I've been searching for a way to convert decimal numbers to hexadecimal format in the Dart programming language.
The hex.encode method in the HexCodec class, for example, cannot convert the decimal 1111 (which has a hex value of 457) and instead gives an exception:
FormatException: Invalid byte 0x457. (at offset 0)
How do I convert a decimal number to hex?
int.toRadixString(16)
does that.
See also https://groups.google.com/a/dartlang.org/forum/m/#!topic/misc/ljkYEzveYWk
Here is a little fuller example:
final myInteger = 2020;
final hexString = myInteger.toRadixString(16); // 7e4
The radix just means the base, so 16 means base-16. You can use the same method to make a binary string:
final binaryString = myInteger.toRadixString(2); // 11111100100
If you want the hex string to always be four characters long then you can pad the left side with zeros:
final paddedString = hexString.padLeft(4, '0'); // 07e4
And if you prefer it in uppercase hex:
final uppercaseString = paddedString.toUpperCase(); // 07E4
Here are a couple other interesting things:
print(0x7e4); // 2020
int myInt = int.parse('07e4', radix: 16);
print(myInt); // 2020
Related
I'm trying to create a variable format specifier for use in $display/$write. I've tried a large number of things, but here is what I have at the moment.
What I want to end up with is: $display(format_var,data_1,data_2), where the format string is pre-calculated using $sformatf or other.
Code:
module test;
function void pprint(input int data_1,input int field_1,input int data_2,input int field_2);
string format;
begin
format = $sformatf("%0d'h%%%0dx,%0d'h%%%0dx",field_1,field_1/4,field_2,field_2/4);
$display("format = %s",format);
$display(format,data_1,data_2);
end
endfunction
initial
begin
pprint(5,8,73737229,128);
$stop;
end
endmodule
The output I expect is:
format = 8'h%2x,128'h%32x
8'h05,128'h000000000000000000000000465240D
The output I get is:
format = 8'h%2x,128'h%32x
8'h%2x,128'h%32x 5 73737229
What do I need to do? The simulator is Vivado 2020.3
Later:
Trying more things, the following function does do what I want. My conclusion is that $display/$write can't take a variable as the format string, but $sformatf can.
function void pprint(input int data_1,input int field_1,input int data_2,input int field_2);
string format;
string outstr;
begin
format = $sformatf("%0d'h%%%0dx,%0d'h%%%0dx",field_1,field_1/4,field_2,field_2/4);
$display("format = %s",format);
$display("%s",$sformatf(format,data_1,data_2));
end
endfunction
Try:
function void pprint(
input logic [4095:0] data_1,
input int field_1,
input logic [4095:0] data_2,
input int field_2 );
string format;
format = $sformatf("%0d'h%%%0dh,%0d'h%%%0dh",
field_1, (field_1+3)/4,
field_2, (field_2+3)/4 );
$display("format = %s",format);
$display($sformatf(format,data_1,data_2));
endfunction
This should give you the output:
format = 8'h%02h,128'h%032h
8'h05,128'h000000000000000000000000465240D
Adding a zero between the % and digit could tells the simulator to pad the upper bits with zeros.
For some reason $display(format,data_1,data_2) did not use the format on simulators on edaplayground, but it did work with $sformatf so I simply nested it.
I needed to increase the bit width of the input data otherwise it would show leading zeros over 8 digits. Adjust if necessary.
Adding 3 to the field is for handling non multiples of 4. It will always round down after division.
According to section 21.3.3 Formatting data to a string of the SystemVerilog LRM, only $sformat and $sformatf have a specific formatting argument that can be a string literal or string variable. All other output tasks like $display treat any string literal argument as format specifiers and do not interpret the strings inside string variables for formatting.
How do you write a Binary Literal in Dart?
I can write a Hex Literal like so:
Int Number = 0xc
If I try the conventional way to write a Binary Literal:
Int Number = 0b1100
I get an error. I've tried to look it up, but I've not been able to find any information other than for hex.
There are currently no built-in binary number literals in Dart (or any base other than 10 and 16).
The closest you can get is: var number = int.parse("1100", radix: 2);.
Maybe you can use this:
// 0b1100 -> 1 at 3th bit and 1 at 2nd bit
final number = 1 << 3 | 1 << 2;
// Print binary string
print(number.toRadixString(2)) // 1100
Try binary package:
import 'package:binary/binary.dart';
void main() {
// New API.S
print(0x0C.toBinaryPadded(8)); // 00001100
}
see: https://pub.dev/documentation/binary/latest/
I'm getting a Bluetooth Characteristic from a Bluetooth controller with flutter blue as a List. This characteristic contains weight measurement of a Bluetooth scale. Is there a function to convert this list of ints to a Double?
I tried to find some background on float representations by reading the IEEE 754 standard. There is the dart library typed_data but I am new to dart and have no experience with this lib.
Example:
I have this List: [191, 100, 29, 173] which is coming from a bluetooth controller as a IEEE754 representation for a float value.
Now i believe i have to convert each int to hex and concat these values: bf 64 1d ad
Next thing need to do is convert this to double, but i cannot find a function to convert hex to double. Only int.parse("0xbf641dad").
I guess your mean to convert the list of ints to a list of floats, not to a single float, right?
First, dart has no type called float. Instead it has type double. To convert it, you can use the map() function:
var listInt = [1, 2, 3];
var listDouble = list.map((i) => i.toDouble()).toList();
Had this same issue.
I think you mean how do you make the four bytes into a float32 ?
I needed to do the same thing.
you will want to do something like this:
first take the List value as a byte buffer, then take the byte data, then you can use the getFloat32 function.
ByteBuffer buffer = new Int8List.fromList(value_in).buffer;
ByteData byteData = new ByteData.view(buffer);
result = byteData.getFloat32(0);
Just be a little aware that the order of bytes from the Bluetooth may be back to front, as the convention varys.
Also you will need the typed_data library:
import 'dart:typed_data'; //for data formatting
I'm trying to go in the other direction now . . . for the obvious reason.
You may need this:
double parseHexString(String hexStr, bool littleEndian){
if(hexStr.length % 2 != 0){
return 0;
}
if(littleEndian == true){
List<int> bytes = hex.decode(hexStr).reversed.toList();
hexStr = hex.encode(bytes);
}
var byteConvert = ByteData(12);
byteConvert.setInt64(0, int.parse(hexStr,radix: 16));
return byteConvert.getFloat64(0);}
And demo :
double lat = parseHexString("0000004069665E40",true);
//lat = 121.60017395019531
If you already have:
int.parse("0xbf641dad")
I don't see why this wouldn't work:
int.parse("0xbf641dad").toDouble();
I used dart:typed_data for this:
import 'dart:typed_data';
List<int> intList = [191, 100, 29, 173];
double asFloat = ByteData.view(Uint8List.fromList(List.from(intList)).buffer).getFloat32(0, Endian.little);
Library reference: https://api.dart.dev/be/136883/dart-typed_data/dart-typed_data-library.html
I have an integer which I want to convert to a string with leading zeros.
So I have 1 and want to turn it into 01. 14 should turn into 14 not 014.
I tried:
let str = (string 1).PadLeft(2, '0') // visual studio suggested this one
let str = (string 1).PadLeft 2 '0'
let str = String.PadLeft 2 '0' (string 1)
But neither work :(
When I search for something like this with F# I get stuff with printfn but I don't want to print to stdout :/
Disclaimer: This is my first F#
You can use sprintf which returns a string rather than printing to stdout. Any of the print functions that start with an s return a string.
Use %0i to pad with zeroes. Add the length of the intended string between 0 and i. For example, to pad to four zeroes, you can use:
sprintf "%04i" 42
// returns "0042"
I wanted to know how does writeInt treat a 32 bit unsigned or a signed integer passed to it?
It is easy to understand that how it works with a hexadecimal number. Util.Print will print the corresponding ASCII Characters.
0x41424344 will be broken down into 4 1 byte characters, A, B, C and D.
It seems like its different when an integer is passed to writeInt.
for instance,
var test: ByteArray = new ByteArray();
test.writeInt(0x41424344); // prints ABCD
test.writeInt(2590463591); // prints gVg
test.writeInt(1119885898); // prints BÀJ
I am unclear how the Util.Print function treats the integers written into the ByteArray by writeInt.
The characters, gVg do not correspond to the integer number, 2590463591
According to the definition of writeInt here:
http://livedocs.adobe.com/livecycle/es/sdkHelp/common/langref/flash/utils/ByteArray.html#writeInt%28%29
It states that it works with a 32 Bit Signed Integer.
If someone can elaborate over how it translates the integers to characters, it would be helpful.
EDIT: And how does it handle negative integers?
For instance,
test.writeInt(-11338743); // prints ÿRü
So,
-11338743 = 0xFF52FC09
is that correct?
Thanks.
If you interpret encoded bytes as ASCII
dec hex ascii
1094861636 = 0x41424344 = ABCD
2590463591 = 0x9A675667 = gVg
1119885898 = 0x42C01A4A = BÀJ
Also, note that int vs unsigned int would implement different functions:
var test:ByteArray = new ByteArray();
test.writeInt(0x41424344);
test.writeUnsignedInt(0x41424344);