This question already has answers here:
How to properly format currency on ios
(8 answers)
How to input currency format on a text field (from right to left) using Swift?
(9 answers)
Closed 4 years ago.
I have a values like that: 100, 1220, 10015 basically last 2 digits are cents and I need to convert to dollar (currency) format similar to:
1.00, 12.20, 100.15
Can somebody suggest a quick implementation?
var a = 1011
var b = Double(a) / 100
Related
This question already has answers here:
How to know if a number is odd or even in Swift?
(5 answers)
Closed 11 months ago.
im absolutely new to development, and trying to learn swift.
Right now i know how to make random number, and my next step is:
Im trying to understand how to check if my random number (127) could be divided by 2 without decimals ?
I have no idea how to do it.
There is a specific API isMultiple(of:) in Standard Library for this purpose
let random = Int.random(in: 0..<100)
let isEven = random.isMultiple(of: 2)
You can use operator % - remainder operator
example:
if randomNumber % 2 == 0 {
print("\(randomNumber) is even")
} else {
print("\(randomNumber) is odd")
}
This question already has answers here:
ultimate short custom number formatting - K, M, B, T, etc., Q, D, Googol
(3 answers)
Closed 6 months ago.
Hello How I can round that number without using custom formats like this "[>999999]0.0,,\M;[>999]0.0,\K;0"
Because if y use the custom format with this formula '="EXAMPLE "&E24' puts the value without that format.
try:
="example "&IF(A1<1000, A1,
IF(A1<1000000, TEXT(A1/1000, "#.0")&"K",
IF(A1<1000000000, TEXT(A1/1000000, "#.0")&"M",
IF(A1<1000000000000, TEXT(A1/1000000000, "#.0")&"B",
TEXT(A1/1000000000000, "#.0")&"T"))))
This question already has answers here:
How to convert a double to an int in Dart?
(11 answers)
How do you round a double in Dart to a given degree of precision AFTER the decimal point?
(28 answers)
Closed 3 years ago.
I want to round a double.
Double x = 5.56753;
x.toStringAsFixed(2);
When i put this, it gives 5.57000.
But i want to get 5.57. How do i get it?
there is num class contained function round():
Num
double numberToRound = 5.56753;
print(numberToRound.round());
//prints 6
If you want decimals
double n = num.parse(numberToRound.toStringAsFixed(2));
print(n);
//prints 5.57
check comment sujestion
For rounding doubles checkout: https://api.dartlang.org/stable/2.4.0/dart-core/double/round.html
Rounding won't work in your case because docs says:
Returns the integer closest to this.
So it will give 6 instead 5.57.
Your solution:
double x = 5.56753;
String roundedX = x.toStringAsFixed(2);
print(roundedX);
This question already has answers here:
A way to round Floats down
(11 answers)
Closed 6 years ago.
I have number num = 24.89808 and want to round it to 24.89
How can i do it?
i tried num.round(2) but it gives me 24.9 also number_to_currency=>24.90
If you are talking about rounding, 24.9 is by all means the correct result. Whether you are interested in ceiling it, here you go:
(24.89808 * 100).floor / 100.0
#⇒ "24.89"
First convert that into a decimal and then round it two two places,
Try this command,
num.to_d.round(2, :truncate).to_f
2.2.4 :040 > num = 24.89808
=> 24.89808
2.2.4 :041 > num.to_d.round(2,:truncate).to_f
=> 24.89
This question already has answers here:
How do I calculate a logarithm in iOS? [duplicate]
(3 answers)
Closed 9 years ago.
I need to calculate Log (base 10) and Log (base e – Naperian/Natural).
I am now assuming that Log (base 10) is:
double log10 ( double );
And am I correct to assume that Log (base e – Naperian/Natural) is just:
double log ( double );
Thanks
Check man 3 log for man page. In iOS 6 there is also vecLib which has logarithmic functions.