multitouch in iOS [duplicate] - ios

Question

So I've been messing around trying to get the coordinates of touches on the screen. So far I can get the coordinates of one touch with this:
override func touchesBegan(touches: NSSet, withEvent event: UIEvent) {
let touch = touches.anyObject()! as UITouch
let location = touch.locationInView(self.view)
println(location)
}
But when touching with two fingers I only get the coordinates of the first touch. Multi-touch works (I tested with this little tutorial: http://www.techotopia.com/index.php/An_Example_Swift_iOS_8_Touch,_Multitouch_and_Tap_Application). So my question is, how do I get the coordinates of the second (and third, fourth...) touch?

Answer 1

** Updated to Swift 4 and Xcode 9 (8 Oct 2017) **
First of all, remember to enable multi-touch events by setting
self.view.isMultipleTouchEnabled = true
in your UIViewController's code, or using the appropriate storyboard option in Xcode:
Otherwise you'll always get a single touch in touchesBegan (see documentation here).
Then, inside touchesBegan, iterate over the set of touches to get their coordinates:
override func touchesBegan(_ touches: Set<UITouch>, with event: UIEvent?) {
for touch in touches {
let location = touch.location(in: self.view)
print(location)
}
}

Answer 2

the given touches argument is a set of detected touches.
You only see one touch because you select one of the touches with :
touches.anyObject() // Selects a random object (touch) from the set
In order to get all touches iterate the given set
for obj in touches.allObjects {
let touch = obj as UITouch
let location = touch.locationInView(self.view)
println(location)
}

Answer 3

You have to iterate over the different touches. That way you can access every touch.
for touch in touches{
//Handle touch
let touchLocation = touch.locationInView(self.view)
}

Answer 4

In Swift 1.2 this has changed, and touchesBegan now provides a Set of NSObjects.
To iterate through them, cast the touches collection as a Set of UITouch objects as follows:
override func touchesBegan(touches: Set<NSObject>, withEvent event: UIEvent) {
var touchSet = touches as! Set<UITouch>
for touch in touchSet{
let location = touch.locationInView(self.view)
println(location)
}
}

Answer 5

For Swift 3, based on #Andrew's answer :
override func touchesMoved(_ touches: Set<UITouch>, with event: UIEvent?) {
let touchSet = touches
for touch in touchSet{
let location = touch.location(in: self.view)
print(location)
}
}
EDIT, My bad, that's not answering your question, had the same problem and someone linked me to this previous answer :
Anyway, I had to change few things to make it works in swift 3, here is my current code :
var fingers = [String?](repeating: nil, count:5)
override func touchesBegan(_ touches: Set<UITouch>, with event: UIEvent?) {
super.touchesBegan(touches, with: event)
for touch in touches{
let point = touch.location(in: self.view)
for (index,finger) in fingers.enumerated() {
if finger == nil {
fingers[index] = String(format: "%p", touch)
print("finger \(index+1): x=\(point.x) , y=\(point.y)")
break
}
}
}
}
override func touchesMoved(_ touches: Set<UITouch>, with event: UIEvent?) {
super.touchesMoved(touches, with: event)
for touch in touches {
let point = touch.location(in: self.view)
for (index,finger) in fingers.enumerated() {
if let finger = finger, finger == String(format: "%p", touch) {
print("finger \(index+1): x=\(point.x) , y=\(point.y)")
break
}
}
}
}
override func touchesEnded(_ touches: Set<UITouch>, with event: UIEvent?) {
super.touchesEnded(touches, with: event)
for touch in touches {
for (index,finger) in fingers.enumerated() {
if let finger = finger, finger == String(format: "%p", touch) {
fingers[index] = nil
break
}
}
}
}
I still have a little problem but I think it's linked to my GestureRecognizer in my code.
But that should do the trick.
It will print you the coordinate of each point in your consol.

Answer 6

In Swift 3,4
Identify touch pointer by its hash:
// SmallDraw
func pointerHashFromTouch(_ touch:UITouch) -> Int {
return Unmanaged.passUnretained(touch).toOpaque().hashValue
}