I'm running on a windows host different server core VMs (hyper-v) and in each one docker service. The containers I try to run, using docker run nanoserver/iis-php command, are created but immediately disappear, exited with exit code 0, no error messages. Since it happens in different VMs, I believe it is something in the VMs host. Any idea?
according to https://hub.docker.com/r/nanoserver/iis-php
use docker run --name nanoiis -d -it -p 80:80 nanoserver/iis-php
so that the container is started in daemon mode, interactive mode and with tty
I do not know iis-php, but from the dockerfile of the image below, the last command is just to make webrequet, do not see any server process started.
https://github.com/nanoserver/IIS-PHP/blob/master/Dockerfile/Dockerfile
the containers [...] are created but immediately disappear, exited with exit code 0, no error messages.
So as I understand they don't disappear but simply exit immediately with an exit code of 0 which you still can see with docker ps -a?
The exit code 0 indicates "success". So it looks like the containers were created and started successfully and the processes started in them executed "successfully". But what this means depends an the actual command started in the containers.
But neither the Dockerfile of the nanoserver/iis-php image nor the Dockerfile of its base image nanoserver/iis specify a CMD. Also no command is specified in your docker run command.
docker logs gives me nothing just: Microsoft Windows [Version 10.0.14393] (c) 2016 Microsoft Corporation. All rights reserved. C:\>
This looks like an interactive command prompt expecting user input. So what most probably is happening here is that the containers start a simple interactive shell since no other command to execute is explicitly specified. But since no stdin is attached to the container it can not read any input and will exit again.
You can test that the containers / your docker setup is working correctly with
docker run -ti nanoserver/iis-php
This should drop you into the interactive shell inside the container. You could then interactively execute commands in the container.
In order to have it run in the background you have to pass and command to execute to docker run
# this is just an example! The exact command you need
# depends on what you actually want to run inside the container
docker run -d nanoserver/iis-php php index.php
Like most docker users, I periodically need to connect to a running container and execute various arbitrary commands via bash.
I'm using 17.06-CE with an ubuntu 16.04 image, and as far as I understand, the only way to do this without installing ssh into the container is via docker exec -it <container_name> bash
However, as is well-documented, for each bash shell process you generate, you leave a zombie process behind when your connection is interrupted. If you connect to your container often, you end up with 1000s of idle shells -a most undesirable outcome!
How can I ensure these zombie shell processes are killed upon disconnection -as they would be over ssh?
One way is to make sure the linux init process runs in your container.
In recent versions of docker there is an --init option to docker run that should do this. This uses tini to run init which can also be used in previous versions.
Another option is something like the phusion-baseimage project that provides a base docker image with this capability and many others (might be overkill).
I am new to docker and I tried to run the linuxconfig/lemp-php7 image. Everything worked fine and I could access the nginx web server installed on the container. To run this image I used this command:
sudo docker run linuxconfig/lemp-php7
When I tried to run the image with the following command to gain access over the container through bash I couldn't connect to nginx and I got the connection refused error message. Command: sudo docker run -ti linuxconfig/lemp-php7 bash
I tried this several times so I'm pretty sure it's not any kind of coincidence.
Why does this happen? Is this a problem specific to this particular image or is this a general problem. And how can I gain access to the shell of the container and access the web server at the same time?
I'd really like to understand this behavior to improve my general understanding of docker.
docker run runs the specified command instead of what that container would normally run. In your case, it appears to be supervisord, which presumably in turn runs the web server. So you're preventing any of that from happening.
My preferred method (except in cases where I'm trying to debug cases where the container won't even start properly) is to do the following after running the container normally:
docker exec -i -t $CONTAINER_ID /bin/bash
I am trying to run a simple docker container with my web application installed (Not using docker file).
During the testing I would always run a container using -t -i option and then start the tomcat service inside it by running a shell script.
How when I am moving to production I dont want to use the -t -i option any more and just need my Tomcat service to start and be the only primary service.
I trying pointing the entrypoint to the start up script for starting tomcat but the container terminates after that script finishes.
How do I run a container, start a service and keep that service as the single primary service of the container?
Note: I read some posts about supervisor but not sure if I would need to start building my image from scratch if I go that route? I would prefer not doing that.
Any suggestions?
If you have a Dockerfile that uses an entrypoint pattern, it will look something like this:
(Dockerfile)
FROM ubuntu
...Some configuration steps...
add start.sh /start.sh
ENTRYPOINT ["/start.sh"]
All you need to do is make sure your start.sh script 'hangs' in some way. Some people like to tail the syslogs, but tailing any file that exists will work.
(start.sh)
#!/bin/bash
service Your_Service_Or_Whatever start
tail -f /var/log/dmesg
A shorter version:
FROM ubuntu
...Some configuration steps...
ENTRYPOINT ["/bin/sh", "-c", "while true; do sleep 1; done"]
tested with Docker version 1.12.1, build 23cf638
Use docker --version to find out your version
Docker containers as default will run according to the configuration in the images Dockerfile. If you usually run a container with the -i flag, you leave STDIN open allowing you access to the containers entrypoint or it could be a bash shell. To achieve what you want, you can run the container in a detached state passing your commands into docker run directly.
docker run -d myapp /opt/catalina/bin/startup.sh
This will run the myapp container in a detached state and will run the command passed as the 3rd argument. If the command results in a long lived service, the container will stay active as long as the service is.
This is explained in detail in the docs.
I've seen a bunch of tutorials that seem do the same thing I'm trying to do, but for some reason my Docker containers exit. Basically, I'm setting up a web-server and a few daemons inside a Docker container. I do the final parts of this through a bash script called run-all.sh that I run through CMD in my Dockerfile. run-all.sh looks like this:
service supervisor start
service nginx start
And I start it inside of my Dockerfile as follows:
CMD ["sh", "/root/credentialize_and_run.sh"]
I can see that the services all start up correctly when I run things manually (i.e. getting on to the image with -i -t /bin/bash), and everything looks like it runs correctly when I run the image, but it exits once it finishes starting up my processes. I'd like the processes to run indefinitely, and as far as I understand, the container has to keep running for this to happen. Nevertheless, when I run docker ps -a, I see:
➜ docker_test docker ps -a
CONTAINER ID IMAGE COMMAND CREATED STATUS PORTS NAMES
c7706edc4189 some_name/some_repo:blah "sh /root/run-all.sh 8 minutes ago Exited (0) 8 minutes ago grave_jones
What gives? Why is it exiting? I know I could just put a while loop at the end of my bash script to keep it up, but what's the right way to keep it from exiting?
If you are using a Dockerfile, try:
ENTRYPOINT ["tail", "-f", "/dev/null"]
(Obviously this is for dev purposes only, you shouldn't need to keep a container alive unless it's running a process eg. nginx...)
I just had the same problem and I found out that if you are running your container with the -t and -d flag, it keeps running.
docker run -td <image>
Here is what the flags do (according to docker run --help):
-d, --detach=false Run container in background and print container ID
-t, --tty=false Allocate a pseudo-TTY
The most important one is the -t flag. -d just lets you run the container in the background.
This is not really how you should design your Docker containers.
When designing a Docker container, you're supposed to build it such that there is only one process running (i.e. you should have one container for Nginx, and one for supervisord or the app it's running); additionally, that process should run in the foreground.
The container will "exit" when the process itself exits (in your case, that process is your bash script).
However, if you really need (or want) to run multiple service in your Docker container, consider starting from "Docker Base Image", which uses runit as a pseudo-init process (runit will stay online while Nginx and Supervisor run), which will stay in the foreground while your other processes do their thing.
They have substantial docs, so you should be able to achieve what you're trying to do reasonably easily.
you can run plain cat without any arguments as mentioned by bro #Sa'ad to simply keep the container working [actually doing nothing but waiting for user input] (Jenkins' Docker plugin does the same thing)
The reason it exits is because the shell script is run first as PID 1 and when that's complete, PID 1 is gone, and docker only runs while PID 1 is.
You can use supervisor to do everything, if run with the "-n" flag it's told not to daemonize, so it will stay as the first process:
CMD ["/usr/bin/supervisord", "-n"]
And your supervisord.conf:
[supervisord]
nodaemon=true
[program:startup]
priority=1
command=/root/credentialize_and_run.sh
stdout_logfile=/var/log/supervisor/%(program_name)s.log
stderr_logfile=/var/log/supervisor/%(program_name)s.log
autorestart=false
startsecs=0
[program:nginx]
priority=10
command=nginx -g "daemon off;"
stdout_logfile=/var/log/supervisor/nginx.log
stderr_logfile=/var/log/supervisor/nginx.log
autorestart=true
Then you can have as many other processes as you want and supervisor will handle the restarting of them if needed.
That way you could use supervisord in cases where you might need nginx and php5-fpm and it doesn't make much sense to have them apart.
Motivation:
There is nothing wrong in running multiple processes inside of a docker container. If one likes to use docker as a light weight VM - so be it. Others like to split their applications into micro services. Me thinks: A LAMP stack in one container? Just great.
The answer:
Stick with a good base image like the phusion base image. There may be others. Please comment.
And this is yet just another plead for supervisor. Because the phusion base image is providing supervisor besides of some other things like cron and locale setup. Stuff you like to have setup when running such a light weight VM. For what it's worth it also provides ssh connections into the container.
The phusion image itself will just start and keep running if you issue this basic docker run statement:
moin#stretchDEV:~$ docker run -d phusion/baseimage
521e8a12f6ff844fb142d0e2587ed33cdc82b70aa64cce07ed6c0226d857b367
moin#stretchDEV:~$ docker ps
CONTAINER ID IMAGE COMMAND CREATED STATUS
521e8a12f6ff phusion/baseimage "/sbin/my_init" 12 seconds ago Up 11 seconds
Or dead simple:
If a base image is not for you... For the quick CMD to keep it running I would suppose something like this for bash:
CMD exec /bin/bash -c "trap : TERM INT; sleep infinity & wait"
Or this for busybox:
CMD exec /bin/sh -c "trap : TERM INT; (while true; do sleep 1000; done) & wait"
This is nice, because it will exit immediately on a docker stop.
Just plain sleep or cat will take a few seconds before the container is forcefully killed by docker.
Updates
As response to Charles Desbiens concerning running multiple processes in one container:
This is an opinion. And the docs are pointing in this direction. A quote: "It’s ok to have multiple processes, but to get the most benefit out of Docker, avoid one container being responsible for multiple aspects of your overall application." For sure it obviously much more powerful to devide your complex service into multiple containers. But there are situations where it can be beneficial to go the one container route. Especially for appliances. The GitLab Docker image is my favourite example of a multi process container. It makes deployment of this complex system easy. There is no way for mis-configuration. GitLab retains all control over their appliance. Win-Win.
Make sure that you add daemon off; to you nginx.conf or run it with CMD ["nginx", "-g", "daemon off;"] as per the official nginx image
Then use the following to run both supervisor as service and nginx as foreground process that will prevent the container from exiting
service supervisor start && nginx
In some cases you will need to have more than one process in your container, so forcing the container to have exactly one process won't work and can create more problems in deployment.
So you need to understand the trade-offs and make your decision accordingly.
Since docker engine v1.25 there is an option called init.
Docker-compose included this command as of version 3.7.
So my current CMD when running a container that should run into infinity:
CMD ["sleep", "infinity"]
and then run it using:
docker build
docker run --rm --init app
crf.:
rm docs and init docs
Capture the PID of the ngnix process in a variable (for example $NGNIX_PID) and at the end of the entrypoint file do
wait $NGNIX_PID
In that way, your container should run until ngnix is alive, when ngnix stops, the container stops as well
Along with having something along the lines of : ENTRYPOINT ["tail", "-f", "/dev/null"] in your docker file, you should also run the docker container with -td option. This is particularly useful when the container runs on a remote m/c. Think of it more like you have ssh'ed into a remote m/c having the image and started the container. In this case, when you exit the ssh session, the container will get killed unless it's started with -td option. Sample command for running your image would be: docker run -td <any other additional options> <image name>
This holds good for docker version 20.10.2
There are some cases during development when there is no service yet but you want to simulate it and keep the container alive.
It is very easy to write a bash placeholder that simulates a running service:
while true; do
sleep 100
done
You replace this by something more serious as the development progress.
How about using the supervise form of service if available?
service YOUR_SERVICE supervise
Once supervise is successfully running, it will not exit unless it is
killed or specifically asked to exit.
Saves having to create a supervisord.conf