`do` block inside a computation expressions got error? - f#

The following code can be compiled.
async {
//do (
use outStream = File.Create(downloading)
do! httpRequestStreamCopyTo url outStream
//)
if File.Exists(fullname) then
File.Delete(fullname)
File.Move(downloading, fullname)
}
And I will need to close the outStream before renaming. So it's changed to
async {
do (
use outStream = File.Create(downloading)
do! httpRequestStreamCopyTo url outStream // Error
)
if File.Exists(fullname) then
File.Delete(fullname)
File.Move(downloading, fullname)
}
And it got the following error on do! httpRequestStreamCopyTo (reportingUri url) outStream?
Error FS0750 This construct may only be used within computation expressions

You can await an embedded async body like this so that outStream is properly scoped:
async {
do! async {
use outStream = File.Create(downloading)
do! httpRequestStreamCopyTo url outStream
}
if File.Exists(fullname) then
File.Delete(fullname)
File.Move(downloading, fullname)
}
Since that embedded body is blocking, this is conceptually equivalent to sequential async calls:
async {
use outStream = File.Create(downloading)
do! httpRequestStreamCopyTo url outStream
}
async {
if File.Exists(fullname) then
File.Delete(fullname)
File.Move(downloading, fullname)
}

Related

Dart Socket one at a time

Hi i am building a blockchain and am trying to sync a list of connected peers,
but if the following code is called twice from different nodes the first call is still busy while the second call kicks in does anyone know how i could wait for the first message to be complete
class Peer {
Peer(
{required this.us,
required this.peers,
required this.allPeers,
required this.myPeers});
String us;
Map<String, int> peers;
Map<String, List<Online>> allPeers;
Map<String, List<Online>> myPeers;
List<String>? keep;
Map<String, List<NewNodePeerMessage>> nnpms = {};
//listen should never trigger a response to connect we will give the address / ip
// so your ndoe two will only sync when a thrid node joins the network
Future listen() async {
ServerSocket ss =
await ServerSocket.bind(us.split(':')[0], int.parse(us.split(':')[1]));
print('listening on ${us.split(':')[1]}');
// List<ReceivePort> lrp = [];
ss.listen((client) {
// ReceivePort rp = ReceivePort();
utf8.decoder.bind(client).listen((data) async {
final PeerMessage pm =
PeerMessage.fromJson(json.decode(data) as Map<String, dynamic>);
print('recieved msg from ${pm.from}');
switch (pm.type) {
case 'new-node':
{
// rp.listen((_) async {
final NewNodePeerMessage nnpm = NewNodePeerMessage.fromJson(
json.decode(data) as Map<String, dynamic>);
print('msg${nnpm.toJson()}');
peers[pm.code] ??= 3;
allPeers[pm.code] ??= [];
final List<Online> news = [];
print('apl ${allPeers[pm.code]!.length}');
// ,maby a list would let me know
// maby we should have a simple check to the loop bool that it doesnt start looping when it is adjusting the peers
print(
'allpeers before looping ${allPeers[pm.code]!.map((e) => e.toJson()).toList()}');
for (Online one in allPeers[pm.code]!.where((element) =>
element.address != pm.from &&
element.address != us &&
!nnpm.recieved.contains(element.address))) {
print(
'i am still loopin current one ${one.toJson()} current from ${pm.from}');
try {
final Socket ones = await Socket.connect(
one.address.split(':')[0],
int.parse(one.address.split(':')[1]));
nnpm.recieved.add(us);
nnpm.recieved.add(pm.from);
// if we would only move ones out of the for loop maby the program wont work at the same point in time
// we could have a bool that keeeps track of the msg is working on printstatement you inside off the msg
// so 8787 trigger 5442 because it has him in the list
// mabe a bool can be added to list if you is inished with listening
// isbusy knows iff its stuck in the loop if we write from here we are
// if we write ffrom connect we arent or this write could know if it is busy
// is busy shoudl be from down
// because if we wirte from here or we write from you is busy is true and false
// so if we write from below can isbusy stop us
// is isusy is true herewe can go into listen but on you we can not
ones.write(json.encode(NewNodePeerMessage(
isBusy: false,
max: peers[pm.code]!,
peer: nnpm.peer,
type: 'new-node',
from: us,
code: pm.code,
recieved: nnpm.recieved)
.toJson()));
print('propablywrote ${one.toJson()} from ${nnpm.from}');
ones.listen((ppmru) async {
print('listentedtoppmru ${one.toJson()}');
final PeersPeerMessageResponse ppmr =
peersPeerMessageResponse(ppmru);
print(
'abouttoaddnewonlines ${ppmr.onlines.map((e) => e.toJson())} and from ${ppmr.from}');
// news.add(Online(online: true, address: ppmr.from));
news.addAll(ppmr.onlines);
await ones.close();
});
} catch (err) {
one.online = false;
// break;
}
print('abouttoloopagain ${one.toJson()} from ${nnpm.from}');
}
print('gothereagainactuallydonelooping ${pm.from}');
// its actually that new node only should write to the client again only if its the first time maby
allPeers[pm.code]!.addAll(news);
allPeers[pm.code]!.removeWhere((element) => !element.online);
print(allPeers[pm.code]!.map((e) => e.toJson()).toList());
/// the problem occurs because of client clients response will shut down base or we could wrap it inside o try an catch
/// we need to know if this message will send the code up here or down to printstatement you to ones.listen or to s that listen
/// one global bool could say like will go down maby even when it goes up herte to printstatement abouttoaddnewonlines
/// how do we know here below that it will go to the you printstatement or down
/// so we need a message from up
allPeers[pm.code]!.add(Online(online: true, address: nnpm.peer));
// print('abouttowriteto ${client.address.address} ${client.port}');
print('abouttorespondto ${pm.from}');
client.write(json.encode(PeersPeerMessageResponse(
isBusy: true,
peer: nnpm.peer,
onlines: allPeers[pm.code]!
.where((element) => element.address != pm.from)
.toList(),
code: pm.code,
from: us)
.toJson()));
// await client.close();
// rp.sendPort.send(null);
// });
client.destroy();
break;
}
case 'new-node-through':
{
break;
}
case 'is-online':
client.write(null);
break;
case 'is-test':
print('recieved');
client.write('irespond');
break;
default:
break;
}
// client.destroy();
}, onDone: () {});
});
}
bool loop = false;
// Future connect(List<dynamic> args) async {
// is busy shoudl bee ffrom down
Future connect(String bootnode, String code) async {
final Socket s = await Socket.connect(
"${bootnode.split(':')[0]}", int.parse(bootnode.split(':')[1]));
print('connected to ${bootnode}');
s.write(json.encode(NewNodePeerMessage(
isBusy: true,
max: 3,
peer: us,
type: 'new-node',
code: code,
from: us,
recieved: []).toJson()));
print('befforelistening');
s.listen((pmmru) async {
print('whatwas first');
PeersPeerMessageResponse ppmr = peersPeerMessageResponse(pmmru);
print(ppmr.toJson());
allPeers[ppmr.code] ??= [];
allPeers[ppmr.code]!.addAll(ppmr.onlines);
allPeers[ppmr.code]!.add(Online(online: true, address: ppmr.from));
print(allPeers);
await s.close();
}, onDone: () {
print('doschopnescheee');
});
//because off up being triggered ffrom this msg we know it will go down because off client that write
// and client that write is up their and it m
// final somekindloop;
//if we would just never listen here would it relay on up might solve problem because up might be busy we could also ssst the isolate
// s.listen((ppmru) async {
// loop = true;
// // whenever we recieve here the ppmru could have the isbusy instead
// // print('you');
// // isBusy
// // while (!loop) {}
// PeersPeerMessageResponse ppmr = peersPeerMessageResponse(ppmru);
// print(ppmr.toJson());
// allPeers[ppmr.code] ??= [];
// allPeers[ppmr.code]!.addAll(ppmr.onlines);
// allPeers[ppmr.code]!.add(Online(online: true, address: ppmr.from));
// print(allPeers);
// await s.close();
// });
}
PeersPeerMessageResponse peersPeerMessageResponse(Uint8List resp) {
final PeersPeerMessageResponse ppm = PeersPeerMessageResponse.fromJson(
json.decode(String.fromCharCodes(resp).trim()) as Map<String, dynamic>);
return ppm;
}
// Future isOnline(String code) async {
// for (Online p in allPeers[code] ??= []) {
// try {
// final Socket peer = await Socket.connect(
// p.address.split(':')[0], int.parse(p.address.split(':')[1]));
// await peer.close();
// } catch (err) {
// p.ischis = false;
// }
// }
// }
}
its about the new node function inside of the switch statement while the first call is inside off the for loop the second call does not loop but increments the allPeers with new peers which because off the first call evolves into
Unhandled exception:
Concurrent modification during iteration: Instance(length:3) of '_GrowableList'.
#0 ListIterator.moveNext (dart:_internal/iterable.dart:336:7)
#1 WhereIterator.moveNext (dart:_internal/iterable.dart:438:22)
#2 Peer.listen.<anonymous closure>.<anonymous closure> (package:gov/peer/peer.dart:180:53)
<asynchronous suspension>
how can is use the on done event to wait or the first call to be complete?

Error thrown from Future.wait() is not caught in a try-catch block

I am failing to understand, why the error thrown from addItem method in below code is not caught in the try-catch block
void main() async {
var executor = Executor();
var stream = Stream.fromIterable([0, 1, 2, 3, 4, 5, 6, 7]);
try {
await for (var _ in stream) {
executor.submit(() => demoMethod());
}
await executor.execute();
} catch (e) {
print(e);
}
}
Future<void> demoMethod() async {
var list = [1, 2, 3, 1, 4, 5];
var executor = Executor();
var test = Test();
for (var element in list) {
executor.submit(() => test.addItem(element));
}
await executor.execute();
test.list.forEach(print);
}
class Test {
var list = <int>[];
Future<void> addItem(int i) async {
if (list.contains(i)) {
throw Exception('Item exists');
}
list.add(i);
}
}
class Executor {
final List<Future<void>> _futures = [];
bool _disposed = false;
void submit(Future<void> Function() computation) {
if (!_disposed) {
_futures.add(computation());
} else {
throw Exception('Executor is already disposed');
}
}
Future<void> execute() async {
await Future.wait(_futures, eagerError: true);
_disposed = true;
}
}
but below code is able to catch the error properly
void main() async {
var executor = Executor();
try {
for (var i = 0; i < 10; i++) {
executor.submit(() => demoMethod());
}
await executor.execute();
} catch (e) {
print(e);
}
}
I am guessing it has something to do with the stream processing.
It's the stream.
In your other examples, you synchronously run through a loop a and call Executor.submit with all the computations, then immediately call executor.execute().
There is no asychronous gap between calling the function which returns a future, and Future.wait starting to wait for that future.
In the stream code, each stream events starts an asynchronous computation by calling Executor.submit. That creates a future, stores it in a list, and goes back to waiting for the stream.
If that future completes, with an error, before the stream ends and Future.wait gets called, then there is no error handler attached to the future yet. The error is then considered unhandled, and is reported to the current Zone's uncaught error handler. Here that's the root zone, which means it's a global uncaught error, which may crash your entire program.
You need to make sure the future doesn't consider its error unhandled.
The easiest way to do that is to change submit to:
void submit(Future<void> Function() computation) {
if (!_disposed) {
_futures.add(computation()..ignore());
} else {
throw StateError('Executor is already disposed');
}
}
The ..ignore() tells the future that it's OK to not have an error handler.
You know, because the code will later come back and call executor.execute, that any errors will still be reported, so it should be safe to just postpone them a little. That's what Future.ignore is for.
(Also changed Exception to StateError, because that's what you should use to report people using objects that have been disposed or otherwise decommissioned.)

Dart program exits without executing last statement

I'm trying to understand Streams and wrote some code.
Everything seems to work, the program exits with status code 0. But it doesn't print the 'loop done' and 'main done' strings. I can't figure out why.
import 'dart:async';
Stream<int> countStream(int to) async* {
for (int i = 1; i <= to; i++) {
yield i;
}
}
class Retry {
StreamController<int> _outgoing;
Retry(Stream<int> incoming) {
_outgoing = StreamController<int>();
_outgoing.addStream(incoming);
}
Future<void> process() async {
await for (final i in _outgoing.stream) {
print("got $i");
}
print('loop done'); // Not printed
}
}
void main() async {
var stream = countStream(4);
var retry = Retry(stream);
await retry.process();
print('main done'); // Not printed
}
The _outgoing.stream is never closed, so code after the await for will never execute. The VM does notice that there also won't be any new events on that stream so nothing else will ever happen, and it can exit. You could fix the bug with:
_outgoing.addStream(incoming).whenComplete(() {
_outgoing.close();
});

async Future StreamSubscription Error

Could someone please explain what's wrong with the following code. I'm making two calls to the function fInputData. The first works ok, the second results in an error :
"unhandled exception"
"Bad state: Stream already has subscriber"
I need to write a test console program that inputs multiple parameters.
import "dart:async" as async;
import "dart:io";
void main() {
fInputData ("Enter Nr of Iterations : ")
.then((String sResult){
int iIters;
try {
iIters = int.parse(sResult);
if (iIters < 0) throw new Exception("Invalid");
} catch (oError) {
print ("Invalid entry");
exit(1);
}
print ("In Main : Iterations selected = ${iIters}");
fInputData("Continue Processing? (Y/N) : ") // this call bombs
.then((String sInput){
if (sInput != "y" && sInput != "Y")
exit(1);
fProcessData(iIters);
print ("Main Completed");
});
});
}
async.Future<String> fInputData(String sPrompt) {
async.Completer<String> oCompleter = new async.Completer();
stdout.write(sPrompt);
async.Stream<String> oStream = stdin.transform(new StringDecoder());
async.StreamSubscription oSub;
oSub = oStream.listen((String sInput) {
oCompleter.complete(sInput);
oSub.cancel();
});
return oCompleter.future;
}
void fProcessData(int iIters) {
print ("In fProcessData");
print ("iIters = ${iIters}");
for (int iPos = 1; iPos <= iIters; iPos++ ) {
if (iPos%100 == 0) print ("Processed = ${iPos}");
}
print ("In fProcessData - completed ${iIters}");
}
Some background reading:
Streams comes in two flavours: single or multiple (also known as
broadcast) subscriber. By default, our stream is a single-subscriber
stream. This means that if you try to listen to the stream more than
once, you will get an exception, and using any of the callback
functions or future properties counts as listening.
You can convert the single-subscriber stream into a broadcast stream
by using the asBroadcastStream() method.
So you've got two options - either re-use a single subscription object. i.e. call listen once, and keep the subscription object alive.
Or use a broadcast stream - note there are a number of differences between broadcast streams and single-subscriber streams, you'll need to read about those and make sure they suit your use-case.
Here's an example of reusing a subscriber to ask multiple questions:
import 'dart:async';
import 'dart:io';
main() {
var console = new Console();
var loop;
loop = () => ask(console).then((_) => loop());
loop();
}
Future ask(Console console) {
print('1 + 1 = ...');
return console.readLine().then((line) {
print(line.trim() == '2' ? 'Yup!' : 'Nope :(');
});
}
class Console {
StreamSubscription<String> _subs;
Console() {
var input = stdin
.transform(new StringDecoder())
.transform(new LineTransformer());
_subs = input.listen(null);
}
Future<String> readLine() {
var completer = new Completer<String>();
_subs.onData(completer.complete);
return completer.future;
}
}

convert the bytes in to readable string format in blackberry?

I am working on an BB app in which I need to maintain a HTTP connection and with a name of image which is stored on server to get the text written in that image document.
I am getting the response in RTF format.
When I directly hit the server on open browser Chrome, I RTF file get downloaded.
Now I needs to perform that programetically,
1) Either convert the bytes which are coming in response in a simple string format so that I can read that.
or
2) Download the file as its happening on the browser manually so that by reading that file I read the information written in the document.
please suggest me how can I read the data from server by hitting any URL?
Currently I am working with this code:
try {
byte []b = send("new_image.JPG");
String s = new String(b, "UTF-8");
System.out.println(s);
} catch (Exception e) {
e.printStackTrace();
}
public byte[] send(String Imagename) throws Exception
{
HttpConnection hc = null;
String imageName = "BasicExp_1345619462234.jpg";
InputStream is = null;
ByteArrayOutputStream bos = new ByteArrayOutputStream();
byte[] res = null;
try
{
hc = (HttpConnection) Connector.open("http://webservice.tvdevphp.com/basisexpdemo/webservices/ocr.php?imgname="+imageName);
hc.setRequestProperty("Content-Type", "multipart/form-data;");
hc.setRequestMethod(HttpConnection.GET);
int ch;
StringBuffer sb= new StringBuffer();
is = hc.openInputStream();
while ((ch = is.read()) != -1)
{
bos.write(ch);
sb.append(ch);
}
System.out.println(sb.toString());
res = bos.toByteArray();
}
catch(Exception e){
e.printStackTrace();
}
finally
{
try
{
if(bos != null)
bos.close();
if(is != null)
is.close();
if(hc != null)
hc.close();
}
catch(Exception e2)
{
e2.printStackTrace();
}
}
return res;
}
The response is like:
{\rtf1\ansi\ansicpg1252\uc1\deflang1033\adeflang1033...................
I can read the data but its not formatted, so that i can read that programetically too.
I have done with this task....
Actually the mistake was on server side.
When they were performing OCR, the format parameter was not corrected that was reason.

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