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I have the Array which contains the mix data.
Its like
["AB_1020", "AB_950", "AB_50", "1000", "570"]
The output should be
AB_50, AB_950, AB_1020, 570, 1000
["AB_1020", "AB_950", "AB_50", "1000", "570"].sort_by do |k|
i, w = k.split('_').rotate
[w.to_s, -i.to_i]
end.reverse
#⇒ ["AB_50", "AB_950", "AB_1020", "570", "1000"]
You can do something like this
p ["AB_1020", "AB_950", "AB_50", "1000", "570"].partition{|x| x.to_i.zero? }
.flat_map{|x| x.sort_by {|x|x[/d+/]}.reverse}
ouptut
#⇒ ["AB_50", "AB_950", "AB_1020", "570", "1000"]
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if you know, how I can write generator with condition in F# - tell me please!) something like that:
let res = [for i in 1..5 if i % 2 = 0 then i]
printfn "%A" res
You were almost on the right track.
let res =
[
for i in 1..5 do
if i % 2 = 0 then
yield i
]
The feature you're looking for is list comprehensions.
This is similar to yield return in C#. The same comprehensions are available for seq and Array.
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x = [1, 2, 3, 4]
x[1, x.size - 1]
#=> [2, 3, 4]
How do I rewrite this code to make it more elegant.
I would like something like
x[1, -1]
Array#[] accepts a Range instance, and the right boundary can be negative, specifying the amount of elements from the end:
x[1..-1]
Try this one instead.
x[1..-1]
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Someone can teach me how to generate a random string with n digits number.
Ex: n=3, myString = "001" or "002" or ... "999" (except number 0 at begin)
p/s: I am using Ruby 1.8.7
n.times.map { (0..9).to_a.sample }.join
If it's for a password or something:
require 'securerandom'
random_number = SecureRandom.random_number(10**n)
formatted_number = "0#{random_number}"
Edit: If it doesn't need to be secure:
random_number = rand(10**n)
formatted_number = "0#{random_number}"
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A custom function that will return a random number with a step option available like in the for loop.
Example:
for i=1,10,**2** do
print(i)
end
Do you mean this:
function randomWithStep(first, last, stepSize)
local maxSteps = math.floor((last-first)/step)
return first + stepSize * math.random(0, maxSteps)
end
This gives the same behavior as math.random(first, last) except that the values will be "stepSize" apart. Note that the highest random # may not be "last", depends if (last-first) is a multiple of stepSize.
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I have php code, where occur sort, like this:
j=0;
while(...){
...
$cancel_alarm_trusee[$j]['created'] = alarm['created'];
...
j++;
}
function Compare($a, $b) {
return $a['created'] < $b['created'];
}
usort($cancel_alarm_trusee, 'Compare');
How to do it in Ruby?
Ruby Has Enumerable#sort and Enumerable#sort_by also.Look those methods.
Example:
%w{apple pear fig}.sort_by { |word| word.length}
#=> ["fig", "pear", "apple"]
%w(rhea kea flea).sort
#=> ["flea", "kea", "rhea"]