unable to convert string date in Format yyyyMMddHHmmss to DateTime dart - dart

Question

i have a string containing date in format yyyyMMddHHmmss (e.g.) (20180626170555) and i am using following code to convert it into date time
dateTimeFromString(json['dateTime'], "yyyyMMddHHmmss")
exception is:
FormatException: Trying to read MM from 20180623130424 at position 14
what can be the reason?

Answer 1

DateTime.parse("string date here") accept some formatted string only. Check below examples of accepted strings.
"2012-02-27 13:27:00"
"2012-02-27 13:27:00.123456789z"
"2012-02-27 13:27:00,123456789z"
"20120227 13:27:00"
"20120227T132700"
"20120227"
"[phone]"
"2012-02-27T14Z"
"2012-02-27T14+00:00"
"-123450101 00:00:00 Z": in the year -12345.
"2002-02-27T14:00:00-0500": Same as "2002-02-27T19:00:00Z"
=> String to DateTime
DateTime tempDate = new DateFormat("yyyy-MM-dd hh:mm:ss").parse(savedDateString);
=> DateTime to String
String date = DateFormat("yyyy-MM-dd hh:mm:ss").format(DateTime.now());
Reference links:
Use intl for DateFormat from flutter package (https://pub.dev/packages/intl)
DateTime.parse() => https://api.dart.dev/stable/2.7.2/dart-core/DateTime/parse.html

Answer 2

intl DateFormat can't cope with your input string as it doesn't have any separators. The whole string gets consumed as the year. However DateTime.parse does cope with this (nearly). It happens to expect precisely the format you have (again, nearly).
One of the acceptable styles to parse is 20120227T132700, which just differs by the T date/time separator.
Try this:
String date = '20180626170555';
String dateWithT = date.substring(0, 8) + 'T' + date.substring(8);
DateTime dateTime = DateTime.parse(dateWithT);

Answer 3

to convert from "yyyy-MM-dd'T'HH:mm:ss.SSS'Z'" to 'MM/dd/yyyy hh:mm a'
date = '2021-01-26T03:17:00.000000Z';
DateTime parseDate =
new DateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'").parse(date);
var inputDate = DateTime.parse(parseDate.toString());
var outputFormat = DateFormat('MM/dd/yyyy hh:mm a');
var outputDate = outputFormat.format(inputDate);
print(outputDate)
output
01/26/2021 03:17 AM

Answer 4

You can use DateFormat to parse a DateTime from string to an object
// With en_US locale by default
var newDateTimeObj = new DateFormat().add_yMd().add_Hms().parse("7/10/1996 10:07:23")
// with a defined format
var newDateTimeObj2 = new DateFormat("dd/MM/yyyy HH:mm:ss").parse("10/02/2000 15:13:09")
Check the doc here.

Answer 5

The Easient way convert a string into Date format is
print(DateTime.parse('2020-01-02')); // 2020-01-02 00:00:00.000
print(DateTime.parse('20200102')); // 2020-01-02 00:00:00.000
print(DateTime.parse('-12345-03-04')); // -12345-03-04 00:00:00.000
print(DateTime.parse('2020-01-02 07')); // 2020-01-02 07:00:00.000
print(DateTime.parse('2020-01-02T07')); // 2020-01-02 07:00:00.000
print(DateTime.parse('2020-01-02T07:12')); // 2020-01-02 07:12:00.000
print(DateTime.parse('2020-01-02T07:12:50')); // 2020-01-02 07:12:50.000
print(DateTime.parse('2020-01-02T07:12:50Z')); // 2020-01-02 07:12:50.000Z
print(DateTime.parse('2020-01-02T07:12:50+07')); // 2020-01-02 00:12:50.000Z
print(DateTime.parse('2020-01-02T07:12:50+0700')); // 2020-01-02 00:12:50.00
print(DateTime.parse('2020-01-02T07:12:50+07:00')); // 2020-01-02 00:12:50.00

Answer 6

From the docs, you need Single M to month in year :
dateTimeFromString(json['dateTime'], "yMdHms")

Answer 7

Basic information about how to convert String to Date and Date to string in flutter. Look at below link
https://quickstartflutterdart.blogspot.com/2018/10/how-to-convert-string-to-date-and-date.html
Might be it will be helped for others.

Answer 8

i did something like this (using the intl package)
final date = '7/10/1996';
final month = DateFormat.LLLL().format(DateTime.parse(date));
LLLL in the code above is date format skeleton meaning 'stand alone month', other date formatter is presented here

Answer 9

add String date as a parameter
DateTime.prase(String userString);

Answer 10

If you have a date and time string in a specific format, you can convert it to a DateTime object by using the parse() method. For example, if you have a string that contains “12/03/2019 9:45 AM”, you can use the parse() method to convert it to a DateTime object like this:
var dateTimeString = “12/03/2019 9:45 AM”;
var dateTimeObject = DateTime.parse(dateTimeString);
print(dateTimeObject); // 12/03/2019 09:45:00.000
The parse() method is very versatile and can handle a variety of different formats. If your string doesn’t follow a strict format, you can use tryParse() instead. This method will return null if it fails to parse the string.
for detail click here
https://mycodingwork.com/flutter-convert-string-to-datetime/

Answer 11

String startdate1="10/31/2022";
String endate1="11/02/2022";
DateTime start = new DateFormat("MM/dd/yyyy").parse(startdate1);
DateTime end = new DateFormat("MM/dd/yyyy").parse(enddate1);
DateTime s = DateTime(start.year, start.month, start.day);
DateTime to = DateTime(end.year, end.month, end.day);
int day= (to.difference(s).inHours / 24).round()+1;