Get Query string as it is passed - url

Question

I'm new to Go. My question is how to get URL encoded string on stdout.
Below is the URL string I am using to hit an api.
schooltubeapi/v1/channeldetails?channelName=long%20division%20.
Below is the code that I am using to get RawQuery
url1 := ChannelName
u, _ := url.Parse(url1)
log.Println(u)
u.RawQuery = u.Query().Encode()
log.Println(u)
[Output]
long division
[Expected]
long%20division%20
I have searched alot But cannot found a similar problem with a solution.

Answer 1

For url encoded string use URL struct of url package to get RawQuery as passed in the URI:
package main
import (
"fmt"
"net/url"
)
func main() {
stringValue := "long division "
t := &url.URL{Path: stringValue}
encodedString := t.String()
fmt.Println(encodedString)
}
Playground Example
In Golang spec for URL. It is stated:-
that the Path field is stored in decoded form: /%47%6f%2f becomes
/Go/. A consequence is that it is impossible to tell which slashes in
the Path were slashes in the raw URL and which were %2f. This
distinction is rarely important, but when it is, code must not use
Path directly. The Parse function sets both Path and RawPath in the
URL it returns, and URL's String method uses RawPath if it is a valid
encoding of Path, by calling the EscapedPath method.
type URL struct {
Scheme string
Opaque string // encoded opaque data
User *Userinfo // username and password information
Host string // host or host:port
Path string // path (relative paths may omit leading slash)
RawPath string // encoded path hint (see EscapedPath method)
ForceQuery bool // append a query ('?') even if RawQuery is empty
RawQuery string // encoded query values, without '?'
Fragment string // fragment for references, without '#'
}
For more information Check Golang spec for URL