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library(randomForest)
rfModel2 = randomForest(formula = Purchased~., data = Network, ntree = 50, importance = TRUE, replace=TRUE)
Error in eval(predvars, data, env) : object 'User ID' not found
The User ID is unique and not needed, how can I get the function to ignore this and work on the 1/0 Purchased column?
Is purchased a value or a factor?
Assuming it is a factor (0: Not Purchased, 1: Purchased for Instance) you will do classification using the following code:
df$Purchased<-as.factor(as.character(df$Purchased))
df$Gender<-as.factor(as.character(df$Gender))
rfModel2<-randomForest(Purchased~.,data=df[,-1])
UserID not included in the calculation
Now if Purchased is a number, meaning the number of items purchased, you should go with regression:
df$Gender<-as.factor(df$Gender)
rfModel2<-randomForest(Purchased~.,data=df[,-1])
and you will get a warning due to the fact that your response variable seems to be a factor
> df$Gender<-as.factor(df$Gender)
> rfModel2<-randomForest(Purchased~.,data=df[,-1])
Warning message:
In randomForest.default(m, y, ...) :
The response has five or fewer unique values. Are you sure you want to do regression?
>
hope this helps
Related
I am trying to create a EA in mql4, but in OrderSend function, when i use some value instead of zero it show ordersend error 130. Please help to solve this problem
Code line is
int order = OrderSend("XAUUSD",OP_SELL,0.01,Bid,3,Bid+20*0.01,tp,"",0,0,Red);
error number 130 means Invalid stops.
so that means there is a problem with the stops you set with the ordersend function.
I suggest you set it like that:
int order = OrderSend("XAUUSD",OP_SELL,0.01,Bid,3,Bid+20*Point,tp,"",0,0,Red);
so you could use Point instead of hard coding it.
and to check what is the error number means. I think you could refer to: https://book.mql4.com/appendix/errors
You should know that there exists a minimum Stop Loss Size (mSLS) given in pips. "mSLS" changes with the currency and broker. So, you need to put in the OnInit() procedure of your EA a variable to get it:
int mSLS = MarketInfo(symbol,MODE_STOPLEVEL);
The distance (in pips) from your Order Open Price (OOP) and the Stop-Loss Price (SLP) can not be smaller than mSLS value.
I will try to explain a general algorithm I use for opening orders in my EAs, and then apply the constrain on Stop-Loss level (at step 3):
Step 1. I introduce a flag (f) for the type of operation I will open, being:
f = 1 for Buy, and
f = -1 for Sell
You know that there are mql4 constants OP_SELL=1 and OP_BUY=0 (https://docs.mql4.com/constants/tradingconstants/orderproperties).
Once I have defined f, I set my operation type variable to
int OP_TYPE = int(0.5((1+f)*OP_BUY+(1-f)*OP_SELL));
that takes value OP_TYPE=OP_BUY when f=1, while OP_TYPE=OP_SELL when f=-1.
NOTE: Regarding the color of the orders I put them in an array
color COL[2]= {clrBlue,clrRed};
then, having OP_TYPE, I set
color COLOR=COL[OP_TYPE];
Step 2. Similarly, I set the Order Open Price as
double OOP = int(0.5*((1+f)*Ask+(1-f)*Bid));
which takes value OOP=Ask when f=1, while OOP=Bid when f=-1.
Step 3. Then, given my desired Stop Loss in pips (an external POSITIVE parameter of my EA, I named sl) I make sure that sl > SLS. In other words, I check
if (sl <= mSLS) // I set my sl as the minimum allowed
{
sl = 1 + mSLS;
}
Step 4. Then I calculate the Stop-Loss Price of the order as
double SLP = OOP - f * sl * Point;
Step 5. Given my desired Take Profit in pips (an external POSITIVE parameter of my EA, I named tp) I calculate the Take-Profit Price (TPP) of the order as
double TPP = OOP + f * tp * Point;
OBSERVATION: I can not affirm, but, according to mql4 documentation, the minimum distance rule between the stop-loss limit prices and the open price also applies to the take profit limit price. In this case, a "tp" check-up needs to be done, similar to that of the sl check-up, above. that is, before calculating TPP it must be executed the control lines below
if (tp <= mSLS) // I set my tp as the minimum allowed
{
tp = 1 + mSLS;
}
Step 5. I call for order opening with a given lot size (ls) and slippage (slip) on the operating currency pair (from where I get the Ask and Bid values)
float ls = 0.01;
int slip = 3; //(pips)
int order = OrderSend(Symbol(),OP_TYPE,ls,OOP,slip,SLP,TPP,"",0,0,COLOR);
Note that with these few lines it is easy to build a function that opens orders of any type under your command, in any currency pair you are operating, without receiving error message 130, passing to the function only 3 parameters: f, sl and tp.
It is worth including in the test phase of your EA a warning when the sl is corrected for being less than the allowed, this will allow you to increase its value so that it does not violate the stop-loss minimum value rule, while you have more control about the risk of its operations. Remember that the "sl" parameter defines how much you will lose if the order fails because the asset price ended up varying too much in the opposite direction to what was expected.
I hope I could help!
Whilst the other two answers are not necessarily wrong (and I will not go over the ground they have already covered), for completeness of answers, they fail to mention that for some brokers (specifically ECN brokers) you must open your order first, without setting a stop loss or take profit. Once the order is opened, use OrderModify() to set you stop loss and/or take profit.
I am using accord.net. I have successfully implemented the two Decision tree algorithms ID3 and C4.5, now I am trying to implement the Naive Bays algorithm. While there is a lot of sample code on the site, most of it seems to be out of date, or have various issues.
The best sample code I have found on the site so far has been here:
http://accord-framework.net/docs/html/T_Accord_MachineLearning_Bayes_NaiveBayes_1.htm
However, when I try and run that code against my data I get:
There are no samples for class label 1. Please make sure that class
labels are contiguous and there is at least one training sample for
each label.
from line 228 of this file:
https://github.com/accord-net/framework/blob/master/Sources/Accord.MachineLearning/Tools.cs
when I call
learner.learn(inputs, outputs) in my code.
I have already run into the Null bugs that accord has when implementing the other two regression trees, and my data has been sanitized against that issue.
Does any accord.net expert have an idea what would trigger this error?
An excerpt from my code:
var codebook = new Codification(fulldata, AllAttributeNames);
/*
* Get list of all possible combinations
* Status software blows up if it encounters a value it has not seen before.
*/
var attributList = new List<IUnivariateFittableDistribution>();
foreach (var attr in DeciAttributeNames)
{
{
/*
* By default we'll use a standard static list of values for this column
*/
var cntLst = codebook[attr].NumberOfSymbols;
// no decisions can be made off of the variable if it is a constant value
if (cntLst > 1)
{
KeptAttributeNames.Add(attr);
attributList.Add(new GeneralDiscreteDistribution(cntLst));
}
}
}
var data = fulldata.Copy(); // this is a datatable
/*
* Translate our training data into integer symbols using our codebook
*/
DataTable symbols = codebook.Apply(data, AllAttributeNames);
double[][] inputs = symbols.ToJagged<double>(KeptAttributeNames.ToArray());
int[] outputs = symbols.ToArray<int>(OutAttributeName);
progBar.PerformStep();
/*
* Create a new instance of the learning algorithm
* and build the algorithm
*/
var learner = new NaiveBayesLearning<IUnivariateFittableDistribution>()
{
// Tell the learner how to initialize the distributions
Distribution = (classIndex, variableIndex) => attributList[variableIndex]
};
var alg = learner.Learn(inputs, outputs);
EDIT: After further experimentation, it seems as though this error only occurs when I am processing a certain number of rows. If I process 60 rows or less than I am fine, if I process 500 rows or more then I am fine. But in between that range I throw this error. Depending on the amount of data I choose, the index number in the error message can change, I have seen it range from 0 to 2.
All the data is coming from the same sql server datasource, the only thing I am adjusting is the Select Top ### portion of the query.
You will receive this error in multi-class scenarios when you have defined a label that does not have any sample data. With a small data set your random sampling may by chance exclude all observations with a given label.
hello I want to select a subchain and analyze it example:
my chain to analyze
NADSU 78000mc0cl0Css
NADBY 7808810008659
PAT 1 21D 089
I need to read and then analyze line by line of a .txt file after that I would like to verify through an if or case cycle that the paramenters could be fulfilled. I clarify the txt file has about 300 lines
the first three characters must be letters with a specific format the following is usually the 4 character or 5 that has a number depends on that number means something and the last is the purchase order number or the amount or type of wrap ... ... this is a generalized idea I'm only giving the minimum to understand ...
Annex example and my code
I put two real cases of the line to analyze
--- here the letters nad = purchase order BY = supplier the remaining one is the purchase order number
NADBY 7808810008659
--- here Pat means = type of payment. the first number = the type of payment if it is one the type of payment is counted if it is two credits. the average 21d = number of days to issue clearance and the 089 = number of days to pay
PAT 1 21D 089
--- here the letters nad = purchase order BY = buyer css = a boxes but it can be ss = minicams
NADSU 78000mc0cl0Css
fileopen ('nombre_doc.txt',r) do |fichero1|
fileopen ('copianombre_doc.txt',w) do |fichero2|
while linea= fichero1.gets
fichero1=gsub(/\s+/,'')
I am making a bank on Minecraft.
I am having trouble with saving a variable after addition or subtraction has been done to it.
For example, if x="balance", x=15, say I want to withdraw from my balance:
x = 15 - y(withdrawn money)
The variable is not saved when the program is run again.
If you want data persistence between program runs, you need to store the data in files. For example, you could save the variable x to a file like this:
h = fs.open("filename","w")
h.writeLine(x)
h.close()
And you could load it like this:
h = fs.open("filename","r")
x = tonumber(h.readLine())
h.close()
Here is the documentation. http://computercraft.info/wiki/Fs.open
Here is a first stab at it. I suppose the account balance is stored in x. Then the following function will withdraw and return money from x.
-- wa is amount to withdraw
-- this function withdraws the maximum allowable
function withdraw(wa)
if wa>0 then
wt=math.min(x,wa)
if wa <= x then
x=x-wt
return wt
end
end
return 0
end
A far more sophisticated way to keep accounts is available in the PiL book: http://www.lua.org/pil/16.html
I am generating a unique and random alphanumeric string segment to represent certain links that will be generated by the users. For doing that I was approaching with "uuid" number to ensure it's uniqueness and randomness, but, as per my requirements the string shouldn't be more than 5 characters long. So I dropped that idea.
Then I decided to generate such a string using random function of ruby and current time stamp.
The code for my random string goes like this:-
temp=DateTime.now
temp=temp + rand(DateTime.now.to_i)
temp= hash.abs.to_s(36)
What I did is that I stored the current DateTime in a temp variable and then I generated a random number passing the current datetime as parameter. Then in the second line actually added current datetime and random number together to make a unique and random string.
Soon I found,while I was testing my application in two different machines and send the request at the same time, it generated the same string(Though it's rare) once after more than 100 trials.
Now I'm thinking that I should add one more parameter like mac address or client ip address before passing to_s(36) on temp variable. But can't figure out how to do it and even then whether it will be unique or nor...
Thanks....
SecureRandom in ruby uses process id (if available) and current time. You can use the urlsafe_base64(n= 16) class method to generate the sequence you need. According to your requirements I think this is your best bet.
Edit: After a bit of testing, I still think that this approach will generate non-unique keys. The way I solved this problem for barcode generation was:
barcode= barcode_sql_id_hash("#{sql_id}#{keyword}")
Here, your keyword can be time + pid.
If you are certain that you will never need more than a given M amount of unique values, and you don't need more than rudimentary protection against guessing the next generated id, you can use a Linear Congruentual Generator to generate your identificators. All you have to do is remember the last id generated, and use that to generate a new one using the following formula:
newid = (A * oldid + B) mod M
If 2³² distinct id values are enough to suit your needs, try:
def generate_id
if #lcg
#lcg = (1664525 * #lcg + 1013904223) % (2**32)
else
#lcg = rand(2**32) # Random seed
end
end
Now just pick a suitable set of characters to represent the id in as little as 6 character. Uppercase and lowercase letters should do the trick, since (26+26)^6 > 2^32:
ENCODE_CHARS = [*?a..?z, *?A..?Z]
def encode(n)
6.times.map { |i|
n, mod = n.divmod(ENCODE_CHARS.size)
ENCODE_CHARS[mod]
}.join
end
Example:
> 10.times { n = generate_id ; puts "%10d = %s" % [n, encode(n)] }
2574974483 = dyhjOg
3636751446 = QxyuDj
368621501 = bBGvYa
1689949688 = yuTgxe
1457610999 = NqzsRd
3936504298 = MPpusk
133820481 = PQLpsa
2956135596 = yvXpOh
3269402651 = VFUhFi
724653758 = knLfVb
Due to the nature of the LCG, the generated id will not repeat until all 2³² values have been used exactly once each.
There is no way you can generate a unique UUID with only five chars, with chars and numbers you have a basic space of around 56 chars, so there is a max of 56^5 combinations , aprox 551 million (Around 2^29).
If with this scheme you were about to generate 10.000 UUIDs (A very low number of UUIDs) you would have a probability of 1/5.000 of generating a collision.
When using crypto, the standard definition of a big enough space to avert collisions is around 2^80.
To put this into perspective, your algorithm would be better off if it generated just a random integer (a 32 bit uint is 2^32, 8 times the size you are proposing) which is clearly a bad idea.