please take a look at the bin-win target in my repository here:
https://github.com/thinlizzy/bazelexample/blob/master/demo/BUILD#L28
it seems to be properly packing the executable inside a file named bin-win.tar.gz, but I still have some questions:
1- in my machine, the file is being generated at this directory:
C:\Users\John\AppData\Local\Temp_bazel_John\aS4O8v3V\execroot__main__\bazel-out\x64_windows-fastbuild\bin\demo
which makes finding the tar.gz file a cumbersome task.
The question is how can I make my bin-win target to move the file from there to a "better location"? (perhaps defined by an environment variable or a cmd line parameter/flag)
2- how can I include more files with my executable? My actual use case is I want to supply data files and some DLLs together with the executable. Should I use a filegroup() rule and refer its name in the "srcs" attribute as well?
2a- for the DLLs, is there a way to make a filegroup() rule to interpret environment variables? (e.g: the directories of the DLLs)
Thanks!
Look for the bazel-bin and bazel-genfiles directories in your workspace. These are actually junctions (directory symlinks) that Bazel updates after every build. If you bazel build //:demo, you can access its output as bazel-bin\demo.
(a) You can also set TMP and TEMP in your environment to point to e.g. c:\tmp. Bazel will pick those up instead of C:\Users\John\AppData\Local\Temp, so the full path for the output directory (that bazel-bin points to) will be c:\tmp\aS4O8v3V\execroot\__main__\bazel-out\x64_windows-fastbuild\bin.
(b) Or you can pass the --output_user_root startup flag, e.g. bazel--output_user_root=c:\tmp build //:demo. That will have the same effect as (a).
There's currently no way to get rid of the _bazel_John\aS4O8v3V\execroot part of the path.
Yes, I think you need to put those files in pkg_tar.srcs. Whether you use a filegroup() rule is irrelevant; filegroup just lets you group files together, so you can refer to the group by name, which is useful when you need to refer to the same files in multiple rules.
2.a. I don't think so.
Related
I am experimenting with Bazel to be added along with an old, make/shell based build system. I can easily make shell commands which returns an absolute path to some tool or library build by the old build system as early prerequisites. These commands I can use in a genrule(), which copies the needed files (like headers and libs) into Bazel proper to be exposed in form of a cc_library().
I found out that genrule() does not detect a dependency if the command uses a file with absolute path - it is not caught by the sandbox. In a way I am (ab)using that behavior.
It is it safe? Will some future update of Bazel refuse access to files based on absolute path in that way in a command in genrule?
Most of Bazel's sandboxes allow access to most paths outside of the source tree by default. Details depend on which sandbox implementation you're using. The docker sandbox, for example, allows access to all those paths inside of a docker image. It's kind of hard to make promises about future Bazel versions, but I think it's unlikely that a sandbox will prevent accessing /bin/bash (for example), which means other absolute paths will probably continue to work too.
--sandbox_block_path can be used to explicitly block a path if you want.
If you always have the files available on every machine you build on, your setup should work. Keep in mind that Bazel will not recognize when the contents of those files change, so you can easily get stale results in various caches. You can avoid that by ensuring the external paths change whenever their contents do.
new_local_repository might be a better fit to avoid those problems, if you know the paths ahead of time.
If you don't know the paths ahead of time, you can write a custom repository rule which runs arbitrary commands via repository_ctx.execute to retrieve the paths and them symlinks them in with repository_ctx.symlink.
Tensorflow's third_party/sycl/sycl_configure.bzl has an example of doing something similar (you would do something other than looking at environment variables like find_computecpp_root does, and you might symlink entire directories instead of all the files in them):
def _symlink_dir(repository_ctx, src_dir, dest_dir):
"""Symlinks all the files in a directory.
Args:
repository_ctx: The repository context.
src_dir: The source directory.
dest_dir: The destination directory to create the symlinks in.
"""
files = repository_ctx.path(src_dir).readdir()
for src_file in files:
repository_ctx.symlink(src_file, dest_dir + "/" + src_file.basename)
def find_computecpp_root(repository_ctx):
"""Find ComputeCpp compiler."""
sycl_name = ""
if _COMPUTECPP_TOOLKIT_PATH in repository_ctx.os.environ:
sycl_name = repository_ctx.os.environ[_COMPUTECPP_TOOLKIT_PATH].strip()
if sycl_name.startswith("/"):
return sycl_name
fail("Cannot find SYCL compiler, please correct your path")
def _sycl_autoconf_imp(repository_ctx):
<snip>
computecpp_root = find_computecpp_root(repository_ctx)
<snip>
_symlink_dir(repository_ctx, computecpp_root + "/lib", "sycl/lib")
_symlink_dir(repository_ctx, computecpp_root + "/include", "sycl/include")
_symlink_dir(repository_ctx, computecpp_root + "/bin", "sycl/bin")
I'd like to specify an environment variable for use in the source path (library path) at a project level.
We often have a couple of versions checked out of our SVN repository at the same time in different directories, and I'd like to specify the repository root for a project in relative terms at a project level. I could then use that path in a project's source path and I wouldn't have to include indecipherable dot dot slashes (..\) in paths.
For example, say I have checked out trunk to c:\projects\trunk. Then underneath there I have a project in <repositoryroot>\Foo\Bar\ under trunk which uses the Delphi Spring framework under <repositoryroot>\components\external\Spring4d. I end up with a whole bunch of directories in the search path with ..\..\External\Spring4D\Source at the beginning. For example ..\..\External\Spring4D\Source\Base\Collections. I would like to be able to be able to use ${Spring4D} instead, producing ${Spring4D}\Base\Collections\, which is much less wordy and it means that if you move a project or component you can change one value and it updates all paths.
I know that you can do this on a Delphi level by specifying paths in Delphi's environment variables, but I would like to achieve the same thing on a project level or repository level.
Does anyone have any ideas on how to achieve this? Are there any settings or even add-ins that would allow this sort of functionality?
You can manually edit your project file (.dproj) and add a variable there:
<PropertyGroup>
<MyVariableName>MyVariableContent</MyVariableName>
</PropertyGroup>
Later on, you can refer to the content of that variable:
<DCC_UnitSearchPath>C:\Components;$(MyVariableName)</DCC_UnitSearchPath>
You can also define a new environment variable (SystemPropertiesAdvanced.exe -> Environment variables -> Add) and then refer to that variable using the same syntax, e.g.:
<DCC_UnitSearchPath>C:\Components;$(PATH)</DCC_UnitSearchPath>
(Note that it is a very bad idea to use PATH here, it's only an example of a variable which will exist in your environment.)
You could also employ some cmd script magic to to create environment variables that point to those subdirectories and at the end call the IDE, so these environment variables are available in the IDE in the same way as global environment variables would be (see pepak's answer for that).
Pointers:
%0 is the name of the current cmd file
use tilde for file name parts
Given I have a list of files, e.g foo/src/main.cpp, foo/src/bar.cpp, foo/README.md is it possible to determine which of those files are part of a bazel package?
In my example, the output would e.g. be foo/src/main.cpp, foo/src/bar.cpp since the README.md would not be part of the build.
One way to do this would be to call bazel query on each file and see if it results in an output, but that is quite inefficient and so I was wondering if there is an easier way.
Background: I am trying to determine if a changes in a set of files have an impact on a target, and I want to use bazel query somepath(//some/target, set($FILES)) for that, but this will fail if any of the files in $FILES is not part of a BUILD file.
How about flipping it around and querying for all the source files of the target with:
bazel query 'kind("source file", deps(//some:target))'
and then checking if the result has any of the files in the set
I am trying to get a value of the full current directory path from within .bzl rule. I have tried following:
ctx.host_configuration.default_shell_env.PATH returns "/Users/[user_name]/.rbenv/shims:/usr/local/bin:/usr/bin:/bin:...
ctx.bin_dir.path returns bazel-out/local-fastbuild/bin
pwd = ctx.expand_make_variables("cmd", "$$PWD", {}) returns string $PWD - I don't think this rule is helpful for me, but may be just using it wrong.
What I need is the directory under which the cmd that runs Bazel .bzl rule is running. For example: /Users/[user_name]/git/workspace/path/to/bazel/rule.bzl or at least first part of the path prior to the WORKSPACE directory.
I can't use pwd because I need this value before I call ctx.actions.run_shell()
Are there no attributes in Bazel configurations that hold this value?
The goal is to have hermetic builds, so you shouldn't depend on the absolute path.
Feel free to use pwd inside the command of ctx.actions.run_shell() (for reproducible builds, be careful, avoid putting the absolute path in the generated files).
Edit.
Technically, there are some workarounds. For example, you can pass the path via the --define flag:
bazel build :all --define=path=$(pwd)
Then the value will be available using ctx.var["path"].
Based on your comment below, you want the path to declare an output. Let me repeat: You shouldn't use an absolute path to declare the output file. Declare an output in your package. Then ask the tool you call to use that output.
For example, when you call gcc, you can use -o to specify the output. When a tool writes to stdout, use the shell to redirect it. If the tool is really not flexible, you may want to wrap it with your own script (e.g. call the tool and copy the output file).
Using an absolute path here is not the right solution. For example, it should be possible to execute the action on a remote machine (where your absolute path won't make sense.
Zip may be a reasonable solution. It's useful when you cannot know in advance the number or the names of the output files.
I have a couple of job in Jenkins that archive artifact from the source tree for another job (some unit tests or alike). I have the current situation :
top_dir
\scripts_dir
\some_files
\dir1
\dir2
\dir3
\other_dir
I would like to archive all that is in "top_dir" including the files in "scripts_dir", but not the subdirectories "dir1, dir2,...", which I do not know the name, that are in "scripts_dir". These subdirs are actually Windows directory joints that point to other places on the disk, and I do not want them to be copied.
How do I achieve this with the inculde/excludes pattern of Jenkins ?
I already tried, having include=top_dir/ , exclude=
**/scripts_dir/*/
**/scripts_dir/*/**
**/scripts_dir/**/*
but it always exculdes the whole "scripts_dir" folder.
Finally, by using brute force, I found that the following expression does exclude all the files in the subdirectories of scripts_dir (whatever symlink or not), then removing these subdirs, while keeping the files directly in scripts_dir :
**/scripts_dir/**/*/*/
Thanks for the help anyway.
Reading the ANT manual, there an followsymlinks attribute that defaults to true. You said those things you want to exclude are symlinks (although i am not sure if this will work with Windows joints). Try adding followsymlinks=false
Another solution: if all your files under scripts_dir have a set number of characters in the extension, you can put that into your include statement. This will only pickup files with extensions of 3 characters:
**/scripts_dir/*.???
More on this here