RxSwift. Execute separate Observables sequently - ios

Question

I'm trying to achieve my Observables to execute only when previous Observable has completed. I can't use flatMap, because subscriptions can be called from different places, and this Observables is not connected with each other. To be specific: I have my CollectionView loading more content from server and 2 seconds after that user clicks "Send comment" button while CollectionView is still loading its batch. So I want to wait until CollectionView update completes and only then execute my comment's posting request. I created a class named ObservableQueue and it's working just fine. But I need to know if it has issues like memory leaks, dead locks or maybe I just missing something. Here it is:
extension CompositeDisposable {
#discardableResult
func insert(disposeAction: #escaping () -> ()) -> DisposeKey? {
return insert(Disposables.create(with: disposeAction))
}
}
class ObservableQueue {
private let lock = NSRecursiveLock()
private let relay = BehaviorRelay(value: 0)
private let scheduler = SerialDispatchQueueScheduler(internalSerialQueueName: "ObservableQueue.scheduler")
func enqueue<T>(_ observable: Observable<T>) -> Observable<T> {
return Observable.create({ observer -> Disposable in
let disposable = CompositeDisposable()
let relayDisposable = self
.relay
.observeOn(self.scheduler)
.filter({ value -> Bool in
if value > 0 {
return false
}
self.lock.lock(); defer { self.lock.unlock() }
if self.relay.value > 0 {
return false
}
self.relay.accept(self.relay.value + 1)
disposable.insert {
self.lock.lock(); defer { self.lock.unlock() }
self.relay.accept(self.relay.value - 1)
}
return true
})
.take(1)
.flatMapLatest { _ in observable }
.subscribe { observer.on($0) }
_ = disposable.insert(relayDisposable)
return disposable
})
}
}
And then I can use it like this:
let queue = ObservableQueue()
...
// first observable
let observable1 = Observable
.just(0)
.delay(5, scheduler: MainScheduler.instance)
queue
.enqueue(observable1)
.subscribe(onNext: { _ in
print("here1")
})
.disposed(by: rx.disposeBag)
// second observable
let observable2 = Observable
.just(0)
.delay(5, scheduler: MainScheduler.instance)
queue
.enqueue(observable2)
.subscribe(onNext: { _ in
print("here2")
})
.disposed(by: rx.disposeBag)
// third observable
let observable3 = Observable
.just(0)
.delay(5, scheduler: MainScheduler.instance)
queue
.enqueue(observable3)
.subscribe(onNext: { _ in
print("here3")
})
.disposed(by: rx.disposeBag)

Answer 1

CLGeocoder has the same issue. According to the documentation, you can't call one of the geocoder methods while it's working on a previous request so very much like what you are trying to do. In this gist (https://gist.github.com/danielt1263/64bda2a32c18b8c28e1e22085a05df5a), you will find that I make the observable calls on a background thread and protect the job with semaphore. That's the key, you need a semaphore, not a lock.
Something like this should work for you:
class ObservableQueue {
private let semaphore = DispatchSemaphore(value: 1)
private let scheduler = ConcurrentDispatchQueueScheduler(qos: .userInitiated)
func enqueue<T>(_ observable: Observable<T>) -> Observable<T> {
let _semaphore = semaphore // To avoid the use of self in the block below
return Observable.create { observer in
_semaphore.wait()
let disposable = observable.subscribe { event in
switch event {
case .next:
observer.on(event)
case .error, .completed:
observer.on(event)
}
}
return Disposables.create {
disposable.dispose()
_semaphore.signal()
}
}
.subscribeOn(scheduler)
}
}

Answer 2

I will give you some suggestions that I think will help you in the future.
Avoid as much as possible the Observable.create, this is the "brute force" creation of an observable and it doesn't handle back pressure at all, you'll have to implement it yourself, and it's not something easy.
Usually for HTTP api calls, you don't need Observable, you should use Single or Completable since you expect only one response from your server, not a stream of responses.
You should be careful with strong self inside the onNext/on..., as a rule of thumb if the class that subscribes to the observer has the dispose bag, you should use a weak self.
Now for your particular case, if you need to just this pair of observers (fetch & send comment), I think the queue is a little bit overkill. You can simply call the post comment observer (if available) on the do(onNext:) method of your "fetch" observer. Do on next is called every time an "onNext" event is triggered.
If you still need a queue, I would go with an OperationQueue that enqueues only operations and has a method like observeOperationchanges() -> Observeble<Operation> this will be triggered every time an operation is completed. In this way you subscribe once and enqueue multiple times, but this might not fit your needs.

Answer 3

I would use .combineLatest() to produce an event once both observables have emitted something. See http://rxmarbles.com/#combineLatest