For 1, I can get 101 to 191 to print. How do I include 203 and up as well so that it includes everything from 10 up? For 2, I can get the first set of names starting with an L to print but not the ones in the and 230. Please don't suggest I use something else like awk or sed, I want to know how to do it the way I am currently trying to do it. How can I expand the ranges I am searching in order to include more. Thanks.
For 1) since it has to be 10 or more, it needs 2 or more digits, so just use this:
grep 'per[0-9]\{2,\}'
For 2), just do
grep 'per[0-9]*:L'
and, of course, you can combine them with
grep 'per[0-9]\{2,\}:L'
Try using the * to grep for repeated Numbers like: grep "per[0-9]*:L" idfile.txt
This is a more detailed answer :)
Regex - Matching arbitrary amount of numbers
Related
so I'm struggling with regex. I'll start with what I want to achieve and then proceed to what I have "so far".
So for example I have commit name lines
merge(#2137): done something
Merge pull request #420 from Example/branch
feat(): done something [#2137JDN]
merge(#690): feat(): done something [#2137JDN]
And I want to grep only by PR ID, or if it's not there then it'd search by that second hash
#2137
#420
#2137JDN
#690
For now I have this regex, but it's not perfect
/(\(|\s|\[)(#\d+|#.+)(\)|\s|\])/g
because it's capturing this
(#2137)
\s#420\s
[#2137JDN]
(#690)[#2137JDN]
How I can improve it to get what I want exactly?
You can use the #[\dA-Z]+ pattern to grep only hashes.
command | grep -Po "#[\dA-Z]+"
Which returns the all matched strings (in our case - hashes)
#2137
#420
#2137JDN
#690
#2137JDN
Unfortunately, grep does not support non-greedy feature. See this answer.
This question already has answers here:
How do you use a plus symbol with a character class as part of a regular expression?
(3 answers)
Closed 2 years ago.
I have a problem to work on and was wondering why my regex won't work. It's a simple exercise to match words in a text dictionary that contains the top row. I believe I have a solution but grep comes up blank every time:
grep ^[qwertyuiop]+$ /opt/~~~~~~/data/web2
this is my command, which does nothing, but if i just put:
grep [qwertyuiop] /opt/~~~~~~/data/web2
it matches words with letters from the top row. Can anybody tell me why it isn't working? Thank you all for your time.
you're super close.
With grep you want to use the -x flag to match the whole line.
grep -x '[qwertyuiop]\+' /usr/share/dict/american-english
then a simple escaped + to match multiple characters.
if you want to avoid the -x you can take your original approach like so:
grep '^[qwertyuiop]\+$' /usr/share/dict/american-english
With an escape and some quotes it works marvelously, although i think the -x is more idiomatic, as some other people have commented, you can also get away with using -e although that can have some unintended consequences. I recommend man grep which gives a nice overview.
I don't think grep recognizes ^ $ or + on it's own. You have to use grep -e or egrep to use special characters like that
This is a common problem I encounter when using grep. Say the pattern is 'chr1' in a third column of a file, when I do the following:
grep 'chr1' file
How can I avoid getting the results including chr10, chr11, chr13 etc as well?
Thanks!
It seems this works:
grep -w 'chr1' file
Since you're interested in values in specific columns, you're much better off using awk:
awk '$3 == "chr1"' file
I need to parse a text file that contains hundreds of records that span more than 1 line each. I'm new to Python and have been trying to do this with grep and awk in several complex ways but no luck yet.
The file contains records that look like this:
409547095517 911033 00:47:41 C44 00:47:46 D44 00:47:53 00:47:55
(555) 555-1212 00:47 10/31 100 Main Street - NW
Some_City TX 323 WRLS METRO PCS
P# 122-5217 ALT# 555-555-1212 LEC:MPCSI WIRELESS CALL Q
UERY CALLER FOR LOCATION QUERY CALLER FOR PHONE #*
Really I can do all I need to if I could just get these multi-line records condensed to 1 line per record. Each record will always begin with "40" or I could let 9110 indicate start as these will always be there and are unqiue providing 40 is at begining of line. I used a HEX editer and found that I could remove all line feeds (hex 0D0A) but this is not better than manually editing the files and programaticaly I'd need to not remove the last one per record. Some records will be only 2 lines but most will be 5 like this one.
Is there a way python or otherwise to concatonate the lines that make up a record into one line where 40 or maybe better choice where 9110 indicates the start of the record?
Any ideas or pointers will be much appreciated. I've got python and a good IDE and I'm good with grep and find but learning awk (don't laugh)...
awk will do it. You need to identify The line that starts a record. In this case it is 409547095517
So let's assume that to be safe if a line starts with 8 numbers it is the start of a record.
awk ' NR> 1 && /^[0-9]{8}/ { printf("\n") }
{printf("%s", $0) }
END{ printf("\n") }' filename > newfilename
Change the {8} to any number that works for you.
I want to grep for the string THREAD: 2. It has a space in between. Not able to figure out how.
I tried with grep "THREAD:[ \2]", but its not working
Please let me know.
Try grep "THREAD: 2" <filename>? You just want a literal '2', right?
If you are using GNU grep you could try using the alias egrep or grep -e with 'THREAD: 2$'
You might have to use '^.*THREAD: 2$'
grep reports back the entire line that has matched your pattern. If you wish to look at lines that contains THREAD: 2 then the following should work -
grep "THREAD: 2" filename
However, if you wish to fetch lines that could contain THREAD: and any number then you can use a character class. So in that case the answer would be -
grep "THREAD: [0-9]" filename
You can add + after the character class which means one or more numbers so that you can match numbers like 1,2,3 or 11,12,13 etc.
If you only want to fetch THREAD: 2 from your line then you will have to use an option of grep which is -o. It means show me only my pattern from the file not the entire line.
grep -o "THREAD: 2" filename
You can look up man page for grep and play around with all the options.