I want to remove white spaces present inside the array values
(I have scor=["1 "," 1"]). Here, first value has white space on right and second value has white space on left. How to remove those white spaces in neo4j?
The cyper has a rich set of functions for working with strings.
In your case, you need the trim function:
UNWIND ["1", "2 ", " 3", " 4 "] as e
RETURN trim(e)
Related
When I use ="""" & TEXT("1468", "# ###") & """", "1 468" is returned. Perfect.
However, once 4 digits become 3 digits, I get an empty space at the beginning. " 468". Not perfect.
enter image description here
What text format can I use to avoid that empty space?
Just wrap the inner portion in TRIM( ):
="""" & TRIM(TEXT("468", "# ###")) & """"
TRIM removes superfluous leading, trailing and interposed space characters.
I am trying to split this number that is in one cell of its own in I2: 0000320193-20-000096
However, when I use the formula '=split(I2, "-")', it gives me three cells with the following: "320193" , "20" , "96".
I need the zeroes behind each number to stay with each number, I just need the hyphens to be removed and each separate number to be in their own cells.
I have tried '=split(I2, "'-")'; however, this does not work either.
In addition, all the cells are formatted to be "plain text."
I can make it work if I use the "split by column" tool; however, it's tedious and removes the surrounding text to I2, which I need.
How can I change this formula to keep the zeroes in front of each number?
Thanks!
Try this:
=ARRAYFORMULA(SUBSTITUTE(SPLIT("'"&I2&"'", "-"), "'", ""))
This will append apostrophe in the beginning and end of cell I2 to avoid auto formatting and since SPLIT return an array, we need ARRAYFORMULA to apply the SUBSTITUTE to all array element.
Output:
References:
SUBSTITUTE
ARRAYFORMULA
SPLIT
try:
=INDEX(REGEXEXTRACT(SPLIT("'"&SUBSTITUTE(A1, "-", "'-'")&"'", "-"), "(.*)'"))
Use regexextract(), like this:
=regexextract(I2, "(\d+)-(\d+)-(\d+)")
Im trying to use array formula to list multiple "rows" without the blank cells not from another area in the sheet.
=ArrayFormula(IFERROR(FILTER(GE2:HQ2,LEN(GE2:HQ2)),""))
Also tried
=ArrayFormula(IFERROR(FILTER(GE2:HQ,LEN(GE2:HQ)),""))
Neither returns an array effect. Also tried dragging down the formula to expand the whole sheet. Which works, until a form is submitted. Then the cell in that row loses its formula
Link to an example Sheet
https://docs.google.com/spreadsheets/d/e/2PACX-1vSl8Olx8fYsgROoCU6xLq4M53liT16DgEgtw1RAt0uqpWPosUGZ6aXjBP5UF5pS6y0ZBwAF-8pZrjZR/pubhtml
Any advice would be appreciated
use:
=INDEX(SPLIT(FLATTEN(QUERY(TRANSPOSE(A2:G4),,9^9)), " "))
if dataset contains words in cells use:
=INDEX(SUBSTITUTE(SPLIT(FLATTEN(QUERY(TRANSPOSE(
SUBSTITUTE(A2:G4, " ", "♥")),,9^9)), " "), "♥", " "))
Say...
cell 1 contains this text: 03400561, 1995-12-31
I need a way to split this cell into 2 raw text columns". i.e.
My expected/wanted output: cell 2 = 03400561 (as text) and cell 3 = 1995-12-31 (as text)
If I use the split function to do this (e.g. cell 2 = split(cell1,",")), it removes leading zero, and convert the yyyy-mm-dd text into a google date. I do not wish to have this conversion to take place. i.e. I just wanted straight and simple split a text, into columns of text (not numbers. not dates).
How do I do this out of the box? (I've tried google around but no luck). Is this even possible?
Side note: the "Data" => "Split text into columns" approach - no luck. It converts all numeric-like texts into numbers, and date-like texts into dates. I wish to have raw text throughout and no conversion like this to happen. How to do this?
Ugly as hell, but seems to work on your example. Basically enclose the separator with double quotation marks to force sheets into interpreting the data as text. Then remove them and use arrayformula() to cover all the columns:
=arrayformula(substitute(SPLIT(char(34)&substitute(U19,",",char(34)&","&char(34))&char(34),",",true,false),char(34),""))
CHAR(34) evaluates to double quotation (i.e. ") to signify text entry. Just be aware that the second variable includes a leading space (' 1995-12-31')
BJ190215P00020000
this is the string. I want to extract the left letters "BJ" (they are from 1 letter up to letters).
I think i need to find the position of the first digit, then apply LEFT function to get out the "BJ". (the letters could be 1-8).
is there a way to find the position of first digit in the string. OR, is there a better way to extract the letters before the first digit?
Try ...
=regexextract(A1,"\D+")