How to create an extension of Collection that removes null values? - ios

I have this code, but it shows error:
extension Collection {
func removingOptionals() -> [Element] {
var result = [Element](); // Error: cannot call value of non-function type '[Self.Element.Type]'
self.forEach({ (element) in if let el = element { result.append(el); } });
return result;
}
}
If I removed the (), the error becomes: Expected member name or constructor call after type name.
This code is supposed to transform [String?] into [String] by discarding all the null values. Or any other optional data types.
How can I do this?

You can use flatMap {} for this, instead of creation own function. Here is example of usage:
let strings: [String?] = ["One", nil, "Two"]
print(strings.flatMap { $0 })
And result will be ["One", "Two"]

You can continue to use the flatMap behavior of the Optional as the other answer shows, but it's going to be deprecated on the next Swift iteration.
If you want to add the extension to the collection type, you need to be a create a type to box the Optional (You can't extend Collection if the type is generic, like Optional).
protocol OptionalType {
associatedtype Wrapped
func map<U>(_ f: (Wrapped) throws -> U) rethrows -> U?
}
extension Optional: OptionalType {}
extension Collection where Iterator.Element: OptionalType {
func removeNils() -> [Iterator.Element.Wrapped] {
var result: [Iterator.Element.Wrapped] = []
result.reserveCapacity(Int(self.count))
for element in self {
if let element = element.map({ $0 }) {
result.append(element)
}
}
return result
}
}

Related

How to get object (self) generic type in extension swift?

I am making am function to convert a Set to an array using extension to Set. But I am not able to get generic type of Set in that extension. For example if there is an object of Set of type String then toArray() function should return an array of String ( [String] ). I am creating this function like this.
extension Set{
func toArray() -> [/*What type should take*/]{
var array = [/*What type should take*/]()
for s in self{
array.append(s)
}
return array
}
}
// Here is what I am expecting from the above func.
var myset = Set<String>()
let arr = myset.toArray() // Should return [String]
It was simple use Element to get its Generic type
extension Set{
func toArray() -> [Element]{
var array = [Element]()
for s in self{
array.append(s)
}
return array
}
}
You can use Element to get the element type, however there is no real need for this extension as you can simply say let arr = Array(mySet)
If you did want to use the extension you can simplify it to:
extension Set {
func toArray() -> [Element] {
return Array(self)
}
}

Generic parameter could not be inferred - Array extension

I have generic method to create object that extend protocol FromResponse.
extension FromResponse {
static func object<T>(_ response: [String: Any]?) -> T? where T: FromResponse, T: NSObject {
guard let response = response else { return nil }
let obj: T = T()
return obj
}
}
So whenever I want to call it from anywhere in a code there is no issue. Let's say:
let myObject: MyObject? = MyObject.object(response)
Work's perfectly. But sometimes I'm getting array of objects from my response so I would like to have generic parser as well:
static func objects<T>(_ response: [[String: Any]]?) -> [T]? where T: FromResponse, T: NSObject {
guard let response = response else { return nil }
var returnArray: [T] = [T]()
for singleResponse in response {
if let object: T = T.object(singleResponse) {
returnArray.append(object)
}
}
return returnArray
}
So I expect from this method to return array of MyObject, but In fact I'm getting compiler error when I'm calling this:
let myObjects: [MyObject]? = MyObject.objects(response)
It says:
Generic parameter 'T' could not be inferred
Well, I know what does it mean but I did specify type, so this error should not happen. Also when I do this:
var typ: [MyObject] = [MyObject]()
for singleResponse in (response as? [[String: Any]])! {
let pack: MyObject? = MyObject.object(singleResponse)
typ.append(pack!)
}
It works!
Why? How to have parser that returns array of generics objects?
I don't know for sure why Swift says “Generic parameter 'T' could not be inferred”, but my guess is it has to do with array covariance.
What's covariance? Consider this:
class Base { }
class Sub: Base { }
func f(_ array: [Base]) { }
Can you pass an [Sub] to f? In Swift, you can. Because Sub is a subtype of Base, [Sub] is a subtype of [Base]. (This is called “covariance”.) So you can pass a [Sub] anywhere that a [Base] is allowed:
f([Sub]())
// No errors.
And you can return a [Sub] where a [Base] is expected:
func g() -> [Base] { return [Sub]() }
// No errors.
And you can assign a [Sub] to a [Base] variable:
let bases: [Base] = [Sub]()
// No errors.
So back to your code:
static func objects<T>(_ response: [[String: Any]]?) -> [T]? ...
let myObjects: [MyObject]? = MyObject.objects(response)
Certainly MyObject.objects(_:) must return a type that can be treated as [MyObject]?. But any subtype of [MyObject]? is also acceptable. The type is not tightly constrained. I guess this is why Swift doesn't like it.
The fix is to tell Swift explicitly what type you want, using a pattern you'll see in many places in the Swift standard library:
static func objects<T>(ofType type: T.Type, from response: [[String: Any]]?) -> [T]? ...
// Note that you might not actually have to use the `type` parameter
// in the method definition.
let myObjects = MyObject.objects(ofType: MyObject.self, from: response)
It's not clear why this method is on the MyObject class at all. Perhaps you should make it a method on [[String: Any]]:
extension Collection where Element == [String: Any] {
func objects<T>(ofType type: T.Type) -> [T]? ...
}
let myObjects = response.objects(ofType: MyObject.self)

GroupBy Extension Usage on Array on Swift

I have an array consists of Dictionary.
I need to group them by Key in a dictionary.
I tried the line, but do not know what to write in handler. I am trying
globalArray.groupBy(handler: {$0["Name"]})
it gives error;
Cannot convert value of type "String?" to closure result type "_"
my group by extension is as follows;
extension Sequence {
// Using a `typealias` because it's shorter to write `E`
// Think of it as a shortcut
typealias E = Iterator.Element
// Declaring a `K` generic that we'll use as the type of the key
// for the resulting dictionary. The only restriction is having
// it conforming to the `Hashable` protocol
func groupBy<K: Hashable>(handler: (E) -> K) -> [K: [E]] {
// Creating the resulting dictionary
var grouped = [K: [E]]()
// Iterating over our elements
self.forEach { item in
// Retrieving the key based on the current item
let key = handler(item)
if grouped[key] == nil {
grouped[key] = []
}
grouped[key]?.append(item)
}
return grouped
}
}
Could you please show me the right usage?
BR,
Erdem
I am using this extension to group array , and it is working superbly
extension Array {
func grouped<T>(by criteria: (Element) -> T) -> [T: [Element]] {
var groups = [T: [Element]]()
for element in self {
let key = criteria(element)
if groups.keys.contains(key) == false {
groups[key] = [Element]()
}
groups[key]?.append(element)
}
return groups
}
}
How I use
array.grouped { (object:MyObjectClass) -> String in
return object.location?.name ?? "EmptyKey"
//Here you need to return your key
}
Hope it is helpful to you

How to make generics in collection type constraint?

I have been trying to extract non-nil values from the String array. Like below. But, my senior wants it to be able to extract non-nil values from other types too.
I read, generics could help me for handling different types. How can I use generics so that I get to use following like extension to work with other types too?
getNonNil must return the extracted non-nil values of the specific type (i.e. if array is [String?] it must return [String], returns [Int] if [Int?])
Because I have to do further calculations.
What I have tried is below:
import Foundation
// Extended the collection-type so that collectiontype is constrained to having element with optional strings
extension CollectionType where Self.Generator.Element == Optional<String>{
func getNonNil() -> [String] {
// filter out all nil elements and forcefully unwrap them using map
return self.filter({$0 != nil}).map({$0!})
}
}
// Usage
let x: [String?] = ["Er", "Err", nil, "errr"]
x.getNonNil().forEach { (str) in
print(str)
}
For getNonNil you could simply use
x.flatMap { $0 }
// returns ["Er", "Err", "errr"] which is [String]
For the original question, typically you could introduce a protocol to the Optional type (e.g. via the muukii/OptionalProtocol package):
protocol OptionalProtocol {
associatedtype Wrapped
var value: Wrapped? { get }
}
extension Optional: OptionalProtocol {
public var value: Wrapped? { return self }
}
extension CollectionType where Self.Generator.Element: OptionalProtocol {
func getNonNil() -> [Self.Generator.Element.Wrapped] {
...
}
}
There's no easy way of achieving this through an extension, as you cannot introduce new generic types into extensions (although this is part of the Swift Generics Manifesto – so may well be possibly in a future version of Swift).
As #kennytm says, the simplest solution is just to use flatMap, which filters out nil:
x.flatMap{$0}.forEach { (str) in
print(str)
}
If however, you still want this as an extension, you could use a protocol workaround in order to allow you to constrain the extension to any optional element type (Swift 3):
protocol _OptionalProtocol {
associatedtype Wrapped
func _asOptional() -> Wrapped?
}
extension Optional : _OptionalProtocol {
func _asOptional() -> Wrapped? {return self}
}
extension Collection where Self.Iterator.Element : _OptionalProtocol {
func getNonNil() -> [Iterator.Element.Wrapped] {
return flatMap{$0._asOptional()}
}
}
...
let x : [String?] = ["Er", "Err", nil, "errr"]
x.getNonNil().forEach { (str) in
print(str)
}
(In Swift 3, CollectionType has been renamed to Collection, and Generator is now Iterator)
Although flatMap is almost certainly preferred in this situation, I'm only really adding this for the sake of completion.
The easiest approach is using flatMap as kennytm suggested, but if you absolutely want to know how to create such a method using generics, one approach would be to create a global method that takes in the collection as a parameter:
public func getNonNil<T, C: CollectionType where C.Generator.Element == Optional<T>>(collection: C) -> [T] {
return collection.filter({$0 != nil}).map({$0!})
}
let x: [String?] = ["Er", "Err", nil, "errr"]
print(getNonNil(x)) // returns ["Er", "Err", "errr"]

is it possible to create a generic closure in Swift? [duplicate]

This question already has answers here:
Closure with generic parameters
(2 answers)
Closed 7 months ago.
func myfunc<T>(i:T) -> T {
return i
}
is it possible to make this generic function a closure?
let myfunc = { <T>(i:T) -> T in
return i
}
this doesn't work...
No, because variables and expressions can't be generic. There are only generic functions and generic types.
To clarify: In some languages you can have types with a universal quantifier, like forall a. a -> a. But in Swift, types cannot have a universal quantifier. So expressions and values cannot be themselves generic. Function declarations and type declarations can be generic, but when you use such a generic function or an instance of such a generic type, some type (which could be a real type or a type variable) is chosen as the type argument, and thereafter the value you get is no longer itself generic.
Probably you need something like this.
Type declaration:
typealias ResultClosure<T> = (ResultCode, String?, T?) -> Void
Function declaration:
func loginUser(userName: String, password: String, resultHandler: ResultClosure<TokenModel>?)
Usage:
NetConnector.shared.loginUser(userName: userName ?? "", password: password ?? "") { (code, message, data) in
self.display?.unlockScreen()
if code == .success {
if let activeToken = data {
AppData.shared.userToken = activeToken
}
self.display?.showHome()
} else {
self.display?.showError(errorMessage: message)
}
}
As mentioned, variables in Swift cannot be generic, so creating a closure, whose generic types are specified by the caller is not possible. However, there are workarounds:
With SE-253, it is possible to make arbitrary (nominal) types callable. So instead of declaring a generic closure, we can declare a (non-generic) struct that has a generic callAsFunction method:
struct MyFunc {
func callAsFunction<T>(_ i: T) -> T {
return i
}
}
Now, we can declare a non-generic variable that we can call with a generic value:
let myFunc = MyFunc()
let x = myFunc(42) // -> Int
let y = myFunc("foo") // -> String
Note that this workaround doesn't apply to all situations, but it can be helpful in some.
I have found some alternative way , you can use Anyobject in your closure and pass any values to your method .
typealias genericCompletion<T:AnyObject> = ((Bool,T,String) -> Void)
struct Student {
var name:String = "Kishore"
var age : String = "125"
}
class ViewController: UIViewController {
override func viewDidLoad() {
super.viewDidLoad()
self.createAGenericReturn { (success, object, message) in
}
self.createStructGeneric { (success, student, message) in
}
}
func createAGenericReturn(callback:#escaping(genericCompletion<AnyObject>)){
callback(true,434.433 as AnyObject,"kishoreTest")
}
func createStructGeneric(callback:#escaping(genericCompletion<AnyObject>)){
callback(true,Student.init() as AnyObject,"kishoreTest")
}
}
Here you can see I mentioned Generic as Anyobject typealias genericCompletion = ((Bool,T,String) -> Void) , So you can pass any values to it .

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