I have a form with tab controls on it. On each of the tabs I have a sub form. One of my sub forms uses a table as a record source. If I open the sub form by itself it works perfect. It allows me to move through several records and view them one at a time. If I insert the sub form in the tab, it no longer displays any records. I have data entry set to no.
Related
When creating additional forms I have created a series of text boxes in design view.
When I select form view or layout view it comes up blank.
When I look at the form property sheet allow layout view and allow form view are both set to yes.
Your form's record source is empty, i.e. it contains no records. The form has no records to show and thus appears empty.
And it's either set to not allow adding new records, or the record source is read-only.
I want to show my records one at a time with navigation options to move to next/previous records. Is there any automatic option in MVC? I think I am looking for something like FormView (from Web Forms) in MVC using which we can show a single record in a form layout with paging options.
This is what I have done so far. Control on the left is a Panel with manual navigation buttons to navigate between records and on the right is the child grid that shows child record for each record selected in the left panel.
I am using MVC 5 and I have the following situation:
I have a drop down list on a view that changes the child view that is displayed based on the selection in the list. This needs to change on the onchange or similar event. The selections in the list are populated from a database and has the following properties:
Link ID - Int (to be used as a value for the selection (must be saved on the main view)
Link Text - What is to be displayed in the drop down list.
LinK URL - The address of the child view action (made up of different areas, controllers, and actions)
In essence, when the list changes, it must call the URL (passing the model) and return the content to a targeted placeholder div on the page
Any Ideas on where to get started on this one?
We were able to get this working using ajax to call the child view. Thanks for the pointers.
I would like to build a Wizard component, where I can guid the user through different pages. When the last page is reached, an action is performed.
That component should work similar as the TPageControl, where I can create sheets at design-time. Creating that 'sheets' is already done, but my problem is, that the last added sheet is always on top of the other sheets, and I cannot select another one anymore (which are behind). In the TPageControl component, I can select a sheet in the Structure Pane, and it comes to the front, where can I put controls on it.
And this is my question: How can I bring a control (my wizard sheet) to the front, when it is selected in the Structre Pane?
I have to override the TWinControl.ShowControl function. That function is fired when you click in the structure pane on the child control. Then, I just need to invoke the BringToFront function of that child.
SHAREPOINT 2007
I've created a customer site column. When the user creates a webparts page the column must be populated.
What I want to do is have the value of this column automatically appear on the web page.
This should not be that hard.....
If you are using the out of the box input form, for them to fill in the data, the column will show up there automatically. If you are referring to a list view that is already on a page, you will need to edit the page, modify the webpart settings and customize the view (or simply pick an existing view that has the column added to it.)
When you put a list on a web part page, the list view format is psuedo copied to the page in that the page will not reflect and changes to the view that existed when it was put on the page, which is why you either have to reselect the default view or else customize the view of the webpart on the page.