I am having trouble with command output formatting.
In terminal this works nicely:
df | grep sda1 | head -c33 | tail -c7 | tr -d " "
In genmon, I get only numbers such as "1145944":
SDAFREE=$(df | grep sda1 | head -c33 | tail -c7 | tr -d " ")
echo="$SDAFREE"
How do I print that command's output through genmon to xfce panel correctly (same as in terminal)?
Thank you.
I have the same issue with every command with a pipe. As a workaround I put the command in a executable script and run the script in genmon.
BTW:
if you want just one value of a table, you can use awk instead of head, tail and tr:
df | awk '/sda1/ {print $4}'
Related
I have this a file.txt with one line, whose content is
/app/jdk/java/bin/java -server -Xms3g -Xmx3g -XX:MaxPermSize=256m -Dweblogic.Name=O2pPod8_mapp_msrv1_1 -Djava.security.policy=/app/Oracle/Middleware/Oracle_Home/wlserver/server/lib/weblogic.policy -Djava.security.egd=file:/dev/./urandom -Dweblogic.ProductionModeEnabled=true -Dweblogic.system.BootIdentityFile=/app/Oracle/Middleware/Oracle_Home/user_projects/domains/O2pPod8_domain/servers/O2pPod8_mapp_msrv1_1/data/nodemanager/boot.properties -Dweblogic.nodemanager.ServiceEnabled=true -Dweblogic.nmservice.RotationEnabled=true -Dweblogic.security.SSL.ignoreHostnameVerification=false -Dweblogic.ReverseDNSAllowed=false -Xms8192m -Xmx8192m -XX:MaxPermSize=2048m -XX:NewSize=1300m -XX:MaxNewSize=1300m -XX:SurvivorRatio=4 -XX:TargetSurvivorRatio=90 -XX:+UseParNewGC -XX:+UseConcMarkSweepGC -XX:+CMSParallelRemarkEnabled
and when I do
cat file.txt | grep -io "Xms.*" | awk '{FS" "; print $1} ' | cut -d "s" -f2
output:
3g
why is grep not reading the second occurrence, i.e. I expect 3g and 8192m.
Infact, how do I print only 8192m in this case?
Your regex just says "find Xms followed by anything repeated 0 to n times". That returns the rest of the row from Xms onward.
What you actually want is something like "find Xms followed by anything until there's a whitespace repeated 0 to n times".
grep -io "Xms[^ ]*" file.txt | awk '{FS" "; print $1} ' | cut -d "s" -f2
In [^ ] the ^ means "not"
I'm not really sure what you are trying to achieve here but if you want the endings of all space-separated strings starting with -Xms, using bare awk is:
$ awk -v RS=" " '/^-Xms/{print substr($0,5)}' file
3g
8192m
Explained:
$ awk -v RS=" " ' # space separated records
/^-Xms/ { # strings starting with -Xms
print substr($0,5) # print starting from 5th position
}' file
If you wanted something else (word repeated in the title puzzles me a bit), please update the question with more detailed requirements.
Edit: I just noticed how do I print only 8192m in this case (that's the repeated maybe). Let's add a counter c and not print the first instance:
$ awk -v RS=" " '/^-Xms/&&++c>1{print substr($0,5)}' file
8192m
You could use grep -io "Xms[0-9]*[a-zA-Z]" instead of grep -io "Xms.*" to match a sequence of digits followed by a single character instead the entire line within a single group:
cat file.txt | grep -io "Xms[0-9]*[a-zA-Z]" | awk '{FS" "; print $1} ' | cut -d "s" -f2
Hope this helps!
The .* in your regexp is matching the rest of the line, you need [^ ]* instead. Look:
$ grep -o 'Xms.*' file
Xms3g -Xmx3g -XX:MaxPermSize=256m -Dweblogic.Name=O2pPod8_mapp_msrv1_1 -Djava.security.policy=/app/Oracle/Middleware/Oracle_Home/wlserver/server/lib/weblogic.policy -Djava.security.egd=file:/dev/./urandom -Dweblogic.ProductionModeEnabled=true -Dweblogic.system.BootIdentityFile=/app/Oracle/Middleware/Oracle_Home/user_projects/domains/O2pPod8_domain/servers/O2pPod8_mapp_msrv1_1/data/nodemanager/boot.properties -Dweblogic.nodemanager.ServiceEnabled=true -Dweblogic.nmservice.RotationEnabled=true -Dweblogic.security.SSL.ignoreHostnameVerification=false -Dweblogic.ReverseDNSAllowed=false -Xms8192m -Xmx8192m -XX:MaxPermSize=2048m -XX:NewSize=1300m -XX:MaxNewSize=1300m -XX:SurvivorRatio=4 -XX:TargetSurvivorRatio=90 -XX:+UseParNewGC -XX:+UseConcMarkSweepGC -XX:+CMSParallelRemarkEnabled
$ grep -o 'Xms[^ ]*' file
Xms3g
Xms8192m
$ grep -o 'Xms[^ ]*' file | cut -d's' -f2
3g
8192m
$ grep -o 'Xms[^ ]*' file | cut -d's' -f2 | tail -1
8192m
or more concisely:
$ sed 's/.*Xms\([^ ]*\).*/\1/' file
8192m
The positive lookbehind of PCRE (the form: (?<=RE1)RE2) can resolve the problem easily:
$ grep -oP '(?<=Xms)\S+' file.txt
3g
8192m
Explains:
-o: show only the part of a line matching PATTERN.
-P: PATTERN is a Perl regular expression.
(?<=Xms)\S+: matches all continuous non-whitespace strings which are just following the string Xms.
We have a portion of code which states,
"diff file1 file2 | /usr/bin/grep -v "#" | /usr/bin/grep ^\> | /usr/bin/awk '{print $3}' | /usr/bin/xargs mkdir"
The whole statement is enclosed in double quotes(is a requirement of the application syntax). When the application reaches this stage , it gives the grep error.
This statement works well on the command line. But through application, gives error for grep.
Usage: grep [OPTION]... PATTERN [FILE]...
Try `grep --help' for more information.
So not sure if it is first grep or second grep which is a problem.
Seems like a problem with double quotes. Try changing your first grep to /usr/bin/grep -v '#' and the second grep to /usr/bin/grep '^>'
You are using grep -v ^> and > means "redirect".
If you for example do:
grep ^>output
all the output will be stored in the file output.
So what you need to do is to quote ^> so that it is interpreted as the pattern you are looking for:
"diff file1 file2 | /usr/bin/grep -v "#" | /usr/bin/grep "^>" | /usr/bin/awk '{print $3}' | /usr/bin/xargs mkdir"
^ ^
By the way, note all your greps can be reduced like this:
diff file1 file2 | awk '/#/ || /^>/ {print $3}' | /usr/bin/xargs mkdir
^^^ ^^ ^^^^
either contains # | |
or starts with >
I'm running this command on OS X to pull the logic board ID:
ioreg -l | grep board-id
which gives me this output:
| "board-id" = <"Mac-FC02E91DDD3FA6A4">
The only part I'm interested in is the "Mac-FC02E91DDD3FA6A4". Is there a way to filter the results from grep to only show me this part? OR is there a second step I could do to clean up the grep results?
Using awk you can do this
ioreg -l | awk -F\" '/board-id/ {print $4}
Mac-FC02E91DDD3FA6A4
This search for board-id, divide output by " and then print part 4
ioreg -l | grep "board-id" | cut -d \" -f 4
one way still with grep, try this line:
ioreg -l|grep -Po 'board-id".*<"\K[^"]*'
This command gives me the following output:
cat /proc/net/dev | awk '{print $1}'
Inter-|
face
eth0:
lo:
wlan0:
Is there a way to dismiss the lines inter-|, face so i can get only the names of the interfaces?
Tweaking your awk a little bit:
awk 'NR>2{print $1}' /proc/net/dev
tail -n +3 /proc/net/dev | awk...
tail -n {+whatever} (note the plus sign) can be used to dump files starting from the nth line.
There are many ways of doing this. If you just need it work for that specific case I'd do something simple like this:
cat /proc/net/dev | awk '{print $1}' | sed -e '1,2d'
Sed '1,2d' just means delete lines 1 and 2.
In addition to the other answers:
just in case you don't want to use awk with tail, you can do also this:
tail -n +3 /proc/net/dev | cut -d':' -f1
I have a file name clfile.me that looks like this;
44433430,"FALSE"
33095934,"TRUE"
41549968,"TRUE"
37945528,"FALSE"
18284764,"FALSE"
15007934,"FALSE"
The number is AIX PID. I have a command that will match the PIDs to a running process.
while read p; do
ps -ef | grep $p | grep 'myproram' | grep -v grep | awk "{ print \$2 }" >> clout.me
done < clfile.me
THe above works but only shows me the PID that matched from the grep command. I want to be able to see the matching PID and the TRUE or FALSE value from the original file. I guess I am asking how I filter the original file by PIDs that match my grep command.
Any thoughts?
Thanks
Chris
Took me a while, but I have it!
cat /dev/null > clout.me
while read p; do
x=$(awk '{ print $1 }')
ps -ef | grep x | grep 'myprogram' | grep -v grep | awk "{ print \$2 }" >> clout.me
done < clfile.me
awk 'FNR==NR{A[$1]=1;next} A[$1]' clout.me clfile.me