 88fc018f>
Update 6/29/2016
I updated the initializer to handle malformed data (i.e., invalid characters or odd number of characters).
public convenience init?(hexString: String, force: Bool) {
let characterSet = NSCharacterSet(charactersInString: "0123456789abcdefABCDEF")
for scalar in hexString.unicodeScalars {
if characterSet.characterIsMember(UInt16(scalar.value)) {
hexString.append(scalar)
}
else if !force {
return nil
}
}
if hexString.characters.count % 2 == 1 {
if force {
hexString = "0" + hexString
}
else {
return nil
}
}
var index = hexString.startIndex
var bytes: [UInt8] = []
repeat {
bytes.append(hexString[index...index.advancedBy(1)].withCString {
return UInt8(strtoul($0, nil, 16))
})
index = index.advancedBy(2)
} while index.distanceTo(hexString.endIndex) != 0
self.init(bytes: &bytes, length: bytes.count)
}
Here is my take on converting hexadecimal string to Data using Swift 4:
extension Data {
private static let hexRegex = try! NSRegularExpression(pattern: "^([a-fA-F0-9][a-fA-F0-9])*$", options: [])
init?(hexString: String) {
if Data.hexRegex.matches(in: hexString, range: NSMakeRange(0, hexString.count)).isEmpty {
return nil // does not look like a hexadecimal string
}
let chars = Array(hexString)
let bytes: [UInt8] =
stride(from: 0, to: chars.count, by: 2)
.map {UInt8(String([chars[$0], chars[$0+1]]), radix: 16)}
.compactMap{$0}
self = Data(bytes)
}
var hexString: String {
return map { String(format: "%02hhx", $0) }.joined()
}
}
(I threw in a small feature for converting back to hex string I found in this answer)
And here is how you would use it:
let data = Data(hexString: "cafecafe")
print(data?.hexString) // will print Optional("cafecafe")
One more solution that is simple to follow and leverages swifts built-in hex parsing
func convertHexToBytes(_ str: String) -> Data? {
let values = str.compactMap { $0.hexDigitValue } // map char to value of 0-15 or nil
if values.count == str.count && values.count % 2 == 0 {
var data = Data()
for x in stride(from: 0, to: values.count, by: 2) {
let byte = (values[x] << 4) + values[x+1] // concat high and low bits
data.append(UInt8(byte))
}
return data
}
return nil
}
let good = "e01AFd"
let bad = "e0671"
let ugly = "GT40"
print("\(convertHexToBytes(good))") // Optional(3 bytes)
print("\(convertHexToBytes(bad))") // nil
print("\(convertHexToBytes(ugly))") // nil
The code worked for me in Swift 3.0.2.
extension String {
/// Expanded encoding
///
/// - bytesHexLiteral: Hex string of bytes
/// - base64: Base64 string
enum ExpandedEncoding {
/// Hex string of bytes
case bytesHexLiteral
/// Base64 string
case base64
}
/// Convert to `Data` with expanded encoding
///
/// - Parameter encoding: Expanded encoding
/// - Returns: data
func data(using encoding: ExpandedEncoding) -> Data? {
switch encoding {
case .bytesHexLiteral:
guard self.characters.count % 2 == 0 else { return nil }
var data = Data()
var byteLiteral = ""
for (index, character) in self.characters.enumerated() {
if index % 2 == 0 {
byteLiteral = String(character)
} else {
byteLiteral.append(character)
guard let byte = UInt8(byteLiteral, radix: 16) else { return nil }
data.append(byte)
}
}
return data
case .base64:
return Data(base64Encoded: self)
}
}
}
Swift 5
With support iOS 13 and iOS2...iOS12.
extension String {
var hex: Data? {
var value = self
var data = Data()
while value.count > 0 {
let subIndex = value.index(value.startIndex, offsetBy: 2)
let c = String(value[..<subIndex])
value = String(value[subIndex...])
var char: UInt8
if #available(iOS 13.0, *) {
guard let int = Scanner(string: c).scanInt32(representation: .hexadecimal) else { return nil }
char = UInt8(int)
} else {
var int: UInt32 = 0
Scanner(string: c).scanHexInt32(&int)
char = UInt8(int)
}
data.append(&char, count: 1)
}
return data
}
}
Swift 5
There is a compact implementation of initialize Data instance from hex string using a regular expression. It searches hex numbers inside a string and combine them to a result data so that it can support different formats of hex representations:
extension Data {
private static let regex = try! NSRegularExpression(pattern: "([0-9a-fA-F]{2})", options: [])
/// Create instance from string with hex numbers.
init(from: String) {
let range = NSRange(location: 0, length: from.utf16.count)
let bytes = Self.regex.matches(in: from, options: [], range: range)
.compactMap { Range($0.range(at: 1), in: from) }
.compactMap { UInt8(from[$0], radix: 16) }
self.init(bytes)
}
/// Hex string representation of data.
var hex: String {
map { String($0, radix: 16) }.joined()
}
}
Examples:
let data = Data(from: "0x11223344aabbccdd")
print(data.hex) // Prints "11223344aabbccdd"
let data2 = Data(from: "11223344aabbccdd")
print(data2.hex) // Prints "11223344aabbccdd"
let data3 = Data(from: "11223344 aabbccdd")
print(data3.hex) // Prints "11223344aabbccdd"
let data4 = Data(from: "11223344 AABBCCDD")
print(data4.hex) // Prints "11223344aabbccdd"
let data5 = Data(from: "Hex: 0x11223344AABBCCDD")
print(data5.hex) // Prints "11223344aabbccdd"
let data6 = Data(from: "word[0]=11223344 word[1]=AABBCCDD")
print(data6.hex) // Prints "11223344aabbccdd"
let data7 = Data(from: "No hex")
print(data7.hex) // Prints ""
Handles prefixes
Ignores invalid characters and incomplete bytes
Uses Swift built in hex character parsing
Doesn't use subscripts
extension Data {
init(hexString: String) {
self = hexString
.dropFirst(hexString.hasPrefix("0x") ? 2 : 0)
.compactMap { $0.hexDigitValue.map { UInt8($0) } }
.reduce(into: (data: Data(capacity: hexString.count / 2), byte: nil as UInt8?)) { partialResult, nibble in
if let p = partialResult.byte {
partialResult.data.append(p + nibble)
partialResult.byte = nil
} else {
partialResult.byte = nibble << 4
}
}.data
}
}
Supposing your string is even size, you can use this to convert to hexadecimal and save it to Data:
Swift 5.2
func hex(from string: String) -> Data {
.init(stride(from: 0, to: string.count, by: 2).map {
string[string.index(string.startIndex, offsetBy: $0) ... string.index(string.startIndex, offsetBy: $0 + 1)]
}.map {
UInt8($0, radix: 16)!
})
}