I have this simple code that doesn't compile.
const s = [_][_]int {
[_]int{08, 02, 22, 97, 38, 15, 00},
[_]int{49, 49, 99, 40, 17, 81, 18},
[_]int{81, 49, 31, 73, 55, 79, 14},
[_]int{52, 70, 95, 23, 04, 60, 11},
[_]int{22, 31, 16, 71, 51, 67, 63},
[_]int{24, 47, 32, 60, 99, 03, 45},
[_]int{32, 98, 81, 28, 64, 23, 67},
[_]int{67, 26, 20, 68, 02, 62, 12},
[_]int{24, 55, 58, 05, 66, 73, 99},
[_]int{21, 36, 23, 09, 75, 00, 76}
};
pub fn main() void
{
const w = s[0].len;
const h = s.len;
}
The compiler says:
./a.zig:1:14: error: inferred array size invalid here
const s = [_][_]int {
^
./a.zig:16:15: note: referenced here
const w = s[0].len;
What is the problem?
I'd be interested to know there's a deeper reason, but my simple understanding is that the current syntax [N]T allows for the array size to be elided using _, but not for more than one dimension.
So you can fix your problem using the following (N.B. I've used u8 because I'm unsure what your int is):
const s = [_][7]u8{
// Your items
}
I suspect this is because of the way the parsing rules are applied, so [7]u8 would be the type your nested array would hold, and will be used by the compiler to check contents are all of type [7]u8; you can confirm this by modifying one of your rows to have 6 elements and examining the resulting error.
If you want a variable number of items, you could start to look into an array of slices: [_][]u8, but I don't think that's what you're currently after.
I'm trying to decode this Bech32 address into a hex.
When given cosmos1qpjrq625nglf3xx9chdkq953nhrd3nygte44rt. It breaks it down into it's head which is 'cosmos' and the remainder is represented as a List of 8-bit unsigned integers (Uint8List).
When this is encoded to hexadecimal (HEX.Encode), i get a value of 00011203001a0a1413081f091106060518170d16000514111317030d11130408.
However, it is meant to be getting me 00643069549a3e9898c5c5db6016919dc6d8cc88 instead.
You can check this if you go to https://slowli.github.io/bech32-buffer/ -> and decode cosmos1qpjrq625nglf3xx9chdkq953nhrd3nygte44rt which gives 00643069549a3e9898c5c5db6016919dc6d8cc88.
I can't figure out the issue, is it perhaps
-The formatting is wrong, different bases? or am i doing this completely wrong.
Thanks and i appreciate any replies
Here is a snippet of code;
import 'package:bech32/bech32.dart';
import 'package:hex/hex.dart';
Bech32Codec bech32codec = Bech32Codec();
// target address : 00643069549a3e9898c5c5db6016919dc6d8cc88 -> to get to this address
String address = 'cosmos1qpjrq625nglf3xx9chdkq953nhrd3nygte44rt';
Bech32 bech32 = bech32codec.decode(address);
print(bech32.data);
// this returns [0, 1, 18, 3, 0, 26, 10, 20, 19, 8, 31, 9, 17, 6, 6, 5, 24, 23, 13, 22, 0, 5, 20, 17, 19, 23, 3, 13, 17, 19, 4, 8]
print(bech32.hrp);
print(bech32codec.encode(Bech32("cosmos", bech32.data)));
var answer2 = HEX.encode(bech32.data);
print(answer2);
var decode = HEX.decode('00643069549a3e9898c5c5db6016919dc6d8cc88');
print(decode);
// this returns [0, 100, 48, 105, 84, 154, 62, 152, 152, 197, 197, 219, 96, 22, 145, 157, 198, 216, 204, 136]
I have an array of DateString , in which I have values of date,month and year .
Now I have sorted it in ascending order . Now I have to put it in to dictionary with this key-value pair :-
Key- "January" (Month Name) and Value:- array of dates in that month
can anyone suggest me how to do this ?
You write code, as everyone would do.
You need a dictionary that maps (year, month) to (array).
You start with an empty mutable dictionary. Then you loop through your items. For each item, get the year and month (I assume you don't want Januarys of different years together). Look up the year / month in the dictionary, getting the mutable array value. If it isn't there, add the (year, month) key with a new mutable array as the value. So now you have an array for the (year, month), and add the item to that array.
If your data is fixed at that point, you can iterate through the dictionary and replace all the mutable arrays with immutable arrays (just use copy). And instead of sorting all the items first, just sort the keys of the dictionary, so you are now sorted by month and year, then sort the arrays when you need them sorted. For example in a tableview, you only need those arrays sorted that are actually being displayed.
NSCalendar *calendar = [NSCalendar currentCalendar];
NSDateComponents *components = [[NSDateComponents alloc] init];
// Set your year and month here
[components setYear:2016];
NSMutableDictionary *dayAndMonthWiseList = [[NSMutableDictionary alloc] init];
for (int i=1; i<=12; i++)
{
[components setMonth:i];
NSDate *date = [calendar dateFromComponents:components];
NSRange range = [calendar rangeOfUnit:NSCalendarUnitDay inUnit:NSCalendarUnitMonth forDate:date];
NSMutableArray *dayList = [[[NSMutableArray alloc] init] mutableCopy];
for (int j=1; j<=range.length; j++)
{
[dayList addObject:[NSString stringWithFormat:#"%d",j]];
}
[dayAndMonthWiseList setObject:dayList forKey:[NSString stringWithFormat:#"%d",i]];
}
NSLog(#"Dic. :%#",dayAndMonthWiseList);
Result is :
Dic. :{
1 = (
1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,
26,
27,
28,
29,
30,
31
);
10 = (
1,
2,
3,
4,
5,
6,
7,
8,
9,
10,
11,
12,
13,
14,
15,
16,
17,
18,
19,
20,
21,
22,
23,
24,
25,
26,
27,
28,
29,
30,
31
);
11 = (
1,
2,
3,
4,
5,
6,
7,
8,
9,
10,
11,
12,
13,
14,
15,
16,
17,
18,
19,
20,
21,
22,
23,
24,
25,
26,
27,
28,
29,
30
);
12 = (
1,
2,
3,
4,
5,
6,
7,
8,
9,
10,
11,
12,
13,
14,
15,
16,
17,
18,
19,
20,
21,
22,
23,
24,
25,
26,
27,
28,
29,
30,
31
);
2 = (
1,
2,
3,
4,
5,
6,
7,
8,
9,
10,
11,
12,
13,
14,
15,
16,
17,
18,
19,
20,
21,
22,
23,
24,
25,
26,
27,
28,
29
);
3 = (
1,
2,
3,
4,
5,
6,
7,
8,
9,
10,
11,
12,
13,
14,
15,
16,
17,
18,
19,
20,
21,
22,
23,
24,
25,
26,
27,
28,
29,
30,
31
);
4 = (
1,
2,
3,
4,
5,
6,
7,
8,
9,
10,
11,
12,
13,
14,
15,
16,
17,
18,
19,
20,
21,
22,
23,
24,
25,
26,
27,
28,
29,
30
);
5 = (
1,
2,
3,
4,
5,
6,
7,
8,
9,
10,
11,
12,
13,
14,
15,
16,
17,
18,
19,
20,
21,
22,
23,
24,
25,
26,
27,
28,
29,
30,
31
);
6 = (
1,
2,
3,
4,
5,
6,
7,
8,
9,
10,
11,
12,
13,
14,
15,
16,
17,
18,
19,
20,
21,
22,
23,
24,
25,
26,
27,
28,
29,
30
);
7 = (
1,
2,
3,
4,
5,
6,
7,
8,
9,
10,
11,
12,
13,
14,
15,
16,
17,
18,
19,
20,
21,
22,
23,
24,
25,
26,
27,
28,
29,
30,
31
);
8 = (
1,
2,
3,
4,
5,
6,
7,
8,
9,
10,
11,
12,
13,
14,
15,
16,
17,
18,
19,
20,
21,
22,
23,
24,
25,
26,
27,
28,
29,
30,
31
);
9 = (
1,
2,
3,
4,
5,
6,
7,
8,
9,
10,
11,
12,
13,
14,
15,
16,
17,
18,
19,
20,
21,
22,
23,
24,
25,
26,
27,
28,
29,
30
);
}
I want to list all weeknumbers together with year.
This is what I have:
start # 2012-05-10
ende # 2013-06-20
while start < ende
weeks << start.cweek
start += 1.week
end
List all weeknumbers:
#kws.each do |w|
w
end
I need some inspiration how to assign the corresponding year to each weeknumber..
So that I get 22 / 2012 23 / 2012 etc..
Thanks for help..
When in your while loop, you can also store the year, and one easy way is just as an array of arrays.
Then in your each loop later you can get access to both:
start = Date.new( 2012, 5, 10 )
ende = Date.new( 2013, 6, 20 )
weeks = []
while start < ende
weeks << [start.cweek, start.year] # <-- enhanced
start += 1.week
end
weeks.each do |w,y| # <-- take two arguments in the block
puts "#{w} / #{y}" # and print them both out
end
Results:
=>
19 / 2012
20 / 2012
21 / 2012
22 / 2012
23 / 2012
24 / 2012
25 / 2012
...
22 / 2013
23 / 2013
24 / 2013
Create a hash instead with key as a year and value as an array of week numbers
start # 2012-05-10
ende # 2013-06-20
weeks ={}
while start < ende
weeks[start.year] = [] unless weeks[start.year]
weeks[start.year] << start.cweek
start += 1.week
end
p weeks
and you get o/p
=> {2012=>[19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35,
36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52],
2013=>[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21,
22, 23, 24]}
(10.weeks.ago.to_date..Date.today.to_date).map(&:beginning_of_week).uniq