Rail convert array into group - ruby-on-rails

I am trying to convert one of my array into some format where it can convert itself into table format.
I have an array which is:
[
{
id: 1,
Revenue_Account: "Revenue Receipt",
Amount: 59567,
Year: "2012-13",
created_at: "2018-08-21T06:30:17.000Z",
updated_at: "2018-08-21T06:30:17.000Z"
},
{
id: 2,
Revenue_Account: "Revenue Expenditure ",
Amount: 54466,
Year: "2012-13",
created_at: "2018-08-21T06:30:17.000Z",
updated_at: "2018-08-21T06:30:17.000Z"
},
...
]
Full code of my array link to my actual array
I want this data to be converted into this format:
data: [
{
id: 1,
Sector: "Revenue Receipt",
2012-13: 59567,
2013-14: 68919,
2014-15: 72570,
2015-16: 96123,
2016-17: 105585,
2017-18_BE: 137158,
},
{
id: 2,
Sector: "Revenue Expenditure",
2012-13: 59567,
2013-14: 68919,
2014-15: 72570,
2015-16: 96123,
2016-17: 105585,
2017-18_BE: 137158,
},
....
]
I am using this code to group my array:
group = b.group_by{|data| data[:Revenue_Account]}
this is grouping my data as I am expecting in order to achieve my goal I am trying this code.
group = b.group_by{|data| data[:Revenue_Account]}
du = []
group.each do |i|
du.push({Sector:i[0]})
end
This is giving me Sector wise result how can I add year in my code.

You can't have a single id in there because you're grouping up many entries with different ids, but this is how you'd get the array in the format you're asking for:
grouped = {}
b.each do |x|
grouped[x[:Revenue_Account]] ||= {}
grouped[x[:Revenue_Account]][:Sector] = x[:Revenue_Account]
grouped[x[:Revenue_Account]][x[:Year]] = x[:Amount]
end
return {data: grouped.values}
Which gets you:
{
:data=>[
{
:Sector=>"Revenue Receipt",
"2012-13"=>59567,
"2013-14"=>68919,
"2014-15"=>78417,
"2015-16"=>96123,
"2016-17"=>105585,
"2017-18_BE"=>137158
},
{
:Sector=>"Revenue Expenditure ",
"2012-13"=>54466,
"2013-14"=>62477,
"2014-15"=>72570,
"2015-16"=>83616,
"2016-17"=>94765,
"2017-18_BE"=>122603
},
]
}
We build a new hash by looping through the original hash and creating hash keys if they don't exist. Then we start assigning values as you want them to be in the output. On each iteration, we're creating a new key in this hash for the Revenue_Account value if its the first time we've seen it. Then we assign that particular Revenue_Account's Date and Amount to the output. So for value 'Revenue Receipt' it looks like this:
Grouped hash starts off as empty
On first iteration, we see that group["Revenue Receipt"] is nil, so we initialize it with an empty hash via ||= (assign if nil)
We then assign :Sector => "Revenue Receipt" and this entry's Year and Amount, "2012-13" => 59567
Our grouped hash looks like: {"Revenue Receipt" => {:Sector => "Revenue Receipt", "2012-13" => 59567}
On the next iteration we see that group["Revenue Receipt"] is not nil, so ||= does not override it with an empty hash
We then assign :Sector => "Revenue Receipt" and this entry's Year and Amount, "2012-14" => 68919, which adds a new key/value to the existing hash
Our grouped hash now looks like: {"Revenue Receipt" => {:Sector => "Revenue Receipt", "2012-13" => 59567, "2012-14" => 68919}
After we parse the entire array, we now have a hash that has a key of the Revenue_Account, and values which look like the hash output you're expecting.
We discard the key and return only the hash values, which gets you the final output.

Another option, directly manipulating the array.
array_of_data = array
.each { |h| h[:Sector] = h.delete(:Revenue_Account) }
.each { |h| h[h[:Year]] = h[:Amount]}
.each { |h| h.delete_if{ |k, _| k == :created_at || k == :updated_at || k == :id || k == :Year || k == :Amount} }
.group_by { |h| h[:Sector] }
.values.map { |a| a.inject(:merge) }
Then just:
h = {}
h[:data] = array_of_data
To understand what happens along the code, just ad line by line outputting the result, like:
p array
.each { |h| h[:Sector] = h.delete(:Revenue_Account) }
Then:
p array
.each { |h| h[:Sector] = h.delete(:Revenue_Account) }
.each { |h| h[h[:Year]] = h[:Amount]}
Etcetera...
To understand .inject(:merge), see here Rails mapping array of hashes onto single hash

Related

Get emails as array from an array of hashes by matching criteria

I have an array of hashes like this:
arr = [
{ email: 'prathab#hotmail.in', valid: true },
{ email: 'another#gmail.com', valid: false },
{ email: 'hello#hotmail.in', has_many: 10, valid: true}
]
What I need is to get list of emails by valid: true.
Expected result:
=> ["prathab#hotmail.in", "hello#hotmail.in"]
# another#gmail.com is not in the list because it's valid is false.
How can I check for such hash in the array without using each loop?
Currently I am doing this:
found = []
arr.each do|v|
if v[:valid] == true
found << v[:email]
end
end
Note: email and valid can be re-ordered or can have other keys along with them. I just minimized the example.
Try with select:
valids = arr.select { |hash| hash[:valid] }
emails = valids.map { |hash| hash[:email] }
Just for having an alternative way:
arr.collect { |h| h[:email] if h[:valid] }.compact
#=> ["prathab#hotmail.in", "hello#hotmail.in"]

rails array of hashes calculate one column

I have an array and it has many columns and I want to change one value of my one column.
My array is:
[
{
id: 1,
Districts: "Lakhisarai",
Area: 15.87,
Production: 67.77,
Productivity: 4271,
Year: 2015,
Area_Colour: "Red",
Production_Colour: "Orange",
Productivity_Colour: "Dark_Green",
created_at: "2018-07-24T11:24:13.000Z",
updated_at: "2018-07-24T11:24:13.000Z"
},
{
id: 29,
Districts: "Begusarai",
Area: 18.53,
Production: 29.35,
Productivity: 1584,
Year: 2015,
Area_Colour: "Red",
Production_Colour: "Red",
Productivity_Colour: "Orange",
created_at: "2018-07-24T11:24:13.000Z",
updated_at: "2018-07-24T11:24:13.000Z"
},
...
]
This is my sample array and I want my Productivity to be divided by 100 for that I am using one empty array and pushing these hashes to my array like:
j = []
b.map do |k|
if k.Productivity
u = k.Productivity/100
j.push({id: k.id, Productivity: u })
else
j.push({id: k.id, Productivity: k.Productivity })
end
Is there any simple way where I can generate this kind of array and reflect my changes to to one column. Is there any way where I don't need to push name of column one by one in push method.
I want to generate exact same array with one modification in productivity
let's say your array is e, then:
e.each { |item| item[:Productivity] = item[:Productivity]/100}
Example:
e = [{p: 12, d: 13}, {p:14, d:70}]
e.each { |item| item[:p] = item[:p]/10}
output: [{:p=>1, :d=>13}, {:p=>1, :d=>70}]
You could take help of map method here to create a new array from your original array, but with the mentioned changes.
ary.map do |elem|
h = elem.slice(:id)
h[:productivity] = elem[:Productivity] / 100 if elem[:Productivity]
h
end
=> [{:id=>1, :productivity=>42}, {:id=>29, :productivity=>15}]
Note, Hash#slice returns a new hash with only the key-value pairs for the keys passed in argument e.g. here, it returns { id: 1 } for first element.
Also, we are assigning the calculated productivity to the output only when it is set on original hash. Hence, the if condition there.

Ruby - Access value from json array

I am creating an array of fields
def create_fields fields
fields_list = []
fields.each do |field|
# puts "adding_field to array: #{field}"
field_def = { field: field, data: { type: 'Text', description: '' } }
fields_list.push field_def
end
fields_list
end
The fields_list is being set to a jsonb field.
Lets say I pass in
create_fields ['Ford', 'BMW', 'Fiat']
Json result is an array:
{"field"=>"Ford", "data"=>{"type"=>"Text", "description"=>""}}
{"field"=>"BMW", "data"=>{"type"=>"Text", "description"=>""}}
{"field"=>"Fiat", "data"=>{"type"=>"Text", "description"=>""}}
How can I access the 'Ford' from the json array? Am i creating the array incorrectly? Is there a better way to create this array so I can access the field i want?
This assertion passes assert_equal(3, fields.count)
However i want to get 'Ford' and check it's properties, e.g. type = 'Text', type could equal 'Number' or whatever.
The result of your create_fields method with the specified parameters is the following:
[
{:field=>"Ford", :data=>{:type=>"Text", :description=>""}},
{:field=>"BMW", :data=>{:type=>"Text", :description=>""}},
{:field=>"Fiat", :data=>{:type=>"Text", :description=>""}}
]
It means that if you want to access the line belonging to "Ford", you need to search for it like:
2.3.1 :019 > arr.select{|e| e[:field] == "Ford" }
=> [{:field=>"Ford", :data=>{:type=>"Text", :description=>""}}]
2.3.1 :020 > arr.select{|e| e[:field] == "Ford" }[0][:data][:type]
=> "Text"
This is not optimal, because you need to search an array O(n) instead of using the pros of a hash. If there are e.g.: 2 "Ford" lines, you'll get an array which contains 2 elements, harder to handle collisions in field value.
It would be better if you created the array like:
def create_fields fields
fields_list = []
fields.each do |field|
# puts "adding_field to array: #{field}"
field_def = [field, { type: 'Text', description: '' } ]
fields_list.push field_def
end
Hash[fields_list]
end
If you choose this version, you can access the members like:
2.3.1 :072 > arr = create_fields ['Ford', 'BMW', 'Fiat']
=> {"Ford"=>{:type=>"Text", :description=>""}, "BMW"=>{:type=>"Text", :description=>""}, "Fiat"=>{:type=>"Text", :description=>""}}
2.3.1 :073 > arr["Ford"]
=> {:type=>"Text", :description=>""}
2.3.1 :074 > arr["Ford"][:type]
=> "Text"
Both of the above examples are Ruby dictionaries / Hashes.
If you want to create a JSON from this, you will need to convert it:
2.3.1 :077 > require 'json'
=> true
2.3.1 :078 > arr.to_json
=> "{\"Ford\":{\"type\":\"Text\",\"description\":\"\"},\"BMW\":{\"type\":\"Text\",\"description\":\"\"},\"Fiat\":{\"type\":\"Text\",\"description\":\"\"}}"
This is a structure that makes more sense to me for accessing values based on known keys:
def create_fields fields
fields_hash = {}
fields.each do |field|
fields_hash[field] = {type: 'Text', description: ''}
end
fields_hash
end
# The hash for fields_hash will look something like this:
{
Ford: {
type: "Text",
description: ""
},
BMW: {...},
Fiat: {...}
}
This will allow you to access the values like so: fields[:Ford][:type] in ruby and fields.Ford.type in JSON. Sounds like it would be easier to return an Object rather than an Array. You can access the values based on the keys more easily this way, and still have the option of looping through the object if you want.
Obviously, there are several ways of creating or accessing your data, but I'd always lean towards the developer picking a data structure best suited for your application.
In your case currently, in order to access the Ford hash, you could use the Ruby Array#detect method as such:
ford = fields_list.detect{|field_hash| field_hash['field'] == 'Ford' }
ford['data'] # => {"type"=>"Text", "description"=>""}
ford['data']['type'] # => 'Text'
So, you have result of your method:
result =
[
{"field"=>"Ford", "data"=>{"type"=>"Text", "description"=>""}},
{"field"=>"BMW", "data"=>{"type"=>"Text", "description"=>""}},
{"field"=>"Fiat", "data"=>{"type"=>"Text", "description"=>""}}
]
to get 'Ford' from it you can use simple method detect
result.detect { |obj| obj['field'] == 'Ford' }
#=> { "field"=>"Ford", "data"=>{"type"=>"Text", "description"=>""}
Also I recommend you to edit your method to make it more readable:
def create_fields(fields)
fields.map do |field|
{
field: field,
data: {
type: 'Text',
description: ''
}
}
end
end

ActiveRecord query from an array of hash

I have an array of hash.
eg) array_of_hash = [ { id: 20, name: 'John' }, { id: 30, name: 'Doe'} ]
I would like to get records which match all the criteria in a particular hash.
So the query I want to get executed is
SELECT persons.* FROM persons WHERE persons.id = 20 AND persons.name = 'John' OR persons.id = 30 AND persons.name = 'Doe'
What is the best way to construct this query from an array of hash?
I think this is okay:
ids = array_of_hash.map { |h| h[:id] }
names = array_of_hash.map { |h| h[:name] }
Person.where(id: ids, name: names)
(although it's not super generic)
other attempt:
people = Person.all
array_of_hash.each do |h|
people = people.where(h)
end
people # => will generate a long long query.
Try to map all conditions to your ActiveRecord model independently and flatten the result array afterwards:
array_of_hash.map{ |where_clause| Person.where(where_clause) }.flatten

There has got to be a cleaner way to do this

I have this code here and it works but there has to be a better way.....i need two arrays that look like this
[
{
"Vector Arena - Auckland Central, New Zealand" => {
"2010-10-10" => [
"Enter Sandman",
"Unforgiven",
"And justice for all"
]
}
},
{
"Brisbane Entertainment Centre - Brisbane Qld, Austr..." => {
"2010-10-11" => [
"Enter Sandman"
]
}
}
]
one for the past and one for the upcoming...the problem i have is i am repeating myself and though it works i want to clean it up ...here is my data
..
Try this:
h = Hash.new {|h1, k1| h1[k1] = Hash.new{|h2, k2| h2[k2] = []}}
result, today = [ h, h.dup], Date.today
Request.find_all_by_artist("Metallica",
:select => "DISTINCT venue, showdate, LOWER(song) AS song"
).each do |req|
idx = req.showdate < today ? 0 : 1
result[idx][req.venue][req.showdate] << req.song.titlecase
end
Note 1
In the first line I am initializing an hash of hashes. The outer hash creates the inner hash when a non existent key is accessed. An excerpt from Ruby Hash documentation:
If this hash is subsequently accessed by a key that doesn‘t correspond to a hash
entry, the block will be called with the hash object and the key, and should
return the default value. It is the block‘s responsibility to store the value in
the hash if required.
The inner hash creates and empty array when the non existent date is accessed.
E.g: Construct an hash containing of content as values and date as keys:
Without a default block:
h = {}
list.each do |data|
h[data.date] = [] unless h[data.date]
h[data.date] << data.content
end
With a default block
h = Hash.new{|h, k| h[k] = []}
list.each do |data|
h[data.date] << data.content
end
Second line simply creates an array with two items to hold the past and future data. Since both past and the present stores the data as Hash of Hash of Array, I simply duplicate the value.
Second line can also be written as
result = [ h, h.dup]
today = Date.today

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